0.999], k, df)
>>> np.allclose([0.001, 0.5, 0.999], studentized_range.cdf(vals, k, df))
True

Rather than using (``studentized_range.rvs``) to generate random variates,
which is very slow for this distribution, we can approximate the inverse
CDF using an interpolator, and then perform inverse transform sampling
with this approximate inverse CDF.

This distribution has an infinite but thin right tail, so we focus our
attention on the leftmost 99.9 percent.

>>> a, b = studentized_range.ppf([0, .999], k, df)
>>> a, b
0, 7.41058083802274

>>> from scipy.interpolate import interp1d
>>> rng = np.random.default_rng()
>>> xs = np.linspace(a, b, 50)
>>> cdf = studentized_range.cdf(xs, k, df)
# Create an interpolant of the inverse CDF
>>> ppf = interp1d(cdf, xs, fill_value='extrapolate')
# Perform inverse transform sampling using the interpolant
>>> r = ppf(rng.uniform(size=1000))

And compare the histogram:

>>> ax.hist(r, density=True, histtype='stepfilled', alpha=0.2)
>>> ax.legend(loc='best', frameon=False)
>>> plt.show()

c