t cleared) - and any subsequent call to
pam_keyinit really does have a session keyring already installed, and so the
check works correctly there.

Reverting to the previous behaviour will cause the kernel to subscribe the
process to the user-session keyring as its session keyring if it doesn't have a
session keyring of its own.  pam_keyinit will detect this and install a new
session keyring anyway (and won't clear the revert flag).

This can be tested by commenting out pam_keyinit in the /etc/pam.d files and
running the following program a couple of times in a row:

	#include <stdio.h>
	#include <stdlib.h>
	#include <keyutils.h>
	int main(int argc, char *argv[])
	{
		key_serial_t uk, usk, sk;
		uk = keyctl_get_keyring_ID(KEY_SPEC_USER_KEYRING, 0);
		usk = keyctl_get_keyring_ID(KEY_SPEC_USER_SESSION_KEYRING, 0);
		sk = keyctl_get_keyring_ID(KEY_SPEC_SESSION_KEYRING, 0);
		printf("keys: %08x %08x %08x\n", uk, usk, sk);
		return 0;
	}

Without the patch, I see:

	keys: 3884e281 24c4dfcf 22825f8e
	keys: 3884e281 24c4dfcf 068772be

With the patch, I see:

	keys: 26be9c83 0e755ce0 0e755ce0
	keys: 26be9c83 0e755ce0 0e755ce0

As can be seen, with the patch, the session keyring is the same as the
user-session keyring each time; without the patch a new session keyring is
generated each time.

Reported-by: Greg Wettstein <greg@enjellic.com>
Signed-off-by: David Howells <dhowells@redhat.com>
Tested-by: Greg Wettstein <greg@enjellic.com>
Signed-off-by: James Morris <jmorris@namei.org>
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