ó âdc@s.dZeZeƒZed„ZdgZdS(s† This module provides a newnext() function in Python 2 that mimics the behaviour of ``next()`` in Python 3, falling back to Python 2's behaviour for compatibility if this fails. ``newnext(iterator)`` calls the iterator's ``__next__()`` method if it exists. If this doesn't exist, it falls back to calling a ``next()`` method. For example: >>> class Odds(object): ... def __init__(self, start=1): ... self.value = start - 2 ... def __next__(self): # note the Py3 interface ... self.value += 2 ... return self.value ... def __iter__(self): ... return self ... >>> iterator = Odds() >>> next(iterator) 1 >>> next(iterator) 3 If you are defining your own custom iterator class as above, it is preferable to explicitly decorate the class with the @implements_iterator decorator from ``future.utils`` as follows: >>> @implements_iterator ... class Odds(object): ... # etc ... pass This next() function is primarily for consuming iterators defined in Python 3 code elsewhere that we would like to run on Python 2 or 3. cCs–ycy|jƒSWnNtk ray|jƒSWqbtk r]tdj|jjƒƒ‚qbXnXWn,tk r‘}|tkrŠ|‚q’|SnXdS(sĵ next(iterator[, default]) Return the next item from the iterator. If default is given and the iterator is exhausted, it is returned instead of raising StopIteration. s'{0}' object is not an iteratorN( t__next__tAttributeErrortnextt TypeErrortformatt __class__t__name__t StopIterationt _SENTINEL(titeratortdefaultte((se/home/josie/.config/GIMP/2.10/plug-ins/export_layers/pygimplib/_lib/future/future/builtins/newnext.pytnewnext+s      R N(t__doc__Rt _builtin_nexttobjectRR t__all__(((se/home/josie/.config/GIMP/2.10/plug-ins/export_layers/pygimplib/_lib/future/future/builtins/newnext.pyt%s  """ ``python-future``: pure Python implementation of Python 3 round(). """ from future.utils import PYPY, PY26, bind_method # Use the decimal module for simplicity of implementation (and # hopefully correctness). from decimal import Decimal, ROUND_HALF_EVEN def newround(number, ndigits=None): """ See Python 3 documentation: uses Banker's Rounding. Delegates to the __round__ method if for some reason this exists. If not, rounds a number to a given precision in decimal digits (default 0 digits). This returns an int when called with one argument, otherwise the same type as the number. ndigits may be negative. See the test_round method in future/tests/test_builtins.py for examples. """ return_int = False if ndigits is None: return_int = True ndigits = 0 if hasattr(number, '__round__'): return number.__round__(ndigits) if ndigits < 0: raise NotImplementedError('negative ndigits not supported yet') exponent = Decimal('10') ** (-ndigits) if PYPY: # Work around issue #24: round() breaks on PyPy with NumPy's types if 'numpy' in repr(type(number)): number = float(number) if not PY26: d = Decimal.from_float(number).quantize(exponent, rounding=ROUND_HALF_EVEN) else: d = from_float_26(number).quantize(exponent, rounding=ROUND_HALF_EVEN) if return_int: return int(d) else: return float(d) ### From Python 2.7's decimal.py. Only needed to support Py2.6: def from_float_26(f): """Converts a float to a decimal number, exactly. Note that Decimal.from_float(0.1) is not the same as Decimal('0.1'). Since 0.1 is not exactly representable in binary floating point, the value is stored as the nearest representable value which is 0x1.999999999999ap-4. The exact equivalent of the value in decimal is 0.1000000000000000055511151231257827021181583404541015625. >>> Decimal.from_float(0.1) Decimal('0.1000000000000000055511151231257827021181583404541015625') >>> Decimal.from_float(float('nan')) Decimal('NaN') >>> Decimal.from_float(float('inf')) Decimal('Infinity') >>> Decimal.from_float(-float('inf')) Decimal('-Infinity') >>> Decimal.from_float(-0.0) Decimal('-0') """ import math as _math from decimal import _dec_from_triple # only available on Py2.6 and Py2.7 (not 3.3) if isinstance(f, (int, long)): # handle integer inputs return Decimal(f) if _math.isinf(f) or _math.isnan(f): # raises TypeError if not a float return Decimal(repr(f)) if _math.copysign(1.0, f) == 1.0: sign = 0 else: sign = 1 n, d = abs(f).as_integer_ratio() # int.bit_length() method doesn't exist on Py2.6: def bit_length(d): if d != 0: return len(bin(abs(d))) - 2 else: return 0 k = bit_length(d) - 1 result = _dec_from_triple(sign, str(n*5**k), -k) return result __all__ = ['newround']