numpy.polynomial.hermite_e.hermefromroots

    Notes
    -----
    The coefficients are determined by multiplying together linear factors
    of the form ``(x - r_i)``, i.e.

    .. math:: p(x) = (x - r_0) (x - r_1) ... (x - r_n)

    where ``n == len(roots) - 1``; note that this implies that ``1`` is always
    returned for :math:`a_n`.

    Examples
    --------
    >>> from numpy.polynomial import polynomial as P
    >>> P.polyfromroots((-1,0,1)) # x(x - 1)(x + 1) = x^3 - x
    array([ 0., -1.,  0.,  1.])
    >>> j = complex(0,1)
    >>> P.polyfromroots((-j,j)) # complex returned, though values are real
    array([1.+0.j,  0.+0.j,  1.+0.j])

    )