ally. inplace : bool, default False If True, perform operation in-place. kind : {'quicksort', 'mergesort', 'heapsort', 'stable'}, default 'quicksort' Choice of sorting algorithm. See also :func:`numpy.sort` for more information. 'mergesort' and 'stable' are the only stable algorithms. For DataFrames, this option is only applied when sorting on a single column or label. na_position : {'first', 'last'}, default 'last' If 'first' puts NaNs at the beginning, 'last' puts NaNs at the end. Not implemented for MultiIndex. sort_remaining : bool, default True If True and sorting by level and index is multilevel, sort by other levels too (in order) after sorting by specified level. ignore_index : bool, default False If True, the resulting axis will be labeled 0, 1, …, n - 1. key : callable, optional If not None, apply the key function to the index values before sorting. This is similar to the `key` argument in the builtin :meth:`sorted` function, with the notable difference that this `key` function should be *vectorized*. It should expect an ``Index`` and return an ``Index`` of the same shape. Returns ------- Series or None The original Series sorted by the labels or None if ``inplace=True``. See Also -------- DataFrame.sort_index: Sort DataFrame by the index. DataFrame.sort_values: Sort DataFrame by the value. Series.sort_values : Sort Series by the value. Examples -------- >>> s = pd.Series(['a', 'b', 'c', 'd'], index=[3, 2, 1, 4]) >>> s.sort_index() 1 c 2 b 3 a 4 d dtype: object Sort Descending >>> s.sort_index(ascending=False) 4 d 3 a 2 b 1 c dtype: object By default NaNs are put at the end, but use `na_position` to place them at the beginning >>> s = pd.Series(['a', 'b', 'c', 'd'], index=[3, 2, 1, np.nan]) >>> s.sort_index(na_position='first') NaN d 1.0 c 2.0 b 3.0 a dtype: object Specify index level to sort >>> arrays = [np.array(['qux', 'qux', 'foo', 'foo', ... 'baz', 'baz', 'bar', 'bar']), ... np.array(['two', 'one', 'two', 'one', ... 'two', 'one', 'two', 'one'])] >>> s = pd.Series([1, 2, 3, 4, 5, 6, 7, 8], index=arrays) >>> s.sort_index(level=1) bar one 8 baz one 6 foo one 4 qux one 2 bar two 7 baz two 5 foo two 3 qux two 1 dtype: int64 Does not sort by remaining levels when sorting by levels >>> s.sort_index(level=1, sort_remaining=False) qux one 2 foo one 4 baz one 6 bar one 8 qux two 1 foo two 3 baz two 5 bar two 7 dtype: int64 Apply a key function before sorting >>> s = pd.Series([1, 2, 3, 4], index=['A', 'b', 'C', 'd']) >>> s.sort_index(key=lambda x : x.str.lower()) A 1 b 2 C 3 d 4 dtype: int64 r*