e(y) = x;
// error: refutable pattern in local binding: `None` not covered
```

If you encounter this error you probably need to use a `match` or `if let` to
deal with the possibility of failure. Example:

```
let x = Some(1);

match x {
    Some(y) => {
        // do something
    },
    None => {}
}

// or:

if let Some(y) = x {
    // do something
}
```
#### Note: this error code is no longer emitted by the compiler.

This error indicates that the bindings in a match arm would require a value to
be moved into more than one location, thus violating unique ownership. Code
like the following is invalid as it requires the entire `Option<String>` to be
moved into a variable called `op_string` while simultaneously requiring the
inner `String` to be moved into a variable called `s`.

Erroneous code example:

```compile_fail,E0382
#![feature(bindings_after_at)]

let x = Some("s".to_string());

match x {
    op_string @ Some(s) => {}, // error: use of moved value
    None => {},
}
```

See also the error E0303.
#### Note: this error code is no longer emitted by the compiler.

In a pattern, all values that don't implement the `Copy` trait have to be bound
the same way. The goal here is to avoid binding simultaneously by-move and
by-ref.

This limitation may be removed in a future version of Rust.

Erroneous code example:

```
#![feature(move_ref_pattern)]

struct X { x: (), }

let x = Some((X { x: () }, X { x: () }));
match x {
    Some((y, ref z)) => {}, // error: cannot bind by-move and by-ref in the
                            //        same pattern
    None => panic!()
}
```

You have two solutions:

Solution #1: Bind the pattern's values the same way.

```
struct X { x: (), }

let x = Some((X { x: () }, X { x: () }));
match x {
    Some((ref y, ref z)) => {},
    // or Some((y, z)) => {}
    None => panic!()
}
```

Solution #2: Implement the `Copy` trait for the `X` structure.

However, please keep in mind that the first solution should be preferred.

```
#[derive(Clone, Copy)]
struct X { x: (), }

let x = Some((X { x: () }, X { x: () }));
match x {
    Some((y, ref z)) => {},
    None => panic!()
}
```
The value of statics and constants must be known at compile time, and they live
for the entire lifetime of a program. Creating a boxed value allocates memory on
the heap at runtime, and therefore cannot be done at compile time.

Erroneous code example:

```compile_fail,E0010
const CON : Vec<i32> = vec![1, 2, 3];
```
#### Note: this error code is no longer emitted by the compiler

Static and const variables can refer to other const variables. But a const
variable cannot refer to a static variable.

Erroneous code example:

```
static X: i32 = 42;
const Y: i32 = X;
```

In this example, `Y` cannot refer to `X`. To fix this, the value can be
extracted as a const and then used:

```
const A: i32 = 42;
static X: i32 = A;
const Y: i32 = A;
```
#### Note: this error code is no longer emitted by the compiler.

Constants can only be initialized by a constant value or, in a future
version of Rust, a call to a const function. This error indicates the use
of a path (like a::b, or x) denoting something other than one of these
allowed items.

Erroneous code example:

```
const FOO: i32 = { let x = 0; x }; // 'x' isn't a constant nor a function!
```

To avoid it, you have to replace the non-constant value:

```
const FOO: i32 = { const X : i32 = 0; X };
// or even:
const FOO2: i32 = { 0 }; // but brackets are useless here
```
A non-`const` function was called in a `const` context.

Erroneous code example:

```compile_fail,E0015
fn create_some() -> Option<u8> {
    Some(1)
}

// error: cannot call non-const function `create_some` in constants
const FOO: Option<u8> = create_some();
```

All functions used in a `const` context (constant or static expression) must
be marked `const`.

To fix this error, you can declare `create_some` as a constant function:

```
// declared as a `const` function:
const fn create_some() -> Option<u8> {
    Some(1)
}

const FOO: Option<u8> = create_some(); // no error!
```
A pattern attempted to extract an incorrect number of fields from a variant.

Erroneous code example:

```compile_fail,E0023
enum Fruit {
    Apple(String, String),
    Pear(u32),
}

let x = Fruit::Apple(String::new(), String::new());

match x {
    Fruit::Apple(a) => {}, // error!
    _ => {}
}
```

A pattern used to match against an enum variant must provide a sub-pattern for
each field of the enum variant.

Here the `Apple` variant has two fields, and should be matched against like so:

```
enum Fruit {
    Apple(String, String),
    Pear(u32),
}

let x = Fruit::Apple(String::new(), String::new());

// Correct.
match x {
    Fruit::Apple(a, b) => {},
    _ => {}
}
```

Matching with the wrong number of fields has no sensible interpretation:

```compile_fail,E0023
enum Fruit {
    Apple(String, String),
    Pear(u32),
}

let x = Fruit::Apple(String::new(), String::new());

// Incorrect.
match x {
    Fruit::Apple(a) => {},
    Fruit::Apple(a, b, c) => {},
}
```

Check how many fields the enum was declared with and ensure that your pattern
uses the same number.
Each field of a struct can only be bound once in a pattern.

Erroneous code example:

```compile_fail,E0025
struct Foo {
    a: u8,
    b: u8,
}

fn main(){
    let x = Foo { a:1, b:2 };

    let Foo { a: x, a: y } = x;
    // error: field `a` bound multiple times in the pattern
}
```

Each occurrence of a field name binds the value of that field, so to fix this
error you will have to remove or alter the duplicate uses of the field name.
Perhaps you misspelled another field name? Example:

```
struct Foo {
    a: u8,
    b: u8,
}

fn main(){
    let x = Foo { a:1, b:2 };

    let Foo { a: x, b: y } = x; // ok!
}
```
A struct pattern attempted to extract a nonexistent field from a struct.

Erroneous code example:

```compile_fail,E0026
struct Thing {
    x: u32,
    y: u32,
}

let thing = Thing { x: 0, y: 0 };

match thing {
    Thing { x, z } => {} // error: `Thing::z` field doesn't exist
}
```

If you are using shorthand field patterns but want to refer to the struct field
by a different name, you should rename it explicitly. Struct fields are
identified by the name used before the colon `:` so struct patterns should
resemble the declaration of the struct type being matched.

```
struct Thing {
    x: u32,
    y: u32,
}

let thing = Thing { x: 0, y: 0 };

match thing {
    Thing { x, y: z } => {} // we renamed `y` to `z`
}
```
A pattern for a struct fails to specify a sub-pattern for every one of the
struct's fields.

Erroneous code example:

```compile_fail,E0027
struct Dog {
    name: String,
    age: u32,
}

let d = Dog { name: "Rusty".to_string(), age: 8 };

// This is incorrect.
match d {
    Dog { age: x } => {}
}
```

To fix this error, ensure that each field from the struct's definition is
mentioned in the pattern, or use `..` to ignore unwanted fields. Example:

```
struct Dog {
    name: String,
    age: u32,
}

let d = Dog { name: "Rusty".to_string(), age: 8 };

match d {
    Dog { name: ref n, age: x } => {}
}

// This is also correct (ignore unused fields).
match d {
    Dog { age: x, .. } => {}
}
```
Something other than numbers and characters has been used for a range.

Erroneous code example:

```compile_fail,E0029
let string = "salutations !";

// The ordering relation for strings cannot be evaluated at compile time,
// so this doesn't work:
match string {
    "hello" ..= "world" => {}
    _ => {}
}

// This is a more general version, using a guard:
match string {
    s if s >= "hello" && s <= "world" => {}
    _ => {}
}
```

In a match expression, only numbers and characters can be matched against a
range. This is because the compiler checks that the range is non-empty at
compile-time, and is unable to evaluate arbitrary comparison functions. If you
want to capture values of an orderable type between two end-points, you can use
a guard.
When matching against a range, the compiler verifies that the range is
non-empty. Range patterns include both end-points, so this is equivalent to
requiring the start of the range to be less than or equal to the end of the
range.

Erroneous code example:

```compile_fail,E0030
match 5u32 {
    // This range is ok, albeit pointless.
    1 ..= 1 => {}
    // This range is empty, and the compiler can tell.
    1000 ..= 5 => {}
}
```
A trait type has been dereferenced.

Erroneous code example:

```compile_fail,E0033
# trait SomeTrait { fn method_one(&self){} fn method_two(&self){} }
# impl<T> SomeTrait for T {}
let trait_obj: &SomeTrait = &"some_value";

// This tries to implicitly dereference to create an unsized local variable.
let &invalid = trait_obj;

// You can call methods without binding to the value being pointed at.
trait_obj.method_one();
trait_obj.method_two();
```

A pointer to a trait type cannot be implicitly dereferenced by a pattern. Every
trait defines a type, but because the size of trait implementers isn't fixed,
this type has no compile-time size. Therefore, all accesses to trait types must
be through pointers. If you encounter this error you should try to avoid
dereferencing the pointer.

You can read more about trait objects in the [Trait Objects] section of the
Reference.

[Trait Objects]: https://doc.rust-lang.org/reference/types.html#trait-objects
The compiler doesn't know what method to call because more than one method
has the same prototype.

Erroneous code example:

```compile_fail,E0034
struct Test;

trait Trait1 {
    fn foo();
}

trait Trait2 {
    fn foo();
}

impl Trait1 for Test { fn foo() {} }
impl Trait2 for Test { fn foo() {} }

fn main() {
    Test::foo() // error, which foo() to call?
}
```

To avoid this error, you have to keep only one of them and remove the others.
So let's take our example and fix it:

```
struct Test;

trait Trait1 {
    fn foo();
}

impl Trait1 for Test { fn foo() {} }

fn main() {
    Test::foo() // and now that's good!
}
```

However, a better solution would be using fully explicit naming of type and
trait:

```
struct Test;

trait Trait1 {
    fn foo();
}

trait Trait2 {
    fn foo();
}

impl Trait1 for Test { fn foo() {} }
impl Trait2 for Test { fn foo() {} }

fn main() {
    <Test as Trait1>::foo()
}
```

One last example:

```
trait F {
    fn m(&self);
}

trait G {
    fn m(&self);
}

struct X;

impl F for X { fn m(&self) { println!("I am F"); } }
impl G for X { fn m(&self) { println!("I am G"); } }

fn main() {
    let f = X;

    F::m(&f); // it displays "I am F"
    G::m(&f); // it displays "I am G"
}
```
For any given trait `Trait` there may be a related _type_ called the _trait
object type_ which is typically written as `dyn Trait`. In earlier editions of
Rust, trait object types were written as plain `Trait` (just the name of the
trait, written in type positions) but this was a bit too confusing, so we now
write `dyn Trait`.

Some traits are not allowed to be used as trait object types. The traits that
are allowed to be used as trait object types are called "dyn-compatible"[^1]
traits. Attempting to use a trait object type for a trait that is not
dyn-compatible will trigger error E0038.

Two general aspects of trait object types give rise to the restrictions:

  1. Trait object types are dynamically sized types (DSTs), and trait objects of
     these types can only be accessed through pointers, such as `&dyn Trait` or
     `Box<dyn Trait>`. The size of such a pointer is known, but the size of the
     `dyn Trait` object pointed-to by the pointer is _opaque_ to code working
     with it, and different trait objects with the same trait object type may
     have different sizes.

  2. The pointer used to access a trait object is paired with an extra pointer
     to a "virtual method table" or "vtable", which is used to implement dynamic
     dispatch to the object's implementations of the trait's methods. There is a
     single such vtable for each trait implementation, but different trait
     objects with the same trait object type may point to vtables from different
     implementations.

The specific conditions that violate dyn-compatibility follow, most of which
relate to missing size information and vtable polymorphism arising from these
aspects.

[^1]: Formerly known as "object-safe".

### The trait requires `Self: Sized`

Traits that are declared as `Trait: Sized` or which otherwise inherit a
constraint of `Self:Sized` are not dyn-compatible.

The reasoning behind this is somewhat subtle. It derives from the fact that Rust
requires (and defines) that every trait object type `dyn Trait` automatically
implements `Trait`. Rust does this to simplify error reporting and ease
interoperation between static and dynamic polymorphism. For example, this code
works:

```
trait Trait {
}

fn static_foo<T:Trait + ?Sized>(b: &T) {
}

fn dynamic_bar(a: &dyn Trait) {
    static_foo(a)
}
```

This code works because `dyn Trait`, if it exists, always implements `Trait`.

However as we know, any `dyn Trait` is also unsized, and so it can never
implement a sized trait like `Trait:Sized`. So, rather than allow an exception
to the rule that `dyn Trait` always implements `Trait`, Rust chooses to prohibit
such a `dyn Trait` from existing at all.

Only unsized traits are considered dyn-compatible.

Generally, `Self: Sized` is used to indicate that the trait should not be used
as a trait object. If the trait comes from your own crate, consider removing
this restriction.

### Method references the `Self` type in its parameters or return type

This happens when a trait has a method like the following:

```
trait Trait {
    fn foo(&self) -> Self;
}

impl Trait for String {
    fn foo(&self) -> Self {
        "hi".to_owned()
    }
}

impl Trait for u8 {
    fn foo(&self) -> Self {
        1
    }
}
```

(Note that `&self` and `&mut self` are okay, it's additional `Self` types which
cause this problem.)

In such a case, the compiler cannot predict the return type of `foo()` in a
situation like the following:

```compile_fail,E0038
trait Trait {
    fn foo(&self) -> Self;
}

fn call_foo(x: Box<dyn Trait>) {
    let y = x.foo(); // What type is y?
    // ...
}
```

If only some methods aren't dyn-compatible, you can add a `where Self: Sized`
bound on them to mark them as explicitly unavailable to trait objects. The
functionality will still be available to all other implementers, including
`Box<dyn Trait>` which is itself sized (assuming you `impl Trait for Box<dyn
Trait>`).

```
trait Trait {
    fn foo(&self) -> Self where Self: Sized;
    // more functions
}
```

Now, `foo()` can no longer be called on a trait object, but you will now be
allowed to make a trait object, and that will be able to call any dyn-compatible
methods. With such a bound, one can still call `foo()` on types implementing
that trait that aren't behind trait objects.

### Method has generic type parameters

As mentioned before, trait objects contain pointers to method tables. So, if we
have:

```
trait Trait {
    fn foo(&self);
}

impl Trait for String {
    fn foo(&self) {
        // implementation 1
    }
}

impl Trait for u8 {
    fn foo(&self) {
        // implementation 2
    }
}
// ...
```

At compile time each implementation of `Trait` will produce a table containing
the various methods (and other items) related to the implementation, which will
be used as the virtual method table for a `dyn Trait` object derived from that
implementation.

This works fine, but when the method gains generic parameters, we can have a
problem.

Usually, generic parameters get _monomorphized_. For example, if I have

```
fn foo<T>(x: T) {
    // ...
}
```

The machine code for `foo::<u8>()`, `foo::<bool>()`, `foo::<String>()`, or any
other instantiation is different. Hence the compiler generates the
implementation on-demand. If you call `foo()` with a `bool` parameter, the
compiler will only generate code for `foo::<bool>()`. When we have additional
type parameters, the number of monomorphized implementations the compiler
generates does not grow drastically, since the compiler will only generate an
implementation if the function is called with fully concrete arguments
(i.e., arguments which do not contain any generic parameters).

However, with trait objects we have to make a table containing _every_ object
that implements the trait. Now, if it has type parameters, we need to add
implementations for every type that implements the trait, and there could
theoretically be an infinite number of types.

For example, with:

```
trait Trait {
    fn foo<T>(&self, on: T);
    // more methods
}

impl Trait for String {
    fn foo<T>(&self, on: T) {
        // implementation 1
    }
}

impl Trait for u8 {
    fn foo<T>(&self, on: T) {
        // implementation 2
    }
}

// 8 more implementations
```

Now, if we have the following code:

```compile_fail,E0038
# trait Trait { fn foo<T>(&self, on: T); }
# impl Trait for String { fn foo<T>(&self, on: T) {} }
# impl Trait for u8 { fn foo<T>(&self, on: T) {} }
# impl Trait for bool { fn foo<T>(&self, on: T) {} }
# // etc.
fn call_foo(thing: Box<dyn Trait>) {
    thing.foo(true); // this could be any one of the 8 types above
    thing.foo(1);
    thing.foo("hello");
}
```

We don't just need to create a table of all implementations of all methods of
`Trait`, we need to create such a table, for each different type fed to
`foo()`. In this case this turns out to be (10 types implementing `Trait`)\*(3
types being fed to `foo()`) = 30 implementations!

With real world traits these numbers can grow drastically.

To fix this, it is suggested to use a `where Self: Sized` bound similar to the
fix for the sub-error above if you do not intend to call the method with type
parameters:

```
trait Trait {
    fn foo<T>(&self, on: T) where Self: Sized;
    // more methods
}
```

If this is not an option, consider replacing the type parameter with another
trait object (e.g., if `T: OtherTrait`, use `on: Box<dyn OtherTrait>`). If the
number of types you intend to feed to this method is limited, consider manually
listing out the methods of different types.

### Method has no receiver

Methods that do not take a `self` parameter can't be called since there won't be
a way to get a pointer to the method table for them.

```
trait Foo {
    fn foo() -> u8;
}
```

This could be called as `<Foo as Foo>::foo()`, which would not be able to pick
an implementation.

Adding a `Self: Sized` bound to these methods will generally make this compile.

```
trait Foo {
    fn foo() -> u8 where Self: Sized;
}
```

### Trait contains associated constants

Just like static functions, associated constants aren't stored on the method
table. If the trait or any subtrait contain an associated constant, they are not
dyn compatible.

```compile_fail,E0038
trait Foo {
    const X: i32;
}

impl dyn Foo {}
```

A simple workaround is to use a helper method instead:

```
trait Foo {
    fn x(&self) -> i32;
}
```

### Trait uses `Self` as a type parameter in the supertrait listing

This is similar to the second sub-error, but subtler. It happens in situations
like the following:

```compile_fail,E0038
trait Super<A: ?Sized> {}

trait Trait: Super<Self> {
}

struct Foo;

impl Super<Foo> for Foo{}

impl Trait for Foo {}

fn main() {
    let x: Box<dyn Trait>;
}
```

Here, the supertrait might have methods as follows:

```
trait Super<A: ?Sized> {
    fn get_a(&self) -> &A; // note that this is dyn-compatible!
}
```

If the trait `Trait` was deriving from something like `Super<String>` or
`Super<T>` (where `Foo` itself is `Foo<T>`), this is okay, because given a type
`get_a()` will definitely return an object of that type.

However, if it derives from `Super<Self>`, even though `Super` is
dyn-compatible, the method `get_a()` would return an object of unknown type when
called on the function. `Self` type parameters let us make dyn-compatible traits
no longer compatible, so they are forbidden when specifying supertraits.

There's no easy fix for this. Generally, code will need to be refactored so that
you no longer need to derive from `Super<Self>`.
It is not allowed to manually call destructors in Rust.

Erroneous code example:

```compile_fail,E0040
struct Foo {
    x: i32,
}

impl Drop for Foo {
    fn drop(&mut self) {
        println!("kaboom");
    }
}

fn main() {
    let mut x = Foo { x: -7 };
    x.drop(); // error: explicit use of destructor method
}
```

It is unnecessary to do this since `drop` is called automatically whenever a
value goes out of scope. However, if you really need to drop a value by hand,
you can use the `std::mem::drop` function:

```
struct Foo {
    x: i32,
}
impl Drop for Foo {
    fn drop(&mut self) {
        println!("kaboom");
    }
}
fn main() {
    let mut x = Foo { x: -7 };
    drop(x); // ok!
}
```
You cannot use type or const parameters on foreign items.

Example of erroneous code:

```compile_fail,E0044
extern "C" { fn some_func<T>(x: T); }
```

To fix this, replace the generic parameter with the specializations that you
need:

```
extern "C" { fn some_func_i32(x: i32); }
extern "C" { fn some_func_i64(x: i64); }
```
Variadic parameters have been used on a non-C ABI function.

Erroneous code example:

```compile_fail,E0045
extern "Rust" {
    fn foo(x: u8, ...); // error!
}
```

Rust only supports variadic parameters for interoperability with C code in its
FFI. As such, variadic parameters can only be used with functions which are
using the C ABI. To fix such code, put them in an extern "C" block:

```
extern "C" {
    fn foo (x: u8, ...);
}
```
Items are missing in a trait implementation.

Erroneous code example:

```compile_fail,E0046
trait Foo {
    fn foo();
}

struct Bar;

impl Foo for Bar {}
// error: not all trait items implemented, missing: `foo`
```

When trying to make some type implement a trait `Foo`, you must, at minimum,
provide implementations for all of `Foo`'s required methods (meaning the
methods that do not have default implementations), as well as any required
trait items like associated types or constants. Example:

```
trait Foo {
    fn foo();
}

struct Bar;

impl Foo for Bar {
    fn foo() {} // ok!
}
```
An attempted implementation of a trait method has the wrong number of type or
const parameters.

Erroneous code example:

```compile_fail,E0049
trait Foo {
    fn foo<T: Default>(x: T) -> Self;
}

struct Bar;

// error: method `foo` has 0 type parameters but its trait declaration has 1
// type parameter
impl Foo for Bar {
    fn foo(x: bool) -> Self { Bar }
}
```

For example, the `Foo` trait has a method `foo` with a type parameter `T`,
but the implementation of `foo` for the type `Bar` is missing this parameter.
To fix this error, they must have the same type parameters:

```
trait Foo {
    fn foo<T: Default>(x: T) -> Self;
}

struct Bar;

impl Foo for Bar {
    fn foo<T: Default>(x: T) -> Self { // ok!
        Bar
    }
}
```
An attempted implementation of a trait method has the wrong number of function
parameters.

Erroneous code example:

```compile_fail,E0050
trait Foo {
    fn foo(&self, x: u8) -> bool;
}

struct Bar;

// error: method `foo` has 1 parameter but the declaration in trait `Foo::foo`
// has 2
impl Foo for Bar {
    fn foo(&self) -> bool { true }
}
```

For example, the `Foo` trait has a method `foo` with two function parameters
(`&self` and `u8`), but the implementation of `foo` for the type `Bar` omits
the `u8` parameter. To fix this error, they must have the same parameters:

```
trait Foo {
    fn foo(&self, x: u8) -> bool;
}

struct Bar;

impl Foo for Bar {
    fn foo(&self, x: u8) -> bool { // ok!
        true
    }
}
```
The parameters of any trait method must match between a trait implementation
and the trait definition.

Erroneous code example:

```compile_fail,E0053
trait Foo {
    fn foo(x: u16);
    fn bar(&self);
}

struct Bar;

impl Foo for Bar {
    // error, expected u16, found i16
    fn foo(x: i16) { }

    // error, types differ in mutability
    fn bar(&mut self) { }
}
```
It is not allowed to cast to a bool.

Erroneous code example:

```compile_fail,E0054
let x = 5;

// Not allowed, won't compile
let x_is_nonzero = x as bool;
```

If you are trying to cast a numeric type to a bool, you can compare it with
zero instead:

```
let x = 5;

// Ok
let x_is_nonzero = x != 0;
```
During a method call, a value is automatically dereferenced as many times as
needed to make the value's type match the method's receiver. The catch is that
the compiler will only attempt to dereference a number of times up to the
recursion limit (which can be set via the `recursion_limit` attribute).

For a somewhat artificial example:

```compile_fail,E0055
#![recursion_limit="4"]

struct Foo;

impl Foo {
    fn foo(&self) {}
}

fn main() {
    let foo = Foo;
    let ref_foo = &&&&&Foo;

    // error, reached the recursion limit while auto-dereferencing `&&&&&Foo`
    ref_foo.foo();
}
```

One fix may be to increase the recursion limit. Note that it is possible to
create an infinite recursion of dereferencing, in which case the only fix is to
somehow break the recursion.
An invalid number of arguments was given when calling a closure.

Erroneous code example:

```compile_fail,E0057
let f = |x| x * 3;
let a = f();        // invalid, too few parameters
let b = f(4);       // this works!
let c = f(2, 3);    // invalid, too many parameters
```

When invoking closures or other implementations of the function traits `Fn`,
`FnMut` or `FnOnce` using call notation, the number of parameters passed to the
function must match its definition.

A generic function must be treated similarly:

```
fn foo<F: Fn()>(f: F) {
    f(); // this is valid, but f(3) would not work
}
```
The built-in function traits are generic over a tuple of the function arguments.
If one uses angle-bracket notation (`Fn<(T,), Output=U>`) instead of parentheses
(`Fn(T) -> U`) to denote the function trait, the type parameter should be a
tuple. Otherwise function call notation cannot be used and the trait will not be
implemented by closures.

The most likely source of this error is using angle-bracket notation without
wrapping the function argument type into a tuple, for example:

```compile_fail,E0059
#![feature(unboxed_closures)]

fn foo<F: Fn<i32>>(f: F) -> F::Output { f(3) }
```

It can be fixed by adjusting the trait bound like this:

```
#![feature(unboxed_closures)]

fn foo<F: Fn<(i32,)>>(f: F) -> F::Output { f(3) }
```

Note that `(T,)` always denotes the type of a 1-tuple containing an element of
type `T`. The comma is necessary for syntactic disambiguation.
External C functions are allowed to be variadic. However, a variadic function
takes a minimum number of arguments. For example, consider C's variadic `printf`
function:

```compile_fail,E0060
use std::os::raw::{c_char, c_int};

extern "C" {
    fn printf(_: *const c_char, ...) -> c_int;
}

unsafe { printf(); } // error!
```

Using this declaration, it must be called with at least one argument, so
simply calling `printf()` is invalid. But the following uses are allowed:

```rust,edition2021
# use std::os::raw::{c_char, c_int};
# #[cfg_attr(all(windows, target_env = "msvc"),
#            link(name = "legacy_stdio_definitions",
#                 kind = "static", modifiers = "-bundle"))]
# extern "C" { fn printf(_: *const c_char, ...) -> c_int; }
# fn main() {
unsafe {
    printf(c"test\n".as_ptr());

    printf(c"number = %d\n".as_ptr(), 3);

    printf(c"%d, %d\n".as_ptr(), 10, 5);
}
# }
```
An invalid number of arguments was passed when calling a function.

Erroneous code example:

```compile_fail,E0061
fn f(u: i32) {}

f(); // error!
```

The number of arguments passed to a function must match the number of arguments
specified in the function signature.

For example, a function like:

```
fn f(a: u16, b: &str) {}
```

Must always be called with exactly two arguments, e.g., `f(2, "test")`.

Note that Rust does not have a notion of optional function arguments or
variadic functions (except for its C-FFI).
A struct's or struct-like enum variant's field was specified more than once.

Erroneous code example:

```compile_fail,E0062
struct Foo {
    x: i32,
}

fn main() {
    let x = Foo {
                x: 0,
                x: 0, // error: field `x` specified more than once
            };
}
```

This error indicates that during an attempt to build a struct or struct-like
enum variant, one of the fields was specified more than once. Each field should
be specified exactly one time. Example:

```
struct Foo {
    x: i32,
}

fn main() {
    let x = Foo { x: 0 }; // ok!
}
```
A struct's or struct-like enum variant's field was not provided.

Erroneous code example:

```compile_fail,E0063
struct Foo {
    x: i32,
    y: i32,
}

fn main() {
    let x = Foo { x: 0 }; // error: missing field: `y`
}
```

Each field should be specified exactly once. Example:

```
struct Foo {
    x: i32,
    y: i32,
}

fn main() {
    let x = Foo { x: 0, y: 0 }; // ok!
}
```
An invalid left-hand side expression was used on an assignment operation.

Erroneous code example:

```compile_fail,E0067
12 += 1; // error!
```

You need to have a place expression to be able to assign it something. For
example:

```
let mut x: i8 = 12;
x += 1; // ok!
```
The compiler found a function whose body contains a `return;` statement but
whose return type is not `()`.

Erroneous code example:

```compile_fail,E0069
// error
fn foo() -> u8 {
    return;
}
```

Since `return;` is just like `return ();`, there is a mismatch between the
function's return type and the value being returned.
An assignment operator was used on a non-place expression.

Erroneous code examples:

```compile_fail,E0070
struct SomeStruct {
    x: i32,
    y: i32,
}

const SOME_CONST: i32 = 12;

fn some_other_func() {}

fn some_function() {
    SOME_CONST = 14; // error: a constant value cannot be changed!
    1 = 3; // error: 1 isn't a valid place!
    some_other_func() = 4; // error: we cannot assign value to a function!
    SomeStruct::x = 12; // error: SomeStruct a structure name but it is used
                        //        like a variable!
}
```

The left-hand side of an assignment operator must be a place expression. A
place expression represents a memory location and can be a variable (with
optional namespacing), a dereference, an indexing expression or a field
reference.

More details can be found in the [Expressions] section of the Reference.

[Expressions]: https://doc.rust-lang.org/reference/expressions.html#places-rvalues-and-temporaries

And now let's give working examples:

```
struct SomeStruct {
    x: i32,
    y: i32,
}
let mut s = SomeStruct { x: 0, y: 0 };

s.x = 3; // that's good !

// ...

fn some_func(x: &mut i32) {
    *x = 12; // that's good !
}
```
A structure-literal syntax was used to create an item that is not a structure
or enum variant.

Example of erroneous code:

```compile_fail,E0071
type U32 = u32;
let t = U32 { value: 4 }; // error: expected struct, variant or union type,
                          // found builtin type `u32`
```

To fix this, ensure that the name was correctly spelled, and that the correct
form of initializer was used.

For example, the code above can be fixed to:

```
type U32 = u32;
let t: U32 = 4;
```

or:

```
struct U32 { value: u32 }
let t = U32 { value: 4 };
```
A recursive type has infinite size because it doesn't have an indirection.

Erroneous code example:

```compile_fail,E0072
struct ListNode {
    head: u8,
    tail: Option<ListNode>, // error: no indirection here so impossible to
                            //        compute the type's size
}
```

When defining a recursive struct or enum, any use of the type being defined
from inside the definition must occur behind a pointer (like `Box`, `&` or
`Rc`). This is because structs and enums must have a well-defined size, and
without the pointer, the size of the type would need to be unbounded.

In the example, the type cannot have a well-defined size, because it needs to be
arbitrarily large (since we would be able to nest `ListNode`s to any depth).
Specifically,

```plain
size of `ListNode` = 1 byte for `head`
                   + 1 byte for the discriminant of the `Option`
                   + size of `ListNode`
```

One way to fix this is by wrapping `ListNode` in a `Box`, like so:

```
struct ListNode {
    head: u8,
    tail: Option<Box<ListNode>>,
}
```

This works because `Box` is a pointer, so its size is well-known.
#### Note: this error code is no longer emitted by the compiler.

You cannot define a struct (or enum) `Foo` that requires an instance of `Foo`
in order to make a new `Foo` value. This is because there would be no way a
first instance of `Foo` could be made to initialize another instance!

Here's an example of a struct that has this problem:

```
struct Foo { x: Box<Foo> } // error
```

One fix is to use `Option`, like so:

```
struct Foo { x: Option<Box<Foo>> }
```

Now it's possible to create at least one instance of `Foo`: `Foo { x: None }`.
#### Note: this error code is no longer emitted by the compiler.

When using the `#[simd]` attribute on a tuple struct, the components of the
tuple struct must all be of a concrete, nongeneric type so the compiler can
reason about how to use SIMD with them. This error will occur if the types
are generic.

This will cause an error:

```
#![feature(repr_simd)]

#[repr(simd)]
struct Bad<T>([T; 4]);
```

This will not:

```
#![feature(repr_simd)]

#[repr(simd)]
struct Good([u32; 4]);
```
A `#[simd]` attribute was applied to an empty or multi-field struct.

Erroneous code examples:

```compile_fail,E0075
#![feature(repr_simd)]

#[repr(simd)]
struct Bad; // error!
```

```compile_fail,E0075
#![feature(repr_simd)]

#[repr(simd)]
struct Bad([u32; 1], [u32; 1]); // error!
```

The `#[simd]` attribute can only be applied to a single-field struct, because
the one field must be the array of values in the vector.

Fixed example:

```
#![feature(repr_simd)]

#[repr(simd)]
struct Good([u32; 2]); // ok!
```
The type of the field in a tuple struct isn't an array when using the `#[simd]`
attribute.

Erroneous code example:

```compile_fail,E0076
#![feature(repr_simd)]

#[repr(simd)]
struct Bad(u16); // error!
```

When using the `#[simd]` attribute to automatically use SIMD operations in tuple
structs, if you want a single-lane vector then the field must be a 1-element
array, or the compiler will trigger this error.

Fixed example:

```
#![feature(repr_simd)]

#[repr(simd)]
struct Good([u16; 1]); // ok!
```
A tuple struct's element isn't a machine type when using the `#[simd]`
attribute.

Erroneous code example:

```compile_fail,E0077
#![feature(repr_simd)]

#[repr(simd)]
struct Bad([String; 2]); // error!
```

When using the `#[simd]` attribute on a tuple struct, the elements in the tuple
must be machine types so SIMD operations can be applied to them.

Fixed example:

```
#![feature(repr_simd)]

#[repr(simd)]
struct Good([u32; 4]); // ok!
```
A constant value failed to get evaluated.

Erroneous code example:

```compile_fail,E0080
enum Enum {
    X = (1 << 500),
    Y = (1 / 0),
}
```

This error indicates that the compiler was unable to sensibly evaluate a
constant expression that had to be evaluated. Attempting to divide by 0
or causing an integer overflow are two ways to induce this error.

Ensure that the expressions given can be evaluated as the desired integer type.

See the [Discriminants] section of the Reference for more information about
setting custom integer types on enums using the
[`repr` attribute][repr-attribute].

[discriminants]: https://doc.rust-lang.org/reference/items/enumerations.html#discriminants
[repr-attribute]: https://doc.rust-lang.org/reference/type-layout.html#representations
A discriminant value is present more than once.

Erroneous code example:

```compile_fail,E0081
enum Enum {
    P = 3,
    X = 3, // error!
    Y = 5,
}
```

Enum discriminants are used to differentiate enum variants stored in memory.
This error indicates that the same value was used for two or more variants,
making it impossible to distinguish them.

```
enum Enum {
    P,
    X = 3, // ok!
    Y = 5,
}
```

Note that variants without a manually specified discriminant are numbered from
top to bottom starting from 0, so clashes can occur with seemingly unrelated
variants.

```compile_fail,E0081
enum Bad {
    X,
    Y = 0, // error!
}
```

Here `X` will have already been specified the discriminant 0 by the time `Y` is
encountered, so a conflict occurs.
An unsupported representation was attempted on a zero-variant enum.

Erroneous code example:

```compile_fail,E0084
#[repr(i32)]
enum NightsWatch {} // error: unsupported representation for zero-variant enum
```

It is impossible to define an integer type to be used to represent zero-variant
enum values because there are no zero-variant enum values. There is no way to
construct an instance of the following type using only safe code. So you have
two solutions. Either you add variants in your enum:

```
#[repr(i32)]
enum NightsWatch {
    JonSnow,
    Commander,
}
```

or you remove the integer representation of your enum:

```
enum NightsWatch {}
```
#### Note: this error code is no longer emitted by the compiler.

Too many type arguments were supplied for a function. For example:

```compile_fail,E0107
fn foo<T>() {}

fn main() {
    foo::<f64, bool>(); // error: wrong number of type arguments:
                        //        expected 1, found 2
}
```

The number of supplied arguments must exactly match the number of defined type
parameters.
#### Note: this error code is no longer emitted by the compiler.

You gave too many lifetime arguments. Erroneous code example:

```compile_fail,E0107
fn f() {}

fn main() {
    f::<'static>() // error: wrong number of lifetime arguments:
                   //        expected 0, found 1
}
```

Please check you give the right number of lifetime arguments. Example:

```
fn f() {}

fn main() {
    f() // ok!
}
```

It's also important to note that the Rust compiler can generally
determine the lifetime by itself. Example:

```
struct Foo {
    value: String
}

impl Foo {
    // it can be written like this
    fn get_value<'a>(&'a self) -> &'a str { &self.value }
    // but the compiler works fine with this too:
    fn without_lifetime(&self) -> &str { &self.value }
}

fn main() {
    let f = Foo { value: "hello".to_owned() };

    println!("{}", f.get_value());
    println!("{}", f.without_lifetime());
}
```
#### Note: this error code is no longer emitted by the compiler.

Too few type arguments were supplied for a function. For example:

```compile_fail,E0107
fn foo<T, U>() {}

fn main() {
    foo::<f64>(); // error: wrong number of type arguments: expected 2, found 1
}
```

Note that if a function takes multiple type arguments but you want the compiler
to infer some of them, you can use type placeholders:

```compile_fail,E0107
fn foo<T, U>(x: T) {}

fn main() {
    let x: bool = true;
    foo::<f64>(x);    // error: wrong number of type arguments:
                      //        expected 2, found 1
    foo::<_, f64>(x); // same as `foo::<bool, f64>(x)`
}
```
#### Note: this error code is no longer emitted by the compiler.

You gave too few lifetime arguments. Example:

```compile_fail,E0107
fn foo<'a: 'b, 'b: 'a>() {}

fn main() {
    foo::<'static>(); // error: wrong number of lifetime arguments:
                      //        expected 2, found 1
}
```

Please check you give the right number of lifetime arguments. Example:

```
fn foo<'a: 'b, 'b: 'a>() {}

fn main() {
    foo::<'static, 'static>();
}
```
An unnecessary type parameter was given in a type alias.

Erroneous code example:

```compile_fail,E0091
type Foo<T> = u32; // error: type parameter `T` is never used
// or:
type Foo<A, B> = Box<A>; // error: type parameter `B` is never used
```

Please check you didn't write too many parameters. Example:

```
type Foo = u32; // ok!
type Foo2<A> = Box<A>; // ok!
```
#### Note: this error code is no longer emitted by the compiler.

An undefined atomic operation function was declared.

Erroneous code example:

```ignore (no longer emitted)
#![feature(intrinsics)]
#![allow(internal_features)]

#[rustc_intrinsic]
unsafe fn atomic_foo(); // error: unrecognized atomic operation
                        //        function
```

Please check you didn't make a mistake in the function's name. All intrinsic
functions are defined in `library/core/src/intrinsics` in the Rust source code.
An unknown intrinsic function was declared.

Erroneous code example:

```compile_fail,E0093
#![feature(intrinsics)]
#![allow(internal_features)]

#[rustc_intrinsic]
unsafe fn foo(); // error: unrecognized intrinsic function: `foo`

fn main() {
    unsafe {
        foo();
    }
}
```

Please check you didn't make a mistake in the function's name. All intrinsic
functions are defined in `library/core/src/intrinsics` in the Rust source code.
An invalid number of generic parameters was passed to an intrinsic function.

Erroneous code example:

```compile_fail,E0094
#![feature(intrinsics)]
#![allow(internal_features)]

#[rustc_intrinsic]
fn size_of<T, U>() -> usize; // error: intrinsic has wrong number
                             //        of type parameters
```

Please check that you provided the right number of type parameters
and verify with the function declaration in the Rust source code.
Example:

```
#![feature(intrinsics)]
#![allow(internal_features)]

#[rustc_intrinsic]
fn size_of<T>() -> usize; // ok!
```
This error indicates that a lifetime is missing from a type. If it is an error
inside a function signature, the problem may be with failing to adhere to the
lifetime elision rules (see below).

Erroneous code examples:

```compile_fail,E0106
struct Foo1 { x: &bool }
              // ^ expected lifetime parameter
struct Foo2<'a> { x: &'a bool } // correct

struct Bar1 { x: Foo2 }
              // ^^^^ expected lifetime parameter
struct Bar2<'a> { x: Foo2<'a> } // correct

enum Baz1 { A(u8), B(&bool), }
                  // ^ expected lifetime parameter
enum Baz2<'a> { A(u8), B(&'a bool), } // correct

type MyStr1 = &str;
           // ^ expected lifetime parameter
type MyStr2<'a> = &'a str; // correct
```

Lifetime elision is a special, limited kind of inference for lifetimes in
function signatures which allows you to leave out lifetimes in certain cases.
For more background on lifetime elision see [the book][book-le].

The lifetime elision rules require that any function signature with an elided
output lifetime must either have:

 - exactly one input lifetime
 - or, multiple input lifetimes, but the function must also be a method with a
   `&self` or `&mut self` receiver

In the first case, the output lifetime is inferred to be the same as the unique
input lifetime. In the second case, the lifetime is instead inferred to be the
same as the lifetime on `&self` or `&mut self`.

Here are some examples of elision errors:

```compile_fail,E0106
// error, no input lifetimes
fn foo() -> &str { }

// error, `x` and `y` have distinct lifetimes inferred
fn bar(x: &str, y: &str) -> &str { }

// error, `y`'s lifetime is inferred to be distinct from `x`'s
fn baz<'a>(x: &'a str, y: &str) -> &str { }
```

[book-le]: https://doc.rust-lang.org/book/ch10-03-lifetime-syntax.html#lifetime-elision
An incorrect number of generic arguments was provided.

Erroneous code example:

```compile_fail,E0107
struct Foo<T> { x: T }

struct Bar { x: Foo }             // error: wrong number of type arguments:
                                  //        expected 1, found 0
struct Baz<S, T> { x: Foo<S, T> } // error: wrong number of type arguments:
                                  //        expected 1, found 2

fn foo<T, U>(x: T, y: U) {}
fn f() {}

fn main() {
    let x: bool = true;
    foo::<bool>(x);                 // error: wrong number of type arguments:
                                    //        expected 2, found 1
    foo::<bool, i32, i32>(x, 2, 4); // error: wrong number of type arguments:
                                    //        expected 2, found 3
    f::<'static>();                 // error: wrong number of lifetime arguments
                                    //        expected 0, found 1
}
```

When using/declaring an item with generic arguments, you must provide the exact
same number:

```
struct Foo<T> { x: T }

struct Bar<T> { x: Foo<T> }               // ok!
struct Baz<S, T> { x: Foo<S>, y: Foo<T> } // ok!

fn foo<T, U>(x: T, y: U) {}
fn f() {}

fn main() {
    let x: bool = true;
    foo::<bool, u32>(x, 12);              // ok!
    f();                                  // ok!
}
```
You tried to provide a generic argument to a type which doesn't need it.

Erroneous code example:

```compile_fail,E0109
type X = u32<i32>; // error: type arguments are not allowed for this type
type Y = bool<'static>; // error: lifetime parameters are not allowed on
                        //        this type
```

Check that you used the correct argument and that the definition is correct.

Example:

```
type X = u32; // ok!
type Y = bool; // ok!
```

Note that generic arguments for enum variant constructors go after the variant,
not after the enum. For example, you would write `Option::None::<u32>`,
rather than `Option::<u32>::None`.
#### Note: this error code is no longer emitted by the compiler.

You tried to provide a lifetime to a type which doesn't need it.
See `E0109` for more details.
An inherent implementation was defined for a type outside the current crate.

Erroneous code example:

```compile_fail,E0116
impl Vec<u8> { } // error
```

You can only define an inherent implementation for a type in the same crate
where the type was defined. For example, an `impl` block as above is not allowed
since `Vec` is defined in the standard library.

To fix this problem, you can either:

 - define a trait that has the desired associated functions/types/constants and
   implement the trait for the type in question
 - define a new type wrapping the type and define an implementation on the new
   type

Note that using the `type` keyword does not work here because `type` only
introduces a type alias:

```compile_fail,E0116
type Bytes = Vec<u8>;

impl Bytes { } // error, same as above
```
Only traits defined in the current crate can be implemented for arbitrary types.

Erroneous code example:

```compile_fail,E0117
impl Drop for u32 {}
```

This error indicates a violation of one of Rust's orphan rules for trait
implementations. The rule prohibits any implementation of a foreign trait (a
trait defined in another crate) where

 - the type that is implementing the trait is foreign
 - all of the parameters being passed to the trait (if there are any) are also
   foreign.

To avoid this kind of error, ensure that at least one local type is referenced
by the `impl`:

```
pub struct Foo; // you define your type in your crate

impl Drop for Foo { // and you can implement the trait on it!
    // code of trait implementation here
#   fn drop(&mut self) { }
}

impl From<Foo> for i32 { // or you use a type from your crate as
                         // a type parameter
    fn from(i: Foo) -> i32 {
        0
    }
}
```

Alternatively, define a trait locally and implement that instead:

```
trait Bar {
    fn get(&self) -> usize;
}

impl Bar for u32 {
    fn get(&self) -> usize { 0 }
}
```

For information on the design of the orphan rules, see [RFC 1023].

[RFC 1023]: https://github.com/rust-lang/rfcs/blob/master/text/1023-rebalancing-coherence.md
An inherent implementation was defined for something which isn't a struct,
enum, union, or trait object.

Erroneous code example:

```compile_fail,E0118
impl<T> T { // error: no nominal type found for inherent implementation
    fn get_state(&self) -> String {
        // ...
    }
}
```

To fix this error, please implement a trait on the type or wrap it in a struct.
Example:

```
// we create a trait here
trait LiveLongAndProsper {
    fn get_state(&self) -> String;
}

// and now you can implement it on T
impl<T> LiveLongAndProsper for T {
    fn get_state(&self) -> String {
        "He's dead, Jim!".to_owned()
    }
}
```

Alternatively, you can create a newtype. A newtype is a wrapping tuple-struct.
For example, `NewType` is a newtype over `Foo` in `struct NewType(Foo)`.
Example:

```
struct TypeWrapper<T>(T);

impl<T> TypeWrapper<T> {
    fn get_state(&self) -> String {
        "Fascinating!".to_owned()
    }
}
```
There are conflicting trait implementations for the same type.

Erroneous code example:

```compile_fail,E0119
trait MyTrait {
    fn get(&self) -> usize;
}

impl<T> MyTrait for T {
    fn get(&self) -> usize { 0 }
}

struct Foo {
    value: usize
}

impl MyTrait for Foo { // error: conflicting implementations of trait
                       //        `MyTrait` for type `Foo`
    fn get(&self) -> usize { self.value }
}
```

When looking for the implementation for the trait, the compiler finds
both the `impl<T> MyTrait for T` where T is all types and the `impl
MyTrait for Foo`. Since a trait cannot be implemented multiple times,
this is an error. So, when you write:

```
trait MyTrait {
    fn get(&self) -> usize;
}

impl<T> MyTrait for T {
    fn get(&self) -> usize { 0 }
}
```

This makes the trait implemented on all types in the scope. So if you
try to implement it on another one after that, the implementations will
conflict. Example:

```
trait MyTrait {
    fn get(&self) -> usize;
}

impl<T> MyTrait for T {
    fn get(&self) -> usize { 0 }
}

struct Foo;

fn main() {
    let f = Foo;

    f.get(); // the trait is implemented so we can use it
}
```
`Drop` was implemented on a trait object or reference, which is not allowed;
only structs, enums, and unions can implement Drop.

Erroneous code examples:

```compile_fail,E0120
trait MyTrait {}

impl Drop for MyTrait {
    fn drop(&mut self) {}
}
```

```compile_fail,E0120
struct Concrete {}

impl Drop for &'_ mut Concrete  {
    fn drop(&mut self) {}
}
```

A workaround for traits is to create a wrapper struct with a generic type,
add a trait bound to the type, and implement `Drop` on the wrapper:

```
trait MyTrait {}
struct MyWrapper<T: MyTrait> { foo: T }

impl <T: MyTrait> Drop for MyWrapper<T> {
    fn drop(&mut self) {}
}

```

Alternatively, the `Drop` wrapper can contain the trait object:

```
trait MyTrait {}

// or Box<dyn MyTrait>, if you wanted an owned trait object
struct MyWrapper<'a> { foo: &'a dyn MyTrait }

impl <'a> Drop for MyWrapper<'a> {
    fn drop(&mut self) {}
}
```
The type placeholder `_` was used within a type on an item's signature.

Erroneous code example:

```compile_fail,E0121
fn foo() -> _ { 5 } // error

static BAR: _ = "test"; // error
```

In those cases, you need to provide the type explicitly:

```
fn foo() -> i32 { 5 } // ok!

static BAR: &str = "test"; // ok!
```

The type placeholder `_` can be used outside item's signature as follows:

```
let x = "a4a".split('4')
    .collect::<Vec<_>>(); // No need to precise the Vec's generic type.
```
A struct was declared with two fields having the same name.

Erroneous code example:

```compile_fail,E0124
struct Foo {
    field1: i32,
    field1: i32, // error: field is already declared
}
```

Please verify that the field names have been correctly spelled. Example:

```
struct Foo {
    field1: i32,
    field2: i32, // ok!
}
```
A type parameter with default value is using forward declared identifier.

Erroneous code example:

```compile_fail,E0128
struct Foo<T = U, U = ()> {
    field1: T,
    field2: U,
}
// error: generic parameters with a default cannot use forward declared
//        identifiers
```

Type parameter defaults can only use parameters that occur before them. Since
type parameters are evaluated in-order, this issue could be fixed by doing:

```
struct Foo<U = (), T = U> {
    field1: T,
    field2: U,
}
```

Please also verify that this wasn't because of a name-clash and rename the type
parameter if so.
A pattern was declared as an argument in a foreign function declaration.

Erroneous code example:

```compile_fail,E0130
extern "C" {
    fn foo((a, b): (u32, u32)); // error: patterns aren't allowed in foreign
                                //        function declarations
}
```

To fix this error, replace the pattern argument with a regular one. Example:

```
struct SomeStruct {
    a: u32,
    b: u32,
}

extern "C" {
    fn foo(s: SomeStruct); // ok!
}
```

Or:

```
extern "C" {
    fn foo(a: (u32, u32)); // ok!
}
```
The `main` function was defined with generic parameters.

Erroneous code example:

```compile_fail,E0131
fn main<T>() { // error: main function is not allowed to have generic parameters
}
```

It is not possible to define the `main` function with generic parameters.
It must not take any arguments.
#### Note: this error code is no longer emitted by the compiler.

A function with the `start` attribute was declared with type parameters.
Unsafe code was used outside of an unsafe block.

Erroneous code example:

```compile_fail,E0133
unsafe fn f() { return; } // This is the unsafe code

fn main() {
    f(); // error: call to unsafe function requires unsafe function or block
}
```

Using unsafe functionality is potentially dangerous and disallowed by safety
checks. Examples:

* Dereferencing raw pointers
* Calling functions via FFI
* Calling functions marked unsafe

These safety checks can be relaxed for a section of the code by wrapping the
unsafe instructions with an `unsafe` block. For instance:

```
unsafe fn f() { return; }

fn main() {
    unsafe { f(); } // ok!
}
```

See the [unsafe section][unsafe-section] of the Book for more details.

#### Unsafe code in functions

Unsafe code is currently accepted in unsafe functions, but that is being phased
out in favor of requiring unsafe blocks here too.

```
unsafe fn f() { return; }

unsafe fn g() {
    f(); // Is accepted, but no longer recommended
    unsafe { f(); } // Recommended way to write this
}
```

Linting against this is controlled via the `unsafe_op_in_unsafe_fn` lint, which
is `warn` by default in the 2024 edition and `allow` by default in earlier
editions.

[unsafe-section]: https://doc.rust-lang.org/book/ch19-01-unsafe-rust.html
#### Note: this error code is no longer emitted by the compiler.

More than one `main` function was found.

Erroneous code example:

```compile_fail
fn main() {
    // ...
}

// ...

fn main() { // error!
    // ...
}
```

A binary can only have one entry point, and by default that entry point is the
`main()` function. If there are multiple instances of this function, please
rename one of them.
#### Note: this error code is no longer emitted by the compiler.

More than one function was declared with the `#[main]` attribute.

Erroneous code example:

```compile_fail
#![feature(main)]

#[main]
fn foo() {}

#[main]
fn f() {} // error: multiple functions with a `#[main]` attribute
```

This error indicates that the compiler found multiple functions with the
`#[main]` attribute. This is an error because there must be a unique entry
point into a Rust program. Example:

```compile_fail
#![feature(main)]

#[main]
fn f() {} // ok!
```
#### Note: this error code is no longer emitted by the compiler.

More than one function was declared with the `#[start]` attribute.
#### Note: this error code is no longer emitted by the compiler.

There are various restrictions on transmuting between types in Rust; for example
types being transmuted must have the same size. To apply all these restrictions,
the compiler must know the exact types that may be transmuted. When type
parameters are involved, this cannot always be done.

So, for example, the following is not allowed:

```
use std::mem::transmute;

struct Foo<T>(Vec<T>);

fn foo<T>(x: Vec<T>) {
    // we are transmuting between Vec<T> and Foo<F> here
    let y: Foo<T> = unsafe { transmute(x) };
    // do something with y
}
```

In this specific case there's a good chance that the transmute is harmless (but
this is not guaranteed by Rust). However, when alignment and enum optimizations
come into the picture, it's quite likely that the sizes may or may not match
with different type parameter instantiations. It's not possible to check this
for _all_ possible types, so `transmute()` simply only accepts types without any
uninstantiated type parameters.

If you need this, there's a good chance you're doing something wrong. Keep in
mind that Rust doesn't guarantee much about the layout of different structs
(even two structs with identical declarations may have different layouts). If
there is a solution that avoids the transmute entirely, try it instead.

If it's possible, hand-monomorphize the code by writing the function for each
possible type instantiation. It's possible to use traits to do this cleanly,
for example:

```
use std::mem::transmute;

struct Foo<T>(Vec<T>);

trait MyTransmutableType: Sized {
    fn transmute(_: Vec<Self>) -> Foo<Self>;
}

impl MyTransmutableType for u8 {
    fn transmute(x: Vec<u8>) -> Foo<u8> {
        unsafe { transmute(x) }
    }
}

impl MyTransmutableType for String {
    fn transmute(x: Vec<String>) -> Foo<String> {
        unsafe { transmute(x) }
    }
}

// ... more impls for the types you intend to transmute

fn foo<T: MyTransmutableType>(x: Vec<T>) {
    let y: Foo<T> = <T as MyTransmutableType>::transmute(x);
    // do something with y
}
```

Each impl will be checked for a size match in the transmute as usual, and since
there are no unbound type parameters involved, this should compile unless there
is a size mismatch in one of the impls.

It is also possible to manually transmute:

```
# use std::ptr;
# let v = Some("value");
# type SomeType = &'static [u8];
unsafe {
    ptr::read(&v as *const _ as *const SomeType) // `v` transmuted to `SomeType`
}
# ;
```

Note that this does not move `v` (unlike `transmute`), and may need a
call to `mem::forget(v)` in case you want to avoid destructors being called.
A lang item was redefined.

Erroneous code example:

```compile_fail,E0152
#![feature(lang_items)]

#[lang = "owned_box"]
struct Foo<T>(T); // error: duplicate lang item found: `owned_box`
```

Lang items are already implemented in the standard library. Unless you are
writing a free-standing application (e.g., a kernel), you do not need to provide
them yourself.

You can build a free-standing crate by adding `#![no_std]` to the crate
attributes:

```ignore (only-for-syntax-highlight)
#![no_std]
```

See also [this section of the Rustonomicon][beneath std].

[beneath std]: https://doc.rust-lang.org/nomicon/beneath-std.html
#### Note: this error code is no longer emitted by the compiler.

Imports (`use` statements) are not allowed after non-item statements, such as
variable declarations and expression statements.

Here is an example that demonstrates the error:

```
fn f() {
    // Variable declaration before import
    let x = 0;
    use std::io::Read;
    // ...
}
```

The solution is to declare the imports at the top of the block, function, or
file.

Here is the previous example again, with the correct order:

```
fn f() {
    use std::io::Read;
    let x = 0;
    // ...
}
```

See the [Declaration Statements][declaration-statements] section of the
reference for more information about what constitutes an item declaration
and what does not.

[declaration-statements]: https://doc.rust-lang.org/reference/statements.html#declaration-statements
A generic parameter or `static` has been referenced in a pattern.

Erroneous code example:

```compile_fail,E0158
enum Foo {
    One,
    Two
}

trait Bar {
    const X: Foo;
}

fn test<A: Bar>(arg: Foo) {
    match arg {
        A::X => println!("A::X"), // error: E0158: constant pattern depends
                                  //        on a generic parameter
        Foo::Two => println!("Two")
    }
}
```

Generic parameters cannot be referenced in patterns because it is impossible
for the compiler to prove exhaustiveness (that some pattern will always match).
Take the above example, because Rust does type checking in the *generic*
method, not the *monomorphized* specific instance. So because `Bar` could have
theoretically arbitrary implementations, there's no way to always be sure that
`A::X` is `Foo::One`. So this code must be rejected. Even if code can be
proven exhaustive by a programmer, the compiler cannot currently prove this.

The same holds true of `static`s.

If you want to match against a `const` that depends on a generic parameter or a
`static`, consider using a guard instead:

```
trait Trait {
    const X: char;
}

static FOO: char = 'j';

fn test<A: Trait, const Y: char>(arg: char) {
    match arg {
        c if c == A::X => println!("A::X"),
        c if c == Y => println!("Y"),
        c if c == FOO => println!("FOO"),
        _ => ()
    }
}
```
A value was moved whose size was not known at compile time.

Erroneous code example:

```compile_fail,E0161
trait Bar {
    fn f(self);
}

impl Bar for i32 {
    fn f(self) {}
}

fn main() {
    let b: Box<dyn Bar> = Box::new(0i32);
    b.f();
    // error: cannot move a value of type dyn Bar: the size of dyn Bar cannot
    //        be statically determined
}
```

In Rust, you can only move a value when its size is known at compile time.

To work around this restriction, consider "hiding" the value behind a reference:
either `&x` or `&mut x`. Since a reference has a fixed size, this lets you move
it around as usual. Example:

```
trait Bar {
    fn f(&self);
}

impl Bar for i32 {
    fn f(&self) {}
}

fn main() {
    let b: Box<dyn Bar> = Box::new(0i32);
    b.f();
    // ok!
}
```
#### Note: this error code is no longer emitted by the compiler.

An `if let` pattern attempts to match the pattern, and enters the body if the
match was successful. If the match is irrefutable (when it cannot fail to
match), use a regular `let`-binding instead. For instance:

```
struct Irrefutable(i32);
let irr = Irrefutable(0);

// This fails to compile because the match is irrefutable.
if let Irrefutable(x) = irr {
    // This body will always be executed.
    // ...
}
```

Try this instead:

```
struct Irrefutable(i32);
let irr = Irrefutable(0);

let Irrefutable(x) = irr;
println!("{}", x);
```
Something which is neither a tuple struct nor a tuple variant was used as a
pattern.

Erroneous code example:

```compile_fail,E0164
enum A {
    B,
    C,
}

impl A {
    fn new() {}
}

fn bar(foo: A) {
    match foo {
        A::new() => (), // error!
        _ => {}
    }
}
```

This error means that an attempt was made to match something which is neither a
tuple struct nor a tuple variant. Only these two elements are allowed as a
pattern:

```
enum A {
    B,
    C,
}

impl A {
    fn new() {}
}

fn bar(foo: A) {
    match foo {
        A::B => (), // ok!
        _ => {}
    }
}
```
#### Note: this error code is no longer emitted by the compiler.

A `while let` pattern attempts to match the pattern, and enters the body if the
match was successful. If the match is irrefutable (when it cannot fail to
match), use a regular `let`-binding inside a `loop` instead. For instance:

```no_run
struct Irrefutable(i32);
let irr = Irrefutable(0);

// This fails to compile because the match is irrefutable.
while let Irrefutable(x) = irr {
    // ...
}
```

Try this instead:

```no_run
struct Irrefutable(i32);
let irr = Irrefutable(0);

loop {
    let Irrefutable(x) = irr;
    // ...
}
```
A pattern binding is using the same name as one of the variants of a type.

Erroneous code example:

```compile_fail,E0170
# #![deny(warnings)]
enum Method {
    GET,
    POST,
}

fn is_empty(s: Method) -> bool {
    match s {
        GET => true,
        _ => false
    }
}

fn main() {}
```

Enum variants are qualified by default. For example, given this type:

```
enum Method {
    GET,
    POST,
}
```

You would match it using:

```
enum Method {
    GET,
    POST,
}

let m = Method::GET;

match m {
    Method::GET => {},
    Method::POST => {},
}
```

If you don't qualify the names, the code will bind new variables named "GET" and
"POST" instead. This behavior is likely not what you want, so `rustc` warns when
that happens.

Qualified names are good practice, and most code works well with them. But if
you prefer them unqualified, you can import the variants into scope:

```
use Method::*;
enum Method { GET, POST }
# fn main() {}
```

If you want others to be able to import variants from your module directly, use
`pub use`:

```
pub use Method::*;
pub enum Method { GET, POST }
# fn main() {}
```
The `+` type operator was used in an ambiguous context.

Erroneous code example:

```compile_fail,E0178
trait Foo {}

struct Bar<'a> {
    x: &'a Foo + 'a,     // error!
    y: &'a mut Foo + 'a, // error!
    z: fn() -> Foo + 'a, // error!
}
```

In types, the `+` type operator has low precedence, so it is often necessary
to use parentheses:

```
trait Foo {}

struct Bar<'a> {
    x: &'a (Foo + 'a),     // ok!
    y: &'a mut (Foo + 'a), // ok!
    z: fn() -> (Foo + 'a), // ok!
}
```

More details can be found in [RFC 438].

[RFC 438]: https://github.com/rust-lang/rfcs/pull/438
Manual implementation of a `Fn*` trait.

Erroneous code example:

```compile_fail,E0183
struct MyClosure {
    foo: i32
}

impl FnOnce<()> for MyClosure {  // error
    type Output = ();
    extern "rust-call" fn call_once(self, args: ()) -> Self::Output {
        println!("{}", self.foo);
    }
}
```

Manually implementing `Fn`, `FnMut` or `FnOnce` is unstable
and requires `#![feature(fn_traits, unboxed_closures)]`.

```
#![feature(fn_traits, unboxed_closures)]

struct MyClosure {
    foo: i32
}

impl FnOnce<()> for MyClosure {  // ok!
    type Output = ();
    extern "rust-call" fn call_once(self, args: ()) -> Self::Output {
        println!("{}", self.foo);
    }
}
```

The arguments must be a tuple representing the argument list.
For more info, see the [tracking issue][iss29625]:

[iss29625]: https://github.com/rust-lang/rust/issues/29625
The `Copy` trait was implemented on a type with a `Drop` implementation.

Erroneous code example:

```compile_fail,E0184
#[derive(Copy)]
struct Foo; // error!

impl Drop for Foo {
    fn drop(&mut self) {
    }
}
```

Explicitly implementing both `Drop` and `Copy` trait on a type is currently
disallowed. This feature can make some sense in theory, but the current
implementation is incorrect and can lead to memory unsafety (see
[issue #20126][iss20126]), so it has been disabled for now.

[iss20126]: https://github.com/rust-lang/rust/issues/20126
An associated function for a trait was defined to be static, but an
implementation of the trait declared the same function to be a method (i.e., to
take a `self` parameter).

Erroneous code example:

```compile_fail,E0185
trait Foo {
    fn foo();
}

struct Bar;

impl Foo for Bar {
    // error, method `foo` has a `&self` declaration in the impl, but not in
    // the trait
    fn foo(&self) {}
}
```

When a type implements a trait's associated function, it has to use the same
signature. So in this case, since `Foo::foo` does not take any argument and
does not return anything, its implementation on `Bar` should be the same:

```
trait Foo {
    fn foo();
}

struct Bar;

impl Foo for Bar {
    fn foo() {} // ok!
}
```
An associated function for a trait was defined to be a method (i.e., to take a
`self` parameter), but an implementation of the trait declared the same function
to be static.

Erroneous code example:

```compile_fail,E0186
trait Foo {
    fn foo(&self);
}

struct Bar;

impl Foo for Bar {
    // error, method `foo` has a `&self` declaration in the trait, but not in
    // the impl
    fn foo() {}
}
```

When a type implements a trait's associated function, it has to use the same
signature. So in this case, since `Foo::foo` takes `self` as argument and
does not return anything, its implementation on `Bar` should be the same:

```
trait Foo {
    fn foo(&self);
}

struct Bar;

impl Foo for Bar {
    fn foo(&self) {} // ok!
}
```
An associated type wasn't specified for a trait object.

Erroneous code example:

```compile_fail,E0191
trait Trait {
    type Bar;
}

type Foo = dyn Trait; // error: the value of the associated type `Bar` (from
                      //        the trait `Trait`) must be specified
```

Trait objects need to have all associated types specified. Please verify that
all associated types of the trait were specified and the correct trait was used.
Example:

```
trait Trait {
    type Bar;
}

type Foo = dyn Trait<Bar=i32>; // ok!
```
#### Note: this error code is no longer emitted by the compiler.

A negative impl was added on a trait implementation.

Erroneous code example:

```compile_fail
trait Trait {
    type Bar;
}

struct Foo;

impl !Trait for Foo { } //~ ERROR

fn main() {}
```

Negative impls are only allowed for auto traits. For more
information see the [opt-in builtin traits RFC][RFC 19].

[RFC 19]: https://github.com/rust-lang/rfcs/blob/master/text/0019-opt-in-builtin-traits.md
#### Note: this error code is no longer emitted by the compiler.

`where` clauses must use generic type parameters: it does not make sense to use
them otherwise. An example causing this error:

```
trait Foo {
    fn bar(&self);
}

#[derive(Copy,Clone)]
struct Wrapper<T> {
    Wrapped: T
}

impl Foo for Wrapper<u32> where Wrapper<u32>: Clone {
    fn bar(&self) { }
}
```

This use of a `where` clause is strange - a more common usage would look
something like the following:

```
trait Foo {
    fn bar(&self);
}

#[derive(Copy,Clone)]
struct Wrapper<T> {
    Wrapped: T
}
impl <T> Foo for Wrapper<T> where Wrapper<T>: Clone {
    fn bar(&self) { }
}
```

Here, we're saying that the implementation exists on Wrapper only when the
wrapped type `T` implements `Clone`. The `where` clause is important because
some types will not implement `Clone`, and thus will not get this method.

In our erroneous example, however, we're referencing a single concrete type.
Since we know for certain that `Wrapper<u32>` implements `Clone`, there's no
reason to also specify it in a `where` clause.
The lifetime parameters of the method do not match the trait declaration.

Erroneous code example:

```compile_fail,E0195
trait Trait {
    fn bar<'a,'b:'a>(x: &'a str, y: &'b str);
}

struct Foo;

impl Trait for Foo {
    fn bar<'a,'b>(x: &'a str, y: &'b str) {
    // error: lifetime parameters or bounds on method `bar`
    // do not match the trait declaration
    }
}
```

The lifetime constraint `'b` for `bar()` implementation does not match the
trait declaration. Ensure lifetime declarations match exactly in both trait
declaration and implementation. Example:

```
trait Trait {
    fn t<'a,'b:'a>(x: &'a str, y: &'b str);
}

struct Foo;

impl Trait for Foo {
    fn t<'a,'b:'a>(x: &'a str, y: &'b str) { // ok!
    }
}
```
An inherent implementation was marked unsafe.

Erroneous code example:

```compile_fail,E0197
struct Foo;

unsafe impl Foo { } // error!
```

Inherent implementations (one that do not implement a trait but provide
methods associated with a type) are always safe because they are not
implementing an unsafe trait. Removing the `unsafe` keyword from the inherent
implementation will resolve this error.

```
struct Foo;

impl Foo { } // ok!
```
A negative implementation was marked as unsafe.

Erroneous code example:

```compile_fail,E0198
struct Foo;

unsafe impl !Clone for Foo { } // error!
```

A negative implementation is one that excludes a type from implementing a
particular trait. Not being able to use a trait is always a safe operation,
so negative implementations are always safe and never need to be marked as
unsafe.

This will compile:

```ignore (ignore auto_trait future compatibility warning)
#![feature(auto_traits)]

struct Foo;

auto trait Enterprise {}

impl !Enterprise for Foo { }
```

Please note that negative impls are only allowed for auto traits.
A trait implementation was marked as unsafe while the trait is safe.

Erroneous code example:

```compile_fail,E0199
struct Foo;

trait Bar { }

unsafe impl Bar for Foo { } // error!
```

Safe traits should not have unsafe implementations, therefore marking an
implementation for a safe trait unsafe will cause a compiler error. Removing
the unsafe marker on the trait noted in the error will resolve this problem:

```
struct Foo;

trait Bar { }

impl Bar for Foo { } // ok!
```
An unsafe trait was implemented without an unsafe implementation.

Erroneous code example:

```compile_fail,E0200
struct Foo;

unsafe trait Bar { }

impl Bar for Foo { } // error!
```

Unsafe traits must have unsafe implementations. This error occurs when an
implementation for an unsafe trait isn't marked as unsafe. This may be resolved
by marking the unsafe implementation as unsafe.

```
struct Foo;

unsafe trait Bar { }

unsafe impl Bar for Foo { } // ok!
```
Two associated items (like methods, associated types, associated functions,
etc.) were defined with the same identifier.

Erroneous code example:

```compile_fail,E0201
struct Foo(u8);

impl Foo {
    fn bar(&self) -> bool { self.0 > 5 }
    fn bar() {} // error: duplicate associated function
}

trait Baz {
    type Quux;
    fn baz(&self) -> bool;
}

impl Baz for Foo {
    type Quux = u32;

    fn baz(&self) -> bool { true }

    // error: duplicate method
    fn baz(&self) -> bool { self.0 > 5 }

    // error: duplicate associated type
    type Quux = u32;
}
```

Note, however, that items with the same name are allowed for inherent `impl`
blocks that don't overlap:

```
struct Foo<T>(T);

impl Foo<u8> {
    fn bar(&self) -> bool { self.0 > 5 }
}

impl Foo<bool> {
    fn bar(&self) -> bool { self.0 }
}
```
Having duplicate relaxed default bounds is unsupported.

Erroneous code example:

```compile_fail,E0203
struct Bad<T: ?Sized + ?Sized>{
    inner: T,
}
```

Here the type parameter `T` cannot have duplicate relaxed bounds for default
trait `Sized`. This can be fixed by only using one relaxed bound:

```
struct Good<T: ?Sized>{
    inner: T
}
```
The `Copy` trait was implemented on a type which contains a field that doesn't
implement the `Copy` trait.

Erroneous code example:

```compile_fail,E0204
struct Foo {
    foo: Vec<u32>,
}

impl Copy for Foo { } // error!
```

The `Copy` trait is implemented by default only on primitive types. If your
type only contains primitive types, you'll be able to implement `Copy` on it.
Otherwise, it won't be possible.

Here's another example that will fail:

```compile_fail,E0204
#[derive(Copy)] // error!
struct Foo<'a> {
    ty: &'a mut bool,
}
```

This fails because `&mut T` is not `Copy`, even when `T` is `Copy` (this
differs from the behavior for `&T`, which is always `Copy`).
#### Note: this error code is no longer emitted by the compiler.

An attempt to implement the `Copy` trait for an enum failed because one of the
variants does not implement `Copy`. To fix this, you must implement `Copy` for
the mentioned variant. Note that this may not be possible, as in the example of

```compile_fail,E0204
enum Foo {
    Bar(Vec<u32>),
    Baz,
}

impl Copy for Foo { }
```

This fails because `Vec<T>` does not implement `Copy` for any `T`.

Here's another example that will fail:

```compile_fail,E0204
#[derive(Copy)]
enum Foo<'a> {
    Bar(&'a mut bool),
    Baz,
}
```

This fails because `&mut T` is not `Copy`, even when `T` is `Copy` (this
differs from the behavior for `&T`, which is always `Copy`).
The `Copy` trait was implemented on a type which is neither a struct, an
enum, nor a union.

Erroneous code example:

```compile_fail,E0206
#[derive(Copy, Clone)]
struct Bar;

impl Copy for &'static mut Bar { } // error!
```

You can only implement `Copy` for a struct, an enum, or a union.
The previous example will fail because `&'static mut Bar`
is not a struct, an enum, or a union.
A type, const or lifetime parameter that is specified for `impl` is not
constrained.

Erroneous code example:

```compile_fail,E0207
struct Foo;

impl<T: Default> Foo {
    // error: the type parameter `T` is not constrained by the impl trait, self
    // type, or predicates [E0207]
    fn get(&self) -> T {
        <T as Default>::default()
    }
}
```

Any type or const parameter of an `impl` must meet at least one of the
following criteria:

 - it appears in the _implementing type_ of the impl, e.g. `impl<T> Foo<T>`
 - for a trait impl, it appears in the _implemented trait_, e.g.
   `impl<T> SomeTrait<T> for Foo`
 - it is bound as an associated type, e.g. `impl<T, U> SomeTrait for T
   where T: AnotherTrait<AssocType=U>`

Any unconstrained lifetime parameter of an `impl` is not supported if the
lifetime parameter is used by an associated type.

### Error example 1

Suppose we have a struct `Foo` and we would like to define some methods for it.
The previous code example has a definition which leads to a compiler error:

The problem is that the parameter `T` does not appear in the implementing type
(`Foo`) of the impl. In this case, we can fix the error by moving the type
parameter from the `impl` to the method `get`:

```
struct Foo;

// Move the type parameter from the impl to the method
impl Foo {
    fn get<T: Default>(&self) -> T {
        <T as Default>::default()
    }
}
```

### Error example 2

As another example, suppose we have a `Maker` trait and want to establish a
type `FooMaker` that makes `Foo`s:

```compile_fail,E0207
trait Maker {
    type Item;
    fn make(&mut self) -> Self::Item;
}

struct Foo<T> {
    foo: T
}

struct FooMaker;

impl<T: Default> Maker for FooMaker {
// error: the type parameter `T` is not constrained by the impl trait, self
// type, or predicates [E0207]
    type Item = Foo<T>;

    fn make(&mut self) -> Foo<T> {
        Foo { foo: <T as Default>::default() }
    }
}
```

This fails to compile because `T` does not appear in the trait or in the
implementing type.

One way to work around this is to introduce a phantom type parameter into
`FooMaker`, like so:

```
use std::marker::PhantomData;

trait Maker {
    type Item;
    fn make(&mut self) -> Self::Item;
}

struct Foo<T> {
    foo: T
}

// Add a type parameter to `FooMaker`
struct FooMaker<T> {
    phantom: PhantomData<T>,
}

impl<T: Default> Maker for FooMaker<T> {
    type Item = Foo<T>;

    fn make(&mut self) -> Foo<T> {
        Foo {
            foo: <T as Default>::default(),
        }
    }
}
```

Another way is to do away with the associated type in `Maker` and use an input
type parameter instead:

```
// Use a type parameter instead of an associated type here
trait Maker<Item> {
    fn make(&mut self) -> Item;
}

struct Foo<T> {
    foo: T
}

struct FooMaker;

impl<T: Default> Maker<Foo<T>> for FooMaker {
    fn make(&mut self) -> Foo<T> {
        Foo { foo: <T as Default>::default() }
    }
}
```

### Error example 3

Suppose we have a struct `Foo` and we would like to define some methods for it.
The following code example has a definition which leads to a compiler error:

```compile_fail,E0207
struct Foo;

impl<const T: i32> Foo {
    // error: the const parameter `T` is not constrained by the impl trait, self
    // type, or predicates [E0207]
    fn get(&self) -> i32 {
        i32::default()
    }
}
```

The problem is that the const parameter `T` does not appear in the implementing
type (`Foo`) of the impl. In this case, we can fix the error by moving the type
parameter from the `impl` to the method `get`:


```
struct Foo;

// Move the const parameter from the impl to the method
impl Foo {
    fn get<const T: i32>(&self) -> i32 {
        i32::default()
    }
}
```

### Error example 4

Suppose we have a struct `Foo` and a struct `Bar` that uses lifetime `'a`. We
would like to implement trait `Contains` for `Foo`. The trait `Contains` have
the associated type `B`. The following code example has a definition which
leads to a compiler error:

```compile_fail,E0207
struct Foo;
struct Bar<'a>;

trait Contains {
    type B;

    fn get(&self) -> i32;
}

impl<'a> Contains for Foo {
    type B = Bar<'a>;

    // error: the lifetime parameter `'a` is not constrained by the impl trait,
    // self type, or predicates [E0207]
    fn get(&self) -> i32 {
        i32::default()
    }
}
```

Please note that unconstrained lifetime parameters are not supported if they are
being used by an associated type.

In cases where the associated type's lifetime is meant to be tied to the
self type, and none of the methods on the trait need ownership or different
mutability, then an option is to implement the trait on a borrowed type:

```rust
struct Foo(i32);

trait Contents {
    type Item;

    fn get(&self) -> Self::Item;
}

// Note the lifetime `'a` is used both for the self type...
impl<'a> Contents for &'a Foo {
    // ...and the associated type.
    type Item = &'a i32;

    fn get(&self) -> Self::Item {
        &self.0
    }
}
```

### Additional information

For more information, please see [RFC 447].

[RFC 447]: https://github.com/rust-lang/rfcs/blob/master/text/0447-no-unused-impl-parameters.md
#### This error code is internal to the compiler and will not be emitted with normal Rust code.
#### Note: this error code is no longer emitted by the compiler.

This error code shows the variance of a type's generic parameters.

Erroneous code example:

```compile_fail
// NOTE: this feature is perma-unstable and should *only* be used for
//       testing purposes.
#![allow(internal_features)]
#![feature(rustc_attrs)]

#[rustc_variance]
struct Foo<'a, T> { // error: deliberate error to display type's variance
    t: &'a mut T,
}
```

which produces the following error:

```text
error: [-, o]
 --> <anon>:4:1
  |
4 | struct Foo<'a, T> {
  | ^^^^^^^^^^^^^^^^^
```

*Note that while `#[rustc_variance]` still exists and is used within the*
*compiler, it no longer is marked as `E0208` and instead has no error code.*

This error is deliberately triggered with the `#[rustc_variance]` attribute
(`#![feature(rustc_attrs)]` must be enabled) and helps to show you the variance
of the type's generic parameters. You can read more about variance and
subtyping in [this section of the Rustonomicon]. For a more in depth look at
variance (including a more complete list of common variances) see
[this section of the Reference]. For information on how variance is implemented
in the compiler, see [this section of `rustc-dev-guide`].

This error can be easily fixed by removing the `#[rustc_variance]` attribute,
the compiler's suggestion to comment it out can be applied automatically with
`rustfix`.

[this section of the Rustonomicon]: https://doc.rust-lang.org/nomicon/subtyping.html
[this section of the Reference]: https://doc.rust-lang.org/reference/subtyping.html#variance
[this section of `rustc-dev-guide`]: https://rustc-dev-guide.rust-lang.org/variance.html
This error indicates a violation of one of Rust's orphan rules for trait
implementations. The rule concerns the use of type parameters in an
implementation of a foreign trait (a trait defined in another crate), and
states that type parameters must be "covered" by a local type.

When implementing a foreign trait for a foreign type,
the trait must have one or more type parameters.
A type local to your crate must appear before any use of any type parameters.

To understand what this means, it is perhaps easier to consider a few examples.

If `ForeignTrait` is a trait defined in some external crate `foo`, then the
following trait `impl` is an error:

```compile_fail,E0210
# #[cfg(for_demonstration_only)]
extern crate foo;
# #[cfg(for_demonstration_only)]
use foo::ForeignTrait;
# use std::panic::UnwindSafe as ForeignTrait;

impl<T> ForeignTrait for T { } // error
# fn main() {}
```

To work around this, it can be covered with a local type, `MyType`:

```
# use std::panic::UnwindSafe as ForeignTrait;
struct MyType<T>(T);
impl<T> ForeignTrait for MyType<T> { } // Ok
```

Please note that a type alias is not sufficient.

For another example of an error, suppose there's another trait defined in `foo`
named `ForeignTrait2` that takes two type parameters. Then this `impl` results
in the same rule violation:

```ignore (cannot-doctest-multicrate-project)
struct MyType2;
impl<T> ForeignTrait2<T, MyType<T>> for MyType2 { } // error
```

The reason for this is that there are two appearances of type parameter `T` in
the `impl` header, both as parameters for `ForeignTrait2`. The first appearance
is uncovered, and so runs afoul of the orphan rule.

Consider one more example:

```ignore (cannot-doctest-multicrate-project)
impl<T> ForeignTrait2<MyType<T>, T> for MyType2 { } // Ok
```

This only differs from the previous `impl` in that the parameters `T` and
`MyType<T>` for `ForeignTrait2` have been swapped. This example does *not*
violate the orphan rule; it is permitted.

To see why that last example was allowed, you need to understand the general
rule. Unfortunately this rule is a bit tricky to state. Consider an `impl`:

```ignore (only-for-syntax-highlight)
impl<P1, ..., Pm> ForeignTrait<T1, ..., Tn> for T0 { ... }
```

where `P1, ..., Pm` are the type parameters of the `impl` and `T0, ..., Tn`
are types. One of the types `T0, ..., Tn` must be a local type (this is another
orphan rule, see the explanation for E0117).

Both of the following must be true:
1. At least one of the types `T0..=Tn` must be a local type.
Let `Ti` be the first such type.
2. No uncovered type parameters `P1..=Pm` may appear in `T0..Ti`
(excluding `Ti`).

For information on the design of the orphan rules,
see [RFC 2451] and [RFC 1023].

[RFC 2451]: https://rust-lang.github.io/rfcs/2451-re-rebalancing-coherence.html
[RFC 1023]: https://github.com/rust-lang/rfcs/blob/master/text/1023-rebalancing-coherence.md
#### Note: this error code is no longer emitted by the compiler.

You used a function or type which doesn't fit the requirements for where it was
used. Erroneous code examples:

```compile_fail
#![feature(intrinsics)]
#![allow(internal_features)]

#[rustc_intrinsic]
unsafe fn unreachable(); // error: intrinsic has wrong type

// or:

fn main() -> i32 { 0 }
// error: main function expects type: `fn() {main}`: expected (), found i32

// or:

let x = 1u8;
match x {
    0u8..=3i8 => (),
    // error: mismatched types in range: expected u8, found i8
    _ => ()
}

// or:

use std::rc::Rc;
struct Foo;

impl Foo {
    fn x(self: Rc<Foo>) {}
    // error: mismatched self type: expected `Foo`: expected struct
    //        `Foo`, found struct `alloc::rc::Rc`
}
```

For the first code example, please check the function definition. Example:

```
#![feature(intrinsics)]
#![allow(internal_features)]

#[rustc_intrinsic]
unsafe fn unreachable() -> !; // ok!
```

The second case example is a bit particular: the main function must always
have this definition:

```compile_fail
fn main();
```

They never take parameters and never return types.

For the third example, when you match, all patterns must have the same type
as the type you're matching on. Example:

```
let x = 1u8;

match x {
    0u8..=3u8 => (), // ok!
    _ => ()
}
```

And finally, for the last example, only `Box<Self>`, `&Self`, `Self`,
or `&mut Self` work as explicit self parameters. Example:

```
struct Foo;

impl Foo {
    fn x(self: Box<Foo>) {} // ok!
}
```
Cannot use the associated type of
a trait with uninferred generic parameters.

Erroneous code example:

```compile_fail,E0212
pub trait Foo<T> {
    type A;

    fn get(&self, t: T) -> Self::A;
}

fn foo2<I : for<'x> Foo<&'x isize>>(
    field: I::A) {} // error!
```

In this example, we have to instantiate `'x`, and
we don't know what lifetime to instantiate it with.
To fix this, spell out the precise lifetimes involved.
Example:

```
pub trait Foo<T> {
    type A;

    fn get(&self, t: T) -> Self::A;
}

fn foo3<I : for<'x> Foo<&'x isize>>(
    x: <I as Foo<&isize>>::A) {} // ok!


fn foo4<'a, I : for<'x> Foo<&'x isize>>(
    x: <I as Foo<&'a isize>>::A) {} // ok!
```
A generic type was described using parentheses rather than angle brackets.

Erroneous code example:

```compile_fail,E0214
let v: Vec(&str) = vec!["foo"];
```

This is not currently supported: `v` should be defined as `Vec<&str>`.
Parentheses are currently only used with generic types when defining parameters
for `Fn`-family traits.

The previous code example fixed:

```
let v: Vec<&str> = vec!["foo"];
```
The associated type used was not defined in the trait.

Erroneous code example:

```compile_fail,E0220
trait T1 {
    type Bar;
}

type Foo = T1<F=i32>; // error: associated type `F` not found for `T1`

// or:

trait T2 {
    type Bar;

    // error: Baz is used but not declared
    fn return_bool(&self, _: &Self::Bar, _: &Self::Baz) -> bool;
}
```

Make sure that you have defined the associated type in the trait body.
Also, verify that you used the right trait or you didn't misspell the
associated type name. Example:

```
trait T1 {
    type Bar;
}

type Foo = T1<Bar=i32>; // ok!

// or:

trait T2 {
    type Bar;
    type Baz; // we declare `Baz` in our trait.

    // and now we can use it here:
    fn return_bool(&self, _: &Self::Bar, _: &Self::Baz) -> bool;
}
```
An attempt was made to retrieve an associated type, but the type was ambiguous.

Erroneous code example:

```compile_fail,E0221
trait T1 {}
trait T2 {}

trait Foo {
    type A: T1;
}

trait Bar : Foo {
    type A: T2;
    fn do_something() {
        let _: Self::A;
    }
}
```

In this example, `Foo` defines an associated type `A`. `Bar` inherits that type
from `Foo`, and defines another associated type of the same name. As a result,
when we attempt to use `Self::A`, it's ambiguous whether we mean the `A` defined
by `Foo` or the one defined by `Bar`.

There are two options to work around this issue. The first is simply to rename
one of the types. Alternatively, one can specify the intended type using the
following syntax:

```
trait T1 {}
trait T2 {}

trait Foo {
    type A: T1;
}

trait Bar : Foo {
    type A: T2;
    fn do_something() {
        let _: <Self as Bar>::A;
    }
}
```
An attempt was made to constrain an associated type.

Erroneous code example:

```compile_fail,E0222
pub trait Vehicle {
    type Color;
}

pub trait Box {
    type Color;
}

pub trait BoxCar : Box + Vehicle {}

fn dent_object<COLOR>(c: dyn BoxCar<Color=COLOR>) {} // Invalid constraint
```

In this example, `BoxCar` has two supertraits: `Vehicle` and `Box`. Both of
these traits define an associated type `Color`. `BoxCar` inherits two types
with that name from both supertraits. Because of this, we need to use the
fully qualified path syntax to refer to the appropriate `Color` associated
type, either `<BoxCar as Vehicle>::Color` or `<BoxCar as Box>::Color`, but this
syntax is not allowed to be used in a function signature.

In order to encode this kind of constraint, a `where` clause and a new type
parameter are needed:

```
pub trait Vehicle {
    type Color;
}

pub trait Box {
    type Color;
}

pub trait BoxCar : Box + Vehicle {}

// Introduce a new `CAR` type parameter
fn foo<CAR, COLOR>(
    c: CAR,
) where
    // Bind the type parameter `CAR` to the trait `BoxCar`
    CAR: BoxCar,
    // Further restrict `<BoxCar as Vehicle>::Color` to be the same as the
    // type parameter `COLOR`
    CAR: Vehicle<Color = COLOR>,
    // We can also simultaneously restrict the other trait's associated type
    CAR: Box<Color = COLOR>
{}
```
An attempt was made to retrieve an associated type, but the type was ambiguous.

Erroneous code example:

```compile_fail,E0223
trait Trait { type X; }

fn main() {
    let foo: Trait::X;
}
```

The problem here is that we're attempting to take the associated type of `X`
from `Trait`. Unfortunately, the type of `X` is not defined, because it's only
made concrete in implementations of the trait. A working version of this code
might look like:

```
trait Trait { type X; }

struct Struct;
impl Trait for Struct {
    type X = u32;
}

fn main() {
    let foo: <Struct as Trait>::X;
}
```

This syntax specifies that we want the associated type `X` from `Struct`'s
implementation of `Trait`.

Due to internal limitations of the current compiler implementation we cannot
simply use `Struct::X`.
A trait object was declared with no traits.

Erroneous code example:

```compile_fail,E0224
type Foo = dyn 'static +;
```

Rust does not currently support this.

To solve, ensure that the trait object has at least one trait:

```
type Foo = dyn 'static + Copy;
```
Multiple types were used as bounds for a closure or trait object.

Erroneous code example:

```compile_fail,E0225
fn main() {
    let _: Box<dyn std::io::Read + std::io::Write>;
}
```

Rust does not currently support this.

Auto traits such as Send and Sync are an exception to this rule:
It's possible to have bounds of one non-builtin trait, plus any number of
auto traits. For example, the following compiles correctly:

```
fn main() {
    let _: Box<dyn std::io::Read + Send + Sync>;
}
```
More than one explicit lifetime bound was used on a trait object.

Example of erroneous code:

```compile_fail,E0226
trait Foo {}

type T<'a, 'b> = dyn Foo + 'a + 'b; // error: Trait object `arg` has two
                                    //        lifetime bound, 'a and 'b.
```

Here `T` is a trait object with two explicit lifetime bounds, 'a and 'b.

Only a single explicit lifetime bound is permitted on trait objects.
To fix this error, consider removing one of the lifetime bounds:

```
trait Foo {}

type T<'a> = dyn Foo + 'a;
```
This error indicates that the compiler is unable to determine whether there is
exactly one unique region in the set of derived region bounds.

Example of erroneous code:

```compile_fail,E0227
trait Foo<'foo>: 'foo {}
trait Bar<'bar>: 'bar {}

trait FooBar<'foo, 'bar>: Foo<'foo> + Bar<'bar> {}

struct Baz<'foo, 'bar> {
    baz: dyn FooBar<'foo, 'bar>,
}
```

Here, `baz` can have either `'foo` or `'bar` lifetimes.

To resolve this error, provide an explicit lifetime:

```rust
trait Foo<'foo>: 'foo {}
trait Bar<'bar>: 'bar {}

trait FooBar<'foo, 'bar>: Foo<'foo> + Bar<'bar> {}

struct Baz<'foo, 'bar, 'baz>
where
    'baz: 'foo + 'bar,
{
    obj: dyn FooBar<'foo, 'bar> + 'baz,
}
```
The lifetime bound for this object type cannot be deduced from context and must
be specified.

Erroneous code example:

```compile_fail,E0228
trait Trait { }

struct TwoBounds<'a, 'b, T: Sized + 'a + 'b> {
    x: &'a i32,
    y: &'b i32,
    z: T,
}

type Foo<'a, 'b> = TwoBounds<'a, 'b, dyn Trait>;
```

When a trait object is used as a type argument of a generic type, Rust will try
to infer its lifetime if unspecified. However, this isn't possible when the
containing type has more than one lifetime bound.

The above example can be resolved by either reducing the number of lifetime
bounds to one or by making the trait object lifetime explicit, like so:

```
trait Trait { }

struct TwoBounds<'a, 'b, T: Sized + 'a + 'b> {
    x: &'a i32,
    y: &'b i32,
    z: T,
}

type Foo<'a, 'b> = TwoBounds<'a, 'b, dyn Trait + 'b>;
```

For more information, see [RFC 599] and its amendment [RFC 1156].

[RFC 599]: https://github.com/rust-lang/rfcs/blob/master/text/0599-default-object-bound.md
[RFC 1156]: https://github.com/rust-lang/rfcs/blob/master/text/1156-adjust-default-object-bounds.md
An associated item constraint was written in an unexpected context.

Erroneous code example:

```compile_fail,E0229
pub trait Foo {
    type A;
    fn boo(&self) -> <Self as Foo>::A;
}

struct Bar;

impl Foo for isize {
    type A = usize;
    fn boo(&self) -> usize { 42 }
}

fn baz<I>(x: &<I as Foo<A = Bar>>::A) {}
// error: associated item constraint are not allowed here
```

To solve this error, please move the associated item constraints to the type
parameter declaration:

```
# struct Bar;
# trait Foo { type A; }
fn baz<I: Foo<A=Bar>>(x: &<I as Foo>::A) {} // ok!
```

Or into the where-clause:

```
# struct Bar;
# trait Foo { type A; }
fn baz<I>(x: &<I as Foo>::A) where I: Foo<A=Bar> {}
```
The `#[rustc_on_unimplemented]` attribute lets you specify a custom error
message for when a particular trait isn't implemented on a type placed in a
position that needs that trait. For example, when the following code is
compiled:

```compile_fail,E0230
#![feature(rustc_attrs)]
#![allow(internal_features)]

#[rustc_on_unimplemented = "error on `{Self}` with params `<{A},{B}>`"] // error
trait BadAnnotation<A> {}
```

There will be an error about `bool` not implementing `Index<u8>`, followed by a
note saying "the type `bool` cannot be indexed by `u8`".

As you can see, you can specify type parameters in curly braces for
instantiation with the actual types (using the regular format string syntax) in
a given situation. Furthermore, `{Self}` will be instantiated to the type (in
this case, `bool`) that we tried to use.

This error appears when the curly braces contain an identifier which doesn't
match with any of the type parameters or the string `Self`. This might happen
if you misspelled a type parameter, or if you intended to use literal curly
braces. If it is the latter, escape the curly braces with a second curly brace
of the same type; e.g., a literal `{` is `{{`.
The `#[rustc_on_unimplemented]` attribute lets you specify a custom error
message for when a particular trait isn't implemented on a type placed in a
position that needs that trait. For example, when the following code is
compiled:

```compile_fail,E0231
#![feature(rustc_attrs)]
#![allow(internal_features)]

#[rustc_on_unimplemented = "error on `{Self}` with params `<{A},{}>`"] // error!
trait BadAnnotation<A> {}
```

there will be an error about `bool` not implementing `Index<u8>`, followed by a
note saying "the type `bool` cannot be indexed by `u8`".

As you can see, you can specify type parameters in curly braces for
instantiation with the actual types (using the regular format string syntax) in
a given situation. Furthermore, `{Self}` will be instantiated to the type (in
this case, `bool`) that we tried to use.

This error appears when the curly braces do not contain an identifier. Please
add one of the same name as a type parameter. If you intended to use literal
braces, use `{{` and `}}` to escape them.
The `#[rustc_on_unimplemented]` attribute lets you specify a custom error
message for when a particular trait isn't implemented on a type placed in a
position that needs that trait. For example, when the following code is
compiled:

```compile_fail,E0232
#![feature(rustc_attrs)]
#![allow(internal_features)]

#[rustc_on_unimplemented(lorem="")] // error!
trait BadAnnotation {}
```

there will be an error about `bool` not implementing `Index<u8>`, followed by a
note saying "the type `bool` cannot be indexed by `u8`".

For this to work, some note must be specified. An empty attribute will not do
anything, please remove the attribute or add some helpful note for users of the
trait.
#### Note: this error code is no longer emitted by the compiler.

This error indicates that not enough type parameters were found in a type or
trait.

For example, the `Foo` struct below is defined to be generic in `T`, but the
type parameter is missing in the definition of `Bar`:

```compile_fail,E0107
struct Foo<T> { x: T }

struct Bar { x: Foo }
```
#### Note: this error code is no longer emitted by the compiler.

This error indicates that too many type parameters were found in a type or
trait.

For example, the `Foo` struct below has no type parameters, but is supplied
with two in the definition of `Bar`:

```compile_fail,E0107
struct Foo { x: bool }

struct Bar<S, T> { x: Foo<S, T> }
```
#### Note: this error code is no longer emitted by the compiler.

Two items of the same name cannot be imported without rebinding one of the
items under a new local name.

An example of this error:

```
use foo::baz;
use bar::*; // error, do `use foo::baz as quux` instead on the previous line

fn main() {}

mod foo {
    pub struct baz;
}

mod bar {
    pub mod baz {}
}
```
Two items of the same name cannot be imported without rebinding one of the
items under a new local name.

Erroneous code example:

```compile_fail,E0252
use foo::baz;
use bar::baz; // error, do `use bar::baz as quux` instead

fn main() {}

mod foo {
    pub struct baz;
}

mod bar {
    pub mod baz {}
}
```

You can use aliases in order to fix this error. Example:

```
use foo::baz as foo_baz;
use bar::baz; // ok!

fn main() {}

mod foo {
    pub struct baz;
}

mod bar {
    pub mod baz {}
}
```

Or you can reference the item with its parent:

```
use bar::baz;

fn main() {
    let x = foo::baz; // ok!
}

mod foo {
    pub struct baz;
}

mod bar {
    pub mod baz {}
}
```
#### Note: this error code is no longer emitted by the compiler.

Attempt was made to import an unimportable type. This can happen when trying
to import a type from a trait.

Erroneous code example:

```
#![feature(import_trait_associated_functions)]

mod foo {
    pub trait MyTrait {
        type SomeType;
    }
}

use foo::MyTrait::SomeType;
// error: `SomeType` is not directly importable

fn main() {}
```

It's invalid to directly import types belonging to a trait.
Attempt was made to import an item whereas an extern crate with this name has
already been imported.

Erroneous code example:

```compile_fail,E0254
extern crate core;

mod foo {
    pub trait core {
        fn do_something();
    }
}

use foo::core;  // error: an extern crate named `core` has already
                //        been imported in this module

fn main() {}
```

To fix this issue, you have to rename at least one of the two imports.
Example:

```
extern crate core as libcore; // ok!

mod foo {
    pub trait core {
        fn do_something();
    }
}

use foo::core;

fn main() {}
```
You can't import a value whose name is the same as another value defined in the
module.

Erroneous code example:

```compile_fail,E0255
use bar::foo; // error: an item named `foo` is already in scope

fn foo() {}

mod bar {
     pub fn foo() {}
}

fn main() {}
```

You can use aliases in order to fix this error. Example:

```
use bar::foo as bar_foo; // ok!

fn foo() {}

mod bar {
     pub fn foo() {}
}

fn main() {}
```

Or you can reference the item with its parent:

```
fn foo() {}

mod bar {
     pub fn foo() {}
}

fn main() {
    bar::foo(); // we get the item by referring to its parent
}
```
#### Note: this error code is no longer emitted by the compiler.

You can't import a type or module when the name of the item being imported is
the same as another type or submodule defined in the module.

An example of this error:

```compile_fail
use foo::Bar; // error

type Bar = u32;

mod foo {
    pub mod Bar { }
}

fn main() {}
```
The name chosen for an external crate conflicts with another external crate
that has been imported into the current module.

Erroneous code example:

```compile_fail,E0259
extern crate core;
extern crate std as core;

fn main() {}
```

The solution is to choose a different name that doesn't conflict with any
external crate imported into the current module.

Correct example:

```
extern crate core;
extern crate std as other_name;

fn main() {}
```
The name for an item declaration conflicts with an external crate's name.

Erroneous code example:

```compile_fail,E0260
extern crate core;

struct core;

fn main() {}
```

There are two possible solutions:

Solution #1: Rename the item.

```
extern crate core;

struct xyz;
```

Solution #2: Import the crate with a different name.

```
extern crate core as xyz;

struct abc;
```

See the [Declaration Statements][declaration-statements] section of the
reference for more information about what constitutes an item declaration
and what does not.

[declaration-statements]: https://doc.rust-lang.org/reference/statements.html#declaration-statements
An undeclared lifetime was used.

Erroneous code example:

```compile_fail,E0261
// error, use of undeclared lifetime name `'a`
fn foo(x: &'a str) { }

struct Foo {
    // error, use of undeclared lifetime name `'a`
    x: &'a str,
}
```

These can be fixed by declaring lifetime parameters:

```
struct Foo<'a> {
    x: &'a str,
}

fn foo<'a>(x: &'a str) {}
```

Impl blocks declare lifetime parameters separately. You need to add lifetime
parameters to an impl block if you're implementing a type that has a lifetime
parameter of its own.
For example:

```compile_fail,E0261
struct Foo<'a> {
    x: &'a str,
}

// error,  use of undeclared lifetime name `'a`
impl Foo<'a> {
    fn foo<'a>(x: &'a str) {}
}
```

This is fixed by declaring the impl block like this:

```
struct Foo<'a> {
    x: &'a str,
}

// correct
impl<'a> Foo<'a> {
    fn foo(x: &'a str) {}
}
```
An invalid name was used for a lifetime parameter.

Erroneous code example:

```compile_fail,E0262
// error, invalid lifetime parameter name `'static`
fn foo<'static>(x: &'static str) { }
```

Declaring certain lifetime names in parameters is disallowed. For example,
because the `'static` lifetime is a special built-in lifetime name denoting
the lifetime of the entire program, this is an error:
#### Note: this error code is no longer emitted by the compiler.

A lifetime was declared more than once in the same scope.

Erroneous code example:

```compile_fail,E0403
fn foo<'a, 'b, 'a>(x: &'a str, y: &'b str, z: &'a str) { // error!
}
```

Two lifetimes cannot have the same name. To fix this example, change
the second `'a` lifetime into something else (`'c` for example):

```
fn foo<'a, 'b, 'c>(x: &'a str, y: &'b str, z: &'c str) { // ok!
}
```
An unknown external lang item was used.

Erroneous code example:

```compile_fail,E0264
#![feature(lang_items)]
#![allow(internal_features)]

extern "C" {
    #[lang = "cake"] // error: unknown external lang item: `cake`
    fn cake();
}
```

A list of available external lang items is available in
`compiler/rustc_hir/src/weak_lang_items.rs`. Example:

```
#![feature(lang_items)]
#![allow(internal_features)]

extern "C" {
    #[lang = "panic_impl"] // ok!
    fn cake();
}
```
A loop keyword (`break` or `continue`) was used inside a closure but outside of
any loop.

Erroneous code example:

```compile_fail,E0267
let w = || { break; }; // error: `break` inside of a closure
```

`break` and `continue` keywords can be used as normal inside closures as long as
they are also contained within a loop. To halt the execution of a closure you
should instead use a return statement. Example:

```
let w = || {
    for _ in 0..10 {
        break;
    }
};

w();
```
A loop keyword (`break` or `continue`) was used outside of a loop.

Erroneous code example:

```compile_fail,E0268
fn some_func() {
    break; // error: `break` outside of a loop
}
```

Without a loop to break out of or continue in, no sensible action can be taken.
Please verify that you are using `break` and `continue` only in loops. Example:

```
fn some_func() {
    for _ in 0..10 {
        break; // ok!
    }
}
```
A type mismatched an associated type of a trait.

Erroneous code example:

```compile_fail,E0271
trait Trait { type AssociatedType; }

fn foo<T>(t: T) where T: Trait<AssociatedType=u32> {
//                    ~~~~~~~~ ~~~~~~~~~~~~~~~~~~
//                        |            |
//         This says `foo` can         |
//           only be used with         |
//              some type that         |
//         implements `Trait`.         |
//                                     |
//                             This says not only must
//                             `T` be an impl of `Trait`
//                             but also that the impl
//                             must assign the type `u32`
//                             to the associated type.
    println!("in foo");
}

impl Trait for i8 { type AssociatedType = &'static str; }
//~~~~~~~~~~~~~~~   ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
//      |                             |
// `i8` does have                     |
// implementation                     |
// of `Trait`...                      |
//                     ... but it is an implementation
//                     that assigns `&'static str` to
//                     the associated type.

foo(3_i8);
// Here, we invoke `foo` with an `i8`, which does not satisfy
// the constraint `<i8 as Trait>::AssociatedType=u32`, and
// therefore the type-checker complains with this error code.
```

The issue can be resolved by changing the associated type:
1) in the `foo` implementation:
```
trait Trait { type AssociatedType; }

fn foo<T>(t: T) where T: Trait<AssociatedType = &'static str> {
    println!("in foo");
}

impl Trait for i8 { type AssociatedType = &'static str; }

foo(3_i8);
```

2) in the `Trait` implementation for `i8`:
```
trait Trait { type AssociatedType; }

fn foo<T>(t: T) where T: Trait<AssociatedType = u32> {
    println!("in foo");
}

impl Trait for i8 { type AssociatedType = u32; }

foo(3_i8);
```
An evaluation of a trait requirement overflowed.

Erroneous code example:

```compile_fail,E0275
trait Foo {}

struct Bar<T>(T);

impl<T> Foo for T where Bar<T>: Foo {}
```

This error occurs when there was a recursive trait requirement that overflowed
before it could be evaluated. This often means that there is an unbounded
recursion in resolving some type bounds.

To determine if a `T` is `Foo`, we need to check if `Bar<T>` is `Foo`. However,
to do this check, we need to determine that `Bar<Bar<T>>` is `Foo`. To
determine this, we check if `Bar<Bar<Bar<T>>>` is `Foo`, and so on. This is
clearly a recursive requirement that can't be resolved directly.

Consider changing your trait bounds so that they're less self-referential.
A trait implementation has stricter requirements than the trait definition.

Erroneous code example:

```compile_fail,E0276
trait Foo {
    fn foo<T>(x: T);
}

impl Foo for bool {
    fn foo<T>(x: T) where T: Copy {}
}
```

Here, all types implementing `Foo` must have a method `foo<T>(x: T)` which can
take any type `T`. However, in the `impl` for `bool`, we have added an extra
bound that `T` is `Copy`, which isn't compatible with the original trait.

Consider removing the bound from the method or adding the bound to the original
method definition in the trait.
You tried to use a type which doesn't implement some trait in a place which
expected that trait.

Erroneous code example:

```compile_fail,E0277
// here we declare the Foo trait with a bar method
trait Foo {
    fn bar(&self);
}

// we now declare a function which takes an object implementing the Foo trait
fn some_func<T: Foo>(foo: T) {
    foo.bar();
}

fn main() {
    // we now call the method with the i32 type, which doesn't implement
    // the Foo trait
    some_func(5i32); // error: the trait bound `i32 : Foo` is not satisfied
}
```

In order to fix this error, verify that the type you're using does implement
the trait. Example:

```
trait Foo {
    fn bar(&self);
}

// we implement the trait on the i32 type
impl Foo for i32 {
    fn bar(&self) {}
}

fn some_func<T: Foo>(foo: T) {
    foo.bar(); // we can now use this method since i32 implements the
               // Foo trait
}

fn main() {
    some_func(5i32); // ok!
}
```

Or in a generic context, an erroneous code example would look like:

```compile_fail,E0277
fn some_func<T>(foo: T) {
    println!("{:?}", foo); // error: the trait `core::fmt::Debug` is not
                           //        implemented for the type `T`
}

fn main() {
    // We now call the method with the i32 type,
    // which *does* implement the Debug trait.
    some_func(5i32);
}
```

Note that the error here is in the definition of the generic function. Although
we only call it with a parameter that does implement `Debug`, the compiler
still rejects the function. It must work with all possible input types. In
order to make this example compile, we need to restrict the generic type we're
accepting:

```
use std::fmt;

// Restrict the input type to types that implement Debug.
fn some_func<T: fmt::Debug>(foo: T) {
    println!("{:?}", foo);
}

fn main() {
    // Calling the method is still fine, as i32 implements Debug.
    some_func(5i32);

    // This would fail to compile now:
    // struct WithoutDebug;
    // some_func(WithoutDebug);
}
```

Rust only looks at the signature of the called function, as such it must
already specify all requirements that will be used for every type parameter.
#### Note: this error code is no longer emitted by the compiler.

You tried to supply a type which doesn't implement some trait in a location
which expected that trait. This error typically occurs when working with
`Fn`-based types. Erroneous code example:

```compile_fail
fn foo<F: Fn(usize)>(x: F) { }

fn main() {
    // type mismatch: ... implements the trait `core::ops::Fn<(String,)>`,
    // but the trait `core::ops::Fn<(usize,)>` is required
    // [E0281]
    foo(|y: String| { });
}
```

The issue in this case is that `foo` is defined as accepting a `Fn` with one
argument of type `String`, but the closure we attempted to pass to it requires
one arguments of type `usize`.
The compiler could not infer a type and asked for a type annotation.

Erroneous code example:

```compile_fail,E0282
let x = Vec::new();
```

This error indicates that type inference did not result in one unique possible
type, and extra information is required. In most cases this can be provided
by adding a type annotation. Sometimes you need to specify a generic type
parameter manually.

In the example above, type `Vec` has a type parameter `T`. When calling
`Vec::new`, barring any other later usage of the variable `x` that allows the
compiler to infer what type `T` is, the compiler needs to be told what it is.

The type can be specified on the variable:

```
let x: Vec<i32> = Vec::new();
```

The type can also be specified in the path of the expression:

```
let x = Vec::<i32>::new();
```

In cases with more complex types, it is not necessary to annotate the full
type. Once the ambiguity is resolved, the compiler can infer the rest:

```
let x: Vec<_> = "hello".chars().rev().collect();
```

Another way to provide the compiler with enough information, is to specify the
generic type parameter:

```
let x = "hello".chars().rev().collect::<Vec<char>>();
```

Again, you need not specify the full type if the compiler can infer it:

```
let x = "hello".chars().rev().collect::<Vec<_>>();
```

Apart from a method or function with a generic type parameter, this error can
occur when a type parameter of a struct or trait cannot be inferred. In that
case it is not always possible to use a type annotation, because all candidates
have the same return type. For instance:

```compile_fail,E0282
struct Foo<T> {
    num: T,
}

impl<T> Foo<T> {
    fn bar() -> i32 {
        0
    }

    fn baz() {
        let number = Foo::bar();
    }
}
```

This will fail because the compiler does not know which instance of `Foo` to
call `bar` on. Change `Foo::bar()` to `Foo::<T>::bar()` to resolve the error.
The compiler could not infer a type and asked for a type annotation.

Erroneous code example:

```compile_fail,E0283
let x = "hello".chars().rev().collect();
```

This error indicates that type inference did not result in one unique possible
type, and extra information is required. In most cases this can be provided
by adding a type annotation. Sometimes you need to specify a generic type
parameter manually.

A common example is the `collect` method on `Iterator`. It has a generic type
parameter with a `FromIterator` bound, which for a `char` iterator is
implemented by `Vec` and `String` among others. Consider the following snippet
that reverses the characters of a string:

In the first code example, the compiler cannot infer what the type of `x` should
be: `Vec<char>` and `String` are both suitable candidates. To specify which type
to use, you can use a type annotation on `x`:

```
let x: Vec<char> = "hello".chars().rev().collect();
```

It is not necessary to annotate the full type. Once the ambiguity is resolved,
the compiler can infer the rest:

```
let x: Vec<_> = "hello".chars().rev().collect();
```

Another way to provide the compiler with enough information, is to specify the
generic type parameter:

```
let x = "hello".chars().rev().collect::<Vec<char>>();
```

Again, you need not specify the full type if the compiler can infer it:

```
let x = "hello".chars().rev().collect::<Vec<_>>();
```

We can see a self-contained example below:

```compile_fail,E0283
struct Foo;

impl Into<u32> for Foo {
    fn into(self) -> u32 { 1 }
}

let foo = Foo;
let bar: u32 = foo.into() * 1u32;
```

This error can be solved by adding type annotations that provide the missing
information to the compiler. In this case, the solution is to specify the
trait's type parameter:

```
struct Foo;

impl Into<u32> for Foo {
    fn into(self) -> u32 { 1 }
}

let foo = Foo;
let bar: u32 = Into::<u32>::into(foo) * 1u32;
```
This error occurs when the compiler is unable to unambiguously infer the
return type of a function or method which is generic on return type, such
as the `collect` method for `Iterator`s.

For example:

```compile_fail,E0284
fn main() {
    let n: u32 = 1;
    let mut d: u64 = 2;
    d = d + n.into();
}
```

Here we have an addition of `d` and `n.into()`. Hence, `n.into()` can return
any type `T` where `u64: Add<T>`. On the other hand, the `into` method can
return any type where `u32: Into<T>`.

The author of this code probably wants `into()` to return a `u64`, but the
compiler can't be sure that there isn't another type `T` where both
`u32: Into<T>` and `u64: Add<T>`.

To resolve this error, use a concrete type for the intermediate expression:

```
fn main() {
    let n: u32 = 1;
    let mut d: u64 = 2;
    let m: u64 = n.into();
    d = d + m;
}
```
#### Note: this error code is no longer emitted by the compiler.

Patterns used to bind names must be irrefutable. That is, they must guarantee
that a name will be extracted in all cases. Instead of pattern matching the
loop variable, consider using a `match` or `if let` inside the loop body. For
instance:

```compile_fail,E0005
let xs : Vec<Option<i32>> = vec![Some(1), None];

// This fails because `None` is not covered.
for Some(x) in xs {
    // ...
}
```

Match inside the loop instead:

```
let xs : Vec<Option<i32>> = vec![Some(1), None];

for item in xs {
    match item {
        Some(x) => {},
        None => {},
    }
}
```

Or use `if let`:

```
let xs : Vec<Option<i32>> = vec![Some(1), None];

for item in xs {
    if let Some(x) = item {
        // ...
    }
}
```
#### Note: this error code is no longer emitted by the compiler.

Mutable borrows are not allowed in pattern guards, because matching cannot have
side effects. Side effects could alter the matched object or the environment
on which the match depends in such a way, that the match would not be
exhaustive. For instance, the following would not match any arm if mutable
borrows were allowed:

```compile_fail,E0596
match Some(()) {
    None => { },
    option if option.take().is_none() => {
        /* impossible, option is `Some` */
    },
    Some(_) => { } // When the previous match failed, the option became `None`.
}
```
#### Note: this error code is no longer emitted by the compiler.

Assignments are not allowed in pattern guards, because matching cannot have
side effects. Side effects could alter the matched object or the environment
on which the match depends in such a way, that the match would not be
exhaustive. For instance, the following would not match any arm if assignments
were allowed:

```compile_fail,E0594
match Some(()) {
    None => { },
    option if { option = None; false } => { },
    Some(_) => { } // When the previous match failed, the option became `None`.
}
```
#### Note: this error code is no longer emitted by the compiler.

Sub-bindings, e.g. `ref x @ Some(ref y)` are now allowed under
`#![feature(bindings_after_at)]` and checked to make sure that
memory safety is upheld.

--------------

In certain cases it is possible for sub-bindings to violate memory safety.
Updates to the borrow checker in a future version of Rust may remove this
restriction, but for now patterns must be rewritten without sub-bindings.

Before:

```compile_fail
match Some("hi".to_string()) {
    ref op_string_ref @ Some(s) => {},
    None => {},
}
```

After:

```
match Some("hi".to_string()) {
    Some(ref s) => {
        let op_string_ref = &Some(s);
        // ...
    },
    None => {},
}
```

The `op_string_ref` binding has type `&Option<&String>` in both cases.

See also [Issue 14587][issue-14587].

[issue-14587]: https://github.com/rust-lang/rust/issues/14587
The `self` parameter in a method has an invalid "receiver type".

Erroneous code example:

```compile_fail,E0307
struct Foo;
struct Bar;

trait Trait {
    fn foo(&self);
}

impl Trait for Foo {
    fn foo(self: &Bar) {}
}
```

Methods take a special first parameter, of which there are three variants:
`self`, `&self`, and `&mut self`. These are syntactic sugar for
`self: Self`, `self: &Self`, and `self: &mut Self` respectively.

```
# struct Foo;
trait Trait {
    fn foo(&self);
//         ^^^^^ `self` here is a reference to the receiver object
}

impl Trait for Foo {
    fn foo(&self) {}
//         ^^^^^ the receiver type is `&Foo`
}
```

The type `Self` acts as an alias to the type of the current trait
implementer, or "receiver type". Besides the already mentioned `Self`,
`&Self` and `&mut Self` valid receiver types, the following are also valid:
`self: Box<Self>`, `self: Rc<Self>`, `self: Arc<Self>`, and `self: Pin<P>`
(where P is one of the previous types except `Self`). Note that `Self` can
also be the underlying implementing type, like `Foo` in the following
example:

```
# struct Foo;
# trait Trait {
#     fn foo(&self);
# }
impl Trait for Foo {
    fn foo(self: &Foo) {}
}
```

This error will be emitted by the compiler when using an invalid receiver type,
like in the following example:

```compile_fail,E0307
# struct Foo;
# struct Bar;
# trait Trait {
#     fn foo(&self);
# }
impl Trait for Foo {
    fn foo(self: &Bar) {}
}
```

The nightly feature [Arbitrary self types][AST] extends the accepted
set of receiver types to also include any type that implements the
`Receiver` trait and can follow its chain of `Target` types to `Self`.
There's a blanket implementation of `Receiver` for `T: Deref`, so any
type which dereferences to `Self` can be used.

```
#![feature(arbitrary_self_types)]

struct Foo;
struct Bar;

// Because you can dereference `Bar` into `Foo`...
impl std::ops::Deref for Bar {
    type Target = Foo;

    fn deref(&self) -> &Foo {
        &Foo
    }
}

impl Foo {
    fn foo(self: Bar) {}
//         ^^^^^^^^^ ...it can be used as the receiver type
}
```

[AST]: https://doc.rust-lang.org/unstable-book/language-features/arbitrary-self-types.html
Expected type did not match the received type.

Erroneous code examples:

```compile_fail,E0308
fn plus_one(x: i32) -> i32 {
    x + 1
}

plus_one("Not a number");
//       ^^^^^^^^^^^^^^ expected `i32`, found `&str`

if "Not a bool" {
// ^^^^^^^^^^^^ expected `bool`, found `&str`
}

let x: f32 = "Not a float";
//     ---   ^^^^^^^^^^^^^ expected `f32`, found `&str`
//     |
//     expected due to this
```

This error occurs when an expression was used in a place where the compiler
expected an expression of a different type. It can occur in several cases, the
most common being when calling a function and passing an argument which has a
different type than the matching type in the function declaration.
A parameter type is missing an explicit lifetime bound and may not live long
enough.

Erroneous code example:

```compile_fail,E0309
// This won't compile because the applicable impl of
// `SomeTrait` (below) requires that `T: 'a`, but the struct does
// not have a matching where-clause.
struct Foo<'a, T> {
    foo: <T as SomeTrait<'a>>::Output,
}

trait SomeTrait<'a> {
    type Output;
}

impl<'a, T> SomeTrait<'a> for T
where
    T: 'a,
{
    type Output = u32;
}
```

The type definition contains some field whose type requires an outlives
annotation. Outlives annotations (e.g., `T: 'a`) are used to guarantee that all
the data in `T` is valid for at least the lifetime `'a`. This scenario most
commonly arises when the type contains an associated type reference like
`<T as SomeTrait<'a>>::Output`, as shown in the previous code.

There, the where clause `T: 'a` that appears on the impl is not known to be
satisfied on the struct. To make this example compile, you have to add a
where-clause like `T: 'a` to the struct definition:

```
struct Foo<'a, T>
where
    T: 'a,
{
    foo: <T as SomeTrait<'a>>::Output
}

trait SomeTrait<'a> {
    type Output;
}

impl<'a, T> SomeTrait<'a> for T
where
    T: 'a,
{
    type Output = u32;
}
```
A parameter type is missing a lifetime constraint or has a lifetime that
does not live long enough.

Erroneous code example:

```compile_fail,E0310
// This won't compile because T is not constrained to the static lifetime
// the reference needs
struct Foo<T> {
    foo: &'static T
}
```

Type parameters in type definitions have lifetimes associated with them that
represent how long the data stored within them is guaranteed to live. This
lifetime must be as long as the data needs to be alive, and missing the
constraint that denotes this will cause this error.

This will compile, because it has the constraint on the type parameter:

```
struct Foo<T: 'static> {
    foo: &'static T
}
```
This error occurs when there is an unsatisfied outlives bound involving an
elided region and a generic type parameter or associated type.

Erroneous code example:

```compile_fail,E0311
fn no_restriction<T>(x: &()) -> &() {
    with_restriction::<T>(x)
}

fn with_restriction<'a, T: 'a>(x: &'a ()) -> &'a () {
    x
}
```

Why doesn't this code compile? It helps to look at the lifetime bounds that are
automatically added by the compiler. For more details see the documentation for
[lifetime elision]( https://doc.rust-lang.org/reference/lifetime-elision.html).

The compiler elides the lifetime of `x` and the return type to some arbitrary
lifetime `'anon` in `no_restriction()`. The only information available to the
compiler is that `'anon` is valid for the duration of the function. When
calling `with_restriction()`, the compiler requires the completely unrelated
type parameter `T` to outlive `'anon` because of the `T: 'a` bound in
`with_restriction()`. This causes an error because `T` is not required to
outlive `'anon` in `no_restriction()`.

If `no_restriction()` were to use `&T` instead of `&()` as an argument, the
compiler would have added an implied bound, causing this to compile.

This error can be resolved by explicitly naming the elided lifetime for `x` and
then explicitly requiring that the generic parameter `T` outlives that lifetime:

```
fn no_restriction<'a, T: 'a>(x: &'a ()) -> &'a () {
    with_restriction::<T>(x)
}

fn with_restriction<'a, T: 'a>(x: &'a ()) -> &'a () {
    x
}
```
#### Note: this error code is no longer emitted by the compiler.

Reference's lifetime of borrowed content doesn't match the expected lifetime.

Erroneous code example:

```compile_fail
pub fn opt_str<'a>(maybestr: &'a Option<String>) -> &'static str {
    if maybestr.is_none() {
        "(none)"
    } else {
        let s: &'a str = maybestr.as_ref().unwrap();
        s  // Invalid lifetime!
    }
}
```

To fix this error, either lessen the expected lifetime or find a way to not have
to use this reference outside of its current scope (by running the code directly
in the same block for example?):

```
// In this case, we can fix the issue by switching from "static" lifetime to 'a
pub fn opt_str<'a>(maybestr: &'a Option<String>) -> &'a str {
    if maybestr.is_none() {
        "(none)"
    } else {
        let s: &'a str = maybestr.as_ref().unwrap();
        s  // Ok!
    }
}
```
A `where` clause contains a nested quantification over lifetimes.

Erroneous code example:

```compile_fail,E0316
trait Tr<'a, 'b> {}

fn foo<T>(t: T)
where
    for<'a> &'a T: for<'b> Tr<'a, 'b>, // error: nested quantification
{
}
```

Rust syntax allows lifetime quantifications in two places within
`where` clauses: Quantifying over the trait bound only (as in
`Ty: for<'l> Trait<'l>`) and quantifying over the whole clause
(as in `for<'l> &'l Ty: Trait<'l>`). Using both in the same clause
leads to a nested lifetime quantification, which is not supported.

The following example compiles, because the clause with the nested
quantification has been rewritten to use only one `for<>`:

```
trait Tr<'a, 'b> {}

fn foo<T>(t: T)
where
    for<'a, 'b> &'a T: Tr<'a, 'b>, // ok
{
}
```
An `if` expression is missing an `else` block.

Erroneous code example:

```compile_fail,E0317
let x = 5;
let a = if x == 5 {
    1
};
```

This error occurs when an `if` expression without an `else` block is used in a
context where a type other than `()` is expected. In the previous code example,
the `let` expression was expecting a value but since there was no `else`, no
value was returned.

An `if` expression without an `else` block has the type `()`, so this is a type
error. To resolve it, add an `else` block having the same type as the `if`
block.

So to fix the previous code example:

```
let x = 5;
let a = if x == 5 {
    1
} else {
    2
};
```
Recursion limit reached while creating drop-check rules.

Example of erroneous code:

```compile_fail,E0320
enum A<T> {
    B,
    C(T, Box<A<(T, T)>>)
}

fn foo<T>() {
    A::<T>::B; // error: overflow while adding drop-check rules for A<T>
}
```

The Rust compiler must be able to reason about how a type is [`Drop`]ped, and
by extension the types of its fields, to be able to generate the glue to
properly drop a value. The code example above shows a type where this inference
is impossible because it is recursive. Note that this is *not* the same as
[E0072](E0072.html), where a type has an infinite size; the type here has a
finite size but any attempt to `Drop` it would recurse infinitely. For more
information, read [the `Drop` docs](../std/ops/trait.Drop.html).

It is not possible to define a type with recursive drop-check rules. All such
recursion must be removed.

[`Drop`]: ../std/ops/trait.Drop.html
A cross-crate opt-out trait was implemented on something which wasn't a struct
or enum type.

Erroneous code example:

```compile_fail,E0321
#![feature(auto_traits)]

struct Foo;

impl !Sync for Foo {}

unsafe impl Send for &'static Foo {}
// error: cross-crate traits with a default impl, like `core::marker::Send`,
//        can only be implemented for a struct/enum type, not
//        `&'static Foo`
```

Only structs and enums are permitted to impl Send, Sync, and other opt-out
trait, and the struct or enum must be local to the current crate. So, for
example, `unsafe impl Send for Rc<Foo>` is not allowed.
A built-in trait was implemented explicitly. All implementations of the trait
are provided automatically by the compiler.

Erroneous code example:

```compile_fail,E0322
struct Foo;

impl Sized for Foo {} // error!
```

The `Sized` trait is a special trait built-in to the compiler for types with a
constant size known at compile-time. This trait is automatically implemented
for types as needed by the compiler, and it is currently disallowed to
explicitly implement it for a type.
An associated const was implemented when another trait item was expected.

Erroneous code example:

```compile_fail,E0323
trait Foo {
    type N;
}

struct Bar;

impl Foo for Bar {
    const N : u32 = 0;
    // error: item `N` is an associated const, which doesn't match its
    //        trait `<Bar as Foo>`
}
```

Please verify that the associated const wasn't misspelled and the correct trait
was implemented. Example:

```
struct Bar;

trait Foo {
    type N;
}

impl Foo for Bar {
    type N = u32; // ok!
}
```

Or:

```
struct Bar;

trait Foo {
    const N : u32;
}

impl Foo for Bar {
    const N : u32 = 0; // ok!
}
```
A method was implemented when another trait item was expected.

Erroneous code example:

```compile_fail,E0324
struct Bar;

trait Foo {
    const N : u32;

    fn M();
}

impl Foo for Bar {
    fn N() {}
    // error: item `N` is an associated method, which doesn't match its
    //        trait `<Bar as Foo>`
}
```

To fix this error, please verify that the method name wasn't misspelled and
verify that you are indeed implementing the correct trait items. Example:

```
struct Bar;

trait Foo {
    const N : u32;

    fn M();
}

impl Foo for Bar {
    const N : u32 = 0;

    fn M() {} // ok!
}
```
An associated type was implemented when another trait item was expected.

Erroneous code example:

```compile_fail,E0325
struct Bar;

trait Foo {
    const N : u32;
}

impl Foo for Bar {
    type N = u32;
    // error: item `N` is an associated type, which doesn't match its
    //        trait `<Bar as Foo>`
}
```

Please verify that the associated type name wasn't misspelled and your
implementation corresponds to the trait definition. Example:

```
struct Bar;

trait Foo {
    type N;
}

impl Foo for Bar {
    type N = u32; // ok!
}
```

Or:

```
struct Bar;

trait Foo {
    const N : u32;
}

impl Foo for Bar {
    const N : u32 = 0; // ok!
}
```
An implementation of a trait doesn't match the type constraint.

Erroneous code example:

```compile_fail,E0326
trait Foo {
    const BAR: bool;
}

struct Bar;

impl Foo for Bar {
    const BAR: u32 = 5; // error, expected bool, found u32
}
```

The types of any associated constants in a trait implementation must match the
types in the trait definition.
The Unsize trait should not be implemented directly. All implementations of
Unsize are provided automatically by the compiler.

Erroneous code example:

```compile_fail,E0328
#![feature(unsize)]

use std::marker::Unsize;

pub struct MyType;

impl<T> Unsize<T> for MyType {}
```

If you are defining your own smart pointer type and would like to enable
conversion from a sized to an unsized type with the
[DST coercion system][RFC 982], use [`CoerceUnsized`] instead.

```
#![feature(coerce_unsized)]

use std::ops::CoerceUnsized;

pub struct MyType<T: ?Sized> {
    field_with_unsized_type: T,
}

impl<T, U> CoerceUnsized<MyType<U>> for MyType<T>
    where T: CoerceUnsized<U> {}
```

[RFC 982]: https://github.com/rust-lang/rfcs/blob/master/text/0982-dst-coercion.md
[`CoerceUnsized`]: https://doc.rust-lang.org/std/ops/trait.CoerceUnsized.html
#### Note: this error code is no longer emitted by the compiler.

An attempt was made to access an associated constant through either a generic
type parameter or `Self`. This is not supported yet. An example causing this
error is shown below:

```
trait Foo {
    const BAR: f64;
}

struct MyStruct;

impl Foo for MyStruct {
    const BAR: f64 = 0f64;
}

fn get_bar_bad<F: Foo>(t: F) -> f64 {
    F::BAR
}
```

Currently, the value of `BAR` for a particular type can only be accessed
through a concrete type, as shown below:

```
trait Foo {
    const BAR: f64;
}

struct MyStruct;

impl Foo for MyStruct {
    const BAR: f64 = 0f64;
}

fn get_bar_good() -> f64 {
    <MyStruct as Foo>::BAR
}
```
Private items cannot be publicly re-exported. This error indicates that you
attempted to `pub use` a type or value that was not itself public.

Erroneous code example:

```compile_fail,E0364
mod a {
    fn foo() {}

    mod a {
        pub use super::foo; // error!
    }
}
```

The solution to this problem is to ensure that the items that you are
re-exporting are themselves marked with `pub`:

```
mod a {
    pub fn foo() {} // ok!

    mod a {
        pub use super::foo;
    }
}
```

See the [Use Declarations][use-declarations] section of the reference for
more information on this topic.

[use-declarations]: https://doc.rust-lang.org/reference/items/use-declarations.html
Private modules cannot be publicly re-exported. This error indicates that you
attempted to `pub use` a module that was not itself public.

Erroneous code example:

```compile_fail,E0365
mod foo {
    pub const X: u32 = 1;
}

pub use foo as foo2;

fn main() {}
```

The solution to this problem is to ensure that the module that you are
re-exporting is itself marked with `pub`:

```
pub mod foo {
    pub const X: u32 = 1;
}

pub use foo as foo2;

fn main() {}
```

See the [Use Declarations][use-declarations] section of the reference for
more information on this topic.

[use-declarations]: https://doc.rust-lang.org/reference/items/use-declarations.html
An attempt was made to implement `Drop` on a concrete specialization of a
generic type. An example is shown below:

```compile_fail,E0366
struct Foo<T> {
    t: T
}

impl Drop for Foo<u32> {
    fn drop(&mut self) {}
}
```

This code is not legal: it is not possible to specialize `Drop` to a subset of
implementations of a generic type. One workaround for this is to wrap the
generic type, as shown below:

```
struct Foo<T> {
    t: T
}

struct Bar {
    t: Foo<u32>
}

impl Drop for Bar {
    fn drop(&mut self) {}
}
```
An attempt was made to implement `Drop` on a specialization of a generic type.

Erroneous code example:

```compile_fail,E0367
trait Foo {}

struct MyStruct<T> {
    t: T
}

impl<T: Foo> Drop for MyStruct<T> {
    fn drop(&mut self) {}
}
```

This code is not legal: it is not possible to specialize `Drop` to a subset of
implementations of a generic type. In order for this code to work, `MyStruct`
must also require that `T` implements `Foo`. Alternatively, another option is
to wrap the generic type in another that specializes appropriately:

```
trait Foo{}

struct MyStruct<T> {
    t: T
}

struct MyStructWrapper<T: Foo> {
    t: MyStruct<T>
}

impl <T: Foo> Drop for MyStructWrapper<T> {
    fn drop(&mut self) {}
}
```
A binary assignment operator like `+=` or `^=` was applied to a type that
doesn't support it.

Erroneous code example:

```compile_fail,E0368
let mut x = 12f32; // error: binary operation `<<` cannot be applied to
                   //        type `f32`

x <<= 2;
```

To fix this error, please check that this type implements this binary
operation. Example:

```
let mut x = 12u32; // the `u32` type does implement the `ShlAssign` trait

x <<= 2; // ok!
```

It is also possible to overload most operators for your own type by
implementing the `[OP]Assign` traits from `std::ops`.

Another problem you might be facing is this: suppose you've overloaded the `+`
operator for some type `Foo` by implementing the `std::ops::Add` trait for
`Foo`, but you find that using `+=` does not work, as in this example:

```compile_fail,E0368
use std::ops::Add;

struct Foo(u32);

impl Add for Foo {
    type Output = Foo;

    fn add(self, rhs: Foo) -> Foo {
        Foo(self.0 + rhs.0)
    }
}

fn main() {
    let mut x: Foo = Foo(5);
    x += Foo(7); // error, `+=` cannot be applied to the type `Foo`
}
```

This is because `AddAssign` is not automatically implemented, so you need to
manually implement it for your type.
A binary operation was attempted on a type which doesn't support it.

Erroneous code example:

```compile_fail,E0369
let x = 12f32; // error: binary operation `<<` cannot be applied to
               //        type `f32`

x << 2;
```

To fix this error, please check that this type implements this binary
operation. Example:

```
let x = 12u32; // the `u32` type does implement it:
               // https://doc.rust-lang.org/stable/std/ops/trait.Shl.html

x << 2; // ok!
```

It is also possible to overload most operators for your own type by
implementing traits from `std::ops`.

String concatenation appends the string on the right to the string on the
left and may require reallocation. This requires ownership of the string
on the left. If something should be added to a string literal, move the
literal to the heap by allocating it with `to_owned()` like in
`"Your text".to_owned()`.
The maximum value of an enum was reached, so it cannot be automatically
set in the next enum value.

Erroneous code example:

```compile_fail,E0370
#[repr(i64)]
enum Foo {
    X = 0x7fffffffffffffff,
    Y, // error: enum discriminant overflowed on value after
       //        9223372036854775807: i64; set explicitly via
       //        Y = -9223372036854775808 if that is desired outcome
}
```

To fix this, please set manually the next enum value or put the enum variant
with the maximum value at the end of the enum. Examples:

```
#[repr(i64)]
enum Foo {
    X = 0x7fffffffffffffff,
    Y = 0, // ok!
}
```

Or:

```
#[repr(i64)]
enum Foo {
    Y = 0, // ok!
    X = 0x7fffffffffffffff,
}
```
A trait was implemented on another which already automatically implemented it.

Erroneous code examples:

```compile_fail,E0371
trait Foo { fn foo(&self) { } }
trait Bar: Foo { }
trait Baz: Bar { }

impl Bar for Baz { } // error, `Baz` implements `Bar` by definition
impl Foo for Baz { } // error, `Baz` implements `Bar` which implements `Foo`
impl Baz for Baz { } // error, `Baz` (trivially) implements `Baz`
impl Baz for Bar { } // Note: This is OK
```

When `Trait2` is a subtrait of `Trait1` (for example, when `Trait2` has a
definition like `trait Trait2: Trait1 { ... }`), it is not allowed to implement
`Trait1` for `Trait2`. This is because `Trait2` already implements `Trait1` by
definition, so it is not useful to do this.
A captured variable in a closure may not live long enough.

Erroneous code example:

```compile_fail,E0373
fn foo() -> Box<dyn Fn(u32) -> u32> {
    let x = 0u32;
    Box::new(|y| x + y)
}
```

This error occurs when an attempt is made to use data captured by a closure,
when that data may no longer exist. It's most commonly seen when attempting to
return a closure as shown in the previous code example.

Notice that `x` is stack-allocated by `foo()`. By default, Rust captures
closed-over data by reference. This means that once `foo()` returns, `x` no
longer exists. An attempt to access `x` within the closure would thus be
unsafe.

Another situation where this might be encountered is when spawning threads:

```compile_fail,E0373
fn foo() {
    let x = 0u32;
    let y = 1u32;

    let thr = std::thread::spawn(|| {
        x + y
    });
}
```

Since our new thread runs in parallel, the stack frame containing `x` and `y`
may well have disappeared by the time we try to use them. Even if we call
`thr.join()` within foo (which blocks until `thr` has completed, ensuring the
stack frame won't disappear), we will not succeed: the compiler cannot prove
that this behavior is safe, and so won't let us do it.

The solution to this problem is usually to switch to using a `move` closure.
This approach moves (or copies, where possible) data into the closure, rather
than taking references to it. For example:

```
fn foo() -> Box<dyn Fn(u32) -> u32> {
    let x = 0u32;
    Box::new(move |y| x + y)
}
```

Now that the closure has its own copy of the data, there's no need to worry
about safety.

This error may also be encountered while using `async` blocks:

```compile_fail,E0373,edition2018
use std::future::Future;

async fn f() {
    let v = vec![1, 2, 3i32];
    spawn(async { //~ ERROR E0373
        println!("{:?}", v)
    });
}

fn spawn<F: Future + Send + 'static>(future: F) {
    unimplemented!()
}
```

Similarly to closures, `async` blocks are not executed immediately and may
capture closed-over data by reference. For more information, see
<https://rust-lang.github.io/async-book/03_async_await/01_chapter.html>.
`CoerceUnsized` or `DispatchFromDyn` was implemented on a struct which does not
contain a field that is being unsized.

Example of erroneous code:

```compile_fail,E0374
#![feature(coerce_unsized)]
use std::ops::CoerceUnsized;

struct Foo<T: ?Sized> {
    a: i32,
}

// error: Struct `Foo` has no unsized fields that need to be coerced.
impl<T, U> CoerceUnsized<Foo<U>> for Foo<T>
    where T: CoerceUnsized<U> {}
```

`CoerceUnsized` is used to coerce structs that have a field that can be unsized,
like a custom `MyBox<T>` being unsized to `MyBox<dyn Trait>`. `DispatchFromDyn`
is used to dispatch from `MyBox<dyn Trait>` to `MyBox<Self>` in a dyn-compatible
trait.

If the struct doesn't have any fields of unsized types then there is no
meaningful way to implement `CoerceUnsized` or `DispatchFromDyn`, since
there is no coercion taking place.

Note that `CoerceUnsized` and `DispatchFromDyn` is mainly used by smart pointers
like `Box`, `Rc` and `Arc` to be able to mark that they can coerce unsized types
that they are pointing at.
`CoerceUnsized` or `DispatchFromDyn` was implemented on a struct which contains
more than one field that is being unsized.

Erroneous code example:

```compile_fail,E0375
#![feature(coerce_unsized)]
use std::ops::CoerceUnsized;

struct Foo<T: ?Sized, U: ?Sized> {
    a: i32,
    b: T,
    c: U,
}

// error: Struct `Foo` has more than one unsized field.
impl<T, U> CoerceUnsized<Foo<U, T>> for Foo<T, U> {}
```

`CoerceUnsized` is used to coerce structs that have a field that can be unsized,
like a custom `MyBox<T>` being unsized to `MyBox<dyn Trait>`. `DispatchFromDyn`
is used to dispatch from `MyBox<dyn Trait>` to `MyBox<Self>` in a dyn-compatible
trait.

If the struct has multiple fields that must be unsized, then the compiler has no
way to generate a valid implementation of `CoerceUnsized` or `DispatchFromDyn`.

Note that `CoerceUnsized` and `DispatchFromDyn` is mainly used by smart pointers
like `Box`, `Rc` and `Arc` to be able to mark that they can coerce unsized types
that they are pointing at.
#### Note: this error code is no longer emitted by the compiler.

`CoerceUnsized` or `DispatchFromDyn` was implemented between two types that
are not structs.

Erroneous code example:

```compile_fail,E0377
#![feature(coerce_unsized)]
use std::ops::CoerceUnsized;

struct Foo<T: ?Sized> {
    a: T,
}

// error: The type `U` is not a struct
impl<T, U> CoerceUnsized<U> for Foo<T> {}
```

`CoerceUnsized` or `DispatchFromDyn` can only be implemented between structs.
`CoerceUnsized` or `DispatchFromDyn` may only be implemented between structs
of the same type.

Example of erroneous code:

```compile_fail,E0377
#![feature(coerce_unsized)]
use std::ops::CoerceUnsized;

pub struct Foo<T: ?Sized> {
    field_with_unsized_type: T,
}

pub struct Bar<T: ?Sized> {
    field_with_unsized_type: T,
}

// error: the trait `CoerceUnsized` may only be implemented for a coercion
//        between structures with the same definition
impl<T, U> CoerceUnsized<Bar<U>> for Foo<T> where T: CoerceUnsized<U> {}
```

`CoerceUnsized` is used to coerce structs that have a field that can be unsized,
like a custom `MyBox<T>` being unsized to `MyBox<dyn Trait>`. `DispatchFromDyn`
is used to dispatch from `MyBox<dyn Trait>` to `MyBox<Self>` in a dyn-compatible
trait.

The compiler cannot support coercions between structs of different types, so
a valid implementation of `CoerceUnsized` or `DispatchFromDyn` should be
implemented between the same struct with different generic parameters.

Note that `CoerceUnsized` and `DispatchFromDyn` is mainly used by smart pointers
like `Box`, `Rc` and `Arc` to be able to mark that they can coerce unsized types
that they are pointing at.
The `DispatchFromDyn` trait was implemented on something which is not a pointer
or a newtype wrapper around a pointer.

Erroneous code example:

```compile_fail,E0378
#![feature(dispatch_from_dyn)]
use std::ops::DispatchFromDyn;

struct WrapperExtraField<T> {
    ptr: T,
    extra_stuff: i32,
}

impl<T, U> DispatchFromDyn<WrapperExtraField<U>> for WrapperExtraField<T>
where
    T: DispatchFromDyn<U>,
{}
```

The `DispatchFromDyn` trait currently can only be implemented for
builtin pointer types and structs that are newtype wrappers around them
— that is, the struct must have only one field (except for `PhantomData`),
and that field must itself implement `DispatchFromDyn`.

```
#![feature(dispatch_from_dyn, unsize)]
use std::{
    marker::Unsize,
    ops::DispatchFromDyn,
};

struct Ptr<T: ?Sized>(*const T);

impl<T: ?Sized, U: ?Sized> DispatchFromDyn<Ptr<U>> for Ptr<T>
where
    T: Unsize<U>,
{}
```

Another example:

```
#![feature(dispatch_from_dyn)]
use std::{
    ops::DispatchFromDyn,
    marker::PhantomData,
};

struct Wrapper<T> {
    ptr: T,
    _phantom: PhantomData<()>,
}

impl<T, U> DispatchFromDyn<Wrapper<U>> for Wrapper<T>
where
    T: DispatchFromDyn<U>,
{}
```
A trait method was declared const.

Erroneous code example:

```compile_fail,E0379
trait Foo {
    const fn bar() -> u32; // error!
}

impl Foo for () {
    const fn bar() -> u32 { 0 } // error!
}
```

Trait methods cannot be declared `const` by design. For more information, see
[RFC 911].

[RFC 911]: https://github.com/rust-lang/rfcs/pull/911
An auto trait was declared with a method or an associated item.

Erroneous code example:

```compile_fail,E0380
unsafe auto trait Trait {
    type Output; // error!
}
```

Auto traits cannot have methods or associated items. For more information see
the [opt-in builtin traits RFC][RFC 19].

[RFC 19]: https://github.com/rust-lang/rfcs/blob/master/text/0019-opt-in-builtin-traits.md
It is not allowed to use or capture an uninitialized variable.

Erroneous code example:

```compile_fail,E0381
fn main() {
    let x: i32;
    let y = x; // error, use of possibly-uninitialized variable
}
```

To fix this, ensure that any declared variables are initialized before being
used. Example:

```
fn main() {
    let x: i32 = 0;
    let y = x; // ok!
}
```
A variable was used after its contents have been moved elsewhere.

Erroneous code example:

```compile_fail,E0382
struct MyStruct { s: u32 }

fn main() {
    let mut x = MyStruct{ s: 5u32 };
    let y = x;
    x.s = 6;
    println!("{}", x.s);
}
```

Since `MyStruct` is a type that is not marked `Copy`, the data gets moved out
of `x` when we set `y`. This is fundamental to Rust's ownership system: outside
of workarounds like `Rc`, a value cannot be owned by more than one variable.

Sometimes we don't need to move the value. Using a reference, we can let another
function borrow the value without changing its ownership. In the example below,
we don't actually have to move our string to `calculate_length`, we can give it
a reference to it with `&` instead.

```
fn main() {
    let s1 = String::from("hello");

    let len = calculate_length(&s1);

    println!("The length of '{}' is {}.", s1, len);
}

fn calculate_length(s: &String) -> usize {
    s.len()
}
```

A mutable reference can be created with `&mut`.

Sometimes we don't want a reference, but a duplicate. All types marked `Clone`
can be duplicated by calling `.clone()`. Subsequent changes to a clone do not
affect the original variable.

Most types in the standard library are marked `Clone`. The example below
demonstrates using `clone()` on a string. `s1` is first set to "many", and then
copied to `s2`. Then the first character of `s1` is removed, without affecting
`s2`. "any many" is printed to the console.

```
fn main() {
    let mut s1 = String::from("many");
    let s2 = s1.clone();
    s1.remove(0);
    println!("{} {}", s1, s2);
}
```

If we control the definition of a type, we can implement `Clone` on it ourselves
with `#[derive(Clone)]`.

Some types have no ownership semantics at all and are trivial to duplicate. An
example is `i32` and the other number types. We don't have to call `.clone()` to
clone them, because they are marked `Copy` in addition to `Clone`. Implicit
cloning is more convenient in this case. We can mark our own types `Copy` if
all their members also are marked `Copy`.

In the example below, we implement a `Point` type. Because it only stores two
integers, we opt-out of ownership semantics with `Copy`. Then we can
`let p2 = p1` without `p1` being moved.

```
#[derive(Copy, Clone)]
struct Point { x: i32, y: i32 }

fn main() {
    let mut p1 = Point{ x: -1, y: 2 };
    let p2 = p1;
    p1.x = 1;
    println!("p1: {}, {}", p1.x, p1.y);
    println!("p2: {}, {}", p2.x, p2.y);
}
```

Alternatively, if we don't control the struct's definition, or mutable shared
ownership is truly required, we can use `Rc` and `RefCell`:

```
use std::cell::RefCell;
use std::rc::Rc;

struct MyStruct { s: u32 }

fn main() {
    let mut x = Rc::new(RefCell::new(MyStruct{ s: 5u32 }));
    let y = x.clone();
    x.borrow_mut().s = 6;
    println!("{}", x.borrow().s);
}
```

With this approach, x and y share ownership of the data via the `Rc` (reference
count type). `RefCell` essentially performs runtime borrow checking: ensuring
that at most one writer or multiple readers can access the data at any one time.

If you wish to learn more about ownership in Rust, start with the
[Understanding Ownership][understanding-ownership] chapter in the Book.

[understanding-ownership]: https://doc.rust-lang.org/book/ch04-00-understanding-ownership.html
#### Note: this error code is no longer emitted by the compiler.

This error occurs when an attempt is made to partially reinitialize a
structure that is currently uninitialized.

For example, this can happen when a drop has taken place:

```compile_fail
struct Foo {
    a: u32,
}
impl Drop for Foo {
    fn drop(&mut self) { /* ... */ }
}

let mut x = Foo { a: 1 };
drop(x); // `x` is now uninitialized
x.a = 2; // error, partial reinitialization of uninitialized structure `t`
```

This error can be fixed by fully reinitializing the structure in question:

```
struct Foo {
    a: u32,
}
impl Drop for Foo {
    fn drop(&mut self) { /* ... */ }
}

let mut x = Foo { a: 1 };
drop(x);
x = Foo { a: 2 };
```
An immutable variable was reassigned.

Erroneous code example:

```compile_fail,E0384
fn main() {
    let x = 3;
    x = 5; // error, reassignment of immutable variable
}
```

By default, variables in Rust are immutable. To fix this error, add the keyword
`mut` after the keyword `let` when declaring the variable. For example:

```
fn main() {
    let mut x = 3;
    x = 5;
}
```

Alternatively, you might consider initializing a new variable: either with a new
bound name or (by [shadowing]) with the bound name of your existing variable.
For example:

[shadowing]: https://doc.rust-lang.org/book/ch03-01-variables-and-mutability.html#shadowing

```
fn main() {
    let x = 3;
    let x = 5;
}
```
#### Note: this error code is no longer emitted by the compiler.

This error occurs when an attempt is made to mutate the target of a mutable
reference stored inside an immutable container.

For example, this can happen when storing a `&mut` inside an immutable `Box`:

```
let mut x: i64 = 1;
let y: Box<_> = Box::new(&mut x);
**y = 2; // error, cannot assign to data in an immutable container
```

This error can be fixed by making the container mutable:

```
let mut x: i64 = 1;
let mut y: Box<_> = Box::new(&mut x);
**y = 2;
```

It can also be fixed by using a type with interior mutability, such as `Cell`
or `RefCell`:

```
use std::cell::Cell;

let x: i64 = 1;
let y: Box<Cell<_>> = Box::new(Cell::new(x));
y.set(2);
```
#### Note: this error code is no longer emitted by the compiler.

This error occurs when an attempt is made to mutate or mutably reference data
that a closure has captured immutably.

Erroneous code example:

```compile_fail
// Accepts a function or a closure that captures its environment immutably.
// Closures passed to foo will not be able to mutate their closed-over state.
fn foo<F: Fn()>(f: F) { }

// Attempts to mutate closed-over data. Error message reads:
// `cannot assign to data in a captured outer variable...`
fn mutable() {
    let mut x = 0u32;
    foo(|| x = 2);
}

// Attempts to take a mutable reference to closed-over data. Error message
// reads: `cannot borrow data mutably in a captured outer variable...`
fn mut_addr() {
    let mut x = 0u32;
    foo(|| { let y = &mut x; });
}
```

The problem here is that foo is defined as accepting a parameter of type `Fn`.
Closures passed into foo will thus be inferred to be of type `Fn`, meaning that
they capture their context immutably.

If the definition of `foo` is under your control, the simplest solution is to
capture the data mutably. This can be done by defining `foo` to take FnMut
rather than Fn:

```
fn foo<F: FnMut()>(f: F) { }
```

Alternatively, we can consider using the `Cell` and `RefCell` types to achieve
interior mutability through a shared reference. Our example's `mutable`
function could be redefined as below:

```
use std::cell::Cell;

fn foo<F: Fn()>(f: F) { }

fn mutable() {
    let x = Cell::new(0u32);
    foo(|| x.set(2));
}
```

You can read more in the API documentation for [Cell][std-cell].

[std-cell]: https://doc.rust-lang.org/std/cell/
#### Note: this error code is no longer emitted by the compiler.
#### Note: this error code is no longer emitted by the compiler.

An attempt was made to mutate data using a non-mutable reference. This
commonly occurs when attempting to assign to a non-mutable reference of a
mutable reference (`&(&mut T)`).

Erroneous code example:

```compile_fail
struct FancyNum {
    num: u8,
}

fn main() {
    let mut fancy = FancyNum{ num: 5 };
    let fancy_ref = &(&mut fancy);
    fancy_ref.num = 6; // error: cannot assign to data in a `&` reference
    println!("{}", fancy_ref.num);
}
```

Here, `&mut fancy` is mutable, but `&(&mut fancy)` is not. Creating an
immutable reference to a value borrows it immutably. There can be multiple
references of type `&(&mut T)` that point to the same value, so they must be
immutable to prevent multiple mutable references to the same value.

To fix this, either remove the outer reference:

```
struct FancyNum {
    num: u8,
}

fn main() {
    let mut fancy = FancyNum{ num: 5 };

    let fancy_ref = &mut fancy;
    // `fancy_ref` is now &mut FancyNum, rather than &(&mut FancyNum)

    fancy_ref.num = 6; // No error!

    println!("{}", fancy_ref.num);
}
```

Or make the outer reference mutable:

```
struct FancyNum {
    num: u8
}

fn main() {
    let mut fancy = FancyNum{ num: 5 };

    let fancy_ref = &mut (&mut fancy);
    // `fancy_ref` is now &mut(&mut FancyNum), rather than &(&mut FancyNum)

    fancy_ref.num = 6; // No error!

    println!("{}", fancy_ref.num);
}
```
A method or constant was implemented on a primitive type.

Erroneous code example:

```compile_fail,E0390
struct Foo {
    x: i32
}

impl *mut Foo {}
// error: cannot define inherent `impl` for primitive types
```

This isn't allowed, but using a trait to implement a method or constant
is a good solution.
Example:

```
struct Foo {
    x: i32
}

trait Bar {
    fn bar();
}

impl Bar for *mut Foo {
    fn bar() {} // ok!
}
```

Instead of defining an inherent implementation on a reference, you could also
move the reference inside the implementation:

```compile_fail,E0390
struct Foo;

impl &Foo { // error: no nominal type found for inherent implementation
    fn bar(self, other: Self) {}
}
```

becomes

```
struct Foo;

impl Foo {
    fn bar(&self, other: &Self) {}
}
```
A type dependency cycle has been encountered.

Erroneous code example:

```compile_fail,E0391
trait FirstTrait : SecondTrait {

}

trait SecondTrait : FirstTrait {

}
```

The previous example contains a circular dependency between two traits:
`FirstTrait` depends on `SecondTrait` which itself depends on `FirstTrait`.

See https://rustc-dev-guide.rust-lang.org/overview.html#queries and
https://rustc-dev-guide.rust-lang.org/query.html for more information.
A type or lifetime parameter has been declared but is not actually used.

Erroneous code example:

```compile_fail,E0392
enum Foo<T> {
    Bar,
}
```

If the type parameter was included by mistake, this error can be fixed
by simply removing the type parameter, as shown below:

```
enum Foo {
    Bar,
}
```

Alternatively, if the type parameter was intentionally inserted, it must be
used. A simple fix is shown below:

```
enum Foo<T> {
    Bar(T),
}
```

This error may also commonly be found when working with unsafe code. For
example, when using raw pointers one may wish to specify the lifetime for
which the pointed-at data is valid. An initial attempt (below) causes this
error:

```compile_fail,E0392
struct Foo<'a, T> {
    x: *const T,
}
```

We want to express the constraint that Foo should not outlive `'a`, because
the data pointed to by `T` is only valid for that lifetime. The problem is
that there are no actual uses of `'a`. It's possible to work around this
by adding a PhantomData type to the struct, using it to tell the compiler
to act as if the struct contained a borrowed reference `&'a T`:

```
use std::marker::PhantomData;

struct Foo<'a, T: 'a> {
    x: *const T,
    phantom: PhantomData<&'a T>
}
```

[PhantomData] can also be used to express information about unused type
parameters.

[PhantomData]: https://doc.rust-lang.org/std/marker/struct.PhantomData.html
A type parameter which references `Self` in its default value was not specified.

Erroneous code example:

```compile_fail,E0393
trait A<T = Self> {}

fn together_we_will_rule_the_galaxy(son: &dyn A) {}
// error: the type parameter `T` must be explicitly specified
```

A trait object is defined over a single, fully-defined trait. With a regular
default parameter, this parameter can just be instantiated in. However, if the
default parameter is `Self`, the trait changes for each concrete type; i.e.
`i32` will be expected to implement `A<i32>`, `bool` will be expected to
implement `A<bool>`, etc... These types will not share an implementation of a
fully-defined trait; instead they share implementations of a trait with
different parameters instantiated in for each implementation. This is
irreconcilable with what we need to make a trait object work, and is thus
disallowed. Making the trait concrete by explicitly specifying the value of the
defaulted parameter will fix this issue. Fixed example:

```
trait A<T = Self> {}

fn together_we_will_rule_the_galaxy(son: &dyn A<i32>) {} // Ok!
```
#### Note: this error code is no longer emitted by the compiler.

In Rust 1.3, the default object lifetime bounds are expected to change, as
described in [RFC 1156]. You are getting a warning because the compiler
thinks it is possible that this change will cause a compilation error in your
code. It is possible, though unlikely, that this is a false alarm.

The heart of the change is that where `&'a Box<SomeTrait>` used to default to
`&'a Box<SomeTrait+'a>`, it now defaults to `&'a Box<SomeTrait+'static>` (here,
`SomeTrait` is the name of some trait type). Note that the only types which are
affected are references to boxes, like `&Box<SomeTrait>` or
`&[Box<SomeTrait>]`. More common types like `&SomeTrait` or `Box<SomeTrait>`
are unaffected.

To silence this warning, edit your code to use an explicit bound. Most of the
time, this means that you will want to change the signature of a function that
you are calling. For example, if the error is reported on a call like `foo(x)`,
and `foo` is defined as follows:

```
# trait SomeTrait {}
fn foo(arg: &Box<SomeTrait>) { /* ... */ }
```

You might change it to:

```
# trait SomeTrait {}
fn foo<'a>(arg: &'a Box<SomeTrait+'a>) { /* ... */ }
```

This explicitly states that you expect the trait object `SomeTrait` to contain
references (with a maximum lifetime of `'a`).

[RFC 1156]: https://github.com/rust-lang/rfcs/blob/master/text/1156-adjust-default-object-bounds.md
#### Note: this error code is no longer emitted by the compiler

You implemented a trait, overriding one or more of its associated types but did
not reimplement its default methods.

Example of erroneous code:

```
#![feature(associated_type_defaults)]

pub trait Foo {
    type Assoc = u8;
    fn bar(&self) {}
}

impl Foo for i32 {
    // error - the following trait items need to be reimplemented as
    //         `Assoc` was overridden: `bar`
    type Assoc = i32;
}
```

To fix this, add an implementation for each default method from the trait:

```
#![feature(associated_type_defaults)]

pub trait Foo {
    type Assoc = u8;
    fn bar(&self) {}
}

impl Foo for i32 {
    type Assoc = i32;
    fn bar(&self) {} // ok!
}
```
Inner items do not inherit the generic parameters from the items
they are embedded in.

Erroneous code example:

```compile_fail,E0401
fn foo<T>(x: T) {
    fn bar(y: T) { // T is defined in the "outer" function
        // ..
    }
    bar(x);
}
```

Nor will this:

```compile_fail,E0401
fn foo<T>(x: T) {
    type MaybeT = Option<T>;
    // ...
}
```

Or this:

```compile_fail,E0401
fn foo<T>(x: T) {
    struct Foo {
        x: T,
    }
    // ...
}
```

Items nested inside other items are basically just like top-level items, except
that they can only be used from the item they are in.

There are a couple of solutions for this.

If the item is a function, you may use a closure:

```
fn foo<T>(x: T) {
    let bar = |y: T| { // explicit type annotation may not be necessary
        // ..
    };
    bar(x);
}
```

For a generic item, you can copy over the parameters:

```
fn foo<T>(x: T) {
    fn bar<T>(y: T) {
        // ..
    }
    bar(x);
}
```

```
fn foo<T>(x: T) {
    type MaybeT<T> = Option<T>;
}
```

Be sure to copy over any bounds as well:

```
fn foo<T: Copy>(x: T) {
    fn bar<T: Copy>(y: T) {
        // ..
    }
    bar(x);
}
```

```
fn foo<T: Copy>(x: T) {
    struct Foo<T: Copy> {
        x: T,
    }
}
```

This may require additional type hints in the function body.

In case the item is a function inside an `impl`, defining a private helper
function might be easier:

```
# struct Foo<T>(T);
impl<T> Foo<T> {
    pub fn foo(&self, x: T) {
        self.bar(x);
    }

    fn bar(&self, y: T) {
        // ..
    }
}
```

For default impls in traits, the private helper solution won't work, however
closures or copying the parameters should still work.
Some type parameters have the same name.

Erroneous code example:

```compile_fail,E0403
fn f<T, T>(s: T, u: T) {} // error: the name `T` is already used for a generic
                          //        parameter in this item's generic parameters
```

Please verify that none of the type parameters are misspelled, and rename any
clashing parameters. Example:

```
fn f<T, Y>(s: T, u: Y) {} // ok!
```

Type parameters in an associated item also cannot shadow parameters from the
containing item:

```compile_fail,E0403
trait Foo<T> {
    fn do_something(&self) -> T;
    fn do_something_else<T: Clone>(&self, bar: T);
}
```
A type that is not a trait was used in a trait position, such as a bound
or `impl`.

Erroneous code example:

```compile_fail,E0404
struct Foo;
struct Bar;

impl Foo for Bar {} // error: `Foo` is not a trait
fn baz<T: Foo>(t: T) {} // error: `Foo` is not a trait
```

Another erroneous code example:

```compile_fail,E0404
type Foo = Iterator<Item=String>;

fn bar<T: Foo>(t: T) {} // error: `Foo` is a type alias
```

Please verify that the trait's name was not misspelled or that the right
identifier was used. Example:

```
trait Foo {
    // some functions
}
struct Bar;

impl Foo for Bar { // ok!
    // functions implementation
}

fn baz<T: Foo>(t: T) {} // ok!
```

Alternatively, you could introduce a new trait with your desired restrictions
as a super trait:

```
# trait Foo {}
# struct Bar;
# impl Foo for Bar {}
trait Qux: Foo {} // Anything that implements Qux also needs to implement Foo
fn baz<T: Qux>(t: T) {} // also ok!
```

Finally, if you are on nightly and want to use a trait alias
instead of a type alias, you should use `#![feature(trait_alias)]`:

```
#![feature(trait_alias)]
trait Foo = Iterator<Item=String>;

fn bar<T: Foo>(t: T) {} // ok!
```
The code refers to a trait that is not in scope.

Erroneous code example:

```compile_fail,E0405
struct Foo;

impl SomeTrait for Foo {} // error: trait `SomeTrait` is not in scope
```

Please verify that the name of the trait wasn't misspelled and ensure that it
was imported. Example:

```
# #[cfg(for_demonstration_only)]
// solution 1:
use some_file::SomeTrait;

// solution 2:
trait SomeTrait {
    // some functions
}

struct Foo;

impl SomeTrait for Foo { // ok!
    // implements functions
}
```
A definition of a method not in the implemented trait was given in a trait
implementation.

Erroneous code example:

```compile_fail,E0407
trait Foo {
    fn a();
}

struct Bar;

impl Foo for Bar {
    fn a() {}
    fn b() {} // error: method `b` is not a member of trait `Foo`
}
```

Please verify you didn't misspell the method name and you used the correct
trait. First example:

```
trait Foo {
    fn a();
    fn b();
}

struct Bar;

impl Foo for Bar {
    fn a() {}
    fn b() {} // ok!
}
```

Second example:

```
trait Foo {
    fn a();
}

struct Bar;

impl Foo for Bar {
    fn a() {}
}

impl Bar {
    fn b() {}
}
```
An "or" pattern was used where the variable bindings are not consistently bound
across patterns.

Erroneous code example:

```compile_fail,E0408
match x {
    Some(y) | None => { /* use y */ } // error: variable `y` from pattern #1 is
                                      //        not bound in pattern #2
    _ => ()
}
```

Here, `y` is bound to the contents of the `Some` and can be used within the
block corresponding to the match arm. However, in case `x` is `None`, we have
not specified what `y` is, and the block will use a nonexistent variable.

To fix this error, either split into multiple match arms:

```
let x = Some(1);
match x {
    Some(y) => { /* use y */ }
    None => { /* ... */ }
}
```

or, bind the variable to a field of the same type in all sub-patterns of the
or pattern:

```
let x = (0, 2);
match x {
    (0, y) | (y, 0) => { /* use y */}
    _ => {}
}
```

In this example, if `x` matches the pattern `(0, _)`, the second field is set
to `y`. If it matches `(_, 0)`, the first field is set to `y`; so in all
cases `y` is set to some value.
An "or" pattern was used where the variable bindings are not consistently bound
across patterns.

Erroneous code example:

```compile_fail,E0409
let x = (0, 2);
match x {
    (0, ref y) | (y, 0) => { /* use y */} // error: variable `y` is bound with
                                          //        different mode in pattern #2
                                          //        than in pattern #1
    _ => ()
}
```

Here, `y` is bound by-value in one case and by-reference in the other.

To fix this error, just use the same mode in both cases.
Generally using `ref` or `ref mut` where not already used will fix this:

```
let x = (0, 2);
match x {
    (0, ref y) | (ref y, 0) => { /* use y */}
    _ => ()
}
```

Alternatively, split the pattern:

```
let x = (0, 2);
match x {
    (y, 0) => { /* use y */ }
    (0, ref y) => { /* use y */}
    _ => ()
}
```
The `Self` keyword was used outside an impl, trait, or type definition.

Erroneous code example:

```compile_fail,E0411
<Self>::foo; // error: use of `Self` outside of an impl, trait, or type
             // definition
```

The `Self` keyword represents the current type, which explains why it can only
be used inside an impl, trait, or type definition. It gives access to the
associated items of a type:

```
trait Foo {
    type Bar;
}

trait Baz : Foo {
    fn bar() -> Self::Bar; // like this
}
```

However, be careful when two types have a common associated type:

```compile_fail
trait Foo {
    type Bar;
}

trait Foo2 {
    type Bar;
}

trait Baz : Foo + Foo2 {
    fn bar() -> Self::Bar;
    // error: ambiguous associated type `Bar` in bounds of `Self`
}
```

This problem can be solved by specifying from which trait we want to use the
`Bar` type:

```
trait Foo {
    type Bar;
}

trait Foo2 {
    type Bar;
}

trait Baz : Foo + Foo2 {
    fn bar() -> <Self as Foo>::Bar; // ok!
}
```
A used type name is not in scope.

Erroneous code examples:

```compile_fail,E0412
impl Something {} // error: type name `Something` is not in scope

// or:

trait Foo {
    fn bar(N); // error: type name `N` is not in scope
}

// or:

fn foo(x: T) {} // type name `T` is not in scope
```

To fix this error, please verify you didn't misspell the type name, you did
declare it or imported it into the scope. Examples:

```
struct Something;

impl Something {} // ok!

// or:

trait Foo {
    type N;

    fn bar(_: Self::N); // ok!
}

// or:

fn foo<T>(x: T) {} // ok!
```

Another case that causes this error is when a type is imported into a parent
module. To fix this, you can follow the suggestion and use File directly or
`use super::File;` which will import the types from the parent namespace. An
example that causes this error is below:

```compile_fail,E0412
use std::fs::File;

mod foo {
    fn some_function(f: File) {}
}
```

```
use std::fs::File;

mod foo {
    // either
    use super::File;
    // or
    // use std::fs::File;
    fn foo(f: File) {}
}
# fn main() {} // don't insert it for us; that'll break imports
```
More than one function parameter have the same name.

Erroneous code example:

```compile_fail,E0415
fn foo(f: i32, f: i32) {} // error: identifier `f` is bound more than
                          //        once in this parameter list
```

Please verify you didn't misspell parameters' name. Example:

```
fn foo(f: i32, g: i32) {} // ok!
```
An identifier is bound more than once in a pattern.

Erroneous code example:

```compile_fail,E0416
match (1, 2) {
    (x, x) => {} // error: identifier `x` is bound more than once in the
                 //        same pattern
}
```

Please verify you didn't misspell identifiers' name. Example:

```
match (1, 2) {
    (x, y) => {} // ok!
}
```

Or maybe did you mean to unify? Consider using a guard:

```
# let (A, B, C) = (1, 2, 3);
match (A, B, C) {
    (x, x2, see) if x == x2 => { /* A and B are equal, do one thing */ }
    (y, z, see) => { /* A and B not equal; do another thing */ }
}
```
An identifier that is neither defined nor a struct was used.

Erroneous code example:

```compile_fail,E0422
fn main () {
    let x = Foo { x: 1, y: 2 };
}
```

In this case, `Foo` is undefined, so it inherently isn't anything, and
definitely not a struct.

```compile_fail
fn main () {
    let foo = 1;
    let x = foo { x: 1, y: 2 };
}
```

In this case, `foo` is defined, but is not a struct, so Rust can't use it as
one.
An identifier was used like a function name or a value was expected and the
identifier exists but it belongs to a different namespace.

Erroneous code example:

```compile_fail,E0423
struct Foo { a: bool };

let f = Foo();
// error: expected function, tuple struct or tuple variant, found `Foo`
// `Foo` is a struct name, but this expression uses it like a function name
```

Please verify you didn't misspell the name of what you actually wanted to use
here. Example:

```
fn Foo() -> u32 { 0 }

let f = Foo(); // ok!
```

It is common to forget the trailing `!` on macro invocations, which would also
yield this error:

```compile_fail,E0423
println("");
// error: expected function, tuple struct or tuple variant,
// found macro `println`
// did you mean `println!(...)`? (notice the trailing `!`)
```

Another case where this error is emitted is when a value is expected, but
something else is found:

```compile_fail,E0423
pub mod a {
    pub const I: i32 = 1;
}

fn h1() -> i32 {
    a.I
    //~^ ERROR expected value, found module `a`
    // did you mean `a::I`?
}
```
The `self` keyword was used inside of an associated function without a "`self`
receiver" parameter.

Erroneous code example:

```compile_fail,E0424
struct Foo;

impl Foo {
    // `bar` is a method, because it has a receiver parameter.
    fn bar(&self) {}

    // `foo` is not a method, because it has no receiver parameter.
    fn foo() {
        self.bar(); // error: `self` value is a keyword only available in
                    //        methods with a `self` parameter
    }
}
```

The `self` keyword can only be used inside methods, which are associated
functions (functions defined inside of a `trait` or `impl` block) that have a
`self` receiver as its first parameter, like `self`, `&self`, `&mut self` or
`self: &mut Pin<Self>` (this last one is an example of an ["arbitrary `self`
type"](https://github.com/rust-lang/rust/issues/44874)).

Check if the associated function's parameter list should have contained a `self`
receiver for it to be a method, and add it if so. Example:

```
struct Foo;

impl Foo {
    fn bar(&self) {}

    fn foo(self) { // `foo` is now a method.
        self.bar(); // ok!
    }
}
```
An unresolved name was used.

Erroneous code examples:

```compile_fail,E0425
something_that_doesnt_exist::foo;
// error: unresolved name `something_that_doesnt_exist::foo`

// or:

trait Foo {
    fn bar() {
        Self; // error: unresolved name `Self`
    }
}

// or:

let x = unknown_variable;  // error: unresolved name `unknown_variable`
```

Please verify that the name wasn't misspelled and ensure that the
identifier being referred to is valid for the given situation. Example:

```
enum something_that_does_exist {
    Foo,
}
```

Or:

```
mod something_that_does_exist {
    pub static foo : i32 = 0i32;
}

something_that_does_exist::foo; // ok!
```

Or:

```
let unknown_variable = 12u32;
let x = unknown_variable; // ok!
```

If the item is not defined in the current module, it must be imported using a
`use` statement, like so:

```
# mod foo { pub fn bar() {} }
# fn main() {
use foo::bar;
bar();
# }
```

If the item you are importing is not defined in some super-module of the
current module, then it must also be declared as public (e.g., `pub fn`).
An undeclared label was used.

Erroneous code example:

```compile_fail,E0426
loop {
    break 'a; // error: use of undeclared label `'a`
}
```

Please verify you spelled or declared the label correctly. Example:

```
'a: loop {
    break 'a; // ok!
}
```
A type or module has been defined more than once.

Erroneous code example:

```compile_fail,E0428
struct Bar;
struct Bar; // error: duplicate definition of value `Bar`
```

Please verify you didn't misspell the type/module's name or remove/rename the
duplicated one. Example:

```
struct Bar;
struct Bar2; // ok!
```
The `self` keyword cannot appear alone as the last segment in a `use`
declaration.

Erroneous code example:

```compile_fail,E0429
use std::fmt::self; // error: `self` imports are only allowed within a { } list
```

To use a namespace itself in addition to some of its members, `self` may appear
as part of a brace-enclosed list of imports:

```
use std::fmt::{self, Debug};
```

If you only want to import the namespace, do so directly:

```
use std::fmt;
```
The `self` import appears more than once in the list.

Erroneous code example:

```compile_fail,E0430
use something::{self, self}; // error: `self` import can only appear once in
                             //        the list
```

Please verify you didn't misspell the import name or remove the duplicated
`self` import. Example:

```
# mod something {}
# fn main() {
use something::{self}; // ok!
# }
```
An invalid `self` import was made.

Erroneous code example:

```compile_fail,E0431
use {self}; // error: `self` import can only appear in an import list with a
            //        non-empty prefix
```

You cannot import the current module into itself, please remove this import
or verify you didn't misspell it.
An import was unresolved.

Erroneous code example:

```compile_fail,E0432
use something::Foo; // error: unresolved import `something::Foo`.
```

In Rust 2015, paths in `use` statements are relative to the crate root. To
import items relative to the current and parent modules, use the `self::` and
`super::` prefixes, respectively.

In Rust 2018 or later, paths in `use` statements are relative to the current
module unless they begin with the name of a crate or a literal `crate::`, in
which case they start from the crate root. As in Rust 2015 code, the `self::`
and `super::` prefixes refer to the current and parent modules respectively.

Also verify that you didn't misspell the import name and that the import exists
in the module from where you tried to import it. Example:

```
use self::something::Foo; // Ok.

mod something {
    pub struct Foo;
}
# fn main() {}
```

If you tried to use a module from an external crate and are using Rust 2015,
you may have missed the `extern crate` declaration (which is usually placed in
the crate root):

```edition2015
extern crate core; // Required to use the `core` crate in Rust 2015.

use core::any;
# fn main() {}
```

Since Rust 2018 the `extern crate` declaration is not required and
you can instead just `use` it:

```edition2018
use core::any; // No extern crate required in Rust 2018.
# fn main() {}
```
An undeclared crate, module, or type was used.

Erroneous code example:

```compile_fail,E0433
let map = HashMap::new();
// error: failed to resolve: use of undeclared type `HashMap`
```

Please verify you didn't misspell the type/module's name or that you didn't
forget to import it:

```
use std::collections::HashMap; // HashMap has been imported.
let map: HashMap<u32, u32> = HashMap::new(); // So it can be used!
```

If you've expected to use a crate name:

```compile_fail
use ferris_wheel::BigO;
// error: failed to resolve: use of undeclared module or unlinked crate
```

Make sure the crate has been added as a dependency in `Cargo.toml`.

To use a module from your current crate, add the `crate::` prefix to the path.
A variable used inside an inner function comes from a dynamic environment.

Erroneous code example:

```compile_fail,E0434
fn foo() {
    let y = 5;
    fn bar() -> u32 {
        y // error: can't capture dynamic environment in a fn item; use the
          //        || { ... } closure form instead.
    }
}
```

Inner functions do not have access to their containing environment. To fix this
error, you can replace the function with a closure:

```
fn foo() {
    let y = 5;
    let bar = || {
        y
    };
}
```

Or replace the captured variable with a constant or a static item:

```
fn foo() {
    static mut X: u32 = 4;
    const Y: u32 = 5;
    fn bar() -> u32 {
        unsafe {
            X = 3;
        }
        Y
    }
}
```
A non-constant value was used in a constant expression.

Erroneous code example:

```compile_fail,E0435
let foo = 42;
let a: [u8; foo]; // error: attempt to use a non-constant value in a constant
```

'constant' means 'a compile-time value'.

More details can be found in the [Variables and Mutability] section of the book.

[Variables and Mutability]: https://doc.rust-lang.org/book/ch03-01-variables-and-mutability.html#differences-between-variables-and-constants

To fix this error, please replace the value with a constant. Example:

```
let a: [u8; 42]; // ok!
```

Or:

```
const FOO: usize = 42;
let a: [u8; FOO]; // ok!
```
The functional record update syntax was used on something other than a struct.

Erroneous code example:

```compile_fail,E0436
enum PublicationFrequency {
    Weekly,
    SemiMonthly { days: (u8, u8), annual_special: bool },
}

fn one_up_competitor(competitor_frequency: PublicationFrequency)
                     -> PublicationFrequency {
    match competitor_frequency {
        PublicationFrequency::Weekly => PublicationFrequency::SemiMonthly {
            days: (1, 15), annual_special: false
        },
        c @ PublicationFrequency::SemiMonthly{ .. } =>
            PublicationFrequency::SemiMonthly {
                annual_special: true, ..c // error: functional record update
                                          //        syntax requires a struct
        }
    }
}
```

The functional record update syntax is only allowed for structs (struct-like
enum variants don't qualify, for example). To fix the previous code, rewrite the
expression without functional record update syntax:

```
enum PublicationFrequency {
    Weekly,
    SemiMonthly { days: (u8, u8), annual_special: bool },
}

fn one_up_competitor(competitor_frequency: PublicationFrequency)
                     -> PublicationFrequency {
    match competitor_frequency {
        PublicationFrequency::Weekly => PublicationFrequency::SemiMonthly {
            days: (1, 15), annual_special: false
        },
        PublicationFrequency::SemiMonthly{ days, .. } =>
            PublicationFrequency::SemiMonthly {
                days, annual_special: true // ok!
        }
    }
}
```
An associated type whose name does not match any of the associated types
in the trait was used when implementing the trait.

Erroneous code example:

```compile_fail,E0437
trait Foo {}

impl Foo for i32 {
    type Bar = bool;
}
```

Trait implementations can only implement associated types that are members of
the trait in question.

The solution to this problem is to remove the extraneous associated type:

```
trait Foo {}

impl Foo for i32 {}
```
An associated constant whose name does not match any of the associated constants
in the trait was used when implementing the trait.

Erroneous code example:

```compile_fail,E0438
trait Foo {}

impl Foo for i32 {
    const BAR: bool = true;
}
```

Trait implementations can only implement associated constants that are
members of the trait in question.

The solution to this problem is to remove the extraneous associated constant:

```
trait Foo {}

impl Foo for i32 {}
```
#### Note: this error code is no longer emitted by the compiler.

The length of the platform-intrinsic function `simd_shuffle` wasn't specified.

Erroneous code example:

```ignore (no longer emitted)
#![feature(platform_intrinsics)]

extern "platform-intrinsic" {
    fn simd_shuffle<A,B>(a: A, b: A, c: [u32; 8]) -> B;
    // error: invalid `simd_shuffle`, needs length: `simd_shuffle`
}
```

The `simd_shuffle` function needs the length of the array passed as
last parameter in its name. Example:

```ignore (no longer compiles)
#![feature(platform_intrinsics)]

extern "platform-intrinsic" {
    fn simd_shuffle8<A,B>(a: A, b: A, c: [u32; 8]) -> B;
}
```
#### Note: this error code is no longer emitted by the compiler.

A private trait was used on a public type parameter bound.

Previously erroneous code examples:

```
trait Foo {
    fn dummy(&self) { }
}

pub trait Bar : Foo {} // error: private trait in public interface
pub struct Bar2<T: Foo>(pub T); // same error
pub fn foo<T: Foo> (t: T) {} // same error

fn main() {}
```

To solve this error, please ensure that the trait is also public. The trait
can be made inaccessible if necessary by placing it into a private inner
module, but it still has to be marked with `pub`. Example:

```
pub trait Foo { // we set the Foo trait public
    fn dummy(&self) { }
}

pub trait Bar : Foo {} // ok!
pub struct Bar2<T: Foo>(pub T); // ok!
pub fn foo<T: Foo> (t: T) {} // ok!

fn main() {}
```
A private type or trait was used in a public associated type signature.

Erroneous code example:

```compile_fail,E0446
struct Bar;

pub trait PubTr {
    type Alias;
}

impl PubTr for u8 {
    type Alias = Bar; // error private type in public interface
}

fn main() {}
```

There are two ways to solve this error. The first is to make the public type
signature only public to a module that also has access to the private type.
This is done by using pub(crate) or pub(in crate::my_mod::etc)
Example:

```
struct Bar;

pub(crate) trait PubTr { // only public to crate root
    type Alias;
}

impl PubTr for u8 {
    type Alias = Bar;
}

fn main() {}
```

The other way to solve this error is to make the private type public.
Example:

```

pub struct Bar; // we set the Bar trait public

pub trait PubTr {
    type Alias;
}

impl PubTr for u8 {
    type Alias = Bar;
}

fn main() {}
```
#### Note: this error code is no longer emitted by the compiler.

The `pub` keyword was used inside a function.

Erroneous code example:

```
fn foo() {
    pub struct Bar; // error: visibility has no effect inside functions
}
```

Since we cannot access items defined inside a function, the visibility of its
items does not impact outer code. So using the `pub` keyword in this context
is invalid.
#### Note: this error code is no longer emitted by the compiler.

The `pub` keyword was used inside a public enum.

Erroneous code example:

```compile_fail
pub enum Foo {
    pub Bar, // error: unnecessary `pub` visibility
}
```

Since the enum is already public, adding `pub` on one its elements is
unnecessary. Example:

```compile_fail
enum Foo {
    pub Bar, // not ok!
}
```

This is the correct syntax:

```
pub enum Foo {
    Bar, // ok!
}
```
A visibility qualifier was used where one is not permitted. Visibility
qualifiers are not permitted on enum variants, trait items, impl blocks, and
extern blocks, as they already share the visibility of the parent item.

Erroneous code examples:

```compile_fail,E0449
struct Bar;

trait Foo {
    fn foo();
}

enum Baz {
    pub Qux, // error: visibility qualifiers are not permitted here
}

pub impl Bar {} // error: visibility qualifiers are not permitted here

pub impl Foo for Bar { // error: visibility qualifiers are not permitted here
    pub fn foo() {} // error: visibility qualifiers are not permitted here
}
```

To fix this error, simply remove the visibility qualifier. Example:

```
struct Bar;

trait Foo {
    fn foo();
}

enum Baz {
    // Enum variants share the visibility of the enum they are in, so
    // `pub` is not allowed here
    Qux,
}

// Directly implemented methods share the visibility of the type itself,
// so `pub` is not allowed here
impl Bar {}

// Trait methods share the visibility of the trait, so `pub` is not
// allowed in either case
impl Foo for Bar {
    fn foo() {}
}
```
A struct constructor with private fields was invoked.

Erroneous code example:

```compile_fail,E0451
mod bar {
    pub struct Foo {
        pub a: isize,
        b: isize,
    }
}

let f = bar::Foo{ a: 0, b: 0 }; // error: field `b` of struct `bar::Foo`
                                //        is private
```

To fix this error, please ensure that all the fields of the struct are public,
or implement a function for easy instantiation. Examples:

```
mod bar {
    pub struct Foo {
        pub a: isize,
        pub b: isize, // we set `b` field public
    }
}

let f = bar::Foo{ a: 0, b: 0 }; // ok!
```

Or:

```
mod bar {
    pub struct Foo {
        pub a: isize,
        b: isize, // still private
    }

    impl Foo {
        pub fn new() -> Foo { // we create a method to instantiate `Foo`
            Foo { a: 0, b: 0 }
        }
    }
}

let f = bar::Foo::new(); // ok!
```
An invalid lint attribute has been given.

Erroneous code example:

```compile_fail,E0452
#![allow(foo = "")] // error: malformed lint attribute
```

Lint attributes only accept a list of identifiers (where each identifier is a
lint name). Ensure the attribute is of this form:

```
#![allow(foo)] // ok!
// or:
#![allow(foo, foo2)] // ok!
```
A lint check attribute was overruled by a `forbid` directive set as an
attribute on an enclosing scope, or on the command line with the `-F` option.

Example of erroneous code:

```compile_fail,E0453
#![forbid(non_snake_case)]

#[allow(non_snake_case)]
fn main() {
    // error: allow(non_snake_case) incompatible with previous forbid
    let MyNumber = 2;
}
```

The `forbid` lint setting, like `deny`, turns the corresponding compiler
warning into a hard error. Unlike `deny`, `forbid` prevents itself from being
overridden by inner attributes.

If you're sure you want to override the lint check, you can change `forbid` to
`deny` (or use `-D` instead of `-F` if the `forbid` setting was given as a
command-line option) to allow the inner lint check attribute:

```
#![deny(non_snake_case)]

#[allow(non_snake_case)]
fn main() {
    let MyNumber = 2; // ok!
}
```

Otherwise, edit the code to pass the lint check, and remove the overruled
attribute:

```
#![forbid(non_snake_case)]

fn main() {
    let my_number = 2;
}
```
A link name was given with an empty name.

Erroneous code example:

```compile_fail,E0454
#[link(name = "")] extern "C" {}
// error: `#[link(name = "")]` given with empty name
```

The rust compiler cannot link to an external library if you don't give it its
name. Example:

```no_run
#[link(name = "some_lib")] extern "C" {} // ok!
```
Some linking kinds are target-specific and not supported on all platforms.

Linking with `kind=framework` is only supported when targeting macOS,
as frameworks are specific to that operating system.

Similarly, `kind=raw-dylib` is only supported when targeting Windows-like
platforms.

Erroneous code example:

```ignore (should-compile_fail-but-cannot-doctest-conditionally-without-macos)
#[link(name = "FooCoreServices", kind = "framework")] extern "C" {}
// OS used to compile is Linux for example
```

To solve this error you can use conditional compilation:

```
#[cfg_attr(target="macos", link(name = "FooCoreServices", kind = "framework"))]
extern "C" {}
```

Learn more in the [Conditional Compilation][conditional-compilation] section
of the Reference.

[conditional-compilation]: https://doc.rust-lang.org/reference/attributes.html#conditional-compilation
#### Note: this error code is no longer emitted by the compiler

Plugin `..` only found in rlib format, but must be available in dylib format.

Erroneous code example:

`rlib-plugin.rs`
```ignore (needs-linkage-with-other-tests)
#![crate_type = "rlib"]
#![feature(rustc_private)]

extern crate rustc_middle;
extern crate rustc_driver;

use rustc_driver::plugin::Registry;

#[no_mangle]
fn __rustc_plugin_registrar(_: &mut Registry) {}
```

`main.rs`
```ignore (needs-linkage-with-other-tests)
#![feature(plugin)]
#![plugin(rlib_plugin)] // error: plugin `rlib_plugin` only found in rlib
                        //        format, but must be available in dylib

fn main() {}
```

The compiler exposes a plugin interface to allow altering the compile process
(adding lints, etc). Plugins must be defined in their own crates (similar to
[proc-macro](../reference/procedural-macros.html) isolation) and then compiled
and linked to another crate. Plugin crates *must* be compiled to the
dynamically-linked dylib format, and not the statically-linked rlib format.
Learn more about different output types in
[this section](../reference/linkage.html) of the Rust reference.

This error is easily fixed by recompiling the plugin crate in the dylib format.
An unknown "kind" was specified for a link attribute.

Erroneous code example:

```compile_fail,E0458
#[link(kind = "wonderful_unicorn")] extern "C" {}
// error: unknown kind: `wonderful_unicorn`
```

Please specify a valid "kind" value, from one of the following:

* static
* dylib
* framework
* raw-dylib
A link was used without a name parameter.

Erroneous code example:

```compile_fail,E0459
#[link(kind = "dylib")] extern "C" {}
// error: `#[link(...)]` specified without `name = "foo"`
```

Please add the name parameter to allow the rust compiler to find the library
you want. Example:

```no_run
#[link(kind = "dylib", name = "some_lib")] extern "C" {} // ok!
```
Found possibly newer version of crate `..` which `..` depends on.

Consider these erroneous files:

`a1.rs`
```ignore (needs-linkage-with-other-tests)
#![crate_name = "a"]

pub fn foo<T>() {}
```

`a2.rs`
```ignore (needs-linkage-with-other-tests)
#![crate_name = "a"]

pub fn foo<T>() {
    println!("foo<T>()");
}
```

`b.rs`
```ignore (needs-linkage-with-other-tests)
#![crate_name = "b"]

extern crate a; // linked with `a1.rs`

pub fn foo() {
    a::foo::<isize>();
}
```

`main.rs`
```ignore (needs-linkage-with-other-tests)
extern crate a; // linked with `a2.rs`
extern crate b; // error: found possibly newer version of crate `a` which `b`
                //        depends on

fn main() {}
```

The dependency graph of this program can be represented as follows:
```text
    crate `main`
         |
         +-------------+
         |             |
         |             v
depends: |         crate `b`
 `a` v1  |             |
         |             | depends:
         |             |  `a` v2
         v             |
      crate `a` <------+
```

Crate `main` depends on crate `a` (version 1) and crate `b` which in turn
depends on crate `a` (version 2); this discrepancy in versions cannot be
reconciled. This difference in versions typically occurs when one crate is
compiled and linked, then updated and linked to another crate. The crate
"version" is a SVH (Strict Version Hash) of the crate in an
implementation-specific way. Note that this error can *only* occur when
directly compiling and linking with `rustc`; [Cargo] automatically resolves
dependencies, without using the compiler's own dependency management that
causes this issue.

This error can be fixed by:
 * Using [Cargo], the Rust package manager, automatically fixing this issue.
 * Recompiling crate `a` so that both crate `b` and `main` have a uniform
   version to depend on.

[Cargo]: ../cargo/index.html
Couldn't find crate `..` with expected target triple `..`.

Example of erroneous code:

`a.rs`
```ignore (cannot-link-with-other-tests)
#![crate_type = "lib"]

fn foo() {}
```

`main.rs`
```ignore (cannot-link-with-other-tests)
extern crate a;

fn main() {
    a::foo();
}
```

`a.rs` is then compiled with `--target powerpc-unknown-linux-gnu` and `b.rs`
with `--target x86_64-unknown-linux-gnu`. `a.rs` is compiled into a binary
format incompatible with `b.rs`; PowerPC and x86 are totally different
architectures. This issue also extends to any difference in target triples, as
`std` is operating-system specific.

This error can be fixed by:
 * Using [Cargo](../cargo/index.html), the Rust package manager, automatically
   fixing this issue.
 * Recompiling either crate so that they target a consistent target triple.
Found `staticlib` `..` instead of `rlib` or `dylib`.

Consider the following two files:

`a.rs`
```ignore (cannot-link-with-other-tests)
#![crate_type = "staticlib"]

fn foo() {}
```

`main.rs`
```ignore (cannot-link-with-other-tests)
extern crate a;

fn main() {
    a::foo();
}
```

Crate `a` is compiled as a `staticlib`. A `staticlib` is a system-dependant
library only intended for linking with non-Rust applications (C programs). Note
that `staticlib`s include all upstream dependencies (`core`, `std`, other user
dependencies, etc) which makes them significantly larger than `dylib`s:
prefer `staticlib` for linking with C programs. Learn more about different
`crate_type`s in [this section of the Reference](../reference/linkage.html).

This error can be fixed by:
 * Using [Cargo](../cargo/index.html), the Rust package manager, automatically
   fixing this issue.
 * Recompiling the crate as a `rlib` or `dylib`; formats suitable for Rust
   linking.
A crate was declared but cannot be found.

Erroneous code example:

```compile_fail,E0463
extern crate foo; // error: can't find crate
```

You need to link your code to the relevant crate in order to be able to use it
(through Cargo or the `-L` option of rustc, for example).

## Common causes

- The crate is not present at all. If using Cargo, add it to `[dependencies]`
  in Cargo.toml.
- The crate is present, but under a different name. If using Cargo, look for
  `package = ` under `[dependencies]` in Cargo.toml.

## Common causes for missing `std` or `core`

- You are cross-compiling for a target which doesn't have `std` prepackaged.
  Consider one of the following:
  + Adding a pre-compiled version of std with `rustup target add`
  + Building std from source with `cargo build -Z build-std`
  + Using `#![no_std]` at the crate root, so you won't need `std` in the first
    place.
- You are developing the compiler itself and haven't built libstd from source.
  You can usually build it with `x.py build library/std`. More information
  about x.py is available in the [rustc-dev-guide].

[rustc-dev-guide]: https://rustc-dev-guide.rust-lang.org/building/how-to-build-and-run.html#building-the-compiler
The compiler found multiple library files with the requested crate name.

```compile_fail
// aux-build:crateresolve-1.rs
// aux-build:crateresolve-2.rs
// aux-build:crateresolve-3.rs

extern crate crateresolve;
//~^ ERROR multiple candidates for `rlib` dependency `crateresolve` found

fn main() {}
```

This error can occur in several different cases -- for example, when using
`extern crate` or passing `--extern` options without crate paths. It can also be
caused by caching issues with the build directory, in which case `cargo clean`
may help.

In the above example, there are three different library files, all of which
define the same crate name. Without providing a full path, there is no way for
the compiler to know which crate it should use.
#### Note: this error code is no longer emitted by the compiler.

Macro import declaration was malformed.

Erroneous code examples:

```compile_fail
#[macro_use(a_macro(another_macro))] // error: invalid import declaration
extern crate core as some_crate;

#[macro_use(i_want = "some_macros")] // error: invalid import declaration
extern crate core as another_crate;
```

This is a syntax error at the level of attribute declarations. The proper
syntax for macro imports is the following:

```ignore (cannot-doctest-multicrate-project)
// In some_crate:
#[macro_export]
macro_rules! get_tacos {
    ...
}

#[macro_export]
macro_rules! get_pimientos {
    ...
}

// In your crate:
#[macro_use(get_tacos, get_pimientos)] // It imports `get_tacos` and
extern crate some_crate;               // `get_pimientos` macros from some_crate
```

If you would like to import all exported macros, write `macro_use` with no
arguments.
A non-root module tried to import macros from another crate.

Example of erroneous code:

```compile_fail,E0468
mod foo {
    #[macro_use(debug_assert)]  // error: must be at crate root to import
    extern crate core;          //        macros from another crate
    fn run_macro() { debug_assert!(true); }
}
```

Only `extern crate` imports at the crate root level are allowed to import
macros.

Either move the macro import to crate root or do without the foreign macros.
This will work:

```
#[macro_use(debug_assert)] // ok!
extern crate core;

mod foo {
    fn run_macro() { debug_assert!(true); }
}
# fn main() {}
```
A macro listed for import was not found.

Erroneous code example:

```compile_fail,E0469
#[macro_use(drink, be_merry)] // error: imported macro not found
extern crate alloc;

fn main() {
    // ...
}
```

Either the listed macro is not contained in the imported crate, or it is not
exported from the given crate.

This could be caused by a typo. Did you misspell the macro's name?

Double-check the names of the macros listed for import, and that the crate
in question exports them.

A working version would be:

```ignore (cannot-doctest-multicrate-project)
// In some_crate crate:
#[macro_export]
macro_rules! eat {
    ...
}

#[macro_export]
macro_rules! drink {
    ...
}

// In your crate:
#[macro_use(eat, drink)]
extern crate some_crate; //ok!
```
Inline assembly (`asm!`) is not supported on this target.

Example of erroneous code:

```ignore (cannot-change-target)
// compile-flags: --target sparc64-unknown-linux-gnu
#![no_std]

use core::arch::asm;

fn main() {
    unsafe {
        asm!(""); // error: inline assembly is not supported on this target
    }
}
```

The Rust compiler does not support inline assembly, with the `asm!` macro
(previously `llvm_asm!`), for all targets. All Tier 1 targets do support this
macro but support among Tier 2 and 3 targets is not guaranteed (even when they
have `std` support). Note that this error is related to
`error[E0658]: inline assembly is not stable yet on this architecture`, but
distinct in that with `E0472` support is not planned or in progress.

There is no way to easily fix this issue, however:
 * Consider if you really need inline assembly, is there some other way to
   achieve your goal (intrinsics, etc)?
 * Consider writing your assembly externally, linking with it and calling it
   from Rust.
 * Consider contributing to <https://github.com/rust-lang/rust> and help
   integrate support for your target!
The coerced type does not outlive the value being coerced to.

Example of erroneous code:

```compile_fail,E0476
#![feature(coerce_unsized)]
#![feature(unsize)]

use std::marker::Unsize;
use std::ops::CoerceUnsized;

// error: lifetime of the source pointer does not outlive lifetime bound of the
//        object type
impl<'a, 'b, T, S> CoerceUnsized<&'a T> for &'b S where S: Unsize<T> {}
```

During a coercion, the "source pointer" (the coerced type) did not outlive the
"object type" (value being coerced to). In the above example, `'b` is not a
subtype of `'a`. This error can currently only be encountered with the unstable
`CoerceUnsized` trait which allows custom coercions of unsized types behind a
smart pointer to be implemented.
#### Note: this error code is no longer emitted by the compiler.

The type does not fulfill the required lifetime.

Erroneous code example:

```compile_fail
use std::sync::Mutex;

struct MyString<'a> {
    data: &'a str,
}

fn i_want_static_closure<F>(a: F)
    where F: Fn() + 'static {}

fn print_string<'a>(s: Mutex<MyString<'a>>) {

    i_want_static_closure(move || {     // error: this closure has lifetime 'a
                                        //        rather than 'static
        println!("{}", s.lock().unwrap().data);
    });
}
```

In this example, the closure does not satisfy the `'static` lifetime constraint.
To fix this error, you need to double check the lifetime of the type. Here, we
can fix this problem by giving `s` a static lifetime:

```
use std::sync::Mutex;

struct MyString<'a> {
    data: &'a str,
}

fn i_want_static_closure<F>(a: F)
    where F: Fn() + 'static {}

fn print_string(s: Mutex<MyString<'static>>) {

    i_want_static_closure(move || {     // ok!
        println!("{}", s.lock().unwrap().data);
    });
}
```
A lifetime bound was not satisfied.

Erroneous code example:

```compile_fail,E0478
// Check that the explicit lifetime bound (`'SnowWhite`, in this example) must
// outlive all the superbounds from the trait (`'kiss`, in this example).

trait Wedding<'t>: 't { }

struct Prince<'kiss, 'SnowWhite> {
    child: Box<Wedding<'kiss> + 'SnowWhite>,
    // error: lifetime bound not satisfied
}
```

In this example, the `'SnowWhite` lifetime is supposed to outlive the `'kiss`
lifetime but the declaration of the `Prince` struct doesn't enforce it. To fix
this issue, you need to specify it:

```
trait Wedding<'t>: 't { }

struct Prince<'kiss, 'SnowWhite: 'kiss> { // You say here that 'SnowWhite
                                          // must live longer than 'kiss.
    child: Box<Wedding<'kiss> + 'SnowWhite>, // And now it's all good!
}
```
#### Note: this error code is no longer emitted by the compiler.

A lifetime of a returned value does not outlive the function call.

Erroneous code example:

```compile_fail,E0700
fn prefix<'a>(
    words: impl Iterator<Item = &'a str>
) -> impl Iterator<Item = String> { // error!
    words.map(|v| format!("foo-{}", v))
}
```

To fix this error, make the lifetime of the returned value explicit:

```
fn prefix<'a>(
    words: impl Iterator<Item = &'a str> + 'a
) -> impl Iterator<Item = String> + 'a { // ok!
    words.map(|v| format!("foo-{}", v))
}
```

The [`impl Trait`] feature in this example uses an implicit `'static` lifetime
restriction in the returned type. However the type implementing the `Iterator`
passed to the function lives just as long as `'a`, which is not long enough.

The solution involves adding lifetime bound to both function argument and
the return value to make sure that the values inside the iterator
are not dropped when the function goes out of the scope.

An alternative solution would be to guarantee that the `Item` references
in the iterator are alive for the whole lifetime of the program.

```
fn prefix(
    words: impl Iterator<Item = &'static str>
) -> impl Iterator<Item = String> {  // ok!
    words.map(|v| format!("foo-{}", v))
}
```

A similar lifetime problem might arise when returning closures:

```compile_fail,E0700
fn foo(
    x: &mut Vec<i32>
) -> impl FnMut(&mut Vec<i32>) -> &[i32] { // error!
    |y| {
        y.append(x);
        y
    }
}
```

Analogically, a solution here is to use explicit return lifetime
and move the ownership of the variable to the closure.

```
fn foo<'a>(
    x: &'a mut Vec<i32>
) -> impl FnMut(&mut Vec<i32>) -> &[i32] + 'a { // ok!
    move |y| {
        y.append(x);
        y
    }
}
```

To better understand the lifetime treatment in the [`impl Trait`],
please see the [RFC 1951].

[`impl Trait`]: https://doc.rust-lang.org/reference/types/impl-trait.html
[RFC 1951]: https://rust-lang.github.io/rfcs/1951-expand-impl-trait.html
A reference has a longer lifetime than the data it references.

Erroneous code example:

```compile_fail,E0491
struct Foo<'a> {
    x: fn(&'a i32),
}

trait Trait<'a, 'b> {
    type Out;
}

impl<'a, 'b> Trait<'a, 'b> for usize {
    type Out = &'a Foo<'b>; // error!
}
```

Here, the problem is that the compiler cannot be sure that the `'b` lifetime
will live longer than `'a`, which should be mandatory in order to be sure that
`Trait::Out` will always have a reference pointing to an existing type. So in
this case, we just need to tell the compiler than `'b` must outlive `'a`:

```
struct Foo<'a> {
    x: fn(&'a i32),
}

trait Trait<'a, 'b> {
    type Out;
}

impl<'a, 'b: 'a> Trait<'a, 'b> for usize { // we added the lifetime enforcement
    type Out = &'a Foo<'b>; // it now works!
}
```
A borrow of a constant containing interior mutability was attempted.

Erroneous code example:

```compile_fail,E0492
use std::sync::atomic::AtomicUsize;

const A: AtomicUsize = AtomicUsize::new(0);
const B: &'static AtomicUsize = &A;
// error: cannot borrow a constant which may contain interior mutability,
//        create a static instead
```

A `const` represents a constant value that should never change. If one takes
a `&` reference to the constant, then one is taking a pointer to some memory
location containing the value. Normally this is perfectly fine: most values
can't be changed via a shared `&` pointer, but interior mutability would allow
it. That is, a constant value could be mutated. On the other hand, a `static` is
explicitly a single memory location, which can be mutated at will.

So, in order to solve this error, use statics which are `Sync`:

```
use std::sync::atomic::AtomicUsize;

static A: AtomicUsize = AtomicUsize::new(0);
static B: &'static AtomicUsize = &A; // ok!
```

You can also have this error while using a cell type:

```compile_fail,E0492
use std::cell::Cell;

const A: Cell<usize> = Cell::new(1);
const B: &Cell<usize> = &A;
// error: cannot borrow a constant which may contain interior mutability,
//        create a static instead

// or:
struct C { a: Cell<usize> }

const D: C = C { a: Cell::new(1) };
const E: &Cell<usize> = &D.a; // error

// or:
const F: &C = &D; // error
```

This is because cell types do operations that are not thread-safe. Due to this,
they don't implement Sync and thus can't be placed in statics.

However, if you still wish to use these types, you can achieve this by an unsafe
wrapper:

```
use std::cell::Cell;

struct NotThreadSafe<T> {
    value: Cell<T>,
}

unsafe impl<T> Sync for NotThreadSafe<T> {}

static A: NotThreadSafe<usize> = NotThreadSafe { value : Cell::new(1) };
static B: &'static NotThreadSafe<usize> = &A; // ok!
```

Remember this solution is unsafe! You will have to ensure that accesses to the
cell are synchronized.
A value with a custom `Drop` implementation may be dropped during const-eval.

Erroneous code example:

```compile_fail,E0493
enum DropType {
    A,
}

impl Drop for DropType {
    fn drop(&mut self) {}
}

struct Foo {
    field1: DropType,
}

static FOO: Foo = Foo { field1: (DropType::A, DropType::A).1 }; // error!
```

The problem here is that if the given type or one of its fields implements the
`Drop` trait, this `Drop` implementation cannot be called within a const
context since it may run arbitrary, non-const-checked code. To prevent this
issue, ensure all values with a custom `Drop` implementation escape the
initializer.

```
enum DropType {
    A,
}

impl Drop for DropType {
    fn drop(&mut self) {}
}

struct Foo {
    field1: DropType,
}

static FOO: Foo = Foo { field1: DropType::A }; // We initialize all fields
                                               // by hand.
```
#### Note: this error code is no longer emitted by the compiler.

A lifetime cannot be determined in the given situation.

Erroneous code example:

```compile_fail
fn transmute_lifetime<'a, 'b, T>(t: &'a (T,)) -> &'b T {
    match (&t,) { // error!
        ((u,),) => u,
    }
}

let y = Box::new((42,));
let x = transmute_lifetime(&y);
```

In this code, you have two ways to solve this issue:
 1. Enforce that `'a` lives at least as long as `'b`.
 2. Use the same lifetime requirement for both input and output values.

So for the first solution, you can do it by replacing `'a` with `'a: 'b`:

```
fn transmute_lifetime<'a: 'b, 'b, T>(t: &'a (T,)) -> &'b T {
    match (&t,) { // ok!
        ((u,),) => u,
    }
}
```

In the second you can do it by simply removing `'b` so they both use `'a`:

```
fn transmute_lifetime<'a, T>(t: &'a (T,)) -> &'a T {
    match (&t,) { // ok!
        ((u,),) => u,
    }
}
```
A lifetime name is shadowing another lifetime name.

Erroneous code example:

```compile_fail,E0496
struct Foo<'a> {
    a: &'a i32,
}

impl<'a> Foo<'a> {
    fn f<'a>(x: &'a i32) { // error: lifetime name `'a` shadows a lifetime
                           //        name that is already in scope
    }
}
```

Please change the name of one of the lifetimes to remove this error. Example:

```
struct Foo<'a> {
    a: &'a i32,
}

impl<'a> Foo<'a> {
    fn f<'b>(x: &'b i32) { // ok!
    }
}

fn main() {
}
```
#### Note: this error code is no longer emitted by the compiler.

A stability attribute was used outside of the standard library.

Erroneous code example:

```compile_fail
#[stable] // error: stability attributes may not be used outside of the
          //        standard library
fn foo() {}
```

It is not possible to use stability attributes outside of the standard library.
Also, for now, it is not possible to write deprecation messages either.
#### Note: this error code is no longer emitted by the compiler.

The `plugin` attribute was malformed.

Erroneous code example:

```ignore (E0498 is no longer emitted)
#![feature(plugin)]
#![plugin(foo(args))] // error: invalid argument
#![plugin(bar="test")] // error: invalid argument
```

The `#[plugin]` attribute should take a single argument: the name of the plugin.

For example, for the plugin `foo`:

```ignore (requires external plugin crate)
#![feature(plugin)]
#![plugin(foo)] // ok!
```

See the [`plugin` feature] section of the Unstable book for more details.

[`plugin` feature]: https://doc.rust-lang.org/nightly/unstable-book/language-features/plugin.html
A variable was borrowed as mutable more than once.

Erroneous code example:

```compile_fail,E0499
let mut i = 0;
let mut x = &mut i;
let mut a = &mut i;
x;
// error: cannot borrow `i` as mutable more than once at a time
```

Please note that in Rust, you can either have many immutable references, or one
mutable reference. For more details you may want to read the
[References & Borrowing][references-and-borrowing] section of the Book.

[references-and-borrowing]: https://doc.rust-lang.org/book/ch04-02-references-and-borrowing.html

Example:

```
let mut i = 0;
let mut x = &mut i; // ok!

// or:
let mut i = 0;
let a = &i; // ok!
let b = &i; // still ok!
let c = &i; // still ok!
b;
a;
```
A borrowed variable was used by a closure.

Erroneous code example:

```compile_fail,E0500
fn you_know_nothing(jon_snow: &mut i32) {
    let nights_watch = &jon_snow;
    let starks = || {
        *jon_snow = 3; // error: closure requires unique access to `jon_snow`
                       //        but it is already borrowed
    };
    println!("{}", nights_watch);
}
```

In here, `jon_snow` is already borrowed by the `nights_watch` reference, so it
cannot be borrowed by the `starks` closure at the same time. To fix this issue,
you can create the closure after the borrow has ended:

```
fn you_know_nothing(jon_snow: &mut i32) {
    let nights_watch = &jon_snow;
    println!("{}", nights_watch);
    let starks = || {
        *jon_snow = 3;
    };
}
```

Or, if the type implements the `Clone` trait, you can clone it between
closures:

```
fn you_know_nothing(jon_snow: &mut i32) {
    let mut jon_copy = jon_snow.clone();
    let starks = || {
        *jon_snow = 3;
    };
    println!("{}", jon_copy);
}
```
A mutable variable is used but it is already captured by a closure.

Erroneous code example:

```compile_fail,E0501
fn inside_closure(x: &mut i32) {
    // Actions which require unique access
}

fn outside_closure(x: &mut i32) {
    // Actions which require unique access
}

fn foo(a: &mut i32) {
    let mut bar = || {
        inside_closure(a)
    };
    outside_closure(a); // error: cannot borrow `*a` as mutable because previous
                        //        closure requires unique access.
    bar();
}
```

This error indicates that a mutable variable is used while it is still captured
by a closure. Because the closure has borrowed the variable, it is not available
until the closure goes out of scope.

Note that a capture will either move or borrow a variable, but in this
situation, the closure is borrowing the variable. Take a look at the chapter
on [Capturing][capturing] in Rust By Example for more information.

[capturing]: https://doc.rust-lang.org/stable/rust-by-example/fn/closures/capture.html

To fix this error, you can finish using the closure before using the captured
variable:

```
fn inside_closure(x: &mut i32) {}
fn outside_closure(x: &mut i32) {}

fn foo(a: &mut i32) {
    let mut bar = || {
        inside_closure(a)
    };
    bar();
    // borrow on `a` ends.
    outside_closure(a); // ok!
}
```

Or you can pass the variable as a parameter to the closure:

```
fn inside_closure(x: &mut i32) {}
fn outside_closure(x: &mut i32) {}

fn foo(a: &mut i32) {
    let mut bar = |s: &mut i32| {
        inside_closure(s)
    };
    outside_closure(a);
    bar(a);
}
```

It may be possible to define the closure later:

```
fn inside_closure(x: &mut i32) {}
fn outside_closure(x: &mut i32) {}

fn foo(a: &mut i32) {
    outside_closure(a);
    let mut bar = || {
        inside_closure(a)
    };
    bar();
}
```
A variable already borrowed with a certain mutability (either mutable or
immutable) was borrowed again with a different mutability.

Erroneous code example:

```compile_fail,E0502
fn bar(x: &mut i32) {}
fn foo(a: &mut i32) {
    let y = &a; // a is borrowed as immutable.
    bar(a); // error: cannot borrow `*a` as mutable because `a` is also borrowed
            //        as immutable
    println!("{}", y);
}
```

To fix this error, ensure that you don't have any other references to the
variable before trying to access it with a different mutability:

```
fn bar(x: &mut i32) {}
fn foo(a: &mut i32) {
    bar(a);
    let y = &a; // ok!
    println!("{}", y);
}
```

For more information on Rust's ownership system, take a look at the
[References & Borrowing][references-and-borrowing] section of the Book.

[references-and-borrowing]: https://doc.rust-lang.org/book/ch04-02-references-and-borrowing.html
A value was used after it was mutably borrowed.

Erroneous code example:

```compile_fail,E0503
fn main() {
    let mut value = 3;
    // Create a mutable borrow of `value`.
    let borrow = &mut value;
    let _sum = value + 1; // error: cannot use `value` because
                          //        it was mutably borrowed
    println!("{}", borrow);
}
```

In this example, `value` is mutably borrowed by `borrow` and cannot be
used to calculate `sum`. This is not possible because this would violate
Rust's mutability rules.

You can fix this error by finishing using the borrow before the next use of
the value:

```
fn main() {
    let mut value = 3;
    let borrow = &mut value;
    println!("{}", borrow);
    // The block has ended and with it the borrow.
    // You can now use `value` again.
    let _sum = value + 1;
}
```

Or by cloning `value` before borrowing it:

```
fn main() {
    let mut value = 3;
    // We clone `value`, creating a copy.
    let value_cloned = value.clone();
    // The mutable borrow is a reference to `value` and
    // not to `value_cloned`...
    let borrow = &mut value;
    // ... which means we can still use `value_cloned`,
    let _sum = value_cloned + 1;
    // even though the borrow only ends here.
    println!("{}", borrow);
}
```

For more information on Rust's ownership system, take a look at the
[References & Borrowing][references-and-borrowing] section of the Book.

[references-and-borrowing]: https://doc.rust-lang.org/book/ch04-02-references-and-borrowing.html
#### Note: this error code is no longer emitted by the compiler.

This error occurs when an attempt is made to move a borrowed variable into a
closure.

Erroneous code example:

```compile_fail
struct FancyNum {
    num: u8,
}

fn main() {
    let fancy_num = FancyNum { num: 5 };
    let fancy_ref = &fancy_num;

    let x = move || {
        println!("child function: {}", fancy_num.num);
        // error: cannot move `fancy_num` into closure because it is borrowed
    };

    x();
    println!("main function: {}", fancy_ref.num);
}
```

Here, `fancy_num` is borrowed by `fancy_ref` and so cannot be moved into
the closure `x`. There is no way to move a value into a closure while it is
borrowed, as that would invalidate the borrow.

If the closure can't outlive the value being moved, try using a reference
rather than moving:

```
struct FancyNum {
    num: u8,
}

fn main() {
    let fancy_num = FancyNum { num: 5 };
    let fancy_ref = &fancy_num;

    let x = move || {
        // fancy_ref is usable here because it doesn't move `fancy_num`
        println!("child function: {}", fancy_ref.num);
    };

    x();

    println!("main function: {}", fancy_num.num);
}
```

If the value has to be borrowed and then moved, try limiting the lifetime of
the borrow using a scoped block:

```
struct FancyNum {
    num: u8,
}

fn main() {
    let fancy_num = FancyNum { num: 5 };

    {
        let fancy_ref = &fancy_num;
        println!("main function: {}", fancy_ref.num);
        // `fancy_ref` goes out of scope here
    }

    let x = move || {
        // `fancy_num` can be moved now (no more references exist)
        println!("child function: {}", fancy_num.num);
    };

    x();
}
```

If the lifetime of a reference isn't enough, such as in the case of threading,
consider using an `Arc` to create a reference-counted value:

```
use std::sync::Arc;
use std::thread;

struct FancyNum {
    num: u8,
}

fn main() {
    let fancy_ref1 = Arc::new(FancyNum { num: 5 });
    let fancy_ref2 = fancy_ref1.clone();

    let x = thread::spawn(move || {
        // `fancy_ref1` can be moved and has a `'static` lifetime
        println!("child thread: {}", fancy_ref1.num);
    });

    x.join().expect("child thread should finish");
    println!("main thread: {}", fancy_ref2.num);
}
```
A value was moved out while it was still borrowed.

Erroneous code example:

```compile_fail,E0505
struct Value {}

fn borrow(val: &Value) {}

fn eat(val: Value) {}

fn main() {
    let x = Value{};
    let _ref_to_val: &Value = &x;
    eat(x);
    borrow(_ref_to_val);
}
```

Here, the function `eat` takes ownership of `x`. However,
`x` cannot be moved because the borrow to `_ref_to_val`
needs to last till the function `borrow`.
To fix that you can do a few different things:

* Try to avoid moving the variable.
* Release borrow before move.
* Implement the `Copy` trait on the type.

Examples:

```
struct Value {}

fn borrow(val: &Value) {}

fn eat(val: &Value) {}

fn main() {
    let x = Value{};

    let ref_to_val: &Value = &x;
    eat(&x); // pass by reference, if it's possible
    borrow(ref_to_val);
}
```

Or:

```
struct Value {}

fn borrow(val: &Value) {}

fn eat(val: Value) {}

fn main() {
    let x = Value{};

    let ref_to_val: &Value = &x;
    borrow(ref_to_val);
    // ref_to_val is no longer used.
    eat(x);
}
```

Or:

```
#[derive(Clone, Copy)] // implement Copy trait
struct Value {}

fn borrow(val: &Value) {}

fn eat(val: Value) {}

fn main() {
    let x = Value{};
    let ref_to_val: &Value = &x;
    eat(x); // it will be copied here.
    borrow(ref_to_val);
}
```

For more information on Rust's ownership system, take a look at the
[References & Borrowing][references-and-borrowing] section of the Book.

[references-and-borrowing]: https://doc.rust-lang.org/book/ch04-02-references-and-borrowing.html
An attempt was made to assign to a borrowed value.

Erroneous code example:

```compile_fail,E0506
struct FancyNum {
    num: u8,
}

let mut fancy_num = FancyNum { num: 5 };
let fancy_ref = &fancy_num;
fancy_num = FancyNum { num: 6 };
// error: cannot assign to `fancy_num` because it is borrowed

println!("Num: {}, Ref: {}", fancy_num.num, fancy_ref.num);
```

Because `fancy_ref` still holds a reference to `fancy_num`, `fancy_num` can't
be assigned to a new value as it would invalidate the reference.

Alternatively, we can move out of `fancy_num` into a second `fancy_num`:

```
struct FancyNum {
    num: u8,
}

let mut fancy_num = FancyNum { num: 5 };
let moved_num = fancy_num;
fancy_num = FancyNum { num: 6 };

println!("Num: {}, Moved num: {}", fancy_num.num, moved_num.num);
```

If the value has to be borrowed, try limiting the lifetime of the borrow using
a scoped block:

```
struct FancyNum {
    num: u8,
}

let mut fancy_num = FancyNum { num: 5 };

{
    let fancy_ref = &fancy_num;
    println!("Ref: {}", fancy_ref.num);
}

// Works because `fancy_ref` is no longer in scope
fancy_num = FancyNum { num: 6 };
println!("Num: {}", fancy_num.num);
```

Or by moving the reference into a function:

```
struct FancyNum {
    num: u8,
}

fn print_fancy_ref(fancy_ref: &FancyNum){
    println!("Ref: {}", fancy_ref.num);
}

let mut fancy_num = FancyNum { num: 5 };

print_fancy_ref(&fancy_num);

// Works because function borrow has ended
fancy_num = FancyNum { num: 6 };
println!("Num: {}", fancy_num.num);
```
A borrowed value was moved out.

Erroneous code example:

```compile_fail,E0507
use std::cell::RefCell;

struct TheDarkKnight;

impl TheDarkKnight {
    fn nothing_is_true(self) {}
}

fn main() {
    let x = RefCell::new(TheDarkKnight);

    x.borrow().nothing_is_true(); // error: cannot move out of borrowed content
}
```

Here, the `nothing_is_true` method takes the ownership of `self`. However,
`self` cannot be moved because `.borrow()` only provides an `&TheDarkKnight`,
which is a borrow of the content owned by the `RefCell`. To fix this error,
you have three choices:

* Try to avoid moving the variable.
* Somehow reclaim the ownership.
* Implement the `Copy` trait on the type.

This can also happen when using a type implementing `Fn` or `FnMut`, as neither
allows moving out of them (they usually represent closures which can be called
more than once). Much of the text following applies equally well to non-`FnOnce`
closure bodies.

Examples:

```
use std::cell::RefCell;

struct TheDarkKnight;

impl TheDarkKnight {
    fn nothing_is_true(&self) {} // First case, we don't take ownership
}

fn main() {
    let x = RefCell::new(TheDarkKnight);

    x.borrow().nothing_is_true(); // ok!
}
```

Or:

```
use std::cell::RefCell;

struct TheDarkKnight;

impl TheDarkKnight {
    fn nothing_is_true(self) {}
}

fn main() {
    let x = RefCell::new(TheDarkKnight);
    let x = x.into_inner(); // we get back ownership

    x.nothing_is_true(); // ok!
}
```

Or:

```
use std::cell::RefCell;

#[derive(Clone, Copy)] // we implement the Copy trait
struct TheDarkKnight;

impl TheDarkKnight {
    fn nothing_is_true(self) {}
}

fn main() {
    let x = RefCell::new(TheDarkKnight);

    x.borrow().nothing_is_true(); // ok!
}
```

Moving a member out of a mutably borrowed struct will also cause E0507 error:

```compile_fail,E0507
struct TheDarkKnight;

impl TheDarkKnight {
    fn nothing_is_true(self) {}
}

struct Batcave {
    knight: TheDarkKnight
}

fn main() {
    let mut cave = Batcave {
        knight: TheDarkKnight
    };
    let borrowed = &mut cave;

    borrowed.knight.nothing_is_true(); // E0507
}
```

It is fine only if you put something back. `mem::replace` can be used for that:

```
# struct TheDarkKnight;
# impl TheDarkKnight { fn nothing_is_true(self) {} }
# struct Batcave { knight: TheDarkKnight }
use std::mem;

let mut cave = Batcave {
    knight: TheDarkKnight
};
let borrowed = &mut cave;

mem::replace(&mut borrowed.knight, TheDarkKnight).nothing_is_true(); // ok!
```

For more information on Rust's ownership system, take a look at the
[References & Borrowing][references-and-borrowing] section of the Book.

[references-and-borrowing]: https://doc.rust-lang.org/book/ch04-02-references-and-borrowing.html
A value was moved out of a non-copy fixed-size array.

Erroneous code example:

```compile_fail,E0508
struct NonCopy;

fn main() {
    let array = [NonCopy; 1];
    let _value = array[0]; // error: cannot move out of type `[NonCopy; 1]`,
                           //        a non-copy fixed-size array
}
```

The first element was moved out of the array, but this is not
possible because `NonCopy` does not implement the `Copy` trait.

Consider borrowing the element instead of moving it:

```
struct NonCopy;

fn main() {
    let array = [NonCopy; 1];
    let _value = &array[0]; // Borrowing is allowed, unlike moving.
}
```

Alternatively, if your type implements `Clone` and you need to own the value,
consider borrowing and then cloning:

```
#[derive(Clone)]
struct NonCopy;

fn main() {
    let array = [NonCopy; 1];
    // Now you can clone the array element.
    let _value = array[0].clone();
}
```

If you really want to move the value out, you can use a destructuring array
pattern to move it:

```
struct NonCopy;

fn main() {
    let array = [NonCopy; 1];
    // Destructuring the array
    let [_value] = array;
}
```
This error occurs when an attempt is made to move out of a value whose type
implements the `Drop` trait.

Erroneous code example:

```compile_fail,E0509
struct FancyNum {
    num: usize
}

struct DropStruct {
    fancy: FancyNum
}

impl Drop for DropStruct {
    fn drop(&mut self) {
        // Destruct DropStruct, possibly using FancyNum
    }
}

fn main() {
    let drop_struct = DropStruct{fancy: FancyNum{num: 5}};
    let fancy_field = drop_struct.fancy; // Error E0509
    println!("Fancy: {}", fancy_field.num);
    // implicit call to `drop_struct.drop()` as drop_struct goes out of scope
}
```

Here, we tried to move a field out of a struct of type `DropStruct` which
implements the `Drop` trait. However, a struct cannot be dropped if one or
more of its fields have been moved.

Structs implementing the `Drop` trait have an implicit destructor that gets
called when they go out of scope. This destructor may use the fields of the
struct, so moving out of the struct could make it impossible to run the
destructor. Therefore, we must think of all values whose type implements the
`Drop` trait as single units whose fields cannot be moved.

This error can be fixed by creating a reference to the fields of a struct,
enum, or tuple using the `ref` keyword:

```
struct FancyNum {
    num: usize
}

struct DropStruct {
    fancy: FancyNum
}

impl Drop for DropStruct {
    fn drop(&mut self) {
        // Destruct DropStruct, possibly using FancyNum
    }
}

fn main() {
    let drop_struct = DropStruct{fancy: FancyNum{num: 5}};
    let ref fancy_field = drop_struct.fancy; // No more errors!
    println!("Fancy: {}", fancy_field.num);
    // implicit call to `drop_struct.drop()` as drop_struct goes out of scope
}
```

Note that this technique can also be used in the arms of a match expression:

```
struct FancyNum {
    num: usize
}

enum DropEnum {
    Fancy(FancyNum)
}

impl Drop for DropEnum {
    fn drop(&mut self) {
        // Destruct DropEnum, possibly using FancyNum
    }
}

fn main() {
    // Creates and enum of type `DropEnum`, which implements `Drop`
    let drop_enum = DropEnum::Fancy(FancyNum{num: 10});
    match drop_enum {
        // Creates a reference to the inside of `DropEnum::Fancy`
        DropEnum::Fancy(ref fancy_field) => // No error!
            println!("It was fancy-- {}!", fancy_field.num),
    }
    // implicit call to `drop_enum.drop()` as drop_enum goes out of scope
}
```
The matched value was assigned in a match guard.

Erroneous code example:

```compile_fail,E0510
let mut x = Some(0);
match x {
    None => {}
    Some(_) if { x = None; false } => {} // error!
    Some(_) => {}
}
```

When matching on a variable it cannot be mutated in the match guards, as this
could cause the match to be non-exhaustive.

Here executing `x = None` would modify the value being matched and require us
to go "back in time" to the `None` arm. To fix it, change the value in the match
arm:

```
let mut x = Some(0);
match x {
    None => {}
    Some(_) => {
        x = None; // ok!
    }
}
```
Invalid monomorphization of an intrinsic function was used.

Erroneous code example:

```compile_fail,E0511
#![feature(intrinsics)]

#[rustc_intrinsic]
unsafe fn simd_add<T>(a: T, b: T) -> T;

fn main() {
    unsafe { simd_add(0, 1); }
    // error: invalid monomorphization of `simd_add` intrinsic
}
```

The generic type has to be a SIMD type. Example:

```
#![feature(repr_simd)]
#![feature(intrinsics)]

#[repr(simd)]
#[derive(Copy, Clone)]
struct i32x2([i32; 2]);

#[rustc_intrinsic]
unsafe fn simd_add<T>(a: T, b: T) -> T;

unsafe { simd_add(i32x2([0, 0]), i32x2([1, 2])); } // ok!
```
Transmute with two differently sized types was attempted.

Erroneous code example:

```compile_fail,E0512
fn takes_u8(_: u8) {}

fn main() {
    unsafe { takes_u8(::std::mem::transmute(0u16)); }
    // error: cannot transmute between types of different sizes,
    //        or dependently-sized types
}
```

Please use types with same size or use the expected type directly. Example:

```
fn takes_u8(_: u8) {}

fn main() {
    unsafe { takes_u8(::std::mem::transmute(0i8)); } // ok!
    // or:
    unsafe { takes_u8(0u8); } // ok!
}
```
Dependency compiled with different version of `rustc`.

Example of erroneous code:

`a.rs`
```ignore (cannot-link-with-other-tests)
// compiled with stable `rustc`

#[crate_type = "lib"]
```

`b.rs`
```ignore (cannot-link-with-other-tests)
// compiled with nightly `rustc`

#[crate_type = "lib"]

extern crate a; // error: found crate `a` compiled by an incompatible version
                //        of rustc
```

This error is caused when the version of `rustc` used to compile a crate, as
stored in the binary's metadata, differs from the version of one of its
dependencies. Many parts of Rust binaries are considered unstable. For
instance, the Rust ABI is not stable between compiler versions. This means that
the compiler cannot be sure about *how* to call a function between compiler
versions, and therefore this error occurs.

This error can be fixed by:
 * Using [Cargo](../cargo/index.html), the Rust package manager and
   [Rustup](https://rust-lang.github.io/rustup/), the Rust toolchain installer,
   automatically fixing this issue.
 * Recompiling the crates with a uniform `rustc` version.
A reference to a local variable was returned.

Erroneous code example:

```compile_fail,E0515
fn get_dangling_reference() -> &'static i32 {
    let x = 0;
    &x
}
```

```compile_fail,E0515
use std::slice::Iter;
fn get_dangling_iterator<'a>() -> Iter<'a, i32> {
    let v = vec![1, 2, 3];
    v.iter()
}
```

Local variables, function parameters and temporaries are all dropped before
the end of the function body. A returned reference (or struct containing a
reference) to such a dropped value would immediately be invalid. Therefore
it is not allowed to return such a reference.

Consider returning a value that takes ownership of local data instead of
referencing it:

```
use std::vec::IntoIter;

fn get_integer() -> i32 {
    let x = 0;
    x
}

fn get_owned_iterator() -> IntoIter<i32> {
    let v = vec![1, 2, 3];
    v.into_iter()
}
```
The `typeof` keyword is currently reserved but unimplemented.

Erroneous code example:

```compile_fail,E0516
fn main() {
    let x: typeof(92) = 92;
}
```

Try using type inference instead. Example:

```
fn main() {
    let x = 92;
}
```
A `#[repr(..)]` attribute was placed on an unsupported item.

Examples of erroneous code:

```compile_fail,E0517
#[repr(C)]
type Foo = u8;

#[repr(packed)]
enum Foo {Bar, Baz}

#[repr(u8)]
struct Foo {bar: bool, baz: bool}

#[repr(C)]
impl Foo {
    // ...
}
```

* The `#[repr(C)]` attribute can only be placed on structs and enums.
* The `#[repr(packed)]` and `#[repr(simd)]` attributes only work on structs.
* The `#[repr(u8)]`, `#[repr(i16)]`, etc attributes only work on enums.

These attributes do not work on typedefs, since typedefs are just aliases.

Representations like `#[repr(u8)]`, `#[repr(i64)]` are for selecting the
discriminant size for enums. For enums with no data fields on any of the
variants, e.g. `enum Color {Red, Blue, Green}`, this effectively sets the size
of the enum to the size of the provided type. Such an enum can be cast to a
value of the same type as well. In short, `#[repr(u8)]` makes a field-less enum
behave like an integer with a constrained set of allowed values.

For a description of how `#[repr(C)]` and representations like `#[repr(u8)]`
affect the layout of enums with data fields, see [RFC 2195][rfc2195].

Only field-less enums can be cast to numerical primitives. Representations like
`#[repr(u8)]` will not apply to structs.

`#[repr(packed)]` reduces padding to make the struct size smaller. The
representation of enums isn't strictly defined in Rust, and this attribute
won't work on enums.

`#[repr(simd)]` will give a struct consisting of a homogeneous series of machine
types (i.e., `u8`, `i32`, etc) a representation that permits vectorization via
SIMD. This doesn't make much sense for enums since they don't consist of a
single list of data.

[rfc2195]: https://github.com/rust-lang/rfcs/blob/master/text/2195-really-tagged-unions.md
#### Note: this error code is no longer emitted by the compiler.

An `#[inline(..)]` attribute was incorrectly placed on something other than a
function or method.

Example of erroneous code:

```ignore (no longer emitted)
#[inline(always)]
struct Foo;

#[inline(never)]
impl Foo {
    // ...
}
```

`#[inline]` hints the compiler whether or not to attempt to inline a method or
function. By default, the compiler does a pretty good job of figuring this out
itself, but if you feel the need for annotations, `#[inline(always)]` and
`#[inline(never)]` can override or force the compiler's decision.

If you wish to apply this attribute to all methods in an impl, manually annotate
each method; it is not possible to annotate the entire impl with an `#[inline]`
attribute.
The current crate is indistinguishable from one of its dependencies, in terms
of metadata.

Example of erroneous code:

`a.rs`
```ignore (cannot-link-with-other-tests)
#![crate_name = "a"]
#![crate_type = "lib"]

pub fn foo() {}
```

`b.rs`
```ignore (cannot-link-with-other-tests)
#![crate_name = "a"]
#![crate_type = "lib"]

// error: the current crate is indistinguishable from one of its dependencies:
//        it has the same crate-name `a` and was compiled with the same
//        `-C metadata` arguments. This will result in symbol conflicts between
//        the two.
extern crate a;

pub fn foo() {}

fn bar() {
    a::foo(); // is this calling the local crate or the dependency?
}
```

The above example compiles two crates with exactly the same name and
`crate_type` (plus any other metadata). This causes an error because it becomes
impossible for the compiler to distinguish between symbols (`pub` item names).

This error can be fixed by:
 * Using [Cargo](../cargo/index.html), the Rust package manager, automatically
   fixing this issue.
 * Recompiling the crate with different metadata (different name/
   `crate_type`).
A non-default implementation was already made on this type so it cannot be
specialized further.

Erroneous code example:

```compile_fail,E0520
#![feature(specialization)]

trait SpaceLlama {
    fn fly(&self);
}

// applies to all T
impl<T> SpaceLlama for T {
    default fn fly(&self) {}
}

// non-default impl
// applies to all `Clone` T and overrides the previous impl
impl<T: Clone> SpaceLlama for T {
    fn fly(&self) {}
}

// since `i32` is clone, this conflicts with the previous implementation
impl SpaceLlama for i32 {
    default fn fly(&self) {}
    // error: item `fly` is provided by an `impl` that specializes
    //        another, but the item in the parent `impl` is not marked
    //        `default` and so it cannot be specialized.
}
```

Specialization only allows you to override `default` functions in
implementations.

To fix this error, you need to mark all the parent implementations as default.
Example:

```
#![feature(specialization)]

trait SpaceLlama {
    fn fly(&self);
}

// applies to all T
impl<T> SpaceLlama for T {
    default fn fly(&self) {} // This is a parent implementation.
}

// applies to all `Clone` T; overrides the previous impl
impl<T: Clone> SpaceLlama for T {
    default fn fly(&self) {} // This is a parent implementation but was
                             // previously not a default one, causing the error
}

// applies to i32, overrides the previous two impls
impl SpaceLlama for i32 {
    fn fly(&self) {} // And now that's ok!
}
```
Borrowed data escapes outside of closure.

Erroneous code example:

```compile_fail,E0521
let mut list: Vec<&str> = Vec::new();

let _add = |el: &str| {
    list.push(el); // error: `el` escapes the closure body here
};
```

A type annotation of a closure parameter implies a new lifetime declaration.
Consider to drop it, the compiler is reliably able to infer them.

```
let mut list: Vec<&str> = Vec::new();

let _add = |el| {
    list.push(el);
};
```

See the [Closure type inference and annotation][closure-infere-annotation] and
[Lifetime elision][lifetime-elision] sections of the Book for more details.

[closure-infere-annotation]: https://doc.rust-lang.org/book/ch13-01-closures.html#closure-type-inference-and-annotation
[lifetime-elision]: https://doc.rust-lang.org/reference/lifetime-elision.html
The lang attribute was used in an invalid context.

Erroneous code example:

```compile_fail,E0522
#![feature(lang_items)]

#[lang = "cookie"]
fn cookie() -> ! { // error: definition of an unknown lang item: `cookie`
    loop {}
}
```

The lang attribute is intended for marking special items that are built-in to
Rust itself. This includes special traits (like `Copy` and `Sized`) that affect
how the compiler behaves, as well as special functions that may be automatically
invoked (such as the handler for out-of-bounds accesses when indexing a slice).
#### Note: this error code is no longer emitted by the compiler.

The compiler found multiple library files with the requested crate name.

```compile_fail
// aux-build:crateresolve-1.rs
// aux-build:crateresolve-2.rs
// aux-build:crateresolve-3.rs

extern crate crateresolve;
//~^ ERROR multiple candidates for `rlib` dependency `crateresolve` found

fn main() {}
```

This error can occur in several different cases -- for example, when using
`extern crate` or passing `--extern` options without crate paths. It can also be
caused by caching issues with the build directory, in which case `cargo clean`
may help.

In the above example, there are three different library files, all of which
define the same crate name. Without providing a full path, there is no way for
the compiler to know which crate it should use.

*Note that E0523 has been merged into E0464.*
A variable which requires unique access is being used in more than one closure
at the same time.

Erroneous code example:

```compile_fail,E0524
fn set(x: &mut isize) {
    *x += 4;
}

fn dragoooon(x: &mut isize) {
    let mut c1 = || set(x);
    let mut c2 = || set(x); // error!

    c2();
    c1();
}
```

To solve this issue, multiple solutions are available. First, is it required
for this variable to be used in more than one closure at a time? If it is the
case, use reference counted types such as `Rc` (or `Arc` if it runs
concurrently):

```
use std::rc::Rc;
use std::cell::RefCell;

fn set(x: &mut isize) {
    *x += 4;
}

fn dragoooon(x: &mut isize) {
    let x = Rc::new(RefCell::new(x));
    let y = Rc::clone(&x);
    let mut c1 = || { let mut x2 = x.borrow_mut(); set(&mut x2); };
    let mut c2 = || { let mut x2 = y.borrow_mut(); set(&mut x2); }; // ok!

    c2();
    c1();
}
```

If not, just run closures one at a time:

```
fn set(x: &mut isize) {
    *x += 4;
}

fn dragoooon(x: &mut isize) {
    { // This block isn't necessary since non-lexical lifetimes, it's just to
      // make it more clear.
        let mut c1 = || set(&mut *x);
        c1();
    } // `c1` has been dropped here so we're free to use `x` again!
    let mut c2 = || set(&mut *x);
    c2();
}
```
A closure was used but didn't implement the expected trait.

Erroneous code example:

```compile_fail,E0525
struct X;

fn foo<T>(_: T) {}
fn bar<T: Fn(u32)>(_: T) {}

fn main() {
    let x = X;
    let closure = |_| foo(x); // error: expected a closure that implements
                              //        the `Fn` trait, but this closure only
                              //        implements `FnOnce`
    bar(closure);
}
```

In the example above, `closure` is an `FnOnce` closure whereas the `bar`
function expected an `Fn` closure. In this case, it's simple to fix the issue,
you just have to implement `Copy` and `Clone` traits on `struct X` and it'll
be ok:

```
#[derive(Clone, Copy)] // We implement `Clone` and `Copy` traits.
struct X;

fn foo<T>(_: T) {}
fn bar<T: Fn(u32)>(_: T) {}

fn main() {
    let x = X;
    let closure = |_| foo(x);
    bar(closure); // ok!
}
```

To better understand how these work in Rust, read the [Closures][closures]
chapter of the Book.

[closures]: https://doc.rust-lang.org/book/ch13-01-closures.html
The number of elements in an array or slice pattern differed from the number of
elements in the array being matched.

Example of erroneous code:

```compile_fail,E0527
let r = &[1, 2, 3, 4];
match r {
    &[a, b] => { // error: pattern requires 2 elements but array
                 //        has 4
        println!("a={}, b={}", a, b);
    }
}
```

Ensure that the pattern is consistent with the size of the matched
array. Additional elements can be matched with `..`:

```
let r = &[1, 2, 3, 4];
match r {
    &[a, b, ..] => { // ok!
        println!("a={}, b={}", a, b);
    }
}
```
An array or slice pattern required more elements than were present in the
matched array.

Example of erroneous code:

```compile_fail,E0528
let r = &[1, 2];
match r {
    &[a, b, c, rest @ ..] => { // error: pattern requires at least 3
                               //        elements but array has 2
        println!("a={}, b={}, c={} rest={:?}", a, b, c, rest);
    }
}
```

Ensure that the matched array has at least as many elements as the pattern
requires. You can match an arbitrary number of remaining elements with `..`:

```
let r = &[1, 2, 3, 4, 5];
match r {
    &[a, b, c, rest @ ..] => { // ok!
        // prints `a=1, b=2, c=3 rest=[4, 5]`
        println!("a={}, b={}, c={} rest={:?}", a, b, c, rest);
    }
}
```
An array or slice pattern was matched against some other type.

Example of erroneous code:

```compile_fail,E0529
let r: f32 = 1.0;
match r {
    [a, b] => { // error: expected an array or slice, found `f32`
        println!("a={}, b={}", a, b);
    }
}
```

Ensure that the pattern and the expression being matched on are of consistent
types:

```
let r = [1.0, 2.0];
match r {
    [a, b] => { // ok!
        println!("a={}, b={}", a, b);
    }
}
```
A binding shadowed something it shouldn't.

A match arm or a variable has a name that is already used by
something else, e.g.

* struct name
* enum variant
* static
* associated constant

This error may also happen when an enum variant *with fields* is used
in a pattern, but without its fields.

```compile_fail
enum Enum {
    WithField(i32)
}

use Enum::*;
match WithField(1) {
    WithField => {} // error: missing (_)
}
```

Match bindings cannot shadow statics:

```compile_fail,E0530
static TEST: i32 = 0;

let r = 123;
match r {
    TEST => {} // error: name of a static
}
```

Fixed examples:

```
static TEST: i32 = 0;

let r = 123;
match r {
    some_value => {} // ok!
}
```

or

```
const TEST: i32 = 0; // const, not static

let r = 123;
match r {
    TEST => {} // const is ok!
    other_values => {}
}
```
An unknown tuple struct/variant has been used.

Erroneous code example:

```compile_fail,E0531
let Type(x) = Type(12); // error!
match Bar(12) {
    Bar(x) => {} // error!
    _ => {}
}
```

In most cases, it's either a forgotten import or a typo. However, let's look at
how you can have such a type:

```edition2018
struct Type(u32); // this is a tuple struct

enum Foo {
    Bar(u32), // this is a tuple variant
}

use Foo::*; // To use Foo's variant directly, we need to import them in
            // the scope.
```

Either way, it should work fine with our previous code:

```edition2018
struct Type(u32);

enum Foo {
    Bar(u32),
}
use Foo::*;

let Type(x) = Type(12); // ok!
match Type(12) {
    Type(x) => {} // ok!
    _ => {}
}
```
Pattern arm did not match expected kind.

Erroneous code example:

```compile_fail,E0532
enum State {
    Succeeded,
    Failed(String),
}

fn print_on_failure(state: &State) {
    match *state {
        // error: expected unit struct, unit variant or constant, found tuple
        //        variant `State::Failed`
        State::Failed => println!("Failed"),
        _ => ()
    }
}
```

To fix this error, ensure the match arm kind is the same as the expression
matched.

Fixed example:

```
enum State {
    Succeeded,
    Failed(String),
}

fn print_on_failure(state: &State) {
    match *state {
        State::Failed(ref msg) => println!("Failed with {}", msg),
        _ => ()
    }
}
```
An item which isn't a unit struct, a variant, nor a constant has been used as a
match pattern.

Erroneous code example:

```compile_fail,E0533
struct Tortoise;

impl Tortoise {
    fn turtle(&self) -> u32 { 0 }
}

match 0u32 {
    Tortoise::turtle => {} // Error!
    _ => {}
}
if let Tortoise::turtle = 0u32 {} // Same error!
```

If you want to match against a value returned by a method, you need to bind the
value first:

```
struct Tortoise;

impl Tortoise {
    fn turtle(&self) -> u32 { 0 }
}

match 0u32 {
    x if x == Tortoise.turtle() => {} // Bound into `x` then we compare it!
    _ => {}
}
```
#### Note: this error code is no longer emitted by the compiler

This is because it was too specific to the `inline` attribute.
Similar diagnostics occur for other attributes too.
The example here will now emit `E0805`

The `inline` attribute was malformed.

Erroneous code example:

```compile_fail,E0805
#[inline()] // error: expected one argument
pub fn something() {}

fn main() {}
```

The parenthesized `inline` attribute requires the parameter to be specified:

```
#[inline(always)]
fn something() {}
```

or:

```
#[inline(never)]
fn something() {}
```

Alternatively, a paren-less version of the attribute may be used to hint the
compiler about inlining opportunity:

```
#[inline]
fn something() {}
```

For more information see the [`inline` attribute][inline-attribute] section
of the Reference.

[inline-attribute]: https://doc.rust-lang.org/reference/attributes/codegen.html#the-inline-attribute
#### Note: this error code is no longer emitted by the compiler

This is because it was too specific to the `inline` attribute.
Similar diagnostics occur for other attributes too.
The example here will now emit `E0539`


Erroneous code example:

```compile_fail,E0539
#[inline(unknown)] // error: invalid argument
pub fn something() {}

fn main() {}
```

The `inline` attribute only supports two arguments:

 * always
 * never

All other arguments given to the `inline` attribute will return this error.
Example:

```
#[inline(never)] // ok!
pub fn something() {}

fn main() {}
```

For more information see the [`inline` Attribute][inline-attribute] section
of the Reference.

[inline-attribute]: https://doc.rust-lang.org/reference/attributes/codegen.html#the-inline-attribute
The `not` cfg-predicate was malformed.

Erroneous code example:

```compile_fail,E0536
pub fn main() {
    if cfg!(not()) { }
}
```

The `not` predicate expects one cfg-pattern. Example:

```
pub fn main() {
    if cfg!(not(target_os = "linux")) { } // ok!
}
```

For more information about the `cfg` macro, read the section on
[Conditional Compilation][conditional-compilation] in the Reference.

[conditional-compilation]: https://doc.rust-lang.org/reference/conditional-compilation.html
An unknown predicate was used inside the `cfg` attribute.

Erroneous code example:

```compile_fail,E0537
#[cfg(unknown())] // error: invalid predicate `unknown`
pub fn something() {}

pub fn main() {}
```

The `cfg` attribute supports only three kinds of predicates:

 * any
 * all
 * not

Example:

```
#[cfg(not(target_os = "linux"))] // ok!
pub fn something() {}

pub fn main() {}
```

For more information about the `cfg` attribute, read the section on
[Conditional Compilation][conditional-compilation] in the Reference.

[conditional-compilation]: https://doc.rust-lang.org/reference/conditional-compilation.html
Attribute contains same meta item more than once.

Erroneous code example:

```compile_fail,E0538
#[deprecated(
    since="1.0.0",
    note="First deprecation note.",
    note="Second deprecation note." // error: multiple same meta item
)]
fn deprecated_function() {}
```

Meta items are the key-value pairs inside of an attribute. Each key may only be
used once in each attribute.

To fix the problem, remove all but one of the meta items with the same key.

Example:

```
#[deprecated(
    since="1.0.0",
    note="First deprecation note."
)]
fn deprecated_function() {}
```
An invalid meta-item was used inside an attribute.

Erroneous code example:

```compile_fail,E0539
#![feature(staged_api)]
#![allow(internal_features)]
#![stable(since = "1.0.0", feature = "test")]

#[deprecated(note)] // error!
#[unstable(feature = "deprecated_fn", issue = "123")]
fn deprecated() {}

#[unstable(feature = "unstable_struct", issue)] // error!
struct Unstable;

#[rustc_const_unstable(feature)] // error!
const fn unstable_fn() {}

#[stable(feature = "stable_struct", since)] // error!
struct Stable;

#[rustc_const_stable(feature)] // error!
const fn stable_fn() {}
```

To fix the above example, you can write the following:

```
#![feature(staged_api)]
#![allow(internal_features)]
#![stable(since = "1.0.0", feature = "test")]

#[deprecated(since = "1.39.0", note = "reason")] // ok!
#[unstable(feature = "deprecated_fn", issue = "123")]
fn deprecated() {}

#[unstable(feature = "unstable_struct", issue = "123")] // ok!
struct Unstable;

#[rustc_const_unstable(feature = "unstable_fn", issue = "124")] // ok!
const fn unstable_fn() {}

#[stable(feature = "stable_struct", since = "1.39.0")] // ok!
struct Stable;

#[stable(feature = "stable_fn", since = "1.39.0")]
#[rustc_const_stable(feature = "stable_fn", since = "1.39.0")] // ok!
const fn stable_fn() {}
```

Several causes of this are,
an attribute may have expected you to give a list but you gave a
`name = value` pair:

```compile_fail,E0539
// wrong, should be `#[repr(C)]`
#[repr = "C"]
struct Foo {}
```

Or a `name = value` pair, but you gave a list:

```compile_fail,E0539
// wrong, should be `note = "reason"`
#[deprecated(since = "1.0.0", note("reason"))]
struct Foo {}
```

Or it expected some specific word but you gave an unexpected one:

```compile_fail,E0539
// should be `always` or `never`
#[inline(maybe_if_you_feel_like_it)]
fn foo() {}
```
An unknown meta item was used.

Erroneous code example:

```compile_fail,E0541
#[deprecated(
    since="1.0.0",
    // error: unknown meta item
    reason="Example invalid meta item. Should be 'note'")
]
fn deprecated_function() {}
```

Meta items are the key-value pairs inside of an attribute. The keys provided
must be one of the valid keys for the specified attribute.

To fix the problem, either remove the unknown meta item, or rename it if you
provided the wrong name.

In the erroneous code example above, the wrong name was provided, so changing
to a correct one it will fix the error. Example:

```
#[deprecated(
    since="1.0.0",
    note="This is a valid meta item for the deprecated attribute."
)]
fn deprecated_function() {}
```
The `since` value is missing in a stability attribute.

Erroneous code example:

```compile_fail,E0542
#![feature(staged_api)]
#![allow(internal_features)]
#![stable(since = "1.0.0", feature = "test")]

#[stable(feature = "_stable_fn")] // invalid
fn _stable_fn() {}

#[rustc_const_stable(feature = "_stable_const_fn")] // invalid
const fn _stable_const_fn() {}

#[stable(feature = "_deprecated_fn", since = "0.1.0")]
#[deprecated(
    note = "explanation for deprecation"
)] // invalid
fn _deprecated_fn() {}
```

To fix this issue, you need to provide the `since` field. Example:

```
#![feature(staged_api)]
#![allow(internal_features)]
#![stable(since = "1.0.0", feature = "test")]

#[stable(feature = "_stable_fn", since = "1.0.0")] // ok!
fn _stable_fn() {}

#[stable(feature = "_stable_const_fn", since = "1.0.0")]
#[rustc_const_stable(feature = "_stable_const_fn", since = "1.0.0")] // ok!
const fn _stable_const_fn() {}

#[stable(feature = "_deprecated_fn", since = "0.1.0")]
#[deprecated(
    since = "1.0.0",
    note = "explanation for deprecation"
)] // ok!
fn _deprecated_fn() {}
```

See the [How Rust is Made and “Nightly Rust”][how-rust-made-nightly] appendix
of the Book and the [Stability attributes][stability-attributes] section of the
Rustc Dev Guide for more details.

[how-rust-made-nightly]: https://doc.rust-lang.org/book/appendix-07-nightly-rust.html
[stability-attributes]: https://rustc-dev-guide.rust-lang.org/stability.html
The `note` value is missing in a stability attribute.

Erroneous code example:

```compile_fail,E0543
#![feature(staged_api)]
#![allow(internal_features)]
#![stable(since = "1.0.0", feature = "test")]

#[stable(since = "0.1.0", feature = "_deprecated_fn")]
#[deprecated(
    since = "1.0.0"
)] // invalid
fn _deprecated_fn() {}
```

To fix this issue, you need to provide the `note` field. Example:

```
#![feature(staged_api)]
#![allow(internal_features)]
#![stable(since = "1.0.0", feature = "test")]

#[stable(since = "0.1.0", feature = "_deprecated_fn")]
#[deprecated(
    since = "1.0.0",
    note = "explanation for deprecation"
)] // ok!
fn _deprecated_fn() {}
```

See the [How Rust is Made and “Nightly Rust”][how-rust-made-nightly] appendix
of the Book and the [Stability attributes][stability-attributes] section of the
Rustc Dev Guide for more details.

[how-rust-made-nightly]: https://doc.rust-lang.org/book/appendix-07-nightly-rust.html
[stability-attributes]: https://rustc-dev-guide.rust-lang.org/stability.html
Multiple stability attributes were declared on the same item.

Erroneous code example:

```compile_fail,E0544
#![feature(staged_api)]
#![allow(internal_features)]
#![stable(since = "1.0.0", feature = "rust1")]

#[stable(feature = "rust1", since = "1.0.0")]
#[stable(feature = "test", since = "2.0.0")] // invalid
fn foo() {}
```

To fix this issue, ensure that each item has at most one stability attribute.

```
#![feature(staged_api)]
#![allow(internal_features)]
#![stable(since = "1.0.0", feature = "rust1")]

#[stable(feature = "test", since = "2.0.0")] // ok!
fn foo() {}
```

See the [How Rust is Made and “Nightly Rust”][how-rust-made-nightly] appendix
of the Book and the [Stability attributes][stability-attributes] section of the
Rustc Dev Guide for more details.

[how-rust-made-nightly]: https://doc.rust-lang.org/book/appendix-07-nightly-rust.html
[stability-attributes]: https://rustc-dev-guide.rust-lang.org/stability.html
The `issue` value is incorrect in a stability attribute.

Erroneous code example:

```compile_fail,E0545
#![feature(staged_api)]
#![allow(internal_features)]
#![stable(since = "1.0.0", feature = "test")]

#[unstable(feature = "_unstable_fn", issue = "0")] // invalid
fn _unstable_fn() {}

#[rustc_const_unstable(feature = "_unstable_const_fn", issue = "0")] // invalid
const fn _unstable_const_fn() {}
```

To fix this issue, you need to provide a correct value in the `issue` field.
Example:

```
#![feature(staged_api)]
#![allow(internal_features)]
#![stable(since = "1.0.0", feature = "test")]

#[unstable(feature = "_unstable_fn", issue = "none")] // ok!
fn _unstable_fn() {}

#[rustc_const_unstable(feature = "_unstable_const_fn", issue = "1")] // ok!
const fn _unstable_const_fn() {}
```

See the [How Rust is Made and “Nightly Rust”][how-rust-made-nightly] appendix
of the Book and the [Stability attributes][stability-attributes] section of the
Rustc Dev Guide for more details.

[how-rust-made-nightly]: https://doc.rust-lang.org/book/appendix-07-nightly-rust.html
[stability-attributes]: https://rustc-dev-guide.rust-lang.org/stability.html
The `feature` value is missing in a stability attribute.

Erroneous code example:

```compile_fail,E0546
#![feature(staged_api)]
#![allow(internal_features)]
#![stable(since = "1.0.0", feature = "test")]

#[unstable(issue = "none")] // invalid
fn unstable_fn() {}

#[stable(since = "1.0.0")] // invalid
fn stable_fn() {}
```

To fix this issue, you need to provide the `feature` field. Example:

```
#![feature(staged_api)]
#![allow(internal_features)]
#![stable(since = "1.0.0", feature = "test")]

#[unstable(feature = "unstable_fn", issue = "none")] // ok!
fn unstable_fn() {}

#[stable(feature = "stable_fn", since = "1.0.0")] // ok!
fn stable_fn() {}
```

See the [How Rust is Made and “Nightly Rust”][how-rust-made-nightly] appendix
of the Book and the [Stability attributes][stability-attributes] section of the
Rustc Dev Guide for more details.

[how-rust-made-nightly]: https://doc.rust-lang.org/book/appendix-07-nightly-rust.html
[stability-attributes]: https://rustc-dev-guide.rust-lang.org/stability.html
The `issue` value is missing in a stability attribute.

Erroneous code example:

```compile_fail,E0547
#![feature(staged_api)]
#![allow(internal_features)]
#![stable(since = "1.0.0", feature = "test")]

#[unstable(feature = "_unstable_fn")] // invalid
fn _unstable_fn() {}

#[rustc_const_unstable(feature = "_unstable_const_fn")] // invalid
const fn _unstable_const_fn() {}
```

To fix this issue, you need to provide the `issue` field. Example:

```
#![feature(staged_api)]
#![allow(internal_features)]
#![stable(since = "1.0.0", feature = "test")]

#[unstable(feature = "_unstable_fn", issue = "none")] // ok!
fn _unstable_fn() {}

#[rustc_const_unstable(
    feature = "_unstable_const_fn",
    issue = "none"
)] // ok!
const fn _unstable_const_fn() {}
```

See the [How Rust is Made and “Nightly Rust”][how-rust-made-nightly] appendix
of the Book and the [Stability attributes][stability-attributes] section of the
Rustc Dev Guide for more details.

[how-rust-made-nightly]: https://doc.rust-lang.org/book/appendix-07-nightly-rust.html
[stability-attributes]: https://rustc-dev-guide.rust-lang.org/stability.html
A `deprecated` attribute wasn't paired with a `stable`/`unstable` attribute with
`#![feature(staged_api)]` enabled.

Erroneous code example:

```compile_fail,E0549
#![feature(staged_api)]
#![allow(internal_features)]
#![stable(since = "1.0.0", feature = "test")]

#[deprecated(
    since = "1.0.1",
    note = "explanation for deprecation"
)] // invalid
fn _deprecated_fn() {}
```

To fix this issue, you need to add also an attribute `stable` or `unstable`.
Example:

```
#![feature(staged_api)]
#![allow(internal_features)]
#![stable(since = "1.0.0", feature = "test")]

#[stable(since = "1.0.0", feature = "test")]
#[deprecated(
    since = "1.0.1",
    note = "explanation for deprecation"
)] // ok!
fn _deprecated_fn() {}
```

See the [How Rust is Made and “Nightly Rust”][how-rust-made-nightly] appendix
of the Book and the [Stability attributes][stability-attributes] section of the
Rustc Dev Guide for more details.

[how-rust-made-nightly]: https://doc.rust-lang.org/book/appendix-07-nightly-rust.html
[stability-attributes]: https://rustc-dev-guide.rust-lang.org/stability.html
#### Note: this error code is no longer emitted by the compiler

More than one `deprecated` attribute has been put on an item.

Erroneous code example:

```compile_fail
#[deprecated(note = "because why not?")]
#[deprecated(note = "right?")] // error!
fn the_banished() {}
```

The `deprecated` attribute can only be present **once** on an item.

```
#[deprecated(note = "because why not, right?")]
fn the_banished() {} // ok!
```
#### Note: this error code is no longer emitted by the compiler

An invalid meta-item was used inside an attribute.

Erroneous code example:

```compile_fail,E0539
#[deprecated(note)] // error!
fn i_am_deprecated() {}
```

Meta items are the key-value pairs inside of an attribute. To fix this issue,
you need to give a value to the `note` key. Example:

```
#[deprecated(note = "because")] // ok!
fn i_am_deprecated() {}
```
A unrecognized representation attribute was used.

Erroneous code example:

```compile_fail,E0552
#[repr(D)] // error: unrecognized representation hint
struct MyStruct {
    my_field: usize
}
```

You can use a `repr` attribute to tell the compiler how you want a struct or
enum to be laid out in memory.

Make sure you're using one of the supported options:

```
#[repr(C)] // ok!
struct MyStruct {
    my_field: usize
}
```

For more information about specifying representations, see the ["Alternative
Representations" section] of the Rustonomicon.

["Alternative Representations" section]: https://doc.rust-lang.org/nomicon/other-reprs.html
Feature attributes are only allowed on the nightly release channel. Stable or
beta compilers will not comply.

Erroneous code example:

```ignore (depends on release channel)
#![feature(lang_items)] // error: `#![feature]` may not be used on the
                        //        stable release channel
```

If you need the feature, make sure to use a nightly release of the compiler
(but be warned that the feature may be removed or altered in the future).
The `feature` attribute was badly formed.

Erroneous code example:

```compile_fail,E0556
#![feature(foo_bar_baz, foo(bar), foo = "baz", foo)] // error!
#![feature] // error!
#![feature = "foo"] // error!
```

The `feature` attribute only accept a "feature flag" and can only be used on
nightly. Example:

```ignore (only works in nightly)
#![feature(flag)]
```
A feature attribute named a feature that has been removed.

Erroneous code example:

```compile_fail,E0557
#![feature(managed_boxes)] // error: feature has been removed
```

Delete the offending feature attribute.
An unknown field was specified into an enum's structure variant.

Erroneous code example:

```compile_fail,E0559
enum Field {
    Fool { x: u32 },
}

let s = Field::Fool { joke: 0 };
// error: struct variant `Field::Fool` has no field named `joke`
```

Verify you didn't misspell the field's name or that the field exists. Example:

```
enum Field {
    Fool { joke: u32 },
}

let s = Field::Fool { joke: 0 }; // ok!
```
An unknown field was specified into a structure.

Erroneous code example:

```compile_fail,E0560
struct Simba {
    mother: u32,
}

let s = Simba { mother: 1, father: 0 };
// error: structure `Simba` has no field named `father`
```

Verify you didn't misspell the field's name or that the field exists. Example:

```
struct Simba {
    mother: u32,
    father: u32,
}

let s = Simba { mother: 1, father: 0 }; // ok!
```
A non-ident or non-wildcard pattern has been used as a parameter of a function
pointer type.

Erroneous code example:

```compile_fail,E0561
type A1 = fn(mut param: u8); // error!
type A2 = fn(&param: u32); // error!
```

When using an alias over a function type, you cannot e.g. denote a parameter as
being mutable.

To fix the issue, remove patterns (`_` is allowed though). Example:

```
type A1 = fn(param: u8); // ok!
type A2 = fn(_: u32); // ok!
```

You can also omit the parameter name:

```
type A3 = fn(i16); // ok!
```
`impl Trait` is only allowed as a function return and argument type.

Erroneous code example:

```compile_fail,E0562
fn main() {
    let count_to_ten: impl Iterator<Item=usize> = 0..10;
    // error: `impl Trait` not allowed outside of function and inherent method
    //        return types
    for i in count_to_ten {
        println!("{}", i);
    }
}
```

Make sure `impl Trait` appears in a function signature.

```
fn count_to_n(n: usize) -> impl Iterator<Item=usize> {
    0..n
}

fn main() {
    for i in count_to_n(10) {  // ok!
        println!("{}", i);
    }
}
```

See the [reference] for more details on `impl Trait`.

[reference]: https://doc.rust-lang.org/stable/reference/types/impl-trait.html
A literal was used in a built-in attribute that doesn't support literals.

Erroneous code example:

```compile_fail,E0565
#[repr("C")] // error: meta item in `repr` must be an identifier
struct Repr {}

fn main() {}
```

Not all attributes support literals in their input,
and in some cases they expect an identifier instead.
That would be the solution in the case of `repr`:
```
#[repr(C)] // ok!
struct Repr {}

fn main() {}
```
Conflicting representation hints have been used on a same item.

Erroneous code example:

```compile_fail,E0566
#[repr(u32, u64)]
enum Repr { A }
```

In most cases (if not all), using just one representation hint is more than
enough. If you want to have a representation hint depending on the current
architecture, use `cfg_attr`. Example:

```
#[cfg_attr(linux, repr(u32))]
#[cfg_attr(not(linux), repr(u64))]
enum Repr { A }
```
Generics have been used on an auto trait.

Erroneous code example:

```compile_fail,E0567
#![feature(auto_traits)]

auto trait Generic<T> {} // error!
# fn main() {}
```

Since an auto trait is implemented on all existing types, the
compiler would not be able to infer the types of the trait's generic
parameters.

To fix this issue, just remove the generics:

```
#![feature(auto_traits)]

auto trait Generic {} // ok!
# fn main() {}
```
A super trait has been added to an auto trait.

Erroneous code example:

```compile_fail,E0568
#![feature(auto_traits)]

auto trait Bound : Copy {} // error!

fn main() {}
```

Since an auto trait is implemented on all existing types, adding a super trait
would filter out a lot of those types. In the current example, almost none of
all the existing types could implement `Bound` because very few of them have the
`Copy` trait.

To fix this issue, just remove the super trait:

```
#![feature(auto_traits)]

auto trait Bound {} // ok!

fn main() {}
```
If an impl has a generic parameter with the `#[may_dangle]` attribute, then
that impl must be declared as an `unsafe impl`.

Erroneous code example:

```compile_fail,E0569
#![feature(dropck_eyepatch)]

struct Foo<X>(X);
impl<#[may_dangle] X> Drop for Foo<X> {
    fn drop(&mut self) { }
}
```

In this example, we are asserting that the destructor for `Foo` will not
access any data of type `X`, and require this assertion to be true for
overall safety in our program. The compiler does not currently attempt to
verify this assertion; therefore we must tag this `impl` as unsafe.
The requested ABI is unsupported by the current target.

The rust compiler maintains for each target a list of unsupported ABIs on
that target. If an ABI is present in such a list this usually means that the
target / ABI combination is currently unsupported by llvm.

If necessary, you can circumvent this check using custom target specifications.
A `break` statement with an argument appeared in a non-`loop` loop.

Example of erroneous code:

```compile_fail,E0571
# let mut i = 1;
# fn satisfied(n: usize) -> bool { n % 23 == 0 }
let result = while true {
    if satisfied(i) {
        break 2 * i; // error: `break` with value from a `while` loop
    }
    i += 1;
};
```

The `break` statement can take an argument (which will be the value of the loop
expression if the `break` statement is executed) in `loop` loops, but not
`for`, `while`, or `while let` loops.

Make sure `break value;` statements only occur in `loop` loops:

```
# let mut i = 1;
# fn satisfied(n: usize) -> bool { n % 23 == 0 }
let result = loop { // This is now a "loop" loop.
    if satisfied(i) {
        break 2 * i; // ok!
    }
    i += 1;
};
```
A return statement was found outside of a function body.

Erroneous code example:

```compile_fail,E0572
const FOO: u32 = return 0; // error: return statement outside of function body

fn main() {}
```

To fix this issue, just remove the return keyword or move the expression into a
function. Example:

```
const FOO: u32 = 0;

fn some_fn() -> u32 {
    return FOO;
}

fn main() {
    some_fn();
}
```
Something other than a type has been used when one was expected.

Erroneous code examples:

```compile_fail,E0573
enum Dragon {
    Born,
}

fn oblivion() -> Dragon::Born { // error!
    Dragon::Born
}

const HOBBIT: u32 = 2;
impl HOBBIT {} // error!

enum Wizard {
    Gandalf,
    Saruman,
}

trait Isengard {
    fn wizard(_: Wizard::Saruman); // error!
}
```

In all these errors, a type was expected. For example, in the first error, if
we want to return the `Born` variant from the `Dragon` enum, we must set the
function to return the enum and not its variant:

```
enum Dragon {
    Born,
}

fn oblivion() -> Dragon { // ok!
    Dragon::Born
}
```

In the second error, you can't implement something on an item, only on types.
We would need to create a new type if we wanted to do something similar:

```
struct Hobbit(u32); // we create a new type

const HOBBIT: Hobbit = Hobbit(2);
impl Hobbit {} // ok!
```

In the third case, we tried to only expect one variant of the `Wizard` enum,
which is not possible. To make this work, we need to using pattern matching
over the `Wizard` enum:

```
enum Wizard {
    Gandalf,
    Saruman,
}

trait Isengard {
    fn wizard(w: Wizard) { // ok!
        match w {
            Wizard::Saruman => {
                // do something
            }
            _ => {} // ignore everything else
        }
    }
}
```
Something other than a struct, variant or union has been used when one was
expected.

Erroneous code example:

```compile_fail,E0574
mod mordor {}

let sauron = mordor { x: () }; // error!

enum Jak {
    Daxter { i: isize },
}

let eco = Jak::Daxter { i: 1 };
match eco {
    Jak { i } => {} // error!
}
```

In all these errors, a type was expected. For example, in the first error,
we tried to instantiate the `mordor` module, which is impossible. If you want
to instantiate a type inside a module, you can do it as follow:

```
mod mordor {
    pub struct TheRing {
        pub x: usize,
    }
}

let sauron = mordor::TheRing { x: 1 }; // ok!
```

In the second error, we tried to bind the `Jak` enum directly, which is not
possible: you can only bind one of its variants. To do so:

```
enum Jak {
    Daxter { i: isize },
}

let eco = Jak::Daxter { i: 1 };
match eco {
    Jak::Daxter { i } => {} // ok!
}
```
Something other than a type or an associated type was given.

Erroneous code example:

```compile_fail,E0575
enum Rick { Morty }

let _: <u8 as Rick>::Morty; // error!

trait Age {
    type Empire;
    fn Mythology() {}
}

impl Age for u8 {
    type Empire = u16;
}

let _: <u8 as Age>::Mythology; // error!
```

In both cases, we're declaring a variable (called `_`) and we're giving it a
type. However, `<u8 as Rick>::Morty` and `<u8 as Age>::Mythology` aren't types,
therefore the compiler throws an error.

`<u8 as Rick>::Morty` is an enum variant, you cannot use a variant as a type,
you have to use the enum directly:

```
enum Rick { Morty }

let _: Rick; // ok!
```

`<u8 as Age>::Mythology` is a trait method, which is definitely not a type.
However, the `Age` trait provides an associated type `Empire` which can be
used as a type:

```
trait Age {
    type Empire;
    fn Mythology() {}
}

impl Age for u8 {
    type Empire = u16;
}

let _: <u8 as Age>::Empire; // ok!
```
An associated item wasn't found in the given type.

Erroneous code example:

```compile_fail,E0576
trait Hello {
    type Who;

    fn hello() -> <Self as Hello>::You; // error!
}
```

In this example, we tried to use the nonexistent associated type `You` of the
`Hello` trait. To fix this error, use an existing associated type:

```
trait Hello {
    type Who;

    fn hello() -> <Self as Hello>::Who; // ok!
}
```
Something other than a module was found in visibility scope.

Erroneous code example:

```compile_fail,E0577,edition2018
pub enum Sea {}

pub (in crate::Sea) struct Shark; // error!

fn main() {}
```

`Sea` is not a module, therefore it is invalid to use it in a visibility path.
To fix this error we need to ensure `sea` is a module.

Please note that the visibility scope can only be applied on ancestors!

```edition2018
pub mod sea {
    pub (in crate::sea) struct Shark; // ok!
}

fn main() {}
```
#### Note: this error code is no longer emitted by the compiler.

A module cannot be found and therefore, the visibility cannot be determined.

Erroneous code example:

```ignore (no longer emitted)
foo!();

pub (in ::Sea) struct Shark; // error!

fn main() {}
```

Because of the call to the `foo` macro, the compiler guesses that the missing
module could be inside it and fails because the macro definition cannot be
found.

To fix this error, please be sure that the module is in scope:

```edition2018
pub mod Sea {
    pub (in crate::Sea) struct Shark;
}

fn main() {}
```
A lower range wasn't less than the upper range.

Erroneous code example:

```compile_fail,E0579

fn main() {
    match 5u32 {
        // This range is ok, albeit pointless.
        1..2 => {}
        // This range is empty, and the compiler can tell.
        5..5 => {} // error!
    }
}
```

When matching against an exclusive range, the compiler verifies that the range
is non-empty. Exclusive range patterns include the start point but not the end
point, so this is equivalent to requiring the start of the range to be less
than the end of the range.
The `main` function was incorrectly declared.

Erroneous code example:

```compile_fail,E0580
fn main(x: i32) { // error: main function has wrong type
    println!("{}", x);
}
```

The `main` function prototype should never take arguments.
Example:

```
fn main() {
    // your code
}
```

If you want to get command-line arguments, use `std::env::args`. To exit with a
specified exit code, use `std::process::exit`.
In a `fn` type, a lifetime appears only in the return type
and not in the arguments types.

Erroneous code example:

```compile_fail,E0581
fn main() {
    // Here, `'a` appears only in the return type:
    let x: for<'a> fn() -> &'a i32;
}
```

The problem here is that the lifetime isn't constrained by any of the arguments,
making it impossible to determine how long it's supposed to live.

To fix this issue, either use the lifetime in the arguments, or use the
`'static` lifetime. Example:

```
fn main() {
    // Here, `'a` appears only in the return type:
    let x: for<'a> fn(&'a i32) -> &'a i32;
    let y: fn() -> &'static i32;
}
```

Note: The examples above used to be (erroneously) accepted by the
compiler, but this was since corrected. See [issue #33685] for more
details.

[issue #33685]: https://github.com/rust-lang/rust/issues/33685
A lifetime is only present in an associated-type binding, and not in the input
types to the trait.

Erroneous code example:

```compile_fail,E0582
fn bar<F>(t: F)
    // No type can satisfy this requirement, since `'a` does not
    // appear in any of the input types (here, `i32`):
    where F: for<'a> Fn(i32) -> Option<&'a i32>
{
}

fn main() { }
```

To fix this issue, either use the lifetime in the inputs, or use
`'static`. Example:

```
fn bar<F, G>(t: F, u: G)
    where F: for<'a> Fn(&'a i32) -> Option<&'a i32>,
          G: Fn(i32) -> Option<&'static i32>,
{
}

fn main() { }
```

This error also includes the use of associated types with lifetime parameters.
```compile_fail,E0582
trait Foo {
    type Assoc<'a>;
}

struct Bar<X, F>
where
    X: Foo,
    F: for<'a> Fn(X::Assoc<'a>) -> &'a i32
{
    x: X,
    f: F
}
```
The latter scenario encounters this error because `Foo::Assoc<'a>` could be
implemented by a type that does not use the `'a` parameter, so there is no
guarantee that `X::Assoc<'a>` actually uses `'a`.

To fix this we can pass a dummy parameter:
```
# trait Foo {
#     type Assoc<'a>;
# }
struct Bar<X, F>
where
    X: Foo,
    F: for<'a> Fn(X::Assoc<'a>, /* dummy */ &'a ()) -> &'a i32
{
    x: X,
    f: F
}
```

Note: The examples above used to be (erroneously) accepted by the
compiler, but this was since corrected. See [issue #33685] for more
details.

[issue #33685]: https://github.com/rust-lang/rust/issues/33685
A file wasn't found for an out-of-line module.

Erroneous code example:

```compile_fail,E0583
mod file_that_doesnt_exist; // error: file not found for module

fn main() {}
```

Please be sure that a file corresponding to the module exists. If you
want to use a module named `file_that_doesnt_exist`, you need to have a file
named `file_that_doesnt_exist.rs` or `file_that_doesnt_exist/mod.rs` in the
same directory.
A doc comment that is not attached to anything has been encountered.

Erroneous code example:

```compile_fail,E0584
trait Island {
    fn lost();

    /// I'm lost!
}
```

A little reminder: a doc comment has to be placed before the item it's supposed
to document. So if you want to document the `Island` trait, you need to put a
doc comment before it, not inside it. Same goes for the `lost` method: the doc
comment needs to be before it:

```
/// I'm THE island!
trait Island {
    /// I'm lost!
    fn lost();
}
```
A documentation comment that doesn't document anything was found.

Erroneous code example:

```compile_fail,E0585
fn main() {
    // The following doc comment will fail:
    /// This is a useless doc comment!
}
```

Documentation comments need to be followed by items, including functions,
types, modules, etc. Examples:

```
/// I'm documenting the following struct:
struct Foo;

/// I'm documenting the following function:
fn foo() {}
```
An inclusive range was used with no end.

Erroneous code example:

```compile_fail,E0586
fn main() {
    let tmp = vec![0, 1, 2, 3, 4, 4, 3, 3, 2, 1];
    let x = &tmp[1..=]; // error: inclusive range was used with no end
}
```

An inclusive range needs an end in order to *include* it. If you just need a
start and no end, use a non-inclusive range (with `..`):

```
fn main() {
    let tmp = vec![0, 1, 2, 3, 4, 4, 3, 3, 2, 1];
    let x = &tmp[1..]; // ok!
}
```

Or put an end to your inclusive range:

```
fn main() {
    let tmp = vec![0, 1, 2, 3, 4, 4, 3, 3, 2, 1];
    let x = &tmp[1..=3]; // ok!
}
```
A type has both `packed` and `align` representation hints.

Erroneous code example:

```compile_fail,E0587
#[repr(packed, align(8))] // error!
struct Umbrella(i32);
```

You cannot use `packed` and `align` hints on a same type. If you want to pack a
type to a given size, you should provide a size to packed:

```
#[repr(packed(8))] // ok!
struct Umbrella(i32);
```
A type with `packed` representation hint has a field with `align`
representation hint.

Erroneous code example:

```compile_fail,E0588
#[repr(align(16))]
struct Aligned(i32);

#[repr(packed)] // error!
struct Packed(Aligned);
```

Just like you cannot have both `align` and `packed` representation hints on the
same type, a `packed` type cannot contain another type with the `align`
representation hint. However, you can do the opposite:

```
#[repr(packed)]
struct Packed(i32);

#[repr(align(16))] // ok!
struct Aligned(Packed);
```
The value of `N` that was specified for `repr(align(N))` was not a power
of two, or was greater than 2^29.

Erroneous code example:

```compile_fail,E0589
#[repr(align(15))] // error: invalid `repr(align)` attribute: not a power of two
enum Foo {
    Bar(u64),
}
```
`break` or `continue` keywords were used in a condition of a `while` loop
without a label.

Erroneous code code:

```compile_fail,E0590
while break {}
```

`break` or `continue` must include a label when used in the condition of a
`while` loop.

To fix this, add a label specifying which loop is being broken out of:

```
'foo: while break 'foo {}
```
Per [RFC 401][rfc401], if you have a function declaration `foo`:

```
struct S;

// For the purposes of this explanation, all of these
// different kinds of `fn` declarations are equivalent:

fn foo(x: S) { /* ... */ }
# #[cfg(for_demonstration_only)]
extern "C" {
    fn foo(x: S);
}
# #[cfg(for_demonstration_only)]
impl S {
    fn foo(self) { /* ... */ }
}
```

the type of `foo` is **not** `fn(S)`, as one might expect.
Rather, it is a unique, zero-sized marker type written here as `typeof(foo)`.
However, `typeof(foo)` can be _coerced_ to a function pointer `fn(S)`,
so you rarely notice this:

```
# struct S;
# fn foo(_: S) {}
let x: fn(S) = foo; // OK, coerces
```

The reason that this matter is that the type `fn(S)` is not specific to
any particular function: it's a function _pointer_. So calling `x()` results
in a virtual call, whereas `foo()` is statically dispatched, because the type
of `foo` tells us precisely what function is being called.

As noted above, coercions mean that most code doesn't have to be
concerned with this distinction. However, you can tell the difference
when using **transmute** to convert a fn item into a fn pointer.

This is sometimes done as part of an FFI:

```compile_fail,E0591
extern "C" fn foo(userdata: Box<i32>) {
    /* ... */
}

# fn callback(_: extern "C" fn(*mut i32)) {}
# use std::mem::transmute;
unsafe {
    let f: extern "C" fn(*mut i32) = transmute(foo);
    callback(f);
}
```

Here, transmute is being used to convert the types of the fn arguments.
This pattern is incorrect because the type of `foo` is a function **item**
(`typeof(foo)`), which is zero-sized, and the target type (`fn()`)
is a function pointer, which is not zero-sized.
This pattern should be rewritten. There are a few possible ways to do this:

- change the original fn declaration to match the expected signature,
  and do the cast in the fn body (the preferred option)
- cast the fn item of a fn pointer before calling transmute, as shown here:

    ```
    # extern "C" fn foo(_: Box<i32>) {}
    # use std::mem::transmute;
    # unsafe {
    let f: extern "C" fn(*mut i32) = transmute(foo as extern "C" fn(_));
    let f: extern "C" fn(*mut i32) = transmute(foo as usize); // works too
    # }
    ```

The same applies to transmutes to `*mut fn()`, which were observed in practice.
Note though that use of this type is generally incorrect.
The intention is typically to describe a function pointer, but just `fn()`
alone suffices for that. `*mut fn()` is a pointer to a fn pointer.
(Since these values are typically just passed to C code, however, this rarely
makes a difference in practice.)

[rfc401]: https://github.com/rust-lang/rfcs/blob/master/text/0401-coercions.md
This error occurs when you defined methods or associated functions with same
name.

Erroneous code example:

```compile_fail,E0592
struct Foo;

impl Foo {
    fn bar() {} // previous definition here
}

impl Foo {
    fn bar() {} // duplicate definition here
}
```

A similar error is E0201. The difference is whether there is one declaration
block or not. To avoid this error, you must give each `fn` a unique name.

```
struct Foo;

impl Foo {
    fn bar() {}
}

impl Foo {
    fn baz() {} // define with different name
}
```
You tried to supply an `Fn`-based type with an incorrect number of arguments
than what was expected.

Erroneous code example:

```compile_fail,E0593
fn foo<F: Fn()>(x: F) { }

fn main() {
    // [E0593] closure takes 1 argument but 0 arguments are required
    foo(|y| { });
}
```

You have to provide the same number of arguments as expected by the `Fn`-based
type. So to fix the previous example, we need to remove the `y` argument:

```
fn foo<F: Fn()>(x: F) { }

fn main() {
    foo(|| { }); // ok!
}
```
A non-mutable value was assigned a value.

Erroneous code example:

```compile_fail,E0594
struct SolarSystem {
    earth: i32,
}

let ss = SolarSystem { earth: 3 };
ss.earth = 2; // error!
```

To fix this error, declare `ss` as mutable by using the `mut` keyword:

```
struct SolarSystem {
    earth: i32,
}

let mut ss = SolarSystem { earth: 3 }; // declaring `ss` as mutable
ss.earth = 2; // ok!
```
#### Note: this error code is no longer emitted by the compiler.

Closures cannot mutate immutable captured variables.

Erroneous code example:

```compile_fail,E0594
let x = 3; // error: closure cannot assign to immutable local variable `x`
let mut c = || { x += 1 };
```

Make the variable binding mutable:

```
let mut x = 3; // ok!
let mut c = || { x += 1 };
```
This error occurs because you tried to mutably borrow a non-mutable variable.

Erroneous code example:

```compile_fail,E0596
let x = 1;
let y = &mut x; // error: cannot borrow mutably
```

In here, `x` isn't mutable, so when we try to mutably borrow it in `y`, it
fails. To fix this error, you need to make `x` mutable:

```
let mut x = 1;
let y = &mut x; // ok!
```
This error occurs because a value was dropped while it was still borrowed.

Erroneous code example:

```compile_fail,E0597
struct Foo<'a> {
    x: Option<&'a u32>,
}

let mut x = Foo { x: None };
{
    let y = 0;
    x.x = Some(&y); // error: `y` does not live long enough
}
println!("{:?}", x.x);
```

Here, `y` is dropped at the end of the inner scope, but it is borrowed by
`x` until the `println`. To fix the previous example, just remove the scope
so that `y` isn't dropped until after the println

```
struct Foo<'a> {
    x: Option<&'a u32>,
}

let mut x = Foo { x: None };

let y = 0;
x.x = Some(&y);

println!("{:?}", x.x);
```
This error occurs when a method is used on a type which doesn't implement it:

Erroneous code example:

```compile_fail,E0599
struct Mouth;

let x = Mouth;
x.chocolate(); // error: no method named `chocolate` found for type `Mouth`
               //        in the current scope
```

In this case, you need to implement the `chocolate` method to fix the error:

```
struct Mouth;

impl Mouth {
    fn chocolate(&self) { // We implement the `chocolate` method here.
        println!("Hmmm! I love chocolate!");
    }
}

let x = Mouth;
x.chocolate(); // ok!
```
An unary operator was used on a type which doesn't implement it.

Erroneous code example:

```compile_fail,E0600
enum Question {
    Yes,
    No,
}

!Question::Yes; // error: cannot apply unary operator `!` to type `Question`
```

In this case, `Question` would need to implement the `std::ops::Not` trait in
order to be able to use `!` on it. Let's implement it:

```
use std::ops::Not;

enum Question {
    Yes,
    No,
}

// We implement the `Not` trait on the enum.
impl Not for Question {
    type Output = bool;

    fn not(self) -> bool {
        match self {
            Question::Yes => false, // If the `Answer` is `Yes`, then it
                                    // returns false.
            Question::No => true, // And here we do the opposite.
        }
    }
}

assert_eq!(!Question::Yes, false);
assert_eq!(!Question::No, true);
```
No `main` function was found in a binary crate.

To fix this error, add a `main` function:

```
fn main() {
    // Your program will start here.
    println!("Hello world!");
}
```

If you don't know the basics of Rust, you can look at the
[Rust Book][rust-book] to get started.

[rust-book]: https://doc.rust-lang.org/book/
An unknown or invalid lint was used on the command line.

Erroneous code example:

```sh
rustc -D bogus rust_file.rs
```

Maybe you just misspelled the lint name or the lint doesn't exist anymore.
Either way, try to update/remove it in order to fix the error.
A private item was used outside its scope.

Erroneous code example:

```compile_fail,E0603
mod foo {
    const PRIVATE: u32 = 0x_a_bad_1dea_u32; // This const is private, so we
                                            // can't use it outside of the
                                            // `foo` module.
}

println!("const value: {}", foo::PRIVATE); // error: constant `PRIVATE`
                                                  //        is private
```

In order to fix this error, you need to make the item public by using the `pub`
keyword. Example:

```
mod foo {
    pub const PRIVATE: u32 = 0x_a_bad_1dea_u32; // We set it public by using the
                                                // `pub` keyword.
}

println!("const value: {}", foo::PRIVATE); // ok!
```
A cast to `char` was attempted on a type other than `u8`.

Erroneous code example:

```compile_fail,E0604
0u32 as char; // error: only `u8` can be cast as `char`, not `u32`
```

`char` is a Unicode Scalar Value, an integer value from 0 to 0xD7FF and
0xE000 to 0x10FFFF. (The gap is for surrogate pairs.) Only `u8` always fits in
those ranges so only `u8` may be cast to `char`.

To allow larger values, use `char::from_u32`, which checks the value is valid.

```
assert_eq!(86u8 as char, 'V'); // ok!
assert_eq!(char::from_u32(0x3B1), Some('α')); // ok!
assert_eq!(char::from_u32(0xD800), None); // not a USV.
```

For more information about casts, take a look at the Type cast section in
[The Reference Book][1].

[1]: https://doc.rust-lang.org/reference/expressions/operator-expr.html#type-cast-expressions
An invalid cast was attempted.

Erroneous code examples:

```compile_fail,E0605
let x = 0u8;
x as Vec<u8>; // error: non-primitive cast: `u8` as `std::vec::Vec<u8>`

// Another example

let v = core::ptr::null::<u8>(); // So here, `v` is a `*const u8`.
v as &u8; // error: non-primitive cast: `*const u8` as `&u8`
```

Only primitive types can be cast into each other. Examples:

```
let x = 0u8;
x as u32; // ok!

let v = core::ptr::null::<u8>();
v as *const i8; // ok!
```

For more information about casts, take a look at the Type cast section in
[The Reference Book][1].

[1]: https://doc.rust-lang.org/reference/expressions/operator-expr.html#type-cast-expressions
An incompatible cast was attempted.

Erroneous code example:

```compile_fail,E0606
let x = &0u8; // Here, `x` is a `&u8`.
let y: u32 = x as u32; // error: casting `&u8` as `u32` is invalid
```

When casting, keep in mind that only primitive types can be cast into each
other. Example:

```
let x = &0u8;
let y: u32 = *x as u32; // We dereference it first and then cast it.
```

For more information about casts, take a look at the Type cast section in
[The Reference Book][1].

[1]: https://doc.rust-lang.org/reference/expressions/operator-expr.html#type-cast-expressions
A cast between a thin and a wide pointer was attempted.

Erroneous code example:

```compile_fail,E0607
let v = core::ptr::null::<u8>();
v as *const [u8];
```

First: what are thin and wide pointers?

Thin pointers are "simple" pointers: they are purely a reference to a memory
address.

Wide pointers are pointers referencing Dynamically Sized Types (also called
DSTs). DSTs don't have a statically known size, therefore they can only exist
behind some kind of pointer that contains additional information. For example,
slices and trait objects are DSTs. In the case of slices, the additional
information the wide pointer holds is their size.

To fix this error, don't try to cast directly between thin and wide pointers.

For more information about type casts, take a look at the section of the
[The Rust Reference][1] on type cast expressions.

[1]: https://doc.rust-lang.org/reference/expressions/operator-expr.html#type-cast-expressions
An attempt to use index on a type which doesn't implement the `std::ops::Index`
trait was performed.

Erroneous code example:

```compile_fail,E0608
0u8[2]; // error: cannot index into a value of type `u8`
```

To be able to index into a type it needs to implement the `std::ops::Index`
trait. Example:

```
let v: Vec<u8> = vec![0, 1, 2, 3];

// The `Vec` type implements the `Index` trait so you can do:
println!("{}", v[2]);
```
Attempted to access a nonexistent field in a struct.

Erroneous code example:

```compile_fail,E0609
struct StructWithFields {
    x: u32,
}

let s = StructWithFields { x: 0 };
println!("{}", s.foo); // error: no field `foo` on type `StructWithFields`
```

To fix this error, check that you didn't misspell the field's name or that the
field actually exists. Example:

```
struct StructWithFields {
    x: u32,
}

let s = StructWithFields { x: 0 };
println!("{}", s.x); // ok!
```
Attempted to access a field on a primitive type.

Erroneous code example:

```compile_fail,E0610
let x: u32 = 0;
println!("{}", x.foo); // error: `{integer}` is a primitive type, therefore
                       //        doesn't have fields
```

Primitive types are the most basic types available in Rust and don't have
fields. To access data via named fields, struct types are used. Example:

```
// We declare struct called `Foo` containing two fields:
struct Foo {
    x: u32,
    y: i64,
}

// We create an instance of this struct:
let variable = Foo { x: 0, y: -12 };
// And we can now access its fields:
println!("x: {}, y: {}", variable.x, variable.y);
```

For more information about [primitives] and [structs], take a look at the Book.

[primitives]: https://doc.rust-lang.org/book/ch03-02-data-types.html
[structs]: https://doc.rust-lang.org/book/ch05-00-structs.html
Attempted to dereference a variable which cannot be dereferenced.

Erroneous code example:

```compile_fail,E0614
let y = 0u32;
*y; // error: type `u32` cannot be dereferenced
```

Only types implementing `std::ops::Deref` can be dereferenced (such as `&T`).
Example:

```
let y = 0u32;
let x = &y;
// So here, `x` is a `&u32`, so we can dereference it:
*x; // ok!
```
Attempted to access a method like a field.

Erroneous code example:

```compile_fail,E0615
struct Foo {
    x: u32,
}

impl Foo {
    fn method(&self) {}
}

let f = Foo { x: 0 };
f.method; // error: attempted to take value of method `method` on type `Foo`
```

If you want to use a method, add `()` after it:

```
# struct Foo { x: u32 }
# impl Foo { fn method(&self) {} }
# let f = Foo { x: 0 };
f.method();
```

However, if you wanted to access a field of a struct check that the field name
is spelled correctly. Example:

```
# struct Foo { x: u32 }
# impl Foo { fn method(&self) {} }
# let f = Foo { x: 0 };
println!("{}", f.x);
```
Attempted to access a private field on a struct.

Erroneous code example:

```compile_fail,E0616
mod some_module {
    pub struct Foo {
        x: u32, // So `x` is private in here.
    }

    impl Foo {
        pub fn new() -> Foo { Foo { x: 0 } }
    }
}

let f = some_module::Foo::new();
println!("{}", f.x); // error: field `x` of struct `some_module::Foo` is private
```

If you want to access this field, you have two options:

1) Set the field public:

```
mod some_module {
    pub struct Foo {
        pub x: u32, // `x` is now public.
    }

    impl Foo {
        pub fn new() -> Foo { Foo { x: 0 } }
    }
}

let f = some_module::Foo::new();
println!("{}", f.x); // ok!
```

2) Add a getter function:

```
mod some_module {
    pub struct Foo {
        x: u32, // So `x` is still private in here.
    }

    impl Foo {
        pub fn new() -> Foo { Foo { x: 0 } }

        // We create the getter function here:
        pub fn get_x(&self) -> &u32 { &self.x }
    }
}

let f = some_module::Foo::new();
println!("{}", f.get_x()); // ok!
```
Attempted to pass an invalid type of variable into a variadic function.

Erroneous code example:

```compile_fail,E0617
# use std::os::raw::{c_char, c_int};
extern "C" {
    fn printf(format: *const c_char, ...) -> c_int;
}

unsafe {
    printf("%f\n\0".as_ptr() as _, 0f32);
    // error: cannot pass an `f32` to variadic function, cast to `c_double`
}
```

Certain Rust types must be cast before passing them to a variadic function,
because of arcane ABI rules dictated by the C standard. To fix the error,
cast the value to the type specified by the error message (which you may need
to import from `std::os::raw`).

In this case, `c_double` has the same size as `f64` so we can use it directly:

```no_run
# use std::os::raw::{c_char, c_int};
# extern "C" {
#     fn printf(format: *const c_char, ...) -> c_int;
# }

unsafe {
    printf("%f\n\0".as_ptr() as _, 0f64); // ok!
}
```
Attempted to call something which isn't a function nor a method.

Erroneous code examples:

```compile_fail,E0618
enum X {
    Entry,
}

X::Entry(); // error: expected function, tuple struct or tuple variant,
            // found `X::Entry`

// Or even simpler:
let x = 0i32;
x(); // error: expected function, tuple struct or tuple variant, found `i32`
```

Only functions and methods can be called using `()`. Example:

```
// We declare a function:
fn i_am_a_function() {}

// And we call it:
i_am_a_function();
```
#### Note: this error code is no longer emitted by the compiler.

The type-checker needed to know the type of an expression, but that type had not
yet been inferred.

Erroneous code example:

```compile_fail
let mut x = vec![];
match x.pop() {
    Some(v) => {
        // Here, the type of `v` is not (yet) known, so we
        // cannot resolve this method call:
        v.to_uppercase(); // error: the type of this value must be known in
                          //        this context
    }
    None => {}
}
```

Type inference typically proceeds from the top of the function to the bottom,
figuring out types as it goes. In some cases -- notably method calls and
overloadable operators like `*` -- the type checker may not have enough
information *yet* to make progress. This can be true even if the rest of the
function provides enough context (because the type-checker hasn't looked that
far ahead yet). In this case, type annotations can be used to help it along.

To fix this error, just specify the type of the variable. Example:

```
let mut x: Vec<String> = vec![]; // We precise the type of the vec elements.
match x.pop() {
    Some(v) => {
        v.to_uppercase(); // Since rustc now knows the type of the vec elements,
                          // we can use `v`'s methods.
    }
    None => {}
}
```
A cast to an unsized type was attempted.

Erroneous code example:

```compile_fail,E0620
let x = &[1_usize, 2] as [usize]; // error: cast to unsized type: `&[usize; 2]`
                                  //        as `[usize]`
```

In Rust, some types don't have a known size at compile-time. For example, in a
slice type like `[u32]`, the number of elements is not known at compile-time and
hence the overall size cannot be computed. As a result, such types can only be
manipulated through a reference (e.g., `&T` or `&mut T`) or other pointer-type
(e.g., `Box` or `Rc`). Try casting to a reference instead:

```
let x = &[1_usize, 2] as &[usize]; // ok!
```
This error code indicates a mismatch between the lifetimes appearing in the
function signature (i.e., the parameter types and the return type) and the
data-flow found in the function body.

Erroneous code example:

```compile_fail,E0621
fn foo<'a>(x: &'a i32, y: &i32) -> &'a i32 { // error: explicit lifetime
                                             //        required in the type of
                                             //        `y`
    if x > y { x } else { y }
}
```

In the code above, the function is returning data borrowed from either `x` or
`y`, but the `'a` annotation indicates that it is returning data only from `x`.
To fix the error, the signature and the body must be made to match. Typically,
this is done by updating the function signature. So, in this case, we change
the type of `y` to `&'a i32`, like so:

```
fn foo<'a>(x: &'a i32, y: &'a i32) -> &'a i32 {
    if x > y { x } else { y }
}
```

Now the signature indicates that the function data borrowed from either `x` or
`y`. Alternatively, you could change the body to not return data from `y`:

```
fn foo<'a>(x: &'a i32, y: &i32) -> &'a i32 {
    x
}
```
#### Note: this error code is no longer emitted by the compiler.

An intrinsic was declared without being a function.

Erroneous code example:

```ignore (no longer emitted)
#![feature(intrinsics)]
#![allow(internal_features)]

extern "C" {
    #[rustc_intrinsic]
    pub static atomic_singlethreadfence_seqcst: unsafe fn();
    // error: intrinsic must be a function
}

fn main() { unsafe { atomic_singlethreadfence_seqcst(); } }
```

An intrinsic is a function available for use in a given programming language
whose implementation is handled specially by the compiler. In order to fix this
error, just declare a function. Example:

```ignore (no longer emitted)
#![feature(intrinsics)]
#![allow(internal_features)]

#[rustc_intrinsic]
pub unsafe fn atomic_singlethreadfence_seqcst(); // ok!

fn main() { unsafe { atomic_singlethreadfence_seqcst(); } }
```
A lifetime didn't match what was expected.

Erroneous code example:

```compile_fail,E0623
struct Foo<'a, 'b, T>(std::marker::PhantomData<(&'a (), &'b (), T)>)
where
    T: Convert<'a, 'b>;

trait Convert<'a, 'b>: Sized {
    fn cast(&'a self) -> &'b Self;
}
impl<'long: 'short, 'short, T> Convert<'long, 'short> for T {
    fn cast(&'long self) -> &'short T {
        self
    }
}
// error
fn badboi<'in_, 'out, T>(
    x: Foo<'in_, 'out, T>,
    sadness: &'in_ T
) -> &'out T {
    sadness.cast()
}
```

In this example, we tried to set a value with an incompatible lifetime to
another one (`'in_` is unrelated to `'out`). We can solve this issue in
two different ways:

Either we make `'in_` live at least as long as `'out`:

```
struct Foo<'a, 'b, T>(std::marker::PhantomData<(&'a (), &'b (), T)>)
where
    T: Convert<'a, 'b>;

trait Convert<'a, 'b>: Sized {
    fn cast(&'a self) -> &'b Self;
}
impl<'long: 'short, 'short, T> Convert<'long, 'short> for T {
    fn cast(&'long self) -> &'short T {
        self
    }
}
fn badboi<'in_: 'out, 'out, T>(
    x: Foo<'in_, 'out, T>,
    sadness: &'in_ T
) -> &'out T {
    sadness.cast()
}
```

Or we use only one lifetime:

```
struct Foo<'a, 'b, T>(std::marker::PhantomData<(&'a (), &'b (), T)>)
where
    T: Convert<'a, 'b>;

trait Convert<'a, 'b>: Sized {
    fn cast(&'a self) -> &'b Self;
}
impl<'long: 'short, 'short, T> Convert<'long, 'short> for T {
    fn cast(&'long self) -> &'short T {
        self
    }
}
fn badboi<'out, T>(x: Foo<'out, 'out, T>, sadness: &'out T) -> &'out T {
    sadness.cast()
}
```
A private item was used outside of its scope.

Erroneous code example:

```compile_fail,E0624
mod inner {
    pub struct Foo;

    impl Foo {
        fn method(&self) {}
    }
}

let foo = inner::Foo;
foo.method(); // error: method `method` is private
```

Two possibilities are available to solve this issue:

1. Only use the item in the scope it has been defined:

```
mod inner {
    pub struct Foo;

    impl Foo {
        fn method(&self) {}
    }

    pub fn call_method(foo: &Foo) { // We create a public function.
        foo.method(); // Which calls the item.
    }
}

let foo = inner::Foo;
inner::call_method(&foo); // And since the function is public, we can call the
                          // method through it.
```

2. Make the item public:

```
mod inner {
    pub struct Foo;

    impl Foo {
        pub fn method(&self) {} // It's now public.
    }
}

let foo = inner::Foo;
foo.method(); // Ok!
```
A compile-time const variable is referring to a thread-local static variable.

Erroneous code example:

```compile_fail,E0625
#![feature(thread_local)]

#[thread_local]
static X: usize = 12;

const Y: usize = 2 * X;
```

Static and const variables can refer to other const variables but a const
variable cannot refer to a thread-local static variable. In this example,
`Y` cannot refer to `X`. To fix this, the value can be extracted as a const
and then used:

```
#![feature(thread_local)]

const C: usize = 12;

#[thread_local]
static X: usize = C;

const Y: usize = 2 * C;
```
This error occurs because a borrow in a movable coroutine persists across a
yield point.

Erroneous code example:

```compile_fail,E0626
# #![feature(coroutines, coroutine_trait, stmt_expr_attributes)]
# use std::ops::Coroutine;
# use std::pin::Pin;
let mut b = #[coroutine] || {
    let a = &String::new(); // <-- This borrow...
    yield (); // ...is still in scope here, when the yield occurs.
    println!("{}", a);
};
Pin::new(&mut b).resume(());
```

Coroutines may be either unmarked, or marked with `static`. If it is unmarked,
then the coroutine is considered "movable". At present, it is not permitted to
have a yield in a movable coroutine that occurs while a borrow is still in
scope. To resolve this error, the coroutine may be marked `static`:

```
# #![feature(coroutines, coroutine_trait, stmt_expr_attributes)]
# use std::ops::Coroutine;
# use std::pin::Pin;
let mut b = #[coroutine] static || { // <-- note the static keyword
    let a = &String::from("hello, world");
    yield ();
    println!("{}", a);
};
let mut b = std::pin::pin!(b);
b.as_mut().resume(());
```

If the coroutine must remain movable, for example to be used as `Unpin`
without pinning it on the stack or in an allocation, we can alternatively
resolve the previous example by removing the borrow and just storing the
type by value:

```
# #![feature(coroutines, coroutine_trait, stmt_expr_attributes)]
# use std::ops::Coroutine;
# use std::pin::Pin;
let mut b = #[coroutine] || {
    let a = String::from("hello, world");
    yield ();
    println!("{}", a);
};
Pin::new(&mut b).resume(());
```

This is a very simple case, of course. In more complex cases, we may
wish to have more than one reference to the value that was borrowed --
in those cases, something like the `Rc` or `Arc` types may be useful.

This error also frequently arises with iteration:

```compile_fail,E0626
# #![feature(coroutines, coroutine_trait, stmt_expr_attributes)]
# use std::ops::Coroutine;
# use std::pin::Pin;
let mut b = #[coroutine] || {
  let v = vec![1,2,3];
  for &x in &v { // <-- borrow of `v` is still in scope...
    yield x; // ...when this yield occurs.
  }
};
Pin::new(&mut b).resume(());
```

Such cases can sometimes be resolved by iterating "by value" (or using
`into_iter()`) to avoid borrowing:

```
# #![feature(coroutines, coroutine_trait, stmt_expr_attributes)]
# use std::ops::Coroutine;
# use std::pin::Pin;
let mut b = #[coroutine] || {
  let v = vec![1,2,3];
  for x in v { // <-- Take ownership of the values instead!
    yield x; // <-- Now yield is OK.
  }
};
Pin::new(&mut b).resume(());
```

If taking ownership is not an option, using indices can work too:

```
# #![feature(coroutines, coroutine_trait, stmt_expr_attributes)]
# use std::ops::Coroutine;
# use std::pin::Pin;
let mut b = #[coroutine] || {
  let v = vec![1,2,3];
  let len = v.len(); // (*)
  for i in 0..len {
    let x = v[i]; // (*)
    yield x; // <-- Now yield is OK.
  }
};
Pin::new(&mut b).resume(());

// (*) -- Unfortunately, these temporaries are currently required.
// See <https://github.com/rust-lang/rust/issues/43122>.
```
A yield expression was used outside of the coroutine literal.

Erroneous code example:

```compile_fail,E0627
#![feature(coroutines, coroutine_trait, stmt_expr_attributes)]

fn fake_coroutine() -> &'static str {
    yield 1;
    return "foo"
}

fn main() {
    let mut coroutine = fake_coroutine;
}
```

The error occurs because keyword `yield` can only be used inside the coroutine
literal. This can be fixed by constructing the coroutine correctly.

```
#![feature(coroutines, coroutine_trait, stmt_expr_attributes)]

fn main() {
    let mut coroutine = #[coroutine] || {
        yield 1;
        return "foo"
    };
}
```
More than one parameter was used for a coroutine.

Erroneous code example:

```compile_fail,E0628
#![feature(coroutines, coroutine_trait, stmt_expr_attributes)]

fn main() {
    let coroutine = #[coroutine] |a: i32, b: i32| {
        // error: too many parameters for a coroutine
        // Allowed only 0 or 1 parameter
        yield a;
    };
}
```

At present, it is not permitted to pass more than one explicit
parameter for a coroutine.This can be fixed by using
at most 1 parameter for the coroutine. For example, we might resolve
the previous example by passing only one parameter.

```
#![feature(coroutines, coroutine_trait, stmt_expr_attributes)]

fn main() {
    let coroutine = #[coroutine] |a: i32| {
        yield a;
    };
}
```
This error indicates a type mismatch in closure arguments.

Erroneous code example:

```compile_fail,E0631
fn foo<F: Fn(i32)>(f: F) {
}

fn main() {
    foo(|x: &str| {});
}
```

The error occurs because `foo` accepts a closure that takes an `i32` argument,
but in `main`, it is passed a closure with a `&str` argument.

This can be resolved by changing the type annotation or removing it entirely
if it can be inferred.

```
fn foo<F: Fn(i32)>(f: F) {
}

fn main() {
    foo(|x: i32| {});
}
```
#### Note: this error code is no longer emitted by the compiler.

An explicit generic argument was provided when calling a function that
uses `impl Trait` in argument position.

Erroneous code example:

```ignore (no longer an error)
fn foo<T: Copy>(a: T, b: impl Clone) {}

foo::<i32>(0i32, "abc".to_string());
```

Either all generic arguments should be inferred at the call site, or
the function definition should use an explicit generic type parameter
instead of `impl Trait`. Example:

```
fn foo<T: Copy>(a: T, b: impl Clone) {}
fn bar<T: Copy, U: Clone>(a: T, b: U) {}

foo(0i32, "abc".to_string());

bar::<i32, String>(0i32, "abc".to_string());
bar::<_, _>(0i32, "abc".to_string());
bar(0i32, "abc".to_string());
```
#### Note: this error code is no longer emitted by the compiler.

The `unwind` attribute was malformed.

Erroneous code example:

```compile_fail
#![feature(unwind_attributes)]

#[unwind()] // error: expected one argument
pub extern "C" fn something() {}

fn main() {}
```

The `#[unwind]` attribute should be used as follows:

- `#[unwind(aborts)]` -- specifies that if a non-Rust ABI function
  should abort the process if it attempts to unwind. This is the safer
  and preferred option.

- `#[unwind(allowed)]` -- specifies that a non-Rust ABI function
  should be allowed to unwind. This can easily result in Undefined
  Behavior (UB), so be careful.

NB. The default behavior here is "allowed", but this is unspecified
and likely to change in the future.
A type has conflicting `packed` representation hints.

Erroneous code examples:

```compile_fail,E0634
#[repr(packed, packed(2))] // error!
struct Company(i32);

#[repr(packed(2))] // error!
#[repr(packed)]
struct Company(i32);
```

You cannot use conflicting `packed` hints on a same type. If you want to pack a
type to a given size, you should provide a size to packed:

```
#[repr(packed)] // ok!
struct Company(i32);
```
The `#![feature]` attribute specified an unknown feature.

Erroneous code example:

```compile_fail,E0635
#![feature(nonexistent_rust_feature)] // error: unknown feature
```
The same feature is enabled multiple times with `#![feature]` attributes

Erroneous code example:

```compile_fail,E0636
#![allow(stable_features)]
#![feature(rust1)]
#![feature(rust1)] // error: the feature `rust1` has already been enabled
```
`'_` lifetime name or `&T` without an explicit lifetime name has been used
in an illegal place.

Erroneous code example:

```compile_fail,E0106,E0637
fn underscore_lifetime<'_>(str1: &'_ str, str2: &'_ str) -> &'_ str {
                     //^^ `'_` is a reserved lifetime name
    if str1.len() > str2.len() {
        str1
    } else {
        str2
    }
}

fn without_explicit_lifetime<T>()
where
    T: Iterator<Item = &u32>,
                     //^ `&` without an explicit lifetime name
{
}

fn without_hrtb<T>()
where
    T: Into<&u32>,
          //^ `&` without an explicit lifetime name
{
}
```

First, `'_` cannot be used as a lifetime identifier in some places
because it is a reserved for the anonymous lifetime. Second, `&T`
without an explicit lifetime name cannot also be used in some places.
To fix them, use a lowercase letter such as `'a`, or a series
of lowercase letters such as `'foo`. For more information about lifetime
identifier, see [the book][bk-no]. For more information on using
the anonymous lifetime in Rust 2018, see [the Rust 2018 blog post][blog-al].

Corrected example:

```
fn underscore_lifetime<'a>(str1: &'a str, str2: &'a str) -> &'a str {
    if str1.len() > str2.len() {
        str1
    } else {
        str2
    }
}

fn without_explicit_lifetime<'a, T>()
where
    T: Iterator<Item = &'a u32>,
{
}

fn without_hrtb<T>()
where
    T: for<'foo> Into<&'foo u32>,
{
}
```

[bk-no]: https://doc.rust-lang.org/book/appendix-02-operators.html#non-operator-symbols
[blog-al]: https://blog.rust-lang.org/2018/12/06/Rust-1.31-and-rust-2018.html#more-lifetime-elision-rules
This error indicates that the struct, enum or enum variant must be matched
non-exhaustively as it has been marked as `non_exhaustive`.

When applied within a crate, downstream users of the crate will need to use the
`_` pattern when matching enums and use the `..` pattern when matching structs.
Downstream crates cannot match against non-exhaustive enum variants.

For example, in the below example, since the enum is marked as
`non_exhaustive`, it is required that downstream crates match non-exhaustively
on it.

```rust,ignore (pseudo-Rust)
#[non_exhaustive]
pub enum Error {
    Message(String),
    Other,
}

impl Display for Error {
    fn fmt(&self, formatter: &mut fmt::Formatter) -> fmt::Result {
        // This will not error, despite being marked as non_exhaustive, as this
        // enum is defined within the current crate, it can be matched
        // exhaustively.
        let display = match self {
            Message(s) => s,
            Other => "other or unknown error",
        };
        formatter.write_str(display)
    }
}
```

An example of matching non-exhaustively on the above enum is provided below:

```rust,ignore (pseudo-Rust)
use mycrate::Error;

// This will not error as the non_exhaustive Error enum has been matched with a
// wildcard.
match error {
    Message(s) => ...,
    Other => ...,
    _ => ...,
}
```

Similarly, for structs, match with `..` to avoid this error.
This error indicates that the struct, enum or enum variant cannot be
instantiated from outside of the defining crate as it has been marked
as `non_exhaustive` and as such more fields/variants may be added in
future that could cause adverse side effects for this code.

Erroneous code example:

```ignore (it only works cross-crate)
#[non_exhaustive]
pub struct NormalStruct {
    pub first_field: u16,
    pub second_field: u16,
}

let ns = NormalStruct { first_field: 640, second_field: 480 }; // error!
```

It is recommended that you look for a `new` function or equivalent in the
crate's documentation.
#### This error code is internal to the compiler and will not be emitted with normal Rust code.
#### Note: this error code is no longer emitted by the compiler.
Attempted to cast to/from a pointer with an unknown kind.

Erroneous code example:

```compile_fail,E0641
let b = 0 as *const _; // error
```

Type information must be provided if a pointer type being cast from/into another
type which cannot be inferred:

```
// Creating a pointer from reference: type can be inferred
let a = &(String::from("Hello world!")) as *const _; // ok!

let b = 0 as *const i32; // ok!

let c: *const i32 = 0 as *const _; // ok!
```
Trait methods currently cannot take patterns as arguments.

Erroneous code example:

```compile_fail,E0642
trait Foo {
    fn foo((x, y): (i32, i32)); // error: patterns aren't allowed
                                //        in trait methods
}
```

You can instead use a single name for the argument:

```
trait Foo {
    fn foo(x_and_y: (i32, i32)); // ok!
}
```
This error indicates that there is a mismatch between generic parameters and
impl Trait parameters in a trait declaration versus its impl.

```compile_fail,E0643
trait Foo {
    fn foo(&self, _: &impl Iterator);
}
impl Foo for () {
    fn foo<U: Iterator>(&self, _: &U) { } // error method `foo` has incompatible
                                          // signature for trait
}
```
A closure or generator was constructed that references its own type.

Erroneous code example:

```compile_fail,E0644
fn fix<F>(f: &F)
  where F: Fn(&F)
{
    f(&f);
}

fn main() {
    fix(&|y| {
        // Here, when `x` is called, the parameter `y` is equal to `x`.
    });
}
```

Rust does not permit a closure to directly reference its own type,
either through an argument (as in the example above) or by capturing
itself through its environment. This restriction helps keep closure
inference tractable.

The easiest fix is to rewrite your closure into a top-level function,
or into a method. In some cases, you may also be able to have your
closure call itself by capturing a `&Fn()` object or `fn()` pointer
that refers to itself. That is permitting, since the closure would be
invoking itself via a virtual call, and hence does not directly
reference its own *type*.
It is not possible to define `main` with a where clause.

Erroneous code example:

```compile_fail,E0646
fn main() where i32: Copy { // error: main function is not allowed to have
                            // a where clause
}
```
#### Note: this error code is no longer emitted by the compiler.

The `start` function was defined with a where clause.
An `export_name` attribute contains null characters (`\0`).

Erroneous code example:

```compile_fail,E0648
#[export_name="\0foo"] // error: `export_name` may not contain null characters
pub fn bar() {}
```

To fix this error, remove the null characters:

```
#[export_name="foo"] // ok!
pub fn bar() {}
```
An `impl Trait` captured a higher-ranked lifetime, which is not supported.

Currently, `impl Trait` types are only allowed to capture lifetimes from
their parent items, and not from any `for<'a>` binders in scope.

Erroneous code example:

```compile_fail,E0657
trait BorrowInto<'a> {
    type Target;

    fn borrow_into(&'a self) -> Self::Target;
}

impl<'a> BorrowInto<'a> for () {
    type Target = &'a ();

    fn borrow_into(&'a self) -> Self::Target {
        self
    }
}

fn opaque() -> impl for<'a> BorrowInto<'a, Target = impl Sized + 'a> {
    ()
}
```
An unstable feature was used.

Erroneous code example:

```compile_fail,E0658
use std::intrinsics; // error: use of unstable library feature `core_intrinsics`
```

If you're using a stable or a beta version of rustc, you won't be able to use
any unstable features. In order to do so, please switch to a nightly version of
rustc (by using [rustup]).

If you're using a nightly version of rustc, just add the corresponding feature
to be able to use it:

```
#![feature(core_intrinsics)]

use std::intrinsics; // ok!
```

[rustup]: https://rust-lang.github.io/rustup/concepts/channels.html
An item usage is ambiguous.

Erroneous code example:

```compile_fail,edition2018,E0659
pub mod moon {
    pub fn foo() {}
}

pub mod earth {
    pub fn foo() {}
}

mod collider {
    pub use crate::moon::*;
    pub use crate::earth::*;
}

fn main() {
    crate::collider::foo(); // ERROR: `foo` is ambiguous
}
```

This error generally appears when two items with the same name are imported into
a module. Here, the `foo` functions are imported and reexported from the
`collider` module and therefore, when we're using `collider::foo()`, both
functions collide.

To solve this error, the best solution is generally to keep the path before the
item when using it. Example:

```edition2018
pub mod moon {
    pub fn foo() {}
}

pub mod earth {
    pub fn foo() {}
}

mod collider {
    pub use crate::moon;
    pub use crate::earth;
}

fn main() {
    crate::collider::moon::foo(); // ok!
    crate::collider::earth::foo(); // ok!
}
```
#### Note: this error code is no longer emitted by the compiler.

The argument to the `llvm_asm` macro is not well-formed.

Erroneous code example:

```ignore (no longer emitted)
llvm_asm!("nop" "nop");
```
#### Note: this error code is no longer emitted by the compiler.

An invalid syntax was passed to the second argument of an `llvm_asm` macro line.

Erroneous code example:

```ignore (no longer emitted)
let a;
llvm_asm!("nop" : "r"(a));
```
#### Note: this error code is no longer emitted by the compiler.

An invalid input operand constraint was passed to the `llvm_asm` macro
(third line).

Erroneous code example:

```ignore (no longer emitted)
llvm_asm!("xor %eax, %eax"
          :
          : "=test"("a")
         );
```
#### Note: this error code is no longer emitted by the compiler.

An invalid input operand constraint was passed to the `llvm_asm` macro
(third line).

Erroneous code example:

```ignore (no longer emitted)
llvm_asm!("xor %eax, %eax"
          :
          : "+test"("a")
         );
```
#### Note: this error code is no longer emitted by the compiler.

A clobber was surrounded by braces in the `llvm_asm` macro.

Erroneous code example:

```ignore (no longer emitted)
llvm_asm!("mov $$0x200, %eax"
          :
          :
          : "{eax}"
         );
```
The `Default` trait was derived on an enum without specifying the default
variant.

Erroneous code example:

```compile_fail,E0665
#[derive(Default)]
enum Food {
    Sweet,
    Salty,
}
```

The `Default` cannot be derived on an enum for the simple reason that the
compiler doesn't know which value to pick by default whereas it can for a
struct as long as all its fields implement the `Default` trait as well.

For the case where the desired default variant has no payload, you can
annotate it with `#[default]` to derive it:

```
#[derive(Default)]
enum Food {
    #[default]
    Sweet,
    Salty,
}
```

In the case where the default variant does have a payload, you will have to
implement `Default` on your enum manually:

```
enum Food {
    Sweet(i32),
    Salty,
}

impl Default for Food {
    fn default() -> Food {
        Food::Sweet(1)
    }
}
```
`impl Trait` types cannot appear nested in the generic arguments of other
`impl Trait` types.

Erroneous code example:

```compile_fail,E0666
trait MyGenericTrait<T> {}
trait MyInnerTrait {}

fn foo(
    bar: impl MyGenericTrait<impl MyInnerTrait>, // error!
) {}
```

Type parameters for `impl Trait` types must be explicitly defined as named
generic parameters:

```
trait MyGenericTrait<T> {}
trait MyInnerTrait {}

fn foo<T: MyInnerTrait>(
    bar: impl MyGenericTrait<T>, // ok!
) {}
```
#### Note: this error code is no longer emitted by the compiler.

`impl Trait` is not allowed in path parameters.

Erroneous code example:

```ignore (removed error code)
fn some_fn(mut x: impl Iterator) -> <impl Iterator>::Item { // error!
    x.next().unwrap()
}
```

You cannot use `impl Trait` in path parameters. If you want something
equivalent, you can do this instead:

```ignore (removed error code)
fn some_fn<T: Iterator>(mut x: T) -> T::Item { // ok!
    x.next().unwrap()
}
```
#### Note: this error code is no longer emitted by the compiler.

Malformed inline assembly rejected by LLVM.

Erroneous code example:

```ignore (no longer emitted)
#![feature(llvm_asm)]

fn main() {
    let rax: u64;
    unsafe {
        llvm_asm!("" :"={rax"(rax));
        println!("Accumulator is: {}", rax);
    }
}
```

LLVM checks the validity of the constraints and the assembly string passed to
it. This error implies that LLVM seems something wrong with the inline
assembly call.

In particular, it can happen if you forgot the closing bracket of a register
constraint (see issue #51430), like in the previous code example.
#### Note: this error code is no longer emitted by the compiler.

Cannot convert inline assembly operand to a single LLVM value.

Erroneous code example:

```ignore (no longer emitted)
#![feature(llvm_asm)]

fn main() {
    unsafe {
        llvm_asm!("" :: "r"("")); // error!
    }
}
```

This error usually happens when trying to pass in a value to an input inline
assembly operand that is actually a pair of values. In particular, this can
happen when trying to pass in a slice, for instance a `&str`. In Rust, these
values are represented internally as a pair of values, the pointer and its
length. When passed as an input operand, this pair of values can not be
coerced into a register and thus we must fail with an error.
Rust 2015 does not permit the use of `async fn`.

Erroneous code example:

```compile_fail,E0670
async fn foo() {}
```

Switch to the Rust 2018 edition to use `async fn`.
#### Note: this error code is no longer emitted by the compiler.

Const parameters cannot depend on type parameters.
The following is therefore invalid:

```compile_fail,E0770
fn const_id<T, const N: T>() -> T { // error
    N
}
```
#### Note: this error code is no longer emitted by the compiler.

In-band lifetimes cannot be used in `fn`/`Fn` syntax.

Erroneous code examples:

```ignore (feature got removed)
#![feature(in_band_lifetimes)]

fn foo(x: fn(&'a u32)) {} // error!

fn bar(x: &Fn(&'a u32)) {} // error!

fn baz(x: fn(&'a u32), y: &'a u32) {} // error!

struct Foo<'a> { x: &'a u32 }

impl Foo<'a> {
    fn bar(&self, x: fn(&'a u32)) {} // error!
}
```

Lifetimes used in `fn` or `Fn` syntax must be explicitly
declared using `<...>` binders. For example:

```
fn foo<'a>(x: fn(&'a u32)) {} // ok!

fn bar<'a>(x: &Fn(&'a u32)) {} // ok!

fn baz<'a>(x: fn(&'a u32), y: &'a u32) {} // ok!

struct Foo<'a> { x: &'a u32 }

impl<'a> Foo<'a> {
    fn bar(&self, x: fn(&'a u32)) {} // ok!
}
```
#### Note: this error code is no longer emitted by the compiler.

In-band lifetimes were mixed with explicit lifetime binders.

Erroneous code example:

```ignore (feature got removed)
#![feature(in_band_lifetimes)]

fn foo<'a>(x: &'a u32, y: &'b u32) {}   // error!

struct Foo<'a> { x: &'a u32 }

impl Foo<'a> {
    fn bar<'b>(x: &'a u32, y: &'b u32, z: &'c u32) {}   // error!
}

impl<'b> Foo<'a> {  // error!
    fn baz() {}
}
```

In-band lifetimes cannot be mixed with explicit lifetime binders.
For example:

```
fn foo<'a, 'b>(x: &'a u32, y: &'b u32) {}   // ok!

struct Foo<'a> { x: &'a u32 }

impl<'a> Foo<'a> {
    fn bar<'b,'c>(x: &'a u32, y: &'b u32, z: &'c u32) {}    // ok!
}

impl<'a> Foo<'a> {  // ok!
    fn baz() {}
}
```
A method was called on an ambiguous numeric type.

Erroneous code example:

```compile_fail,E0689
2.0.neg(); // error!
```

This error indicates that the numeric value for the method being passed exists
but the type of the numeric value or binding could not be identified.

The error happens on numeric literals and on numeric bindings without an
identified concrete type:

```compile_fail,E0689
let x = 2.0;
x.neg();  // same error as above
```

Because of this, you must give the numeric literal or binding a type:

```
use std::ops::Neg;

let _ = 2.0_f32.neg(); // ok!
let x: f32 = 2.0;
let _ = x.neg(); // ok!
let _ = (2.0 as f32).neg(); // ok!
```
A struct with the representation hint `repr(transparent)` had two or more fields
that were not guaranteed to be zero-sized.

Erroneous code example:

```compile_fail,E0690
#[repr(transparent)]
struct LengthWithUnit<U> { // error: transparent struct needs at most one
    value: f32,            //        non-zero-sized field, but has 2
    unit: U,
}
```

Because transparent structs are represented exactly like one of their fields at
run time, said field must be uniquely determined. If there are multiple fields,
it is not clear how the struct should be represented.
Note that fields of zero-sized types (e.g., `PhantomData`) can also exist
alongside the field that contains the actual data, they do not count for this
error. When generic types are involved (as in the above example), an error is
reported because the type parameter could be non-zero-sized.

To combine `repr(transparent)` with type parameters, `PhantomData` may be
useful:

```
use std::marker::PhantomData;

#[repr(transparent)]
struct LengthWithUnit<U> {
    value: f32,
    unit: PhantomData<U>,
}
```
#### Note: this error code is no longer emitted by the compiler.

A struct, enum, or union with the `repr(transparent)` representation hint
contains a zero-sized field that requires non-trivial alignment.

Erroneous code example:

```ignore (error is no longer emitted)
#![feature(repr_align)]

#[repr(align(32))]
struct ForceAlign32;

#[repr(transparent)]
struct Wrapper(f32, ForceAlign32); // error: zero-sized field in transparent
                                   //        struct has alignment of 32, which
                                   //        is larger than 1
```

A transparent struct, enum, or union is supposed to be represented exactly like
the piece of data it contains. Zero-sized fields with different alignment
requirements potentially conflict with this property. In the example above,
`Wrapper` would have to be aligned to 32 bytes even though `f32` has a smaller
alignment requirement.

Consider removing the over-aligned zero-sized field:

```
#[repr(transparent)]
struct Wrapper(f32);
```

Alternatively, `PhantomData<T>` has alignment 1 for all `T`, so you can use it
if you need to keep the field for some reason:

```
#![feature(repr_align)]

use std::marker::PhantomData;

#[repr(align(32))]
struct ForceAlign32;

#[repr(transparent)]
struct Wrapper(f32, PhantomData<ForceAlign32>);
```

Note that empty arrays `[T; 0]` have the same alignment requirement as the
element type `T`. Also note that the error is conservatively reported even when
the alignment of the zero-sized type is less than or equal to the data field's
alignment.
A `repr(transparent)` type was also annotated with other, incompatible
representation hints.

Erroneous code example:

```compile_fail,E0692
#[repr(transparent, C)] // error: incompatible representation hints
struct Grams(f32);
```

A type annotated as `repr(transparent)` delegates all representation concerns to
another type, so adding more representation hints is contradictory. Remove
either the `transparent` hint or the other hints, like this:

```
#[repr(transparent)]
struct Grams(f32);
```

Alternatively, move the other attributes to the contained type:

```
#[repr(C)]
struct Foo {
    x: i32,
    // ...
}

#[repr(transparent)]
struct FooWrapper(Foo);
```

Note that introducing another `struct` just to have a place for the other
attributes may have unintended side effects on the representation:

```
#[repr(transparent)]
struct Grams(f32);

#[repr(C)]
struct Float(f32);

#[repr(transparent)]
struct Grams2(Float); // this is not equivalent to `Grams` above
```

Here, `Grams2` is a not equivalent to `Grams` -- the former transparently wraps
a (non-transparent) struct containing a single float, while `Grams` is a
transparent wrapper around a float. This can make a difference for the ABI.
`align` representation hint was incorrectly declared.

Erroneous code examples:

```compile_fail,E0693
#[repr(align=8)] // error!
struct Align8(i8);

#[repr(align="8")] // error!
struct Align8(i8);
```

This is a syntax error at the level of attribute declarations. The proper
syntax for `align` representation hint is the following:

```
#[repr(align(8))] // ok!
struct Align8(i8);
```
A `break` statement without a label appeared inside a labeled block.

Erroneous code example:

```compile_fail,E0695
loop {
    'a: {
        break;
    }
}
```

Make sure to always label the `break`:

```
'l: loop {
    'a: {
        break 'l;
    }
}
```

Or if you want to `break` the labeled block:

```
loop {
    'a: {
        break 'a;
    }
    break;
}
```
A function is using `continue` keyword incorrectly.

Erroneous code example:

```compile_fail,E0696
fn continue_simple() {
    'b: {
        continue; // error!
    }
}
fn continue_labeled() {
    'b: {
        continue 'b; // error!
    }
}
fn continue_crossing() {
    loop {
        'b: {
            continue; // error!
        }
    }
}
```

Here we have used the `continue` keyword incorrectly. As we
have seen above that `continue` pointing to a labeled block.

To fix this we have to use the labeled block properly.
For example:

```
fn continue_simple() {
    'b: loop {
        continue ; // ok!
    }
}
fn continue_labeled() {
    'b: loop {
        continue 'b; // ok!
    }
}
fn continue_crossing() {
    loop {
        'b: loop {
            continue; // ok!
        }
    }
}
```
A closure has been used as `static`.

Erroneous code example:

```compile_fail,E0697
fn main() {
    static || {}; // used as `static`
}
```

Closures cannot be used as `static`. They "save" the environment,
and as such a static closure would save only a static environment
which would consist only of variables with a static lifetime. Given
this it would be better to use a proper function. The easiest fix
is to remove the `static` keyword.
#### Note: this error code is no longer emitted by the compiler.

When using coroutines (or async) all type variables must be bound so a
coroutine can be constructed.

Erroneous code example:

```edition2018,compile_fail,E0282
async fn bar<T>() -> () {}

async fn foo() {
    bar().await; // error: cannot infer type for `T`
}
```

In the above example `T` is unknowable by the compiler.
To fix this you must bind `T` to a concrete type such as `String`
so that a coroutine can then be constructed:

```edition2018
async fn bar<T>() -> () {}

async fn foo() {
    bar::<String>().await;
    //   ^^^^^^^^ specify type explicitly
}
```
#### Note: this error code is no longer emitted by the compiler.

A method was called on a raw pointer whose inner type wasn't completely known.

Erroneous code example:

```compile_fail,edition2018
# #![deny(warnings)]
# fn main() {
let foo = &1;
let bar = foo as *const _;
if bar.is_null() {
    // ...
}
# }
```

Here, the type of `bar` isn't known; it could be a pointer to anything. Instead,
specify a type for the pointer (preferably something that makes sense for the
thing you're pointing to):

```
let foo = &1;
let bar = foo as *const i32;
if bar.is_null() {
    // ...
}
```

Even though `is_null()` exists as a method on any raw pointer, Rust shows this
error because  Rust allows for `self` to have arbitrary types (behind the
arbitrary_self_types feature flag).

This means that someone can specify such a function:

```ignore (cannot-doctest-feature-doesnt-exist-yet)
impl Foo {
    fn is_null(self: *const Self) -> bool {
        // do something else
    }
}
```

and now when you call `.is_null()` on a raw pointer to `Foo`, there's ambiguity.

Given that we don't know what type the pointer is, and there's potential
ambiguity for some types, we disallow calling methods on raw pointers when
the type is unknown.
The `impl Trait` return type captures lifetime parameters that do not
appear within the `impl Trait` itself.

Erroneous code example:

```compile_fail,E0700
use std::cell::Cell;

trait Trait<'a> { }

impl<'a, 'b> Trait<'b> for Cell<&'a u32> { }

fn foo<'x, 'y>(x: Cell<&'x u32>) -> impl Trait<'y>
where 'x: 'y
{
    x
}
```

Here, the function `foo` returns a value of type `Cell<&'x u32>`,
which references the lifetime `'x`. However, the return type is
declared as `impl Trait<'y>` -- this indicates that `foo` returns
"some type that implements `Trait<'y>`", but it also indicates that
the return type **only captures data referencing the lifetime `'y`**.
In this case, though, we are referencing data with lifetime `'x`, so
this function is in error.

To fix this, you must reference the lifetime `'x` from the return
type. For example, changing the return type to `impl Trait<'y> + 'x`
would work:

```
use std::cell::Cell;

trait Trait<'a> { }

impl<'a,'b> Trait<'b> for Cell<&'a u32> { }

fn foo<'x, 'y>(x: Cell<&'x u32>) -> impl Trait<'y> + 'x
where 'x: 'y
{
    x
}
```
#### Note: this error code is no longer emitted by the compiler.

This error indicates that a `#[non_exhaustive]` attribute was incorrectly placed
on something other than a struct or enum.

Erroneous code example:

```ignore (no longer emitted)
#[non_exhaustive]
trait Foo { }
```
Invalid ABI (Application Binary Interface) used in the code.

Erroneous code example:

```compile_fail,E0703
extern "invalid" fn foo() {} // error!
# fn main() {}
```

At present few predefined ABI's (like Rust, C, system, etc.) can be
used in Rust. Verify that the ABI is predefined. For example you can
replace the given ABI from 'Rust'.

```
extern "Rust" fn foo() {} // ok!
# fn main() { }
```
An incorrect visibility restriction was specified.

Erroneous code example:

```compile_fail,E0704
mod foo {
    pub(foo) struct Bar {
        x: i32
    }
}
```

To make struct `Bar` only visible in module `foo` the `in` keyword should be
used:

```
mod foo {
    pub(in crate::foo) struct Bar {
        x: i32
    }
}
# fn main() {}
```

For more information see the Rust Reference on [Visibility].

[Visibility]: https://doc.rust-lang.org/reference/visibility-and-privacy.html
#### Note: this error code is no longer emitted by the compiler.

A `#![feature]` attribute was used for a feature that is stable in the
current edition, but not in all editions.

Erroneous code example:

```compile_fail
#![feature(rust_2018_preview)]
#![feature(test_2018_feature)] // error: the feature
                               // `test_2018_feature` is
                               // included in the Rust 2018 edition
```
#### Note: this error code is no longer emitted by the compiler.

`async fn`s are not yet supported in traits in Rust.

Erroneous code example:

```ignore,edition2018
trait T {
    // Neither case is currently supported.
    async fn foo() {}
    async fn bar(&self) {}
}
```

`async fn`s return an `impl Future`, making the following two examples
equivalent:

```ignore,edition2018 (example-of-desugaring-equivalence)
async fn foo() -> User {
    unimplemented!()
}
// The async fn above gets desugared as follows:
fn foo(&self) -> impl Future<Output = User> + '_ {
    unimplemented!()
}
```

But when it comes to supporting this in traits, there are [a few implementation
issues][async-is-hard]. One of them is returning `impl Trait` in traits is not
supported, as it would require [Generic Associated Types] to be supported:

```edition2018,ignore (example-of-desugaring-equivalence)
impl MyDatabase {
    async fn get_user(&self) -> User {
        unimplemented!()
    }
}

impl MyDatabase {
    fn get_user(&self) -> impl Future<Output = User> + '_ {
        unimplemented!()
    }
}
```

Until these issues are resolved, you can use the [`async-trait` crate], allowing
you to use `async fn` in traits by desugaring to "boxed futures"
(`Pin<Box<dyn Future + Send + 'async>>`).

Note that using these trait methods will result in a heap allocation
per-function-call. This is not a significant cost for the vast majority of
applications, but should be considered when deciding whether to use this
functionality in the public API of a low-level function that is expected to be
called millions of times a second.

You might be interested in visiting the [async book] for further information.

[`async-trait` crate]: https://crates.io/crates/async-trait
[async-is-hard]: https://smallcultfollowing.com/babysteps/blog/2019/10/26/async-fn-in-traits-are-hard/
[Generic Associated Types]: https://github.com/rust-lang/rust/issues/44265
[async book]: https://rust-lang.github.io/async-book/07_workarounds/05_async_in_traits.html
#### Note: this error code is no longer emitted by the compiler.

`async` non-`move` closures with parameters are currently not supported.

Erroneous code example:

```edition2018
fn main() {
    let add_one = async |num: u8| {
        num + 1
    };
}
```

`async` with non-move is currently not supported with the current
version, you can use successfully by using move:

```edition2018
fn main() {
    let add_one = async move |num: u8| { // ok!
        num + 1
    };
}
```
An unknown tool name was found in a scoped lint.

Erroneous code examples:

```compile_fail,E0710
#[allow(clipp::filter_map)] // error!
fn main() {
    // business logic
}
```

```compile_fail,E0710
#[warn(clipp::filter_map)] // error!
fn main() {
    // business logic
}
```

Please verify you didn't misspell the tool's name or that you didn't
forget to import it in you project:

```
#[allow(clippy::filter_map)] // ok!
fn main() {
    // business logic
}
```

```
#[warn(clippy::filter_map)] // ok!
fn main() {
    // business logic
}
```
A borrow of a thread-local variable was made inside a function which outlived
the lifetime of the function.

Erroneous code example:

```compile_fail,E0712
#![feature(thread_local)]

#[thread_local]
static FOO: u8 = 3;

fn main() {
    let a = &FOO; // error: thread-local variable borrowed past end of function

    std::thread::spawn(move || {
        println!("{}", a);
    });
}
```
This error occurs when an attempt is made to borrow state past the end of the
lifetime of a type that implements the `Drop` trait.

Erroneous code example:

```compile_fail,E0713
pub struct S<'a> { data: &'a mut String }

impl<'a> Drop for S<'a> {
    fn drop(&mut self) { self.data.push_str("being dropped"); }
}

fn demo<'a>(s: S<'a>) -> &'a mut String { let p = &mut *s.data; p }
```

Here, `demo` tries to borrow the string data held within its
argument `s` and then return that borrow. However, `S` is
declared as implementing `Drop`.

Structs implementing the `Drop` trait have an implicit destructor that
gets called when they go out of scope. This destructor gets exclusive
access to the fields of the struct when it runs.

This means that when `s` reaches the end of `demo`, its destructor
gets exclusive access to its `&mut`-borrowed string data. allowing
another borrow of that string data (`p`), to exist across the drop of
`s` would be a violation of the principle that `&mut`-borrows have
exclusive, unaliased access to their referenced data.

This error can be fixed by changing `demo` so that the destructor does
not run while the string-data is borrowed; for example by taking `S`
by reference:

```
pub struct S<'a> { data: &'a mut String }

impl<'a> Drop for S<'a> {
    fn drop(&mut self) { self.data.push_str("being dropped"); }
}

fn demo<'a>(s: &'a mut S<'a>) -> &'a mut String { let p = &mut *(*s).data; p }
```

Note that this approach needs a reference to S with lifetime `'a`.
Nothing shorter than `'a` will suffice: a shorter lifetime would imply
that after `demo` finishes executing, something else (such as the
destructor!) could access `s.data` after the end of that shorter
lifetime, which would again violate the `&mut`-borrow's exclusive
access.
A `#[marker]` trait contained an associated item.

Erroneous code example:

```compile_fail,E0714
#![feature(marker_trait_attr)]
#![feature(associated_type_defaults)]

#[marker]
trait MarkerConst {
    const N: usize; // error!
}

fn main() {}
```

The items of marker traits cannot be overridden, so there's no need to have them
when they cannot be changed per-type anyway. If you wanted them for ergonomic
reasons, consider making an extension trait instead.
An `impl` for a `#[marker]` trait tried to override an associated item.

Erroneous code example:

```compile_fail,E0715
#![feature(marker_trait_attr)]

#[marker]
trait Marker {
    const N: usize = 0;
    fn do_something() {}
}

struct OverrideConst;
impl Marker for OverrideConst { // error!
    const N: usize = 1;
}
# fn main() {}
```

Because marker traits are allowed to have multiple implementations for the same
type, it's not allowed to override anything in those implementations, as it
would be ambiguous which override should actually be used.
A temporary value is being dropped while a borrow is still in active use.

Erroneous code example:

```compile_fail,E0716
fn foo() -> i32 { 22 }
fn bar(x: &i32) -> &i32 { x }
let p = bar(&foo());
         // ------ creates a temporary
let q = *p;
```

Here, the expression `&foo()` is borrowing the expression `foo()`. As `foo()` is
a call to a function, and not the name of a variable, this creates a
**temporary** -- that temporary stores the return value from `foo()` so that it
can be borrowed. You could imagine that `let p = bar(&foo());` is equivalent to
the following, which uses an explicit temporary variable.

Erroneous code example:

```compile_fail,E0597
# fn foo() -> i32 { 22 }
# fn bar(x: &i32) -> &i32 { x }
let p = {
  let tmp = foo(); // the temporary
  bar(&tmp) // error: `tmp` does not live long enough
}; // <-- tmp is freed as we exit this block
let q = p;
```

Whenever a temporary is created, it is automatically dropped (freed) according
to fixed rules. Ordinarily, the temporary is dropped at the end of the enclosing
statement -- in this case, after the `let p`. This is illustrated in the example
above by showing that `tmp` would be freed as we exit the block.

To fix this problem, you need to create a local variable to store the value in
rather than relying on a temporary. For example, you might change the original
program to the following:

```
fn foo() -> i32 { 22 }
fn bar(x: &i32) -> &i32 { x }
let value = foo(); // dropped at the end of the enclosing block
let p = bar(&value);
let q = *p;
```

By introducing the explicit `let value`, we allocate storage that will last
until the end of the enclosing block (when `value` goes out of scope). When we
borrow `&value`, we are borrowing a local variable that already exists, and
hence no temporary is created.

Temporaries are not always dropped at the end of the enclosing statement. In
simple cases where the `&` expression is immediately stored into a variable, the
compiler will automatically extend the lifetime of the temporary until the end
of the enclosing block. Therefore, an alternative way to fix the original
program is to write `let tmp = &foo()` and not `let tmp = foo()`:

```
fn foo() -> i32 { 22 }
fn bar(x: &i32) -> &i32 { x }
let value = &foo();
let p = bar(value);
let q = *p;
```

Here, we are still borrowing `foo()`, but as the borrow is assigned directly
into a variable, the temporary will not be dropped until the end of the
enclosing block. Similar rules apply when temporaries are stored into aggregate
structures like a tuple or struct:

```
// Here, two temporaries are created, but
// as they are stored directly into `value`,
// they are not dropped until the end of the
// enclosing block.
fn foo() -> i32 { 22 }
let value = (&foo(), &foo());
```
#### This error code is internal to the compiler and will not be emitted with normal Rust code.

Feature declared with conflicting stability requirements.

```compile_fail,E0711
// NOTE: this attribute is perma-unstable and should *never* be used outside of
//       stdlib and the compiler.
#![feature(staged_api)]

#![stable(feature = "...", since = "1.0.0")]

#[stable(feature = "foo", since = "1.0.0")]
fn foo_stable_1_0_0() {}

// error: feature `foo` is declared stable since 1.29.0
#[stable(feature = "foo", since = "1.29.0")]
fn foo_stable_1_29_0() {}

// error: feature `foo` is declared unstable
#[unstable(feature = "foo", issue = "none")]
fn foo_unstable() {}
```

In the above example, the `foo` feature is first defined to be stable since
1.0.0, but is then re-declared stable since 1.29.0. This discrepancy in
versions causes an error. Furthermore, `foo` is then re-declared as unstable,
again the conflict causes an error.

This error can be fixed by splitting the feature, this allows any
stability requirements and removes any possibility of conflict.
#### This error code is internal to the compiler and will not be emitted with normal Rust code.
A `#[lang = ".."]` attribute was placed on the wrong item type.

Erroneous code example:

```compile_fail,E0718
#![feature(lang_items)]

#[lang = "owned_box"]
static X: u32 = 42;
```
An associated type value was specified more than once.

Erroneous code example:

```compile_fail,E0719
trait FooTrait {}
trait BarTrait {}

// error: associated type `Item` in trait `Iterator` is specified twice
struct Foo<T: Iterator<Item: FooTrait, Item: BarTrait>> { f: T }
```

`Item` in trait `Iterator` cannot be specified multiple times for struct `Foo`.
To fix this, create a new trait that is a combination of the desired traits and
specify the associated type with the new trait.

Corrected example:

```
trait FooTrait {}
trait BarTrait {}
trait FooBarTrait: FooTrait + BarTrait {}

struct Foo<T: Iterator<Item: FooBarTrait>> { f: T } // ok!
```

For more information about associated types, see [the book][bk-at]. For more
information on associated type bounds, see [RFC 2289][rfc-2289].

[bk-at]: https://doc.rust-lang.org/book/ch19-03-advanced-traits.html#specifying-placeholder-types-in-trait-definitions-with-associated-types
[rfc-2289]: https://rust-lang.github.io/rfcs/2289-associated-type-bounds.html
An `impl Trait` type expands to a recursive type.

Erroneous code example:

```compile_fail,E0720
fn make_recursive_type() -> impl Sized {
    [make_recursive_type(), make_recursive_type()]
}
```

An `impl Trait` type must be expandable to a concrete type that contains no
`impl Trait` types. For example the previous example tries to create an
`impl Trait` type `T` that is equal to `[T, T]`.
#### Note: this error code is no longer emitted by the compiler

This is because it was too specific to the `optimize` attribute.
Similar diagnostics occur for other attributes too.
The example here will now emit `E0539`

The `optimize` attribute was malformed.

Erroneous code example:

```compile_fail,E0539
#![feature(optimize_attribute)]

#[optimize(something)] // error: invalid argument
pub fn something() {}
```

The `#[optimize]` attribute should be used as follows:

- `#[optimize(size)]` -- instructs the optimization pipeline to generate code
  that's smaller rather than faster

- `#[optimize(speed)]` -- instructs the optimization pipeline to generate code
  that's faster rather than smaller

For example:

```
#![feature(optimize_attribute)]

#[optimize(size)]
pub fn something() {}
```

See [RFC 2412] for more details.

[RFC 2412]: https://rust-lang.github.io/rfcs/2412-optimize-attr.html
#### Note: this error code is no longer emitted by the compiler.


`#[ffi_returns_twice]` was used on something other than a foreign function
declaration.

Erroneous code example:

```compile_fail
#![feature(ffi_returns_twice)]
#![crate_type = "lib"]

#[ffi_returns_twice] // error!
pub fn foo() {}
```

`#[ffi_returns_twice]` can only be used on foreign function declarations.
For example, we might correct the previous example by declaring
the function inside of an `extern` block.

```compile_fail
#![feature(ffi_returns_twice)]

extern "C" {
   #[ffi_returns_twice] // ok!
   pub fn foo();
}
```
A feature attribute named a feature that was disallowed in the compiler
command line flags.

Erroneous code example:

```ignore (can't specify compiler flags from doctests)
#![feature(never_type)] // error: the feature `never_type` is not in
                        // the list of allowed features
```

Delete the offending feature attribute, or add it to the list of allowed
features in the `-Z allow_features` flag.
An argument lifetime was elided in an async function.

Erroneous code example:

When a struct or a type is bound/declared with a lifetime it is important for
the Rust compiler to know, on usage, the lifespan of the type. When the
lifetime is not explicitly mentioned and the Rust Compiler cannot determine
the lifetime of your type, the following error occurs.

```compile_fail,E0726
use futures::executor::block_on;
struct Content<'a> {
    title: &'a str,
    body: &'a str,
}
async fn create(content: Content) { // error: implicit elided
                                    // lifetime not allowed here
    println!("title: {}", content.title);
    println!("body: {}", content.body);
}
let content = Content { title: "Rust", body: "is great!" };
let future = create(content);
block_on(future);
```

Specify desired lifetime of parameter `content` or indicate the anonymous
lifetime like `content: Content<'_>`. The anonymous lifetime tells the Rust
compiler that `content` is only needed until the `create` function is done with
its execution.

The `implicit elision` meaning the omission of suggested lifetime that is
`pub async fn create<'a>(content: Content<'a>) {}` is not allowed here as
lifetime of the `content` can differ from current context:

```ignore (needs futures dependency)
async fn create(content: Content<'_>) { // ok!
    println!("title: {}", content.title);
    println!("body: {}", content.body);
}
```

Know more about lifetime elision in this [chapter][lifetime-elision] and a
chapter on lifetimes can be found [here][lifetimes].

[lifetime-elision]: https://doc.rust-lang.org/book/ch10-03-lifetime-syntax.html#lifetime-elision
[lifetimes]: https://doc.rust-lang.org/rust-by-example/scope/lifetime.html
A `yield` clause was used in an `async` context.

Erroneous code example:

```compile_fail,E0727,edition2018
#![feature(coroutines, stmt_expr_attributes)]

fn main() {
    let coroutine = #[coroutine] || {
        async {
            yield;
        }
    };
}
```

Here, the `yield` keyword is used in an `async` block,
which is not yet supported.

To fix this error, you have to move `yield` out of the `async` block:

```edition2018
#![feature(coroutines, stmt_expr_attributes)]

fn main() {
    let coroutine = #[coroutine] || {
        yield;
    };
}
```
[`await`] has been used outside [`async`] function or [`async`] block.

Erroneous code example:

```edition2018,compile_fail,E0728
# use std::pin::Pin;
# use std::future::Future;
# use std::task::{Context, Poll};
#
# struct WakeOnceThenComplete(bool);
#
# fn wake_and_yield_once() -> WakeOnceThenComplete {
#     WakeOnceThenComplete(false)
# }
#
# impl Future for WakeOnceThenComplete {
#     type Output = ();
#     fn poll(mut self: Pin<&mut Self>, cx: &mut Context<'_>) -> Poll<()> {
#         if self.0 {
#             Poll::Ready(())
#         } else {
#             cx.waker().wake_by_ref();
#             self.0 = true;
#             Poll::Pending
#         }
#     }
# }
#
fn foo() {
    wake_and_yield_once().await // `await` is used outside `async` context
}
```

[`await`] is used to suspend the current computation until the given
future is ready to produce a value. So it is legal only within
an [`async`] context, like an `async` function or an `async` block.

```edition2018
# use std::pin::Pin;
# use std::future::Future;
# use std::task::{Context, Poll};
#
# struct WakeOnceThenComplete(bool);
#
# fn wake_and_yield_once() -> WakeOnceThenComplete {
#     WakeOnceThenComplete(false)
# }
#
# impl Future for WakeOnceThenComplete {
#     type Output = ();
#     fn poll(mut self: Pin<&mut Self>, cx: &mut Context<'_>) -> Poll<()> {
#         if self.0 {
#             Poll::Ready(())
#         } else {
#             cx.waker().wake_by_ref();
#             self.0 = true;
#             Poll::Pending
#         }
#     }
# }
#
async fn foo() {
    wake_and_yield_once().await // `await` is used within `async` function
}

fn bar(x: u8) -> impl Future<Output = u8> {
    async move {
        wake_and_yield_once().await; // `await` is used within `async` block
        x
    }
}
```

[`async`]: https://doc.rust-lang.org/std/keyword.async.html
[`await`]: https://doc.rust-lang.org/std/keyword.await.html
#### Note: this error code is no longer emitted by the compiler

Support for Non-Lexical Lifetimes (NLL) has been included in the Rust compiler
since 1.31, and has been enabled on the 2015 edition since 1.36. The new borrow
checker for NLL uncovered some bugs in the old borrow checker, which in some
cases allowed unsound code to compile, resulting in memory safety issues.

### What do I do?

Change your code so the warning does no longer trigger. For backwards
compatibility, this unsound code may still compile (with a warning) right now.
However, at some point in the future, the compiler will no longer accept this
code and will throw a hard error.

### Shouldn't you fix the old borrow checker?

The old borrow checker has known soundness issues that are basically impossible
to fix. The new NLL-based borrow checker is the fix.

### Can I turn these warnings into errors by denying a lint?

No.

### When are these warnings going to turn into errors?

No formal timeline for turning the warnings into errors has been set. See
[GitHub issue 58781](https://github.com/rust-lang/rust/issues/58781) for more
information.

### Why do I get this message with code that doesn't involve borrowing?

There are some known bugs that trigger this message.
An array without a fixed length was pattern-matched.

Erroneous code example:

```compile_fail,E0730
fn is_123<const N: usize>(x: [u32; N]) -> bool {
    match x {
        [1, 2, ..] => true, // error: cannot pattern-match on an
                            //        array without a fixed length
        _ => false
    }
}
```

To fix this error, you have two solutions:
 1. Use an array with a fixed length.
 2. Use a slice.

Example with an array with a fixed length:

```
fn is_123(x: [u32; 3]) -> bool { // We use an array with a fixed size
    match x {
        [1, 2, ..] => true, // ok!
        _ => false
    }
}
```

Example with a slice:

```
fn is_123(x: &[u32]) -> bool { // We use a slice
    match x {
        [1, 2, ..] => true, // ok!
        _ => false
    }
}
```
An enum with the representation hint `repr(transparent)` had zero or more than
one variants.

Erroneous code example:

```compile_fail,E0731
#[repr(transparent)]
enum Status { // error: transparent enum needs exactly one variant, but has 2
    Errno(u32),
    Ok,
}
```

Because transparent enums are represented exactly like one of their variants at
run time, said variant must be uniquely determined. If there is no variant, or
if there are multiple variants, it is not clear how the enum should be
represented.
An `enum` with a discriminant must specify a `#[repr(inttype)]`.

Erroneous code example:

```compile_fail,E0732
enum Enum { // error!
    Unit = 1,
    Tuple() = 2,
    Struct{} = 3,
}
# fn main() {}
```

A `#[repr(inttype)]` must be provided on an `enum` if it has a non-unit
variant with a discriminant, or where there are both unit variants with
discriminants and non-unit variants. This restriction ensures that there
is a well-defined way to extract a variant's discriminant from a value;
for instance:

```
#[repr(u8)]
enum Enum {
    Unit = 3,
    Tuple(u16) = 2,
    Struct {
        a: u8,
        b: u16,
    } = 1,
}

fn discriminant(v : &Enum) -> u8 {
    unsafe { *(v as *const Enum as *const u8) }
}

fn main() {
    assert_eq!(3, discriminant(&Enum::Unit));
    assert_eq!(2, discriminant(&Enum::Tuple(5)));
    assert_eq!(1, discriminant(&Enum::Struct{a: 7, b: 11}));
}
```
An [`async`] function used recursion without boxing.

Erroneous code example:

```edition2018,compile_fail,E0733
async fn foo(n: usize) {
    if n > 0 {
        foo(n - 1).await;
    }
}
```

The recursive invocation can be boxed:

```edition2018
async fn foo(n: usize) {
    if n > 0 {
        Box::pin(foo(n - 1)).await;
    }
}
```

The `Box<...>` ensures that the result is of known size, and the pin is
required to keep it in the same place in memory.

Alternatively, the body can be boxed:

```edition2018
use std::future::Future;
use std::pin::Pin;
fn foo(n: usize) -> Pin<Box<dyn Future<Output = ()>>> {
    Box::pin(async move {
        if n > 0 {
            foo(n - 1).await;
        }
    })
}
```

[`async`]: https://doc.rust-lang.org/std/keyword.async.html
A stability attribute has been used outside of the standard library.

Erroneous code example:

```compile_fail,E0734
#[stable(feature = "a", since = "b")] // invalid
#[unstable(feature = "b", issue = "none")] // invalid
fn foo(){}
```

These attributes are meant to only be used by the standard library and are
rejected in your own crates.
Type parameter defaults cannot use `Self` on structs, enums, or unions.

Erroneous code example:

```compile_fail,E0735
struct Foo<X = Box<Self>> {
    field1: Option<X>,
    field2: Option<X>,
}
// error: type parameters cannot use `Self` in their defaults.
```
Functions marked with the `#[naked]` attribute are restricted in what other
attributes they may be marked with.

Notable attributes that are incompatible with `#[naked]` are:

* `#[inline]`
* `#[track_caller]`
* `#[test]`, `#[ignore]`, `#[should_panic]`

Erroneous code example:

```compile_fail,E0736
#[inline]
#[unsafe(naked)]
fn foo() {}
```

These incompatibilities are due to the fact that naked functions deliberately
impose strict restrictions regarding the code that the compiler is
allowed to produce for this function.
`#[track_caller]` requires functions to have the `"Rust"` ABI for implicitly
receiving caller location. See [RFC 2091] for details on this and other
restrictions.

Erroneous code example:

```compile_fail,E0737
#[track_caller]
extern "C" fn foo() {}
```

[RFC 2091]: https://github.com/rust-lang/rfcs/blob/master/text/2091-inline-semantic.md
#### Note: this error code is no longer emitted by the compiler.

`#[track_caller]` must  be applied to a function

Erroneous code example:

```ignore (no longer emitted)
#[track_caller]
struct Bar {
    a: u8,
}
```

[RFC 2091]: https://github.com/rust-lang/rfcs/blob/master/text/2091-inline-semantic.md
A `union` was declared with fields with destructors.

Erroneous code example:

```compile_fail,E0740
union Test {
    a: A, // error!
}

#[derive(Debug)]
struct A(i32);

impl Drop for A {
    fn drop(&mut self) { println!("A"); }
}
```

A `union` cannot have fields with destructors.
A non-structural-match type was used as the type of a const generic parameter.

Erroneous code example:

```compile_fail,E0741
#![feature(adt_const_params)]

struct A;

struct B<const X: A>; // error!
```

Only structural-match types, which are types that derive `PartialEq` and `Eq`
and implement `ConstParamTy`, may be used as the types of const generic
parameters.

To fix the previous code example, we derive `PartialEq`, `Eq`, and
`ConstParamTy`:

```
#![feature(adt_const_params)]

use std::marker::ConstParamTy;

#[derive(PartialEq, Eq, ConstParamTy)] // We derive both traits here.
struct A;

struct B<const X: A>; // ok!
```
Visibility is restricted to a module which isn't an ancestor of the current
item.

Erroneous code example:

```compile_fail,E0742,edition2018
pub mod sea {}

pub (in crate::sea) struct Shark; // error!

fn main() {}
```

To fix this error, we need to move the `Shark` struct inside the `sea` module:

```edition2018
pub mod sea {
    pub (in crate::sea) struct Shark; // ok!
}

fn main() {}
```

Of course, you can do it as long as the module you're referring to is an
ancestor:

```edition2018
pub mod earth {
    pub mod sea {
        pub (in crate::earth) struct Shark; // ok!
    }
}

fn main() {}
```
The C-variadic type `...` has been nested inside another type.

Erroneous code example:

```compile_fail,E0743
fn foo2(x: u8, y: &...) {} // error!
```

Only foreign functions can use the C-variadic type (`...`). In such functions,
`...` may only occur non-nested. That is, `y: &'a ...` is not allowed.

A C-variadic type is used to give an undefined number of parameters to a given
function (like `printf` in C). The equivalent in Rust would be to use macros
directly (like `println!` for example).
#### Note: this error code is no longer emitted by the compiler.

An unsupported expression was used inside a const context.

Erroneous code example:

```ignore (removed error code)
const _: i32 = {
    async { 0 }.await
};
```

At the moment, `.await` is forbidden inside a `const`, `static`, or `const fn`.

This may be allowed at some point in the future, but the implementation is not
yet complete. See the tracking issue for [`async`] in `const fn`.

[`async`]: https://github.com/rust-lang/rust/issues/69431
The address of temporary value was taken.

Erroneous code example:

```compile_fail,E0745
fn temp_address() {
    let ptr = &raw const 2; // error!
}
```

In this example, `2` is destroyed right after the assignment, which means that
`ptr` now points to an unavailable location.

To avoid this error, first bind the temporary to a named local variable:

```
fn temp_address() {
    let val = 2;
    let ptr = &raw const val; // ok!
}
```
An unboxed trait object was used as a return value.

Erroneous code example:

```compile_fail,E0746
trait T {
    fn bar(&self);
}
struct S(usize);
impl T for S {
    fn bar(&self) {}
}

// Having the trait `T` as return type is invalid because
// unboxed trait objects do not have a statically known size:
fn foo() -> dyn T { // error!
    S(42)
}
```

Return types cannot be `dyn Trait`s as they must be `Sized`.

To avoid the error there are a couple of options.

If there is a single type involved, you can use [`impl Trait`]:

```
# trait T {
#     fn bar(&self);
# }
# struct S(usize);
# impl T for S {
#     fn bar(&self) {}
# }
// The compiler will select `S(usize)` as the materialized return type of this
// function, but callers will only know that the return type implements `T`.
fn foo() -> impl T { // ok!
    S(42)
}
```

If there are multiple types involved, the only way you care to interact with
them is through the trait's interface, and having to rely on dynamic dispatch
is acceptable, then you can use [trait objects] with `Box`, or other container
types like `Rc` or `Arc`:

```
# trait T {
#     fn bar(&self);
# }
# struct S(usize);
# impl T for S {
#     fn bar(&self) {}
# }
struct O(&'static str);
impl T for O {
    fn bar(&self) {}
}

// This now returns a "trait object" and callers are only be able to access
// associated items from `T`.
fn foo(x: bool) -> Box<dyn T> { // ok!
    if x {
        Box::new(S(42))
    } else {
        Box::new(O("val"))
    }
}
```

Finally, if you wish to still be able to access the original type, you can
create a new `enum` with a variant for each type:

```
# trait T {
#     fn bar(&self);
# }
# struct S(usize);
# impl T for S {
#     fn bar(&self) {}
# }
# struct O(&'static str);
# impl T for O {
#     fn bar(&self) {}
# }
enum E {
    S(S),
    O(O),
}

// The caller can access the original types directly, but it needs to match on
// the returned `enum E`.
fn foo(x: bool) -> E {
    if x {
        E::S(S(42))
    } else {
        E::O(O("val"))
    }
}
```

You can even implement the `trait` on the returned `enum` so the callers
*don't* have to match on the returned value to invoke the associated items:

```
# trait T {
#     fn bar(&self);
# }
# struct S(usize);
# impl T for S {
#     fn bar(&self) {}
# }
# struct O(&'static str);
# impl T for O {
#     fn bar(&self) {}
# }
# enum E {
#     S(S),
#     O(O),
# }
impl T for E {
    fn bar(&self) {
        match self {
            E::S(s) => s.bar(),
            E::O(o) => o.bar(),
        }
    }
}
```

If you decide to use trait objects, be aware that these rely on
[dynamic dispatch], which has performance implications, as the compiler needs
to emit code that will figure out which method to call *at runtime* instead of
during compilation. Using trait objects we are trading flexibility for
performance.

[`impl Trait`]: https://doc.rust-lang.org/book/ch10-02-traits.html#returning-types-that-implement-traits
[trait objects]: https://doc.rust-lang.org/book/ch17-02-trait-objects.html#using-trait-objects-that-allow-for-values-of-different-types
[dynamic dispatch]: https://doc.rust-lang.org/book/ch17-02-trait-objects.html#trait-objects-perform-dynamic-dispatch
Generic arguments were not provided in the same order as the corresponding
generic parameters are declared.

Erroneous code example:

```compile_fail,E0747
struct S<'a, T>(&'a T);

type X = S<(), 'static>; // error: the type argument is provided before the
                         // lifetime argument
```

The argument order should be changed to match the parameter declaration
order, as in the following:

```
struct S<'a, T>(&'a T);

type X = S<'static, ()>; // ok
```
A raw string isn't correctly terminated because the trailing `#` count doesn't
match its leading `#` count.

Erroneous code example:

```compile_fail,E0748
let dolphins = r##"Dolphins!"#; // error!
```

To terminate a raw string, you have to have the same number of `#` at the end
as at the beginning. Example:

```
let dolphins = r#"Dolphins!"#; // One `#` at the beginning, one at the end so
                               // all good!
```
An item was added on a negative impl.

Erroneous code example:

```compile_fail,E0749
# #![feature(negative_impls)]
trait MyTrait {
    type Foo;
}

impl !MyTrait for u32 {
    type Foo = i32; // error!
}
```

Negative impls are not allowed to have any items. Negative impls declare that a
trait is **not** implemented (and never will be) and hence there is no need to
specify the values for trait methods or other items.

One way to fix this is to remove the items in negative impls:

```
# #![feature(negative_impls)]
trait MyTrait {
    type Foo;
}

impl !MyTrait for u32 {}
```
A negative impl was made default impl.

Erroneous code example:

```compile_fail,E0750
# #![feature(negative_impls)]
# #![feature(specialization)]
trait MyTrait {
    type Foo;
}

default impl !MyTrait for u32 {} // error!
# fn main() {}
```

Negative impls cannot be default impls. A default impl supplies default values
for the items within to be used by other impls, whereas a negative impl declares
that there are no other impls. Combining it does not make sense.
There are both a positive and negative trait implementation for the same type.

Erroneous code example:

```compile_fail,E0751
trait MyTrait {}
impl MyTrait for i32 { }
impl !MyTrait for i32 { } // error!
```

Negative implementations are a promise that the trait will never be implemented
for the given types. Therefore, both cannot exist at the same time.
The entry point of the program was marked as `async`.

Erroneous code example:

```compile_fail,E0752
async fn main() -> Result<(), ()> { // error!
    Ok(())
}
```

`fn main()` or the specified start function is not allowed to be `async`. Not
having a correct async runtime library setup may cause this error. To fix it,
declare the entry point without `async`:

```
fn main() -> Result<(), ()> { // ok!
    Ok(())
}
```
An inner doc comment was used in an invalid context.

Erroneous code example:

```compile_fail,E0753
fn foo() {}
//! foo
// ^ error!
fn main() {}
```

Inner document can only be used before items. For example:

```
//! A working comment applied to the module!
fn foo() {
    //! Another working comment!
}
fn main() {}
```

In case you want to document the item following the doc comment, you might want
to use outer doc comment:

```
/// I am an outer doc comment
#[doc = "I am also an outer doc comment!"]
fn foo() {
    // ...
}
```
A non-ASCII identifier was used in an invalid context.

Erroneous code examples:

```compile_fail,E0754

mod řųśť; // error!

#[no_mangle]
fn řųśť() {} // error!

fn main() {}
```

Non-ASCII can be used as module names if it is inlined or if a `#[path]`
attribute is specified. For example:

```
mod řųśť { // ok!
    const IS_GREAT: bool = true;
}

fn main() {}
```
#### Note: this error code is no longer emitted by the compiler.

The `ffi_pure` attribute was used on a non-foreign function.

Erroneous code example:

```ignore (no longer emitted)
#![feature(ffi_pure)]

#[unsafe(ffi_pure)] // error!
pub fn foo() {}
# fn main() {}
```

The `ffi_pure` attribute can only be used on foreign functions which do not have
side effects or infinite loops:

```
#![feature(ffi_pure)]

extern "C" {
    #[unsafe(ffi_pure)] // ok!
    pub fn strlen(s: *const i8) -> isize;
}
# fn main() {}
```

You can find more information about it in the [unstable Rust Book].

[unstable Rust Book]: https://doc.rust-lang.org/unstable-book/language-features/ffi-pure.html
#### Note: this error code is no longer emitted by the compiler.

The `ffi_const` attribute was used on something other than a foreign function
declaration.

Erroneous code example:

```ignore (no longer emitted)
#![feature(ffi_const)]

#[unsafe(ffi_const)] // error!
pub fn foo() {}
# fn main() {}
```

The `ffi_const` attribute can only be used on foreign function declarations
which have no side effects except for their return value:

```
#![feature(ffi_const)]

extern "C" {
    #[unsafe(ffi_const)] // ok!
    pub fn strlen(s: *const i8) -> i32;
}
# fn main() {}
```

You can get more information about it in the [unstable Rust Book].

[unstable Rust Book]: https://doc.rust-lang.org/nightly/unstable-book/language-features/ffi-const.html
A function was given both the `ffi_const` and `ffi_pure` attributes.

Erroneous code example:

```compile_fail,E0757
#![feature(ffi_const, ffi_pure)]

extern "C" {
    #[unsafe(ffi_const)]
    #[unsafe(ffi_pure)]
    //~^ ERROR `#[ffi_const]` function cannot be `#[ffi_pure]`
    pub fn square(num: i32) -> i32;
}
```

As `ffi_const` provides stronger guarantees than `ffi_pure`, remove the
`ffi_pure` attribute:

```
#![feature(ffi_const)]

extern "C" {
    #[unsafe(ffi_const)]
    pub fn square(num: i32) -> i32;
}
```

You can get more information about `const` and `pure` in the [GCC documentation
on Common Function Attributes]. The unstable Rust Book has more information
about [`ffi_const`] and [`ffi_pure`].

[GCC documentation on Common Function Attributes]: https://gcc.gnu.org/onlinedocs/gcc/Common-Function-Attributes.html
[`ffi_const`]: https://doc.rust-lang.org/nightly/unstable-book/language-features/ffi-const.html
[`ffi_pure`]: https://doc.rust-lang.org/nightly/unstable-book/language-features/ffi-pure.html
A multi-line (doc-)comment is unterminated.

Erroneous code example:

```compile_fail,E0758
/* I am not terminated!
```

The same goes for doc comments:

```compile_fail,E0758
/*! I am not terminated!
```

You need to end your multi-line comment with `*/` in order to fix this error:

```
/* I am terminated! */
/*! I am also terminated! */
```
#### Note: this error code is no longer emitted by the compiler.

Return type involving a trait did not require `'static` lifetime.

Erroneous code examples:

```compile_fail
use std::fmt::Debug;

fn foo(x: &i32) -> impl Debug { // error!
    x
}

fn bar(x: &i32) -> Box<dyn Debug> { // error!
    Box::new(x)
}
```

Add `'static` requirement to fix them:

```
# use std::fmt::Debug;
fn foo(x: &'static i32) -> impl Debug + 'static { // ok!
    x
}

fn bar(x: &'static i32) -> Box<dyn Debug + 'static> { // ok!
    Box::new(x)
}
```

Both [`dyn Trait`] and [`impl Trait`] in return types have an implicit
`'static` requirement, meaning that the value implementing them that is being
returned has to be either a `'static` borrow or an owned value.

In order to change the requirement from `'static` to be a lifetime derived from
its arguments, you can add an explicit bound, either to an anonymous lifetime
`'_` or some appropriate named lifetime.

```
# use std::fmt::Debug;
fn foo(x: &i32) -> impl Debug + '_ {
    x
}
fn bar(x: &i32) -> Box<dyn Debug + '_> {
    Box::new(x)
}
```

These are equivalent to the following explicit lifetime annotations:

```
# use std::fmt::Debug;
fn foo<'a>(x: &'a i32) -> impl Debug + 'a {
    x
}
fn bar<'a>(x: &'a i32) -> Box<dyn Debug + 'a> {
    Box::new(x)
}
```

[`dyn Trait`]: https://doc.rust-lang.org/book/ch17-02-trait-objects.html#using-trait-objects-that-allow-for-values-of-different-types
[`impl Trait`]: https://doc.rust-lang.org/book/ch10-02-traits.html#returning-types-that-implement-traits
#### Note: this error code is no longer emitted by the compiler.

`async fn`/`impl trait` return type cannot contain a projection
or `Self` that references lifetimes from a parent scope.

Erroneous code example:

```ignore,edition2018
struct S<'a>(&'a i32);

impl<'a> S<'a> {
    async fn new(i: &'a i32) -> Self {
        S(&22)
    }
}
```

To fix this error we need to spell out `Self` to `S<'a>`:

```edition2018
struct S<'a>(&'a i32);

impl<'a> S<'a> {
    async fn new(i: &'a i32) -> S<'a> {
        S(&22)
    }
}
```

This will be allowed at some point in the future,
but the implementation is not yet complete.
See the [issue-61949] for this limitation.

[issue-61949]: https://github.com/rust-lang/rust/issues/61949
Multiple candidate files were found for an out-of-line module.

Erroneous code example:

```ignore (Multiple source files are required for compile_fail.)
// file: ambiguous_module/mod.rs

fn foo() {}

// file: ambiguous_module.rs

fn foo() {}

// file: lib.rs

mod ambiguous_module; // error: file for module `ambiguous_module`
                      // found at both ambiguous_module.rs and
                      // ambiguous_module/mod.rs
```

Please remove this ambiguity by deleting/renaming one of the candidate files.
A character literal wasn't ended with a quote.

Erroneous code example:

```compile_fail,E0762
static C: char = '●; // error!
```

To fix this error, add the missing quote:

```
static C: char = '●'; // ok!
```
A byte constant wasn't correctly ended.

Erroneous code example:

```compile_fail,E0763
let c = b'a; // error!
```

To fix this error, add the missing quote:

```
let c = b'a'; // ok!
```
A mutable reference was used in a constant.

Erroneous code example:

```compile_fail,E0764
fn main() {
    const OH_NO: &'static mut usize = &mut 1; // error!
}
```

Mutable references (`&mut`) can only be used in constant functions, not statics
or constants. This limitation exists to prevent the creation of constants that
have a mutable reference in their final value. If you had a constant of
`&mut i32` type, you could modify the value through that reference, making the
constant essentially mutable.

While there could be a more fine-grained scheme in the future that allows
mutable references if they are not "leaked" to the final value, a more
conservative approach was chosen for now. `const fn` do not have this problem,
as the borrow checker will prevent the `const fn` from returning new mutable
references.

Remember: you cannot use a function call inside a constant or static. However,
you can totally use it in constant functions:

```
const fn foo(x: usize) -> usize {
    let mut y = 1;
    let z = &mut y;
    *z += x;
    y
}

fn main() {
    const FOO: usize = foo(10); // ok!
}
```
A double quote string (`"`) was not terminated.

Erroneous code example:

```compile_fail,E0765
let s = "; // error!
```

To fix this error, add the missing double quote at the end of the string:

```
let s = ""; // ok!
```
A double quote byte string (`b"`) was not terminated.

Erroneous code example:

```compile_fail,E0766
let s = b"; // error!
```

To fix this error, add the missing double quote at the end of the string:

```
let s = b""; // ok!
```
An unreachable label was used.

Erroneous code example:

```compile_fail,E0767
'a: loop {
    || {
        loop { break 'a } // error: use of unreachable label `'a`
    };
}
```

Ensure that the label is within scope. Labels are not reachable through
functions, closures, async blocks or modules. Example:

```
'a: loop {
    break 'a; // ok!
}
```
A number in a non-decimal base has no digits.

Erroneous code example:

```compile_fail,E0768
let s: i32 = 0b; // error!
```

To fix this error, add the missing digits:

```
let s: i32 = 0b1; // ok!
```
A tuple struct or tuple variant was used in a pattern as if it were a struct or
struct variant.

Erroneous code example:

```compile_fail,E0769
enum E {
    A(i32),
}

let e = E::A(42);

match e {
    E::A { number } => { // error!
        println!("{}", number);
    }
}
```

To fix this error, you can use the tuple pattern:

```
# enum E {
#     A(i32),
# }
# let e = E::A(42);
match e {
    E::A(number) => { // ok!
        println!("{}", number);
    }
}
```

Alternatively, you can also use the struct pattern by using the correct field
names and binding them to new identifiers:

```
# enum E {
#     A(i32),
# }
# let e = E::A(42);
match e {
    E::A { 0: number } => { // ok!
        println!("{}", number);
    }
}
```
The type of a const parameter references other generic parameters.

Erroneous code example:

```compile_fail,E0770
fn foo<T, const N: T>() {} // error!
```

To fix this error, use a concrete type for the const parameter:

```
fn foo<T, const N: usize>() {}
```
#### Note: this error code is no longer emitted by the compiler

A non-`'static` lifetime was used in a const generic. This is currently not
allowed.

Erroneous code example:

```compile_fail,E0770
#![feature(adt_const_params, unsized_const_params)]

fn function_with_str<'a, const STRING: &'a str>() {} // error!
```

To fix this issue, the lifetime in the const generic need to be changed to
`'static`:

```
#![feature(adt_const_params, unsized_const_params)]

fn function_with_str<const STRING: &'static str>() {} // ok!
```

For more information, see [GitHub issue #74052].

[GitHub issue #74052]: https://github.com/rust-lang/rust/issues/74052
#### Note: this error code is no longer emitted by the compiler.

A trait object has some specific lifetime `'1`, but it was used in a way that
requires it to have a `'static` lifetime.

Example of erroneous code:

```compile_fail
trait BooleanLike {}
trait Person {}

impl BooleanLike for bool {}

impl dyn Person {
    fn is_cool(&self) -> bool {
        // hey you, you're pretty cool
        true
    }
}

fn get_is_cool<'p>(person: &'p dyn Person) -> impl BooleanLike {
    // error: `person` has an anonymous lifetime `'p` but calling
    //        `print_cool_fn` introduces an implicit `'static` lifetime
    //        requirement
    person.is_cool()
}
```

The trait object `person` in the function `get_is_cool`, while already being
behind a reference with lifetime `'p`, also has it's own implicit lifetime,
`'2`.

Lifetime `'2` represents the data the trait object might hold inside, for
example:

```
trait MyTrait {}

struct MyStruct<'a>(&'a i32);

impl<'a> MyTrait for MyStruct<'a> {}
```

With this scenario, if a trait object of `dyn MyTrait + '2` was made from
`MyStruct<'a>`, `'a` must live as long, if not longer than `'2`. This allows the
trait object's internal data to be accessed safely from any trait methods. This
rule also goes for any lifetime any struct made into a trait object may have.

In the implementation for `dyn Person`, the `'2` lifetime representing the
internal data was omitted, meaning that the compiler inferred the lifetime
`'static`. As a result, the implementation's `is_cool` is inferred by the
compiler to look like this:

```
# trait Person {}
#
# impl dyn Person {
fn is_cool<'a>(self: &'a (dyn Person + 'static)) -> bool {unimplemented!()}
# }
```

While the `get_is_cool` function is inferred to look like this:

```
# trait Person {}
# trait BooleanLike {}
#
fn get_is_cool<'p, R: BooleanLike>(person: &'p (dyn Person + 'p)) -> R {
    unimplemented!()
}
```

Which brings us to the core of the problem; the assignment of type
`&'_ (dyn Person + '_)` to type `&'_ (dyn Person + 'static)` is impossible.

Fixing it is as simple as being generic over lifetime `'2`, as to prevent the
compiler from inferring it as `'static`:

```
# trait Person {}
#
impl<'d> dyn Person + 'd {/* ... */}

// This works too, and is more elegant:
//impl dyn Person + '_ {/* ... */}
```

See the [Rust Reference on Trait Object Lifetime Bounds][trait-objects] for
more information on trait object lifetimes.

[trait-object-lifetime-bounds]: https://doc.rust-lang.org/reference/types/trait-object.html#trait-object-lifetime-bounds
#### this error code is no longer emitted by the compiler.

This was triggered when multiple macro definitions used the same
`#[rustc_builtin_macro(..)]`. This is no longer an error.
`derive` was applied on something which is not a struct, a union or an enum.

Erroneous code example:

```compile_fail,E0774
trait Foo {
    #[derive(Clone)] // error!
    type Bar;
}
```

As said above, the `derive` attribute is only allowed on structs, unions or
enums:

```
#[derive(Clone)] // ok!
struct Bar {
    field: u32,
}
```

You can find more information about `derive` in the [Rust Book].

[Rust Book]: https://doc.rust-lang.org/book/appendix-03-derivable-traits.html
#### Note: this error code is no longer emitted by the compiler.

`#[cmse_nonsecure_entry]` is only valid for targets with the TrustZone-M
extension.

Erroneous code example:

```ignore (no longer emitted)
#![feature(cmse_nonsecure_entry)]

pub extern "cmse-nonsecure-entry" fn entry_function() {}
```

To fix this error, compile your code for a Rust target that supports the
TrustZone-M extension. The current possible targets are:
* `thumbv8m.main-none-eabi`
* `thumbv8m.main-none-eabihf`
* `thumbv8m.base-none-eabi`
#### Note: this error code is no longer emitted by the compiler.

`#[cmse_nonsecure_entry]` functions require a C ABI

Erroneous code example:

```ignore (no longer emitted)
#![feature(cmse_nonsecure_entry)]

#[no_mangle]
#[cmse_nonsecure_entry]
pub fn entry_function(input: Vec<u32>) {}
```

To fix this error, declare your entry function with a C ABI, using `extern "C"`.
A literal value was used inside `#[derive]`.

Erroneous code example:

```compile_fail,E0777
#[derive("Clone")] // error!
struct Foo;
```

Only paths to traits are allowed as argument inside `#[derive]`. You can find
more information about the `#[derive]` attribute in the [Rust Book].


```
#[derive(Clone)] // ok!
struct Foo;
```

[Rust Book]: https://doc.rust-lang.org/book/appendix-03-derivable-traits.html
The `instruction_set` attribute was malformed.

Erroneous code example:

```compile_fail,E0778
#![feature(isa_attribute)]

#[instruction_set()] // error: expected one argument
pub fn something() {}
fn main() {}
```

The parenthesized `instruction_set` attribute requires the parameter to be
specified:

```
#![feature(isa_attribute)]

#[cfg_attr(target_arch="arm", instruction_set(arm::a32))]
fn something() {}
```

or:

```
#![feature(isa_attribute)]

#[cfg_attr(target_arch="arm", instruction_set(arm::t32))]
fn something() {}
```

For more information see the [`instruction_set` attribute][isa-attribute]
section of the Reference.

[isa-attribute]: https://doc.rust-lang.org/reference/attributes/codegen.html
An unknown argument was given to the `instruction_set` attribute.

Erroneous code example:

```compile_fail,E0779
#![feature(isa_attribute)]

#[instruction_set(intel::x64)] // error: invalid argument
pub fn something() {}
fn main() {}
```

The `instruction_set` attribute only supports two arguments currently:

 * arm::a32
 * arm::t32

All other arguments given to the `instruction_set` attribute will return this
error. Example:

```
#![feature(isa_attribute)]

#[cfg_attr(target_arch="arm", instruction_set(arm::a32))] // ok!
pub fn something() {}
fn main() {}
```

For more information see the [`instruction_set` attribute][isa-attribute]
section of the Reference.

[isa-attribute]: https://doc.rust-lang.org/reference/attributes/codegen.html
Cannot use `doc(inline)` with anonymous imports

Erroneous code example:

```ignore (cannot-doctest-multicrate-project)

#[doc(inline)] // error: invalid doc argument
pub use foo::Foo as _;
```

Anonymous imports are always rendered with `#[doc(no_inline)]`. To fix this
error, remove the `#[doc(inline)]` attribute.

Example:

```ignore (cannot-doctest-multicrate-project)

pub use foo::Foo as _;
```
The `cmse-nonsecure-call` ABI can only be used with function pointers.

Erroneous code example:

```compile_fail,E0781
#![feature(abi_cmse_nonsecure_call)]

pub extern "cmse-nonsecure-call" fn test() {}
```

The `cmse-nonsecure-call` ABI should be used by casting function pointers to
specific addresses.
Trait objects must include the `dyn` keyword.

Erroneous code example:

```edition2021,compile_fail,E0782
trait Foo {}
fn test(arg: Box<Foo>) {} // error!
```

Trait objects are a way to call methods on types that are not known until
runtime but conform to some trait.

Trait objects should be formed with `Box<dyn Foo>`, but in the code above
`dyn` is left off.

This makes it harder to see that `arg` is a trait object and not a
simply a heap allocated type called `Foo`.

To fix this issue, add `dyn` before the trait name.

```edition2021
trait Foo {}
fn test(arg: Box<dyn Foo>) {} // ok!
```

This used to be allowed before edition 2021, but is now an error.
The range pattern `...` is no longer allowed.

Erroneous code example:

```edition2021,compile_fail,E0783
match 2u8 {
    0...9 => println!("Got a number less than 10"), // error!
    _ => println!("Got a number 10 or more"),
}
```

Older Rust code using previous editions allowed `...` to stand for inclusive
ranges which are now signified using `..=`.

To make this code compile replace the `...` with `..=`.

```edition2021
match 2u8 {
    0..=9 => println!("Got a number less than 10"), // ok!
    _ => println!("Got a number 10 or more"),
}
```
A union expression does not have exactly one field.

Erroneous code example:

```compile_fail,E0784
union Bird {
    pigeon: u8,
    turtledove: u16,
}

let bird = Bird {}; // error
let bird = Bird { pigeon: 0, turtledove: 1 }; // error
```

The key property of unions is that all fields of a union share common storage.
As a result, writes to one field of a union can overwrite its other fields, and
size of a union is determined by the size of its largest field.

You can find more information about the union types in the [Rust reference].

Working example:

```
union Bird {
    pigeon: u8,
    turtledove: u16,
}

let bird = Bird { pigeon: 0 }; // OK
```

[Rust reference]: https://doc.rust-lang.org/reference/items/unions.html
An inherent `impl` was written on a dyn auto trait.

Erroneous code example:

```compile_fail,E0785
#![feature(auto_traits)]

auto trait AutoTrait {}

impl dyn AutoTrait {}
```

Dyn objects allow any number of auto traits, plus at most one non-auto trait.
The non-auto trait becomes the "principal trait".

When checking if an impl on a dyn trait is coherent, the principal trait is
normally the only one considered. Since the erroneous code has no principal
trait, it cannot be implemented at all.

Working example:

```
#![feature(auto_traits)]

trait PrincipalTrait {}

auto trait AutoTrait {}

impl dyn PrincipalTrait + AutoTrait + Send {}
```
A metadata file was invalid.

Erroneous code example:

```ignore (needs extern files)
use ::foo; // error: found invalid metadata files for crate `foo`
```

When loading crates, each crate must have a valid metadata file.
Invalid files could be caused by filesystem corruption,
an IO error while reading the file, or (rarely) a bug in the compiler itself.

Consider deleting the file and recreating it,
or reporting a bug against the compiler.
An unsupported naked function definition.

Erroneous code example:

```compile_fail,E0787
#[unsafe(naked)]
pub extern "C" fn f() -> u32 {
    42
}
```

The naked function must be defined using a single `naked_asm!` assembly block.

The execution must never fall through past the end of the assembly
code, so it must either return or diverge. The asm block can also
use `att_syntax` and `raw` options, but others options are not allowed.

The asm block must not contain any operands other than `const` and
`sym`.

### Additional information

For more information, please see [RFC 2972].

[RFC 2972]: https://github.com/rust-lang/rfcs/blob/master/text/2972-constrained-naked.md
#### Note: this error code is no longer emitted by the compiler.

A `#[coverage(off|on)]` attribute was found in a position where it is not
allowed.

Coverage attributes can be applied to:
- Function and method declarations that have a body, including trait methods
  that have a default implementation.
- Closure expressions, in situations where attributes can be applied to
  expressions.
- `impl` blocks (inherent or trait), and modules.

Example of erroneous code:

```ignore (no longer emitted)
unsafe extern "C" {
    #[coverage(off)]
    fn foreign_fn();
}
```

When using the `-C instrument-coverage` flag, coverage attributes act as a
hint to the compiler that it should instrument or not instrument the
corresponding function or enclosed functions. The precise effect of applying
a coverage attribute is not guaranteed and may change in future compiler
versions.
#### This error code is internal to the compiler and will not be emitted with normal Rust code.

The internal `rustc_allowed_through_unstable_modules` attribute must be used
on an item with a `stable` attribute.

Erroneous code example:

```compile_fail,E0789
// NOTE: both of these attributes are perma-unstable and should *never* be
//       used outside of the compiler and standard library.
#![feature(rustc_attrs)]
#![feature(staged_api)]
#![allow(internal_features)]

#![unstable(feature = "foo_module", reason = "...", issue = "123")]

#[rustc_allowed_through_unstable_modules = "deprecation message"]
// #[stable(feature = "foo", since = "1.0")]
struct Foo;
// ^^^ error: `rustc_allowed_through_unstable_modules` attribute must be
//            paired with a `stable` attribute
```

Typically when an item is marked with a `stable` attribute, the modules that
enclose the item must also be marked with `stable` attributes, otherwise the
item becomes *de facto* unstable. `#[rustc_allowed_through_unstable_modules]`
is a workaround which allows an item to "escape" its unstable parent modules.
This error occurs when an item is marked with
`#[rustc_allowed_through_unstable_modules]` but no supplementary `stable`
attribute exists. See [#99288](https://github.com/rust-lang/rust/pull/99288)
for an example of `#[rustc_allowed_through_unstable_modules]` in use.
You need to specify a specific implementation of the trait in order to call the
method.

Erroneous code example:

```compile_fail,E0790
trait Coroutine {
    fn create() -> u32;
}

struct Impl;

impl Coroutine for Impl {
    fn create() -> u32 { 1 }
}

struct AnotherImpl;

impl Coroutine for AnotherImpl {
    fn create() -> u32 { 2 }
}

let cont: u32 = Coroutine::create();
// error, impossible to choose one of Coroutine trait implementation
// Should it be Impl or AnotherImpl, maybe something else?
```

This error can be solved by adding type annotations that provide the missing
information to the compiler. In this case, the solution is to use a concrete
type:

```
trait Coroutine {
    fn create() -> u32;
}

struct AnotherImpl;

impl Coroutine for AnotherImpl {
    fn create() -> u32 { 2 }
}

let gen1 = AnotherImpl::create();

// if there are multiple methods with same name (different traits)
let gen2 = <AnotherImpl as Coroutine>::create();
```
Static variables with the `#[linkage]` attribute within external blocks
must have one of the following types, which are equivalent to a nullable
pointer in C:

* `*mut T` or `*const T`, where `T` may be any type.

* An enumerator type with no `#[repr]` attribute and with two variants, where
  one of the variants has no fields, and the other has a single field of one of
  the following non-nullable types:
  * Reference type
  * Function pointer type

  The variants can appear in either order.

For example, the following declaration is invalid:

```compile_fail,E0791
#![feature(linkage)]

extern "C" {
    #[linkage = "extern_weak"]
    static foo: i8;
}
```

The following declarations are valid:

```
#![feature(linkage)]

extern "C" {
    #[linkage = "extern_weak"]
    static foo: Option<unsafe extern "C" fn()>;

    #[linkage = "extern_weak"]
    static bar: Option<&'static i8>;

    #[linkage = "extern_weak"]
    static baz: *mut i8;
}
```
A type alias impl trait can only have its hidden type assigned
when used fully generically (and within their defining scope).
This means

```compile_fail,E0792
#![feature(type_alias_impl_trait)]

type Foo<T> = impl std::fmt::Debug;

#[define_opaque(Foo)]
fn foo() -> Foo<u32> {
    5u32
}
```

is not accepted. If it were accepted, one could create unsound situations like

```compile_fail,E0792
#![feature(type_alias_impl_trait)]

type Foo<T> = impl Default;

#[define_opaque(Foo)]
fn foo() -> Foo<u32> {
    5u32
}

fn main() {
    let x = Foo::<&'static mut String>::default();
}
```


Instead you need to make the function generic:

```
#![feature(type_alias_impl_trait)]

type Foo<T> = impl std::fmt::Debug;

#[define_opaque(Foo)]
fn foo<U>() -> Foo<U> {
    5u32
}

fn main() {}
```

This means that no matter the generic parameter to `foo`,
the hidden type will always be `u32`.
If you want to link the generic parameter to the hidden type,
you can do that, too:


```
#![feature(type_alias_impl_trait)]

use std::fmt::Debug;

type Foo<T: Debug> = impl Debug;

#[define_opaque(Foo)]
fn foo<U: Debug>() -> Foo<U> {
    Vec::<U>::new()
}

fn main() {}
```
An unaligned reference to a field of a [packed] `struct` or `union` was created.

The `#[repr(packed)]` attribute removes padding between fields, which can
cause fields to be stored at unaligned memory addresses. Creating references
to such fields violates Rust's memory safety guarantees and can lead to
undefined behavior in optimized code.

Erroneous code example:

```compile_fail,E0793
#[repr(packed)]
pub struct Foo {
    field1: u64,
    field2: u8,
}

unsafe {
    let foo = Foo { field1: 0, field2: 0 };
    // Accessing the field directly is fine.
    let val = foo.field1;
    // A reference to a packed field causes a error.
    let val = &foo.field1; // ERROR
    // An implicit `&` is added in format strings, causing the same error.
    println!("{}", foo.field1); // ERROR
}
```

Creating a reference to an insufficiently aligned packed field is
[undefined behavior] and therefore disallowed. Using an `unsafe` block does not
change anything about this. Instead, the code should do a copy of the data in
the packed field or use raw pointers and unaligned accesses.

```
#[repr(packed)]
pub struct Foo {
    field1: u64,
    field2: u8,
}

unsafe {
    let foo = Foo { field1: 0, field2: 0 };

    // Instead of a reference, we can create a raw pointer...
    let ptr = std::ptr::addr_of!(foo.field1);
    // ... and then (crucially!) access it in an explicitly unaligned way.
    let val = unsafe { ptr.read_unaligned() };
    // This would *NOT* be correct:
    // let val = unsafe { *ptr }; // Undefined Behavior due to unaligned load!

    // For formatting, we can create a copy to avoid the direct reference.
    let copy = foo.field1;
    println!("{}", copy);

    // Creating a copy can be written in a single line with curly braces.
    // (This is equivalent to the two lines above.)
    println!("{}", { foo.field1 });

    // A reference to a field that will always be sufficiently aligned is safe:
    println!("{}", foo.field2);
}
```

### Unions

Although creating a reference to a `union` field is `unsafe`, this error
will still be triggered if the referenced field is not sufficiently
aligned. Use `addr_of!` and raw pointers in the same way as for struct fields.

```compile_fail,E0793
#[repr(packed)]
pub union Foo {
    field1: u64,
    field2: u8,
}

unsafe {
    let foo = Foo { field1: 0 };
    // Accessing the field directly is fine.
    let val = foo.field1;

    // A reference to a packed union field causes an error.
    let val = &foo.field1; // ERROR
}
```

### Additional information

Note that this error is specifically about *references* to packed fields.
Direct by-value access of those fields is fine, since then the compiler has
enough information to generate the correct kind of access.

See [issue #82523] for more information.

[packed]: https://doc.rust-lang.org/reference/type-layout.html#the-alignment-modifiers
[undefined behavior]: https://doc.rust-lang.org/reference/behavior-considered-undefined.html
[issue #82523]: https://github.com/rust-lang/rust/issues/82523
A lifetime parameter of a function definition is called *late-bound* if it both:

1. appears in an argument type
2. does not appear in a generic type constraint

You cannot specify lifetime arguments for late-bound lifetime parameters.

Erroneous code example:

```compile_fail,E0794
fn foo<'a>(x: &'a str) -> &'a str { x }
let _ = foo::<'static>;
```

The type of a concrete instance of a generic function is universally quantified
over late-bound lifetime parameters. This is because we want the function to
work for any lifetime instantiated for the late-bound lifetime parameter, no
matter where the function is called. Consequently, it doesn't make sense to
specify arguments for late-bound lifetime parameters, since they are not
resolved until the function's call site(s).

To fix the issue, remove the specified lifetime:

```
fn foo<'a>(x: &'a str) -> &'a str { x }
let _ = foo;
```

### Additional information

Lifetime parameters that are not late-bound are called *early-bound*.
Confusion may arise from the fact that late-bound and early-bound
lifetime parameters are declared the same way in function definitions.
When referring to a function pointer type, universal quantification over
late-bound lifetime parameters can be made explicit:

```
trait BarTrait<'a> {}

struct Bar<'a> {
    s: &'a str
}

impl<'a> BarTrait<'a> for Bar<'a> {}

fn bar<'a, 'b, T>(x: &'a str, _t: T) -> &'a str
where T: BarTrait<'b>
{
    x
}

let bar_fn: for<'a> fn(&'a str, Bar<'static>) -> &'a str = bar; // OK
let bar_fn2 = bar::<'static, Bar>; // Not allowed
let bar_fn3 = bar::<Bar>; // OK
```

In the definition of `bar`, the lifetime parameter `'a` is late-bound, while
`'b` is early-bound. This is reflected in the type annotation for `bar_fn`,
where `'a` is universally quantified and `'b` is instantiated with a specific
lifetime. It is not allowed to explicitly specify early-bound lifetime
arguments when late-bound lifetime parameters are present (as for `bar_fn2`,
see [issue #42868](https://github.com/rust-lang/rust/issues/42868)), although
the types that are constrained by early-bound parameters can be specified (as
for `bar_fn3`).
Invalid argument for the `offset_of!` macro.

Erroneous code example:

```compile_fail,E0795
#![feature(offset_of_enum)]

let x = std::mem::offset_of!(Option<u8>, Some);
```

The `offset_of!` macro gives the offset of a field within a type. It can
navigate through enum variants, but the final component of its second argument
must be a field and not a variant.

The offset of the contained `u8` in the `Option<u8>` can be found by specifying
the field name `0`:

```
#![feature(offset_of_enum)]

let x: usize = std::mem::offset_of!(Option<u8>, Some.0);
```

The discriminant of an enumeration may be read with `core::mem::discriminant`,
but this is not always a value physically present within the enum.

Further information about enum layout may be found at
https://rust-lang.github.io/unsafe-code-guidelines/layout/enums.html.
#### Note: this error code is no longer emitted by the compiler.

You have created a reference to a mutable static.

Erroneous code example:

```
static mut X: i32 = 23;
fn work() {
  let _val = unsafe { X };
}
let x_ref = unsafe { &mut X };
work();
// The next line has Undefined Behavior!
// `x_ref` is a mutable reference and allows no aliases,
// but `work` has been reading the reference between
// the moment `x_ref` was created and when it was used.
// This violates the uniqueness of `x_ref`.
*x_ref = 42;
```

A reference to a mutable static has lifetime `'static`. This is very dangerous
as it is easy to accidentally overlap the lifetime of that reference with
other, conflicting accesses to the same static.

References to mutable statics are a hard error in the 2024 edition.
Struct update syntax was used without a base expression.

Erroneous code example:

```compile_fail,E0797
struct Foo {
    fizz: u8,
    buzz: u8
}

let f1 = Foo { fizz: 10, buzz: 1};
let f2 = Foo { fizz: 10, .. }; // error
```

Using struct update syntax requires a 'base expression'.
This will be used to fill remaining fields.

```
struct Foo {
    fizz: u8,
    buzz: u8
}

let f1 = Foo { fizz: 10, buzz: 1};
let f2 = Foo { fizz: 10, ..f1 };
```
Functions marked as `cmse-nonsecure-call` place restrictions on their
inputs and outputs.

- inputs must fit in the 4 available 32-bit argument registers. Alignment
is relevant.
- outputs must either fit in 4 bytes, or be a foundational type of
size 8 (`i64`, `u64`, `f64`).
- no generics can be used in the signature

For more information,
see [arm's aapcs32](https://github.com/ARM-software/abi-aa/releases).

Erroneous code example:

```ignore (host errors will not match for target)
#![feature(abi_cmse_nonsecure_call)]

#[no_mangle]
pub fn test(
    f: extern "cmse-nonsecure-call" fn(u32, u32, u32, u32, u32) -> u32,
) -> u32 {
    f(1, 2, 3, 4, 5)
}
```

Arguments' alignment is respected. In the example below, padding is inserted
so that the `u64` argument is passed in registers r2 and r3. There is then no
room left for the final `f32` argument

```ignore (host errors will not match for target)
#![feature(abi_cmse_nonsecure_call)]

#[no_mangle]
pub fn test(
    f: extern "cmse-nonsecure-call" fn(u32, u64, f32) -> u32,
) -> u32 {
    f(1, 2, 3.0)
}
```
Something other than a type or const parameter has been used when one was
expected.

Erroneous code example:

```compile_fail,E0799
fn bad1() -> impl Sized + use<main> {}

fn bad2(x: ()) -> impl Sized + use<x> {}

fn main() {}
```

In the given examples, for `bad1`, the name `main` corresponds to a function
rather than a type or const parameter. In `bad2`, the name `x` corresponds to
a function argument rather than a type or const parameter.

Only type and const parameters, including `Self`, may be captured by
`use<...>` precise capturing bounds.
A type or const parameter of the given name is not in scope.

Erroneous code examples:

```compile_fail,E0800
fn missing() -> impl Sized + use<T> {}
```

To fix this error, please verify you didn't misspell the type or const
parameter, or double-check if you forgot to declare the parameter in
the list of generics.
The `self` parameter in a method has an invalid generic "receiver type".

Erroneous code example:

```compile_fail,E0801
struct Foo;

impl Foo {
    fn foo<R: std::ops::Deref<Target=Self>>(self: R) {}
}
```

or alternatively,

```compile_fail,E0801
struct Foo;

impl Foo {
    fn foo(self: impl std::ops::Deref<Target=Self>) {}
}
```

Methods take a special first parameter, termed `self`. It's normal to
use `self`, `&self` or `&mut self`, which are syntactic sugar for
`self: Self`, `self: &Self`, and `self: &mut Self` respectively.
But it's also possible to use more sophisticated types of `self`
parameter, for instance `std::rc::Rc<Self>`. The set of allowable
`Self` types is extensible using the nightly feature
[Arbitrary self types][AST].
This will extend the valid set of `Self` types to anything which implements
`std::ops::Deref<Target=Self>`, for example `Rc<Self>`, `Box<Self>`, or
your own smart pointers that do the same.

However, even with that feature, the `self` type must be concrete.
Generic `self` types are not permitted. Specifically, a `self` type will
be rejected if it is a type parameter defined on the method.

These are OK:

```
struct Foo;

impl Foo {
    fn foo(self) {}
    fn foo2(self: std::rc::Rc<Self>) {} // or some other similar
        // smart pointer if you enable arbitrary self types and
        // the pointer implements Deref<Target=Self>
}
```

[AST]: https://doc.rust-lang.org/unstable-book/language-features/arbitrary-self-types.html
The target of `derive(CoercePointee)` macro has inadmissible specification for
a meaningful use.

Erroneous code examples:

The target data is not a `struct`.

```compile_fail,E0802
#![feature(coerce_pointee)]
use std::marker::CoercePointee;
#[derive(CoercePointee)]
enum NotStruct<'a, T: ?Sized> {
    Variant(&'a T),
}
```

The target data has a layout that is not transparent, or `repr(transparent)`
in other words.

```compile_fail,E0802
#![feature(coerce_pointee)]
use std::marker::CoercePointee;
#[derive(CoercePointee)]
struct NotTransparent<'a, #[pointee] T: ?Sized> {
    ptr: &'a T,
}
```

The target data has no data field.

```compile_fail,E0802
#![feature(coerce_pointee)]
use std::marker::CoercePointee;
#[derive(CoercePointee)]
#[repr(transparent)]
struct NoField<'a, #[pointee] T: ?Sized> {}
```

The target data is not generic over any data, or has no generic type parameter.

```compile_fail,E0802
#![feature(coerce_pointee)]
use std::marker::CoercePointee;
#[derive(CoercePointee)]
#[repr(transparent)]
struct NoGeneric<'a>(&'a u8);
```

The target data has multiple generic type parameters, but none is designated as
a pointee for coercion.

```compile_fail,E0802
#![feature(coerce_pointee)]
use std::marker::CoercePointee;
#[derive(CoercePointee)]
#[repr(transparent)]
struct AmbiguousPointee<'a, T1: ?Sized, T2: ?Sized> {
    a: (&'a T1, &'a T2),
}
```

The target data has multiple generic type parameters that are designated as
pointees for coercion.

```compile_fail,E0802
#![feature(coerce_pointee)]
use std::marker::CoercePointee;
#[derive(CoercePointee)]
#[repr(transparent)]
struct TooManyPointees<
    'a,
    #[pointee] A: ?Sized,
    #[pointee] B: ?Sized>
((&'a A, &'a B));
```

The type parameter that is designated as a pointee is not marked `?Sized`.

```compile_fail,E0802
#![feature(coerce_pointee)]
use std::marker::CoercePointee;
#[derive(CoercePointee)]
#[repr(transparent)]
struct NoMaybeSized<'a, #[pointee] T> {
    ptr: &'a T,
}
```

In summary, the `CoercePointee` macro demands the type to be a `struct` that is
generic over at least one type or over more types, one of which is marked with
`#[pointee]`, and has at least one data field and adopts a `repr(transparent)`
layout.
The only generic type or the type marked with `#[pointee]` has to be also
marked as `?Sized`.
A trait implementation returns a reference without an
explicit lifetime linking it to `self`.
It commonly arises in generic trait implementations
requiring explicit lifetime bounds.

Erroneous code example:

```compile_fail,E0803
trait DataAccess<T> {
    fn get_ref(&self) -> T;
}

struct Container<'a> {
    value: &'a f64,
}

// Attempting to implement reference return
impl<'a> DataAccess<&f64> for Container<'a> {
    fn get_ref(&self) -> &f64 { // Error: Lifetime mismatch
        self.value
    }
}
```

The trait method returns &f64 requiring an independent lifetime
The struct Container<'a> carries lifetime parameter 'a
The compiler cannot verify if the returned reference satisfies 'a constraints
Solution
Explicitly bind lifetimes to clarify constraints:
```
// Modified trait with explicit lifetime binding
trait DataAccess<'a, T> {
    fn get_ref(&'a self) -> T;
}

struct Container<'a> {
    value: &'a f64,
}

// Correct implementation (bound lifetimes)
impl<'a> DataAccess<'a, &'a f64> for Container<'a> {
    fn get_ref(&'a self) -> &'a f64 {
        self.value
    }
}
```
An auto trait cannot be added to the bounds of a `dyn Trait` type via
a pointer cast.

Erroneous code example:

```rust,edition2021,compile_fail,E0804
let ptr: *const dyn core::any::Any = &();
_ = ptr as *const (dyn core::any::Any + Send);
```

Adding an auto trait can make the vtable invalid, potentially causing
UB in safe code afterwards. For example:

```rust,edition2021,no_run
use core::{mem::transmute, ptr::NonNull};

trait Trait {
    fn f(&self)
    where
        Self: Send;
}

impl Trait for NonNull<()> {
    fn f(&self) {
        unreachable!()
    }
}

fn main() {
    let unsend: &dyn Trait = &NonNull::dangling();
    let bad: &(dyn Trait + Send) = unsafe { transmute(unsend) };
    // This crashes, since the vtable for `NonNull as dyn Trait` does
    // not have an entry for `Trait::f`.
    bad.f();
}
```

To fix this error, you can use `transmute` rather than pointer casts,
but you must ensure that the vtable is valid for the pointer's type
before calling a method on the trait object or allowing other code to
do so.
An attribute was given an invalid number of arguments

Erroneous code example:

```compile_fail,E0805
#[inline()] // error! should either have a single argument, or no parentheses
fn foo() {}

#[inline(always, never)] // error! should have only one argument, not two
fn bar() {}
```

To fix this, either give the right number of arguments the attribute needs.
In the case of inline, this could be none at all:

```
#[inline]
fn foo() {}
```

or only one:

```
#[inline(always)]
fn foo() {}
```
E