> linalg.det(b)
3.0
>>> # An array with the shape (3, 2, 2, 2)
>>> c = np.array([[[[1., 2.], [3., 4.]],
...                [[5., 6.], [7., 8.]]],
...               [[[9., 10.], [11., 12.]],
...                [[13., 14.], [15., 16.]]],
...               [[[17., 18.], [19., 20.]],
...                [[21., 22.], [23., 24.]]]])
>>> linalg.det(c)  # The resulting shape is (3, 2)
array([[-2., -2.],
       [-2., -2.],
       [-2., -2.]])
>>> linalg.det(c[0, 0])  # Confirm the (0, 0) slice, [[1, 2], [3, 4]]
-2.0
rG